Answer:
B) △DEF ~ △GHI
E) △JKL ~ △ABC
Step-by-step explanation:
i just did the assignment
The pairs of triangles are similar
△DEF ~ △GHI and △JKL ~ △ABC.
What is similarity ?If two triangles have an equal number of corresponding sides and an equal number of corresponding angles, then they are comparable. Similar figures are described as items with the same shape but varying sizes, such as two or more figures.
Given:
AC = 14
BC = 20
DF = 8
FE= 10
HI = 15
IG = 12
KL = 10
LJ = 7
As, In Right Triangle we can use Pythagoras theorem
AB = √14²+ 20² = 24.41
DE= √8²+10²= 12.8
HG= √15²+ 12² = 19.2
KJ= √10² + 7² = 12.2
Then, from the ratio of Corresponding sides we get
△DEF ~ △GHI and △JKL ~ △ABC.
Learn more about similarity here:
https://brainly.com/question/26451866
#SPJ2
Write an recursive rule for the sequence 7,14,21,28
Find f(-2)for f(x)-3 . 2^x
A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by C=0.3X^2+8,000. How fast is the cost per month changing when production is changing at the rate of 14 units per month and the production level is 70 UNITS?
Costs are ___ at the rate of $___ per month at this production level.
Answer:
Costs are changing at the rate of $588 per month at this production level.
Step-by-step explanation:
From the question, we have:
C = 0.3X^2 + 8,000 ........................ (1)
Differentiating equation (1) with respect to time, t, we have:
dC/dt = (0.3 * 2) X (dX/dt)....................... (2)
Where;
X = 70
dX/dt = 14
Substituting this into equation (2), we have:
dC/dt = (0.3 * 2) * 70 * 14
dC/dt = 588
This implies that costs are changing at the rate of $588 per month at this production level.
Can someone help pls !
Answer:
(B). [tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]
Step-by-step explanation:
12x - 13y = 7
17x - 22y = - 51
A = [tex]\left[\begin{array}{cc}12&-13\\17&-22\end{array}\right][/tex]
[tex]A_{x}[/tex] = [tex]\left[\begin{array}{cc}7&-13\\-51&-22\end{array}\right][/tex]
[tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]