TiCl4+H2O-->TiO2+HCl I need to balance this

This question is incomplete, the complete question is;

Describe how to use a transfer pipet to deliver 10.00 mL of liquid by placing the following steps in the correct order;

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

Answer:

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.  

Explanation:  

First of all, We use a suction device to suck up liquid into pipet. Then we will fill the pipet up to the 10 mL marks and will discard the initial two volumes of liquid and will take a final third volume. We will replace the bulb with index finger and will drain it by placing the tip of pipet at the wall of beaker and drain the liquid.

Arranged in the following steps correctly;

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.

Answer:

They are the same.

Explanation:

Hello!

In this case, according to the Avogadro's number, we take into account that for molecules such as gaseous oxygen (O₂) and nitrogen (N₂), we realize that 1 mole of these contain 6.022x10²³ moles of molecules; as we are given  1 mol each, we notice they both have 6.022x10²³ molecules, therefore, they number of molecules is the same because they have the same number of moles.

Best regards!

Answer:

608 g

Explanation:

Mass of flask + contents = 489.1 g

Mass of flask = 241.3 g.

Mass of water = 489.1 - 241.3 = 247.8 g

Density of water = 1.0 g/cm^3

volume of water = 247.8 g/1.0 g/cm^3

Volume = 247.8 cm^3

But

Volume of flask = volume of water

Volume of flask = 247.8 cm^3

volume of chloroform = volume of flask

mass of chloroform = 1.48 g/cm^3× 247.8 cm^3

Mass of flask + chloroform = 366.7 g + 241.3 = 608 g

Answer:

C) The law of conservation of matter

Explanation:

Conservation means keeping/ retaining something, in this case it is matter. Hope this helps!

Answer:

[tex]\mathbf{H_2SeO_{4(aq)} + 3SO_{2(aq)} + 2H_2O_{(l) } \to Se_{(s)} + 3H_2SO_{4(aq)} }[/tex]

Explanation:

We are to write a balanced equation from the information given above by including the states of their matter according to SATP conditions;

[tex]\mathbf{H_2SeO_{4(aq)} + 3SO_{2(aq)} + 2H_2O_{(l) } \to Se_{(s)} + 3H_2SO_{4(aq)} }[/tex]

From above;

The oxidizing agent is [tex]\mathbf{H_2SeO_{4(aq)} }[/tex]

The reducing agent is [tex]\mathbf{SO_{2(aq)} }[/tex]

Answer:

14 days.

Explanation:

If today were October 7 and we observed a waxing gibbous moon, that is, a moon with an illumination greater than a first quarter but less than a full moon, we would have to wait 14 days to see a waning crescent moon, which would be a moon with a visibility less than the last quarter but greater than a new moon.

Answer:

pH

Explanation:

We define the pH of a solution as the negative logarithm of hydronium ions concentration in solution.

Thus when we want to define pH mathematically, we write;

pH = - log {H3O^+]

Where;

{H3O^+] means the concentration of hydronium ions in solution.

Answer:

mercury (I) silicate

Explanation:

Answer:

57.6 KJ/mol

Explanation:

We have that;

T1 = 301 K

T2= 311 K

k1 = k1

k2= 2k1

R = 8.314 JK-1

Ea= ?

So;

ln(k1/k2) = (-Ea/R) (1/T1 - 1/T2)

ln (k1/2k1) = -(Ea/8.314) (1/301 - 1/311)

ln(1/2) = -(Ea/8.314) (3.3 * 10^-3 - 3.2 * 10^-3)

-0.693 = -(Ea/8.314) 0.1 * 10^-3

-0.693/ 0.1  * 10^-3 = -(Ea/8.314)

-6930 =  -(Ea/8.314)

Ea = 6930 * 8.314

Ea = 57.6 KJ/mol

Answer:

A

Explanation:

Sana makatulong tong answer ko

The total number of molecules in 34.0 g of ammonia is equal to 12.044×10[tex]^23[/tex] molecules according to the concept of Avogadro's number.

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number.

In the given example,number of molecules is determined as follows,

17 g ammonia has 6.022×10²³ molecules

So,34 g ammonia has, 34×6.022×10²³/17=12.044×10²³ molecules.

Hence, the total number of molecules in 34 g of ammonia is 12.044×10²³ molecules.

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Your question is incomplete, but the most probable answer is 12.044×10²³ molecules.

Answer:

2.48 g

Explanation:

From the question given above, the following data were obtained:

Number of atoms = 2.53×10³⁴ atoms

Mass of Ni =?

From Avogadro's hypothesis,

we understood that 1 mole of any substance contains 6.02×10²³ atoms.

Therefore, 1 mole of Ni contains 6.02×10²³ atoms.

Recall:

1 mole Ni = 59 g

Therefore, 59 g of Ni contains 6.02×10²³ atoms.

Finally, we shall determine the mass of 2.53×10³⁴ atoms of Ni. This can be obtained as follow:

6.02×10²³ atoms = 59 g

Therefore,

2.53×10³⁴ = 2.53×10³⁴ × 59 / 6.02×10²³

2.53×10³⁴ atoms = 2.48 g

Thus, the mass of 2.53×10³⁴ atoms of Ni is 2.48 g.

Answer:Prokaryotic cells carry out cellular respiration within the cytoplasm and eukaryotic cells carry out respiration in the mitochondria

Explanation:

Answer:

The answer is "35 atoms".

Explanation:

The Formula for isopropyl alcohol is: [tex]C_3H_8O[/tex]

In 1 molecule of [tex]C_3H_8O[/tex] = 8 atoms of hydrogen  

In 4 molecule of = atoms of hydrogen

According to the given formula [tex]C_3H_7O[/tex]

In 5 molecule of [tex]C_3H_7O[/tex] [tex]= 5 \times 7 = 35[/tex] atoms of hydrogen.

Answer: Their main aim was to provide goods, specifically furs and sugar exportation.

Explanation:

Answer:

the first one

Explanation:

Answer:

1930g

Explanation:

We have been given that the salinity of sea water is 3.5%;

  Now the mass of sea water sample is 2000g

So, problem here is to find the quantity of pure water in the sample = ?

Solution:

Let us find the quantity of the salt in the sample;

       Salt content  = 3.5% x 2000  = 70g

Amount of pure water  = 2000 - 70 = 1930g

Answer:

false

Explanation:

The genotype of 50% of offspring will be Gg, 25% will be gg, and 25% will be GG. Hence, it is true.

An organism's genotype is made up of all of its genetic components. The alleles or variations that an individual carries in a specific gene or genetic region are also referred to as the genotype. In other words, it is the genetic makeup of an organism. Phenotypes are determined by genotypes.

There are three different genotype types: homozygous dominant (PP), homozygous recessive (PP), and heterozygous (Pp). Examples of genotypes are hair color, skin color, height, hair texture, and blood group.

When two parents who are both Gg (Bb) for a gene are crossed, then the genotype of their offspring will be GG, gg, Gg. Hence, it is true.

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Answer:

I don't think that answer is right. I got 543.04 grams.

Explanation:

I think the question is asking for grams in the samlpe instead of the moles in the sample because it already gives you the amount of moles.

Answer:

[tex]pH=4.63[/tex]

Explanation:

Hello!

In this case, since the ionization of ammonia, which is a weak base, is written as:

[tex]NH_3+H_2O\rightleftharpoons NH_4^++OH^-[/tex]

We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:

[tex]pH=pKb+log(\frac{[conj\ acid]}{[base]} )[/tex]

In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:

[tex]pH=4.75+log(\frac{0.15}{0.2} )\\\\pH=4.63[/tex]

Best regards!

The ionic formula for the ionic crystal is Fe₃O₂

Ionic crystals are solid, crystalline ionic substances that are made up of ions linked together in a regular lattice structure by electrostatic attraction.

From the given structure; the key element shows that:

Therefore, from the diagram, the correct formula of the ionic crystal by considering the lone pairs and valence electrons is Fe₃O₂

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2 L Ne

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

0.07 mol Ne (g)

Step 2: Identify Conversions

STP - 22.4 L per mole

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 1 sig fig.

1.568 L Ne ≈ 2 L Ne

Answer:

it takes two hydrogen atoms for every oxygen atom to produce this reaction, so the mole ratio between hydrogen and oxygen is 2:1

Answer:

3 one

Explanation:

Answer:

No. of moles, n = 7.52 moles

Explanation:

Given that,

Mass, m = 563.9 grams

Molar mass of arsenic = 74.92 g/mol

We need to find the number of moles in 563.9 grams of arsenic. Let it is denoted by n. It is equal to given mass divided by total molar mass.

[tex]n=\dfrac{563.9 }{74.92}\\\\=7.52\ \text{moles}[/tex]

So, there are 7.52 moles in 563.9 grams of arsenic.

Answer:

d

Explanation:

i think its d but im not sure.