Answer:
The kinetic-molecular theory applies on to ideal gases.. Many gases behave nearly ideally if pressure is not very high and temperature is not very slow. ... Because the attractive forces between gas particles are insignificant, gas particles glide easily past one another.
F
Explanation:
2. A plant growing in response to the sunlight.
Gravitropism
Phototropism
Thigmotropism
Hydrotropism
Answer:
Phototropism.
Explanation:
Phototropism is the phenomenon of plants growing in response to light. This is a response to the plants to align or steer towards the source of sunlight, thereby becoming the 'path' to their growth.
The term "photo" means light and "tropism" means "growth" or movement towards". So, we can safely say that phototropism is the scientific and natural phenomenon of plants growing towards or in response to the sunlight.
Thus, the correct answer is phototropism.
If 45 grams of solid aluminum and 301 grams of ammonium perchlorate are reacted. How much excess reactant is left over? Show your work using equation editor.
Answer: Your balanced equation is 2Al + 3S --> Al_2S_3. In two separate equations, first use the 48.5g of Al to find the amount (in moles) of Al_2S_3. Then use the 62.8g of S to find the amount (in moles) of Al_2S_3. By doing these, you find which reactant (the Al or the S) produces the least amount of Al_2S_3. Since it's the S, that's the limiting reactant: you then use that 62.8g of S to find how many grams of Al will be used in the reaction. (Use the same balanced equation.) You find that 35.2g of Al will be used, then find the excess by subtracting that 35.19 from the original 48.5g. Your excess amount is 13.3g of Al!
Explanation:
hopefully this is what you were looking for <3 :)
The amount of excess reactant that left over the chemical reaction between aluminum and ammonium perchlorate is 0.9 moles.
How do we convert mass into moles?Mass into moles (n) will be converted by using the below equation as:
n = W/M, where
W = given mass
M = molar mass
Moles of 45g of Aluminum = 45g / 27g/mol = 1.66 mol
Moles of 301g of ammonium perchlorate = 301g / 117.4g/mol = 2.56 mol
Both reactants are reacted with each other and one of the reactant is fully consumed, so the excess reactant will be calculated as:
Excess reactant = 2.56mol - 1.66mol = 0.9 moles
Hence amount of excess reactant is 0.9 moles.
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A solution contains some or all of the ions Cu2+, Al3+, K+, Ca2+, Ba2+, Pb2+, and NH4+. The following tests were performed, in order, on the solution.
Addition of 6 M HCl produced no reaction.
Addition of H2S with 0.2 M HCl produced a black solid.
Addition of (NH4)2S produced a white solid.
Addition of (NH4)2HPO4 in NH3 produced no reaction.
The final supernatant when heated produced a purple flame.
Identify which of these ions were present in the solution, which were absent, and for which ones no conclusions can be drawn.
Answer:
See explanation
Explanation:
If we look at the tests to be performed on the compounds carefully, we will notice that;
i) Addition of H2S with 0.2 M HCl produced a black solid. This black solid may result from the reaction;
H2S + Cu2+ ---->CuS(balck solid) + H2
or
H2S + Pb2+ ---->PbS(balck solid) + H2
Hence, Cu2+ or Pb2+ may be present
ii) Addition of (NH4)2S produced a white solid. This means that K^+ may be present because the white precipitate is formed during metathesis.
iii) Potassium ion is known to burn with a purple flame.
Hence the suspected ions are;
Cu2+ , Pb2+ and K^+
What is the type of the synthesis reaction between Chromium + oxygen???
Answer:
Explanation: Reaction of oxygen with chromium(II) and chromium(III) porphyrins and synthesis of a .mu.-oxo chromium porphyrin derivative.
tion:
An inventor claims to have developed a new perfume that lasts a long time because it doesn't evaporate. Comment on this claim.
a. This would be impossible to make because the perfume would have to be pressurized in order to not evaporate.
b. This product is sure sweep the market making many happy customers.
c. In order to smell something, the molecules must evaporate and reach your nose. If the new perfume doesn't evaporate, it will not have an odor.
d. A perfume that does not evaporate could be toxic since the molecules never leave the skin.
Answer:
C
Explanation:
Perfume needs to evaporate in order to smell. If this perfume didn't evaporate, it would stay as a liquid and never smell.
It wouldn't be D, as no toxic perfumes is sold.
It's not A because perfume doesn't have to be pressurized in order to not evaporate.
It's not B, as it is a hasty conclusion to the claim. Plus, if the perfume did have an odor, even while not evaporating, the sales would be low as the product is that good.
In this equation Ry stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the absorption line spectrum of hydrogen caused by the transition of the electron from an orbital with
The question is incomplete, the complete question is;
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with =n10 to an orbital with =n8. Round your answer to 3 significant digits.
Answer:
162 * 10^-7 m
Explanation:
The Rydberg formula is;
1/λ= R(1/n2^2 - 1/n1^2)
R = Rydberg constant = 1.097 * 10^7 m-1
n2 = final state of the electron = 8
n1 = initial state of the electron = 10
Substituting values;
1/λ= 1.097 * 10^7(1/8^2 - 1/10^2)
1/λ= 1.097 * 10^7(1/64 - 1/100)
1 / λ = 1.097 10⁷ (0.015625 - 0.01)
1 /λ = 0.006170625 10⁷
λ = (0.006170625 10⁷)^-1
λ = 162 * 10^-7 m
2.56 x 10^13 molecules of HgO equates to how many moles of HgO?
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
[tex]n = \frac{2.56 \times {10}^{13} }{6.02 \times {10}^{23} } \\ \\ \\ = 4.25 \times {10}^{ - 11} \: \: \: moles[/tex]
Hope this helps you
I NEED HELP ASAP PLZ LOOK AT THE PICTURE CAREFULLY!!!!
Answer:
it is a little fuzzy
Explanation:
Which method is most appropriate for finding the age of the earth in years?
a.absolute dating
b.mass number counting
c.atomic number counting
d.radiometric dating
Answer: D
Explanation:
The radioactive dating is also called the radiometric dating. It involves the use of several radioactive substances like Argon, uranium, etc. The correct option is D.
What is radioactive dating?The method of dating rocks and minerals using the radioactive isotopes is defined as the radioactive dating. This method is very helpful to determine the age of igneous and metamorphic rocks which cannot be measured using correlation method.
Many different radioactive isotopes and methods can be used for dating. The elements like uranