Answer:
True
Explanation:
Atoms of the same element will always have the same atomic mass or the mass listed in the periodic table.
A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the heavier ball moves at 2m/s in the opposite direction
Answer:
Speed of lighter ball is 4 m/s.
Explanation:
Applying the principle of conservation of linear momentum,
momentum before collision = momentum after collision.
[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]
[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?
(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])
24 + 0 = 16 - 2[tex]v_{2}[/tex]
2[tex]v_{2}[/tex] = 16 - 24
2[tex]v_{2}[/tex] = -8
[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]
= -4 m/s
This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.
Which example illustrates Newton's second law?
A. A wheelbarrow remains stationary when no one pushes on it.
B. More mass is added to a wheelbarrow, and a larger force is
required to move it.
C. A person pushes a wheelbarrow, causing it to move forward.
D. The force of a wheelbarrow on the ground is equal to the force of
the ground on the wheelbarrow.
Answer:B
Explanation:
Mass
More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."
Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.
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PLEASE HELP ME QUICKLY!!!!!!!!!!!!!!
Answer:
I think thats the correct answer
Explanation:
Due to the friction between a tire and the road surface, the temperature of the air inside a tire increases as one drives. If the tire pressure is 37 psi when the car is in the driveway at 25° C, What is the pressure of the tire when the temperature increases to 50° C?
Answer:
40.10 atm .
Explanation:
Here volume of tire is assumed to be nearly constant .
Modified gas law ,
P₁ / T₁ = P₂ / T₂
37 / ( 273 + 25 ) = P₂ / ( 273 + 50)
37 / 298 = P₂ / 323
P₂ = 37 x 323 / 298
= 40.10 atm .
Which has the most momentum?
Select one:
A. 100 kg at rest
B. 20 kg at 2 m/s
C. 5 kg at 50 m/s
D. 10 kg at 5 m/s
Answer: C
Explanation:
A: 100kg*0m/s (obviously not answer)
B: 20kg*2m/s (=40)
C: 5kg*50m/s (=250, safe bet this one is it)
D: 10kg*5m/s (=50)
5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
To calculate momentum, we use the formula:
Momentum (p) = Mass (m) × Velocity (v)
Let's calculate the momentum for each option:
A. 100 kg at rest
Momentum = 100 kg × 0 m/s = 0 kg m/s
B. 20 kg at 2 m/s
Momentum = 20 kg × 2 m/s = 40 kg m/s
C. 5 kg at 50 m/s
Momentum = 5 kg × 50 m/s = 250 kg m/s
D. 10 kg at 5 m/s
Momentum = 10 kg × 5 m/s = 50 kg m/s
Therefore, 5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
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Which of the following is a FALSE statement? (A) Heat moves through solids by conduction (B) Molecules move faster in warmer substances (C) Warm water is denser than cold water (D) Heat moves through liquids and gases by convection
Answer:
C.
Explanation:
Which quantities define momentum?
Answer:
velocity and mass
Explanation:
:) apek
A cannon sitting on the edge of a cliff 500 meters above the ground shoots a cannon ball with a horizontal velocity of 100m/s. At some point the cannon hits the ground. How far away from the point it was launched will the cannon ball land?
Answer:
1010 m
Explanation:
The following data were obtained from the question:
Height (h) of cliff = 500 m
Horizontal velocity (u) = 100 m/s
Horizontal distance (s) =?
Next we shall determine the time taken for the cannon ball to hit the ground. This can be obtained as follow:
Height (h) of cliff = 500 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
500 = ½ × 9.8 × t²
500 = 4.9 × t²
Divide both side by 4.9
t² = 500/4.9
Take the square root of both side
t = √(500/4.9)
t = 10.1 s
Finally, we shall determine the horizontal distance travelled by the cannon ball.
This can be obtained by using the following formula (s = ut) as illustrated below:
Horizontal velocity (u) = 100 m/s
Time (t) = 10.1 s
Horizontal distance (s) =?
s = ut
s = 100 × 10.1
s = 1010 m
Thus, the cannon ball was launched 1010 m away from the cliff.
