This is a glitch ? 


 











































Answer:

Database Tools, The Line Connecting the Tables, Cascade Delete Related Records

Explanation:

Answer:

1. for what purpose?

2. the pattern design of web

3. what the client wants to add in the web

4. his contact number and email

5. the logo of the business

6. talk about pricing  

Explanation:

for such experiment, you do it with care and to acquire and determine to put experience in it

Explanation:

because without you been or using experience the experiment will not correct

Answer:

Digital marketing is the component of marketing that utilizes internet and online based digital technologies such as desktop computers, mobile phones and other digital media and platforms to promote products and services.

Explanation:

Answer:

The program in Python is as follows:

dollar = float(input("Dollars: "))

t20bill = int(dollar//20)

dollar -= t20bill * 20

t10bill = int(dollar//10)

dollar -= t10bill * 10

t5bill = int(dollar//5)

dollar -= t5bill * 5

t1bill = int(dollar//1)

dollar-= t1bill * 1

qtr = int(dollar//0.25)

dollar -= qtr * 0.25

dime = int(dollar//0.10)

dollar -= dime * 0.10

nkl = int(dollar//0.05)

dollar -= nkl * 0.05

pny = round(dollar/0.01)

if t20bill != 0:    print(t20bill,"$20 bills")

if t10bill != 0:    print(t10bill,"$10 bills")

if t5bill != 0:    print(t5bill,"$5 bills")

if t1bill != 0:    print(t1bill,"$1 bills")

if qtr != 0:    print(qtr,"quarters")

if dime != 0:    print(dime,"dimes")

if nkl != 0:    print(nkl,"nickels")

if pny != 0:    print(pny,"pennies")

Explanation:

This gets input for dollars

dollar = float(input("Dollars: "))

Calculate the number of $20 bills

t20bill = int(dollar//20)

Calculate the remaining dollars

dollar -= t20bill * 20

Calculate the number of $10 bills

t10bill = int(dollar//10)

Calculate the remaining dollars

dollar -= t10bill * 10

Calculate the number of $5 bills

t5bill = int(dollar//5)

Calculate the remaining dollars

dollar -= t5bill * 5

Calculate the number of $1 bills

t1bill = int(dollar//1)

Calculate the remaining dollars

dollar-= t1bill * 1

Calculate the number of quarter coins

qtr = int(dollar//0.25)

Calculate the remaining dollars

dollar -= qtr * 0.25

Calculate the number of dime coins

dime = int(dollar//0.10)

Calculate the remaining dollars

dollar -= dime * 0.10

Calculate the number of nickel coins

nkl = int(dollar//0.05)

Calculate the remaining dollars

dollar -= nkl * 0.05

Calculate the number of penny coins

pny = round(dollar/0.01)

The following print the number of bills or coins. The if statement is used to prevent printing of 0

if t20bill != 0:    print(t20bill,"$20 bills")

if t10bill != 0:    print(t10bill,"$10 bills")

if t5bill != 0:    print(t5bill,"$5 bills")

if t1bill != 0:    print(t1bill,"$1 bills")

if qtr != 0:    print(qtr,"quarters")

if dime != 0:    print(dime,"dimes")

if nkl != 0:    print(nkl,"nickels")

if pny != 0:    print(pny,"pennies")

Answer:

[tex](a)\ 222_{10} = DE_{16}[/tex] --- True

[tex](b)\ D7_{16} = 11010011_2[/tex] --- False

[tex](c)\ 13_{16} = 19_{10}[/tex] --- True

Explanation:

Required

Determine if the statements are true or not.

[tex](a)\ 222_{10} = DE_{16}[/tex]

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

[tex]DE_{16} = D * 16^1 + E * 16^0[/tex]

In hexadecimal.

