The winery sold 81 cases of wine this week. If twice
as many red cases were sold than white, how many
white cases were sold this week?


A. 32 cases
B. 61 cases
C. 27 cases
D. 54 cases​

Answers

Answer 1

Answer:

Option (C)

Step-by-step explanation:

Let the red cases sold = r

and the number of white cases sold = w

Total number of cases sold by the winery = 81

r + w = 81 -------(1)

If number of red cases sold is twice of white cases sold,

r = 2w ------- (2)

By substituting the value of r from equation (2) to equation (1),

2w + w = 81

3w = 81

w = 27 cases

From equation (1),

r + 27 = 81

r = 54 cases

Therefore, number of white cases sold are 27 cases

Option (C) is he answer.


Related Questions

The set is a basis for a subspace W. Use the Gram-Schmidt process to produce an orthogonal basis for W. Assume the vectors are in the order bold x1 and bold x2
1 7
-4 -7
0 -6
1 1
The orthogonal basis produced using the Gram-Schmidt process for W is:__________. (Use a comma to separate vectors as needed.)

Answers

Answer:

[tex]y_1 = \left[\begin{array}{ccc}1\\-4\\0\\1\end{array}\right][/tex]  ,  [tex]y_2 = \left[\begin{array}{ccc}5\\1\\-6\\-1\end{array}\right][/tex]

Step-by-step explanation:

[tex]x_1 = \left[\begin{array}{ccc}1\\-4\\0\\1\end{array}\right][/tex]    and [tex]x_2 = \left[\begin{array}{ccc}7\\-7\\-6\\1\end{array}\right][/tex]

Using Gram-Schmidt process to produce an orthogonal basis for W

[tex]y_1 = x_1 = \left[\begin{array}{ccc}1\\-4\\0\\1\end{array}\right][/tex]

Now we know X₁ , X₂ and Y₁

Lets solve for Y₂

[tex]y_2 = x_2- \frac{x_2*y_1}{y_1*y_1}y_1[/tex]

see attached for the solution of Y₂

plzzz help 6≥ -6(a+2)

Answers

Answer:

a[tex]\geq[/tex]-3

Step-by-step explanation:

Answer:

-3  ≤  a

Step-by-step explanation:

6≥ -6(a+2)

Divide each side by -6, remembering to flip the inequality

6/-6 ≤ -6/-6(a+2)

-1 ≤ (a+2)

Subtract 2 from each side

-1 -2  ≤  a+2-2

-3  ≤  a

(I NEED HELP) The data below shows the scores of some students on a test: 23, 27, 21, 20, 25, 31, 22 Which box-and-whisker plot represents the data?

Answers

Answer:

B

Step-by-step explanation:

Answer:

the 2nd one

Step-by-step explanation:

because the Minimum is 20

the Maximum is 31

the median is 23

20, 21, 22, 23, 25, 27,  31,

21, 22, 23, 25, 27

22, 23, 25,

23

Linda, Reuben, and Manuel have a total of $70 in their wallets. Reuben has $10 more than Linda. Manuel has 2 times what Linda has. How much does each have? Amount in Linda's wallet: $ Amount in Reuben's wallet: $ Amount in Manuel's wallet:

Answers

Answer:

Linda has $15Reuben has $25Manuel has $30

Step-by-step explanation:

Together, they have 4 times what Linda has, plus $10. So, Linda has 1/4 of $60 = $15.