An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.
Answer:
Resultant force = [tex]\sqrt{91}[/tex]N
Explanation:
Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]
Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]
Rf = [tex]\sqrt{36+25+30}[/tex]
Rf = [tex]\sqrt{91}[/tex]
doesn't look right though...
The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given parameters:
Two forces are 6 N and 5N.
Angle between them is 60 degree.
So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N = = 9.54 N.
Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°) } = 33⁰.
Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
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Which two fundamental forces are only attractive?
O A. Gravitational and strong nuclear
O B. Electromagnetic and weak nuclear
O C. Electromagnetic and strong nuclear
O D. Gravitational and weak nuclear
The two fundamental forces that are only attractive is A. Gravitational and strong nuclear.
What connection exists between the strong nuclear force and gravity?The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.
Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.
Therefore, option A is correct.
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If the velocity of an object is zero, then that object cannot be accelerating. | True or False
Answer: False
Explanation:
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance travelled by the truck during this?
Answer:
82.7 m
Explanation:
u= 22m/s
a= 2.4 m/s^2.
t= 3.2 secs
Therefore the distance travelled can be calculated as follows
S= ut + 1/2at^2
= 22 × 3.2 + 1/2 × 2.4 × 3.2^2
= 70.4 + 1/2×24.58
= 70.4 + 12.29
= 82.7 m
Hence the distance travelled by the truck is 82.7 m
A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
Answer:
Mass, m = 71.42 kg
Explanation:
Given that,
Normal force acting on a box, F = 700 N
We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,
F = mg
Where m is the mass of the box
[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]
So, the mass of the box is 71.42 kg.
If a car manufacturer reduced the mass of a new car model, so that it took a force of 4000 N
to accelerate towards the barrier at 4 m/s2, what would be the mass of
the new car?
Answer:
1000 kg
Explanation:
Force = mass x acceleration, Hence, mass = Force/acceleration
mass = 4000/4 = 1000 kg
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Answer:
The answer is 1376 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 8 × 10 × 17.2
We have the final answer as
1376 JHope this helps you
Explanation:
potential energy = mgh
potential energy = 8 * 10 * 17.2
potential energy = 1376 joules
A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum height reached by the ball?
Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]
Therefore, the maximum height reached by the ball is 2.84 m
According to the Declaration of Independence, all people are created in what manner?
Answer:
All men are created equal.
Explanation:
We hold these truths to be self-evident, that all men are created equal, that they are endowed by their Creator with certain unalienable Rights, that among these are Life, Liberty and the pursuit of Happiness.
-Declaration of Independence
If a planet has more mass, the acceleration of gravity you feel on that planet will be greater than on a planet with less mass. true or false
Answer:
Yes
Explanation:
Objects with greater mass have more gravity. For example a feather and a phone. A feather falls slower than a phone becasue their is less gravity.
Hope this helps :)
There is friction between the block and the
table.
The suspended 2 kg mass on the left is
moving up, the 4 kg mass slides to the right
on the table, and the suspended mass 4 kg on
the right is moving down.
The acceleration of gravity is 9.8 m/s
2
.What is the magnitude of the acceleration
of the system?
1. 1.67253
2. 1.9845
3. 1.75311
4. 2.47673
5. 2.1315
6. 2.058
7. 2.548
8. 1.33933
9. 1.5288
10. 2.03127
Answer in units of m/s
2
.
Answer:
5 no
Explanation:
actually the 4kg lying on table has no influence
it slides towards 4kg weight hung
as it has excess 2kg force
force=miu × m ×g
The magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
Given data:
The masses suspended from the table are, m = 2 kg and m' = 4 kg.
And the mass kept on the table is, m'' = 4 kg.
The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,
[tex]f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N[/tex]
Since, the mass kept on the right side is more. Then at equilibrium,
-f + m''g + (m' +m)a = m'g
Here,
a is the magnitude of acceleration of the system.