[tex]D =13 \\E = 14[/tex]

So, we have:

[tex]DE_{16} = 13 * 16^1 + 14 * 16^0[/tex]

[tex]DE_{16} = 222_{10}[/tex]

Hence:

(a) is true

[tex](b)\ D7_{16} = 11010011_2[/tex]

First, convert D7 to base 10 using product rule

[tex]D7_{16} = D * 16^1 + 7 * 16^0[/tex]

[tex]D = 13[/tex]

So, we have:

[tex]D7_{16} = 13 * 16^1 + 7 * 16^0[/tex]

[tex]D7_{16} = 215_{10}[/tex]

Next convert 215 to base 2, using division rule

[tex]215 / 2 = 107 R 1[/tex]

[tex]107/2 =53 R 1[/tex]

[tex]53/2 =26 R1[/tex]

[tex]26/2 = 13 R 0[/tex]

[tex]13/2 = 6 R 1[/tex]

[tex]6/2 = 3 R 0[/tex]

[tex]3/2 = 1 R 1[/tex]

[tex]1/2 = 0 R1[/tex]

Write the remainders from bottom to top.

[tex]D7_{16} = 11010111_2[/tex]

Hence (b) is false

[tex](c)\ 13_{16} = 19_{10}[/tex]

Convert 13 to base 10 using product rule

[tex]13_{16} = 1 * 16^1 + 3 * 16^0[/tex]

[tex]13_{16} = 19[/tex]

Hence; (c) is true

Too much to read,Thanks for the points

Answer:

c is the answer hope you get it right

The effect when one part of a system changes C. The open-loop system becomes a closed-loop system.

Systemic change is generally understood to require adjustments or transformations in the policies, practices, power dynamics, social norms or mindsets that underlie the societal issue at stake. It often involves the collaboration of a diverse set of players and can take place on a local, national or global level.

All systems organize individual pieces into some sort of interrelated whole. Put simply, systemic change occurs when change reaches all or most parts of a system, thus affecting the general behavior of the entire system.

A systems-change approach is more appropriate for problems that are complex, unpredictable, and context-dependent. For example, the challenge of inadequate access to educational opportunities for children from low-income neighborhoods cannot be addressed with a straightforward, logistical fix.

To learn more about A systems-change, refer

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#SPJ2

Answer:

C

Explanation:

Various companies crowdsource programs in order to have image libraries available to do certain tasks, one of those could be to see the landmark over time from different photos.

Answer: C) Think before you post.

Explanation:

There's a very good chance that whatever you post online will remain there indefinitely. So it's best to think about what would happen if you were to post a certain message on a public place. Keep in mind that you should also safeguard against your privacy as well.

Answer:

In Python:

prices = []

pounds = []

print("Enter 0 to stop input")

for i in range(10):

   pr = float(input("P rice: "+str(i+1)+": "))

   pd = float(input("Pound: "+str(i+1)+": "))

   if pr != 0 and pd != 0:

       prices.append(pr)

       pounds.append(pd)

   else:

       break

amount = 0

for i in range(len(pounds)):

   amount+= (pounds[i]*prices[i])

print("Amount: $",amount)

Explanation:

These initialize the prices and pounds lists

prices = []

pounds = []

This prompts the user to enter up to 10 items of press 0 to quit

print("Enter 0 to stop input")

This iterates through all inputs

for i in range(10):

This gets the price of each item

   pr = float(input("P rice: "+str(i+1)+": "))

This gets the pound of each item

   pd = float(input("Pound: "+str(i+1)+": "))

If price and pound are not 0

   if pr != 0 and pd != 0:

The inputs are appended to their respective lists

       prices.append(pr)

       pounds.append(pd)

If otherwise, the loop is exited

   else:

       break

This initializes total to 0

amount = 0

This iterates through all inputs

for i in range(len(pounds)):

This multiplies each pound and each price and sum them up

   amount+= (pounds[i]*prices[i])

The total is then printed

print("Amount: $",amount)

Answer:

Explanation:

The following code is written in Java and creates all the classes as requested with their variables, and methods. Each extending to the Person class if needed. Due to technical difficulties I have attached the code as a txt file below, as well as a picture with the test output of calling the Staff class.