  Linda has $15

  Reuben has $25 . . . . . . $10 more than Linda

  Manuel has $30 . . . . . . twice what Linda has

Degree Of Length Degree Of Width Degree Of Height Degree Of Volume

Answers

Answer: length = 1, width = 1, height = 3, volume = 5

Step-by-step explanation:

Degree is the biggest exponent for the variables in the expression

Length = 4x - 1. The exponent for x is 1 --> degree = 1

Width = x          The exponent for x is 1  --> degree = 1

Height = x³       The exponent for x³ is 3  --> degree = 3

Volume = 4x⁵ - x⁴.  The biggest exponent for x is 5  --> degree = 5

Answer:

- First answer: 1

- Second answer: 1

- Third answer: 3

- Last answer: 5

Step-by-step explanation:

Correct on E2020

f(x)=x^2+12x+7 f(x)=(x+_)^2+_ Rewrite the function by completing the square

Answers

Answer:

f(x) = (x + 6)² - 29

Step-by-step explanation:

Given

f(x) = x² + 12x + 7

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² + 12x

x² + 2(6)x + 36 - 36 + 7

= (x + 6)² - 29, thus

f(x) = (x + 6)² - 29

answers are 6, and -29

show all work!! Plus this is the same question as my last one so you get a total of 25 points if you answer both! Just copy the answer you got from this one and paste it in the other question (the same question)

Answers

Answer:

increase of 30

Step-by-step explanation:

1255- 1075 = 180

This is an increase of 180

Divide by the number of numbers which is 6

180 /6 = 30

The mean will increase by 30

Answer:

+30

Step-by-step explanation:

1255- 1075 = 180

180 /6 = 30

an auto dealer offers a compact car, a midsize, a sport utility vehicle, and a light truck, each either in standard, custom, or sport styling, a choice of manual or automatic transmission, and a selection from 7 colors. How many ways of buying a vehicle from this dealer are there?

Answers

Answer: 168

Step-by-step explanation:

First, let's count the types of selection:

We can select:

Type of car: a compact car, a midsize, a sport utility vehicle, and a light truck (4 options)

Pack: standard, custom, or sport styling, (3 options)

type of transmission: Manual or automatic (2 options)

Color: (7 options)

The total number of combinations is equal to the product of the number of options in each selection:

C = 4*3*2*7 = 168

The alpha level that a researcher sets at the beginning of the experiment is the level to which he wishes to limit the probability of making the error of____________

Answers

Answer:

not rejecting the null hypothesis when it is false.

Step-by-step explanation:

Significance level or alpha level is the probability of rejecting the null hypothesis when null hypothesis is true. It is considered as a probability of making a wrong decision. It is a statistical test which determines probability of type I error. If the obtained probability is equal of less than critical probability value then reject the null hypothesis.

For making the error, it should not reject the null hypothesis at the time when it should be false.

What is alpha level?

It is the level where the probability of rejecting the null hypothesis at the time when the null hypothesis should be true. It is relevant for making the incorrect decision. Also, it is the statistical test that measured the probability of type 1 error.

Therefore, For making the error, it should not reject the null hypothesis at the time when it should be false.

Learn more about error here: https://brainly.com/question/18831983

Rewrite the equation in =+AxByC form. Use integers for A, B, and C. =−y6−6+x4

Answers

Answer:

6x + y = -18

Step-by-step explanation:

The given equation is,

y - 6 = -6(x + 4)

We have to rewrite this equation in the form of Ax + By = C

Where A, B and C are the integers.

By solving the given equation,

y - 6 = -6x - 24 [Distributive property]

y - 6 + 6 = -6x - 24 + 6 [By adding 6 on both the sides of the equation]

y = -6x - 18

y + 6x = -6x + 6x - 18

6x + y = -18

Here A = 6, B = 1 and C = -18.

Therefore, 6x + y = -18 will be the equation.

Find the area of the surface given by z = f(x, y) that lies above the region R. f(x, y) = 64 + x2 − y2 R = {(x, y): x2 + y2 ≤ 64}

Answers

The area of the surface above the region R is 4096π square units.

Given that:

The function: [tex]f(x, y) = 64 + x^2 - y^2[/tex]

The region R is the disk with a radius of 8 units [tex]x^2 + y^2 \le 64[/tex].

To find the area of the surface given by z = f(x, y) that lies above the region R, to calculate the double integral over the region R of the function f(x, y) with respect to dA.

The integral for the area is given by:

[tex]Area = \int\int_R f(x, y) dA[/tex]

To evaluate this integral, we need to set up the limits of integration for x and y over the region R, which is the disk cantered at the origin with a radius of 8 units.

Using polar coordinates, we can parameterize the region R as follows:

x = rcos(θ)

y = rsin(θ)

where r goes from 0 to 8, and θ goes from 0 to 2π.

Now, rewrite the integral in polar coordinates:

[tex]Area =\int\int_R f(x, y) dA\\Area = \int_0 ^{2\pi} \int_0^8(64 + r^2cos^2(\theta) - r^2sin^2(\theta)) \times r dr d \theta[/tex]

Now, we can integrate with respect to r first and then with respect to θ:

[tex]Area = \int_0^{2\pi} \int_0^8] (64r + r^3cos^2(\theta) - r^3sin^2(\theta)) dr d \theta[/tex]

Integrate with respect to r:

[tex]Area = \int_0^{2\pi}[(32r^2 + (1/4)r^4cos^2(\theta) - (1/4)r^4sin^2(\theta))]_0^8 d \theta\\Area = \int_0^{2\pi} (2048 + 256cos^2(\theta) - 256sin^2(\theta)) d \theta[/tex]

Now, we can integrate with respect to θ:

[tex]Area = [2048\theta + 128(sin(2\theta) + \theta)]_0 ^{2\pi}[/tex]

Area = 2048(2π) + 128(sin(4π) + 2π) - (2048(0) + 128(sin(0) + 0))

Area = 4096π + 128(0) - 0

Area = 4096π square units

So, the area of the surface above the region R is 4096π square units.

Learn more about Integration here:

https://brainly.com/question/31744185

#SPJ4

The area of an Equilateral triangle is given by the formula A= 3pi squared/4(s)Squared. Which formula represents the length of equilateral triangle’s side S?

Answers

Answer:

The formula that represents the length of an equilateral triangle’s side (s) in terms of the triangle's area (A) is [tex]\text{s}= \sqrt{ \frac{4 \text{A}}{\sqrt{3} }}[/tex] .

Step-by-step explanation:

We are given the area of an Equilateral triangle which is A = [tex]\frac{\sqrt{3} }{4} \times \text{s}^{2}[/tex] . And we have to represent the length of an equilateral triangle’s side (s) in terms of the triangle's area (A).

So, the area of an equilateral triangle =  [tex]\frac{\sqrt{3} }{4} \times \text{s}^{2}[/tex]

where, s = side of an equilateral triangle

A  =  [tex]\frac{\sqrt{3} }{4} \times \text{s}^{2}[/tex]

Cross multiplying the fractions we get;

[tex]4 \times A = \sqrt{3} \times \text{s}^{2}[/tex]

[tex]\sqrt{3} \times \text{s}^{2}= 4\text{A}[/tex]

Now. moving [tex]\sqrt{3}[/tex] to the right side of the equation;

[tex]\text{s}^{2}= \frac{4 \text{A}}{\sqrt{3} }[/tex]

Taking square root both sides we get;

[tex]\sqrt{\text{s}^{2}} = \sqrt{ \frac{4 \text{A}}{\sqrt{3} }}[/tex]

[tex]\text{s}= \sqrt{ \frac{4 \text{A}}{\sqrt{3} }}[/tex]

Hence, this formula represents the length of an equilateral triangle’s side (s) in terms of the triangle's area (A).

given sin theta=3/5 and 180°<theta<270°, find the following: a. cos(2theta) b. sin(2theta) c. tan(2theta)​

Answers

I hope this will help uh.....

Which of the following ordered pairs satisfied the inequality 5x-2y<8

A) (-1,1)
B) (-3,4)
C) (4,0)
D) (-2,3)

Answers

Answer:  A, B, and D

Step-by-step explanation:

Input the coordinates into the inequality to see which makes a true statement:

                             5x - 2y < 8

A) x = -1, y = 1       5(-1) - 2(1) < 8

                              -5  -  2   < 8

                                    -7     < 8       TRUE!

B) x = -3, y = 4       5(-3) - 2(4) < 8

                              -15  -  8   < 8

                                    -23    < 8     TRUE!

C) x = 4, y = 0       5(4) - 2(0) < 8

                              20  -  0   < 8

                                    20     < 8    False

D) x = -2, y = 3       5(-2) - 2(3) < 8

                              -10  -  6   < 8

                                    -16     < 8   TRUE!

Rotate the figure 90 counterclockwise about the origin. Determine the orientation of the rotated figure and place it in the correct position (PLS HELP)

Answers

Answer:

  see below

Step-by-step explanation:

The rotated location of D' is (-2, 1). The "arrow" points to the left. The attached figure is the best I could do with your distorted image.

You have to rotate the figure 90 counterclockwise about the origin.

A normal population has a mean of 61 and a standard deviation of 13. You select a random sample of 16. Compute the probability that the sample mean is: (

Answers

This question is incomplete

Complete Question

A normal population has a mean of 61 and a standard deviation of 13. You select a random sample of 16. Compute the probability that the sample mean is: (Round z values to 2 decimal places and final answers to 4 decimal places.)

(a) Greater than 64

(b) Less than 57

Answer:

(a) Greater than 64 = 0.1788

(b) Less than 57 = 0.1094

Step-by-step explanation:

To solve the above questions we would be using the z score formula

The formula for calculating a z-score :

z = (x - μ)/σ,

where x is the raw score

μ is the population mean = 61

σ is the population standard deviation = 13

(a) Greater than 64

z = (x - μ)/σ,

where x is 64

μ is the 61

σ is the 13

In the above question, we are given the number of samples = 16

Sample standard deviation = popular standard deviation/ √16

= 13/√16

z = 64 - 61 ÷ 13/√16

z = 3/3.25

z = 0.92308

Approximately, z values to 2 decimal places ≈ 0.92

Using the z score table of normal distribution to find the Probability (P) value of z score of 0.92

P(z = 0.92) = 0.82121

P(x>64) = 1 - P(z = 0.92)

= 1 - 0.82121

= 0.17879

Approximately , Probability value to 4 decimal places = 0.1788

(b) Less than 57

z = (x - μ)/σ,

where x is 57

μ is the 61

σ is the 13

In the above question, we are given the number of samples = 16

Sample standard deviation = popular standard deviation/ √16

= 13/√16

z = 57 - 61 ÷ 13/√16

z = -4/3.25

z = -1.23077

Approximately, z values to 2 decimal places ≈ -1.23

Using the z score table of normal distribution to find the Probability (P) value of z score of -1.23

P(z = -1.23) = P(x<Z) = 0.10935

Approximately , Probability value to 4 decimal places = 0.1094

(very urgent) will gave 20 pts
Suppose that you pick a bit string from the set of all bit strings of length ten. Find the probability that

a) the bit string has exactly two 1s;

b) the bit string begins and ends with 0;

c) the bit string has the sum of its digits equal to seven;

d) the bit string has more 0s than 1s;

e) the bit string has exactly two 1s, given that the string begins with a 1.

Answers

Answer:

a. 45/1024

b. 1/4

c. 15/128

d. 193/512

e. 9/256

Step-by-step explanation:

Here, each position can be either a 0 or a 1.

So, total number of strings possible = 2^10 = 1024

a) For strings that have exactly two 1's,

it means there must also be exactly eight 0's.

Thus, total number of such strings possible

10!/2!8!=45

Thus, probability is

45/1024

b) Here, we have fixed the 1st and the last positions, and eight positions are available.

Each of these 8 positions can take either a 0 or a 1.

Thus, total number of such strings possible

=2^8=256

Thus, probability is

256/1024 = 1/4

c) For sum of bits to be equal to seven, we must have exactly seven 1's in the string.

Also, it means there must also be exactly three 0's

Thus, total number of such strings possible

10!/7!3!=120

Thus, probability

120/1024 = 15/128

d) Following are the possibilities :

There are six 0's, four 1's :

So, number of strings

10!/6!4!=210

There are seven 0's, three 1's :

So, number of strings

10!/7!3!=120

There are eight 0's, two 1's :

So, number of strings

10!/8!2!=45

There are nine 0's, one 1's :

So, number of strings

10!/9!1!=10

There are ten 0's, zero 1's :

So, number of strings

10!/10!0!=1

Thus, total number of string possible

= 210 + 120 + 45 + 10 + 1

= 386

Thus, probability is

386/1024 = 193/512

e) Here, we have fixed the starting position, so 9 positions remain.

In these 9 positions, there must be exactly two 1's, which means there must also be exactly seven 0's.

Thus, total number of such strings possible

9!/2!7!=36

Thus, probability is

36/1024 = 9/256

Use the Limit Comparison Test to determine whether the series converges.
[infinity]∑ from k = 1 StartFraction 8/k StartRoot k + 7 EndRoot EndFraction

Answers

Answer:

The infinite series [tex]\displaystyle \sum\limits_{k = 1}^{\infty} \frac{8/k}{\sqrt{k + 7}}[/tex] indeed converges.

Step-by-step explanation:

The limit comparison test for infinite series of positive terms compares the convergence of an infinite sequence (where all terms are greater than zero) to that of a similar-looking and better-known sequence (for example, a power series.)

For example, assume that it is known whether [tex]\displaystyle \sum\limits_{k = 1}^{\infty} b_k[/tex] converges or not. Compute the following limit to study whether [tex]\displaystyle \sum\limits_{k = 1}^{\infty} a_k[/tex] converges:

[tex]\displaystyle \lim\limits_{k \to \infty} \frac{a_k}{b_k}\; \begin{tabular}{l}\\ $\leftarrow$ Series whose convergence is known\end{tabular}[/tex].

If that limit is a finite positive number, then the convergence of the these two series are supposed to be the same.If that limit is equal to zero while [tex]a_k[/tex] converges, then [tex]b_k[/tex] is supposed to converge, as well.If that limit approaches infinity while [tex]a_k[/tex] does not converge, then [tex]b_k[/tex] won't converge, either.

Let [tex]a_k[/tex] denote each term of this infinite Rewrite the infinite sequence in this question:

[tex]\begin{aligned}a_k &= \frac{8/k}{\sqrt{k + 7}}\\ &= \frac{8}{k\cdot \sqrt{k + 7}} = \frac{8}{\sqrt{k^2\, (k + 7)}} = \frac{8}{\sqrt{k^3 + 7\, k^2}} \end{aligned}[/tex].

Compare that to the power series [tex]\displaystyle \sum\limits_{k = 1}^{\infty} b_k[/tex] where [tex]\displaystyle b_k = \frac{1}{\sqrt{k^3}} = \frac{1}{k^{3/2}} = k^{-3/2}[/tex]. Note that this

Verify that all terms of [tex]a_k[/tex] are indeed greater than zero. Apply the limit comparison test:

[tex]\begin{aligned}& \lim\limits_{k \to \infty} \frac{a_k}{b_k}\; \begin{tabular}{l}\\ $\leftarrow$ Series whose convergence is known\end{tabular}\\ &= \lim\limits_{k \to \infty} \frac{\displaystyle \frac{8}{\sqrt{k^3 + 7\, k^2}}}{\displaystyle \frac{1}{{\sqrt{k^3}}}}\\ &= 8\left(\lim\limits_{k \to \infty} \sqrt{\frac{k^3}{k^3 + 7\, k^2}}\right) = 8\left(\lim\limits_{k \to \infty} \sqrt{\frac{1}{\displaystyle 1 + (7/k)}}\right)\end{aligned}[/tex].