Solving as,
-4.312+ 4(9.8) + (4 -2)a = 4(9.8)
2a = 4.312
[tex]a \approx 2.1315 \;\rm m/s^{2}[/tex]
Thus, we can conclude that the magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
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Light is reflected from a crystal of table salt with an index of refraction of 1.544. An analyser is placed to intercept the reflected ray, and is able to completely absorb the reflected light. What is the angle of incidence?
Answer:
hola me llamo bruno y tu?
Explanation:
pero yo soy de mexico
Where would you find the photosphere
pls help me with this question pls
Explanation:
pls help me with this question pls
can u plz help
Define: Medium
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
A ball that is out of play is called a __________________. 2. Volleyballs are made out of __________________ material. 3. A __________________ occurs when the server steps on or over the end line. 4. Contact of the ball by a player is called __________________. 5. The __________________ decides who will serve and the choice of playing area.
Answer:
1) Deadball
2) Leather
3) Foot Fault
4) Pass
5) Captain
Explanation:
1) In most sports when a ball is out of play or termed temporarily unplayable, it is said to be a Deadball.
2) Volleyballs are generally made of leather materials be it synthetic or genuine leather.
3) In volleyball, when a server steps on or over the end line, it is called foot fault.
4) The first contact of a ball by a player after a serve from a passer is usually called a pass.
5) In volleyball, the referee issues a coin toss in presence of both captains and the captain with the winning toss is the one that makes the choice of play area and the first server.
Will give brainliest!! How would you write the direction of the vector above as a global angle?
Answer:
Assuming they're unit vectors (length of 1)
You simply add them together.
The vector pointing right can be described with X and Y
(1, 0).
The vector pointing down
(0, -1).
The numbers are taken from the axis in X and Y directions.
If you add them together you get a final vector.
(1, - 1)
This gives you -45° pointing South East.
Or 360°-45°=315°
A man drops a penny V=0 off the top of the Golden Gate Bridge how fast will the penny be moving when it hits the ground? The golden hat bridge is 275 meters tall
Answer:
Vf = 73.4 m/s
Explanation:
This is the case of vertical motion where we have to find the final velocity of the penny when it hits the ground. We can use 3rd equation of motion to find the final velocity:
2gh = Vf² - Vi²
where,
g = 9.8 m/s²
h = height = 275 m
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s
Therefore,
2(9.8 m/s²)(275 m) = Vf² - (0 m/s)²
Vf = √5390 m²/s²
Vf = 73.4 m/s
The speed with penny dropped from the Golden Gate Bridge hits the ground is 73.4m/s.
Given the data in the question;
Since the penny was at rest before it was dropped
Initial velocity; [tex]u = 0[/tex]Height or distance of the golden hat bridge; [tex]s = 275m[/tex]Final velocity; [tex]v = \ ?[/tex]
To determine the speed with which the penny hits the ground, we use the Third Equation of Motion:
[tex]v^2 = u^2 + 2as[/tex]
Where v is the final velocity, u is the initial velocity, s is the height of the bridge and a is acceleration due to gravity ( since its under gravity; [tex]a = g = 9.8m/s^2[/tex] )
We substitute our values into the equation
[tex]v^2 = 0 + [ 2\ *\ 9.8m/s^2\ *\ 275m]\\\\v^2 = 5390m^2/s^2\\\\v = \sqrt{5390m^2/s^2}\\\\v = 73.4 m/s[/tex]
Therefore, the speed with penny dropped from the Golden Gate Bridge hits the ground is 73.4m/s.
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If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately
Answer:
14.3 m/s
Explanation:
velocity equation
v= d/t
v= 60/4.2
v=14.28
round it to 1 decimal place
v= 14.3m/s
write an essay on the great wall of china
What do scientists use to measure force?
Answer:
force meter
Explanation:
Answer:
Wrong, the correct answer is "newton"
Explanation:
1 Newton = 1 kilogram-meter per second2