Answer:

N = [1,1,1,1,1],

[2,2,2,2,2],

[3,3,3,3,3],

[4,4,4,4,4]

def printIt(ar):

  for row in range(len(ar)):

      for col in range(len(ar[0])):

          print(ar[row][col], end=" ")

      print("")

N=[]

for r in range(4):

  N.append([])

for r in range(len(N)):

  value=1

  for c in range(5):

      N[r].append(value)

      value=value + 1

printIt(N)

print("")

newValue=1

for r in range (len(N)):

  for c in range(len(N[0])):

      N[r][c] = newValue

  newValue = newValue + 1

printIt(N)

Explanation:

:D

Below is the required program of Python.

Program:

# Array name will be "N".

# Start program

# Defining a function and taking input array

def printIt(ar):

# Using for loop to scan the rows as well as columns of array

 for row in range(len(ar)):

     for col in range(len(ar[0])):

# Printing the element of array

         print(ar[row][col], end=" ")

     print("")

# Passing the array N

N=[]

# Again using the loop

for r in range(4):

 N.append([])

# Loop to control rows

for r in range(len(N)):

 value=1

# Loop to control columns

 for c in range(5):

     N[r].append(value)

     value=value + 1

# Calling the function

printIt(N)

print("")

newValue=1

# Value in row and column

for r in range (len(N)):

 for c in range(len(N[0])):

# Assigning the values to the array

     N[r][c] = newValue

 newValue = newValue + 1

# Printing the array

# End program

printIt(N)

Program code:

Output:

Find below the attachment of the output of the program code.

Find out more information about Python here:

https://brainly.com/question/26497128

Answer:

Una computadora es una herramienta muy básica para hacer tareas repetitivas de forma más eficiente. Una computadora no es capaz de analizar un problema y obtener una solución.

Explanation:

// Begin class declaration

public class Exceptioner {

   // Define the exceptionable method

   public static void exceptionable(int number){

      //check if number is 0.

       if(number == 0) {

           //if it is 0, return an IllegalStateException

           throw new IllegalStateException("number is 0");

       }

      //check if number is 1        

       else if(number == 1) {

           //if it is 1, return a NullPointerException

           throw new NullPointerException("number is 1");

       }

      //check if number is 2        

       else if(number == 2) {

           //if it is 2, return an ArithmeticException

           throw new ArithmeticException("number is 2");

       }

      //check if number is 3

       else if(number == 3) {

           //if it is 3, return an IllegalArgumentException

           throw new IllegalArgumentException("number is 3");

       }

   }

}

Exception in thread "main" java.lang.ArithmeticException: number is 2                                                                          

       at Main.exceptionable(Main.java:26)                                                                                                    

       at Main.main(Main.java:36)  

The code is written in Java with comments explaining important parts of the code.

A sample output for the call of the method with number 2 is also provided. i.e

exception(2)

gives the output provided above.

Answer:

no

Explanation:

A hybrid topology is a type of network topology that uses two or more differing network topologies. These topologies can include a mix of bus topology, mesh topology, ring topology, star topology, and tree topology.

Answer:

You didn't list any choices, but in order to avoid all plagiarism, you must focus on rewriting the following script/paragraph in your own words. This could be anything from completely changing the paragraph (not the context) to summarizing the paragraph in your own words.

Answer:

Simon cites anything that he didnt know before he read it in any given source

Explanation:

a p e x

Answer:

For listening sake

To listen to information from the computer

They receive audio input from the computer's sound card and produce audio output in the form of sound waves.

Answer:

The program in Python is as follows:

nums = []

isum = 0

num = int(input("Num: "))

while num >= 0:

   isum+=num

   nums.append(num)

   num = int(input("Num: "))

print("Sum: ",isum)

print("Average: ",isum/len(nums))

print("Minimum: ",min(nums))

print("Maximum: ",max(nums))

Explanation:

My solution uses list to answer the question

This initializes an empty list, num

nums = []

This initializes the sum of the input to 0

isum = 0

This prompts the user for input

num = int(input("Num: "))

The loop is repeated until the user enters a negative number

while num >= 0:

This calculates the sum of the list

   isum+=num

This appends the input to the list

   nums.append(num)

This prompts the user for another input

   num = int(input("Num: "))

This prints the sum of the list

print("Sum: ",isum)

This prints the average of the list

print("Average: ",isum/len(nums))

This prints the minimum of the list

print("Minimum: ",min(nums))

This prints the maximum of the list

print("Maximum: ",max(nums))

Answer:

The program in C++ is as follows:

#include <iostream>

#include <iomanip>

using namespace std;

int main(){

   int cars;

   cin>>cars;

   double weights[cars];

   double total = 0;

   for(int i = 0; i<cars;i++){

       cin>>weights[i];

       total+=weights[i];    }

   double avg = total/cars;

   for(int i = 0; i<cars;i++){

       cout<<fixed<<setprecision(1)<<avg-weights[i]<<endl;    }

   return 0;

}

Explanation:

This declares the number of cars as integers

   int cars;

This gets input for the number of cars

   cin>>cars;

This declares the weight of the cars as an array of double datatype

   double weights[cars];

This initializes the total weights to 0

   double total = 0;

This iterates through the number of cars

   for(int i = 0; i<cars;i++){

This gets input for each weight

       cin>>weights[i];

This adds up the total weight

       total+=weights[i];    }

This calculates the average weights

   double avg = total/cars;

This iterates through the number of cars

   for(int i = 0; i<cars;i++){

This prints how much weight to be added or subtracted

       cout<<fixed<<setprecision(1)<<avg-weights[i]<<endl;    }

Answer:

Follows are code to the given question:

def countdown_trigger(begin):#defining a method countdown_trigger that accepts a parameter

   i = begin#defining variable that holds parameter value

   while i >= 0:#defining while loop that check i value greater than equal to0

       print(i)#print i value

       i -= 2  # decreasing i value by 2  

print(countdown_trigger(2))#calling method

Output:

2

0

None

Explanation:

In this code, a method "countdown_trigger" is declared, that accepts "begin" variable value in its parameters, and inside the method "i" declared, that holds parameters values.

By using a while loop, that checks "i" value which is greater than equal to 0, and prints "value" by decreasing a value by 2.

Answer:

Explanation:

The following program is written in Java and creates the divBySum method using a enhanced for loop. In the picture attached below I have provided an example of the output given if called using the array provided in the question and a divisible parameter of 3.

public static int divBySum(int[] arr, int num) {

       int sum = 0;

       for (int x : arr) {

           if ((x % num) == 0) {

               sum += x;

           }

       }  

       return sum;

   }

Answer:

Answer of CPU

Explanation:

Central Processing Unit (CPU) consists of the following features − CPU is considered as the brain of the computer. CPU performs all types of data processing operations. It stores data, intermediate results, and instructions (program). It controls the operation of all parts of the computer.

Answer:

A central processing unit (CPU), also called a central processor, main processor or just processor, is the electronic circuitry that executes instructions comprising a computer program.

Answer:

false

Explanation:

plants do that, they absorb carbon dioxide and then they create oxygen, then humans breathe the oxygen and makes CB

Answer:

Dobji is consider to be the first model dzong in Bhutan

Answer:

once per month

Explanation:

The correct answer is - once per month

Reason -

Probability of 1 failure of 1000 hard disk = 750,000/1000 = 750 hrs

So,

750/24 = 31.25 days

⇒ approximately one in a month.

Answer:

Following are the code to the given question:

def match_sequence(s1,s2):#Defining a method match_sequence that accepts two parameters

for l in range(len(s1)):#defining a loop that checks range of s1 value

if(s1[l] != s2[l]): # use if block to match each sequences

print('The sequence does not match at index: ',l+1)#print value with message

s1 = 'CATCGTCCT'#defining a string varible s1

s2 = 'CACCGACCG'#defining a string varible s1

match_sequence(s1,s2)#calling a method that prints its values

Output:

The sequence does not match at index: 3

The sequence does not match at index: 6

The sequence does not match at index: 9

Explanation:

In this code, a method "match_sequence" is declared that takes two string variable "s1 and s2" in its parameters, and inside the method, a loop is declared that checks the range of s1 value and use if block to match each sequence and use a print method that prints it values.

Outside the method, two string variables are declared that holds a string value that passes into the "match_sequence" method and calls it.