Note, that both the square root function and fractions are continuous over all real numbers. Therefore, it is possible to move the limit inside these two functions. That is:

[tex]\begin{aligned}& \lim\limits_{k \to \infty} \frac{a_k}{b_k}\\ &= \cdots \\ &= 8\left(\lim\limits_{k \to \infty} \sqrt{\frac{1}{\displaystyle 1 + (7/k)}}\right)\\ &= 8\left(\sqrt{\frac{1}{\displaystyle 1 + \lim\limits_{k \to \infty} (7/k)}}\right) \\ &= 8\left(\sqrt{\frac{1}{1 + 0}}\right) \\ &= 8 \end{aligned}[/tex].

Because the limit of this ratio is a finite positive number, it can be concluded that the convergence of [tex]\displaystyle a_k &= \frac{8/k}{\sqrt{k + 7}}[/tex] and [tex]\displaystyle b_k = \frac{1}{\sqrt{k^3}}[/tex] are the same. Because the power series [tex]\displaystyle \sum\limits_{k = 1}^{\infty} b_k[/tex] converges, (by the limit comparison test) the infinite series [tex]\displaystyle \sum\limits_{k = 1}^{\infty} a_k[/tex] should also converge.

which quadratic function in standard form has the value a= -3.5, b=2.7, and c= -8.2?

Answers

Answer:

y = -3.5x² + 2.7x -8.2

Step-by-step explanation:

the quadratic equation is set up as a² + bx + c, so just plug in the values

Answer:

[tex]-3.5x^2 + 2.7x -8.2[/tex]

Step-by-step explanation:

Quadratic functions are always formatted in the form [tex]ax^2+bx+c[/tex].

So, we can use your values of a, b, and c, and plug them into the equation.

A is -3.5, so the first term becomes [tex]-3.5x^2[/tex].

B is 2.7, so the second term is [tex]2.7x[/tex]

And -8.2 is the C, so the third term is [tex]-8.2[/tex]

So we have [tex]-3.5x^2+2.7x-8.2[/tex]

Hope this helped!

Which transformation should be applied to the graph of the function y=cot(x) to obtain the graph of the function y=6 cot(3x-pi/2)+4

Answers

Answer:

The correct answer is the first one.

Step-by-step explanation:

Let's analyse the effect of each modification in the function.

The value 6 multiplying the cot function means a vertical stretch.

The value of 3 multiplying the x inside the function is a horizontal compression, which causes the period to be 3 times lower the original period.

The original period of the cotangent function is pi, so the horizontal compression will make the period be pi/3.

The value of -pi/2 inside the cotangent function normally causes a horizontal shift of pi/2 to the right, but the x-values were compressed by a factor of 3 (horizontal stretch), so the horizontal shift will be 3 times lower: (pi/2) /3 = pi/6

And the value of 4 summing the whole equation is a vertical shift of 4 units up.

So the correct answer is the first one.

Answer:

option 1

Step-by-step explanation:

Given: ∠N ≅ ∠S, line ℓ bisects at Q. Prove: ∆NQT ≅ ∆SQR Which reason justifies Step 2 in the proof? If two lines are parallel, then the corresponding angles formed are congruent. If two lines are parallel, then the alternate interior angles formed are congruent. Vertical angles are congruent. If two lines are parallel, then the same-side interior angles formed are congruent.

Answers

Answer:

Vertical angles are congruent.

Step-by-step explanation:

Vertical angles are opposite angles formed by intersecting lines, and are always congruent.

Use all the information below to find the missing x-value for the point that is on this line. m = - 1 / 3 b = 7 ( x, 4 )

Answers

Answer:

[tex]\boxed{x = 9}[/tex]

Step-by-step explanation:

m = -1/3

b = 7

And y = 4 (Given)

Putting all of the givens in [tex]y = mx+b[/tex] to solve for x

=> 4 = (-1/3) x + 7

Subtracting 7 to both sides

=> 4-7 = (-1/3) x

=> -3 = (-1/3) x

Multiplying both sides by -3

=> -3 * -3 = x

=> 9 = x

OR

=> x = 9

Answer:

x = 9

Step-by-step explanation:

m = -1/3

b = 7

Using slope-intercept form:

y = mx + b

m is slope, b is y-intercept.

y = -1/3x + 7

Solve for x:

Plug y as 4

4 = 1/3x + 7

Subtract 7 on both sides.

-3 = -1/3x

Multiply both sides by -3.

9 = x

If Juan drives 50 mph for 1/2 hour then 60 mph for 1 1/2 an hour, how far does he drive?

Answers

Answer:

115 miles

Step-by-step explanation:

First find the distance at 50 mph

d = 50 mph * .5 hours

   = 25 miles

Then find the distance at 60 mph

d = 60 mph * 1.5 hours

   = 90 miles

Add the distances together

25+90

115 miles

Answer:

he drives a 115 miles

Step-by-step explanation:

if he drives 50 mph for half an hour he drove 25 miles then if he drives 60 mph for 1 hour and 30 minutes he would of drove 90 miles. 60 + 30=90

90+25=115 so he drove 115 miles.

3 sides of the triangle are distinct perfect squares. What is the smallest possible perimeter of the triangle?

Answers

Answer:

77

Step-by-step explanation:

At first, you would probably think that the side lengths are 1², 2², 3² = 1, 4 and 9 but these side lengths don't form a triangle. The Triangle Inequality states that the sum of the two shortest side lengths must be greater than the largest side length, and since 1 + 4 > 9 is a false statement, it's not a triangle. Let's try 2², 3², 4² = 4, 9, 16. 4 + 9 > 16 is also false so that doesn't work. 3², 4², 5² = 9, 16, 25 but since 9 + 16 > 25 is false (25 isn't greater than 25), that doesn't work either. 4², 5², 6² = 16, 25, 36 and since 16 + 25 > 36 is true, this is our triangle which means that the perimeter is 16 + 25 + 36 = 77.

Answer:

e

Step-by-step explanation:

e

Let f(x) = -2x - 7 and g(x) = -4x + 6. Find (f o g)(-5)

Answers

It’s probably-67 on the top of my head

Two similar data sets are being compared. The standard deviation of Set A is 4.8. The standard deviation of Set B is 6.5.

Answers

Answer:

The spread of the data in Set B is greater than the spread of the data in Set A.

Step-by-step explanation:

Just took the test :3

Which set of integers does NOT represent the lengths of the sides of a triangle? A. {6,6,11} B. {9,10,11} C. {4,8,12} D. {4,7,9}

Answers

Answer:

C

Step-by-step explanation:

I suppose you have learned that for the sides of a triangle to work, it has to be a + b > c, the 4 is the a, the 8 is the b, the 12 is the c.

So: 4 + 8 > 12; however this is not true, they are equal so the triangle wont be a triangle, it would be lines that never connect.

can someone EXPLAIN this to me? you don't have to answer the questions. They are for my college class. Last assignment! thank you..

Answers

Your questions are rational expressions.

Essentially, you are adding/subtracting fractions with unknown values (i.e. the variable x).

If you want to add/subtract these, you need a common denominator. Just like you find a CD in 1/2 + 1/3, you have to find a CD between x^2 + x and x (question 20).

Rearranging gives us x(x + 1) and x. Now to find a common denominator, we multiply both the denominator by (x + 1), so now our denominators are both x(x+1) (common). Except that if we multiply on the denominator, we must also multiply on the numerator.

After doing these steps, you can finally add the numerator. Same concept with subtraction.

I hope this helps!

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly
selected from the drawer and set aside. Then another shirt is randomly selected from the
drawer.
What is the probability that the first shirt is white and the second shirt is gray?

Answers

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}[/tex]

[tex]P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}[/tex]

[tex]P(First\ White) = \dfrac{3}{10}[/tex]

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

[tex]P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }[/tex]

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = [tex]\frac{1}{4}[/tex]

A machine fills containers with 35 ounces of raisins

Answers

What’s the question?

The correct graph will be the first one (A)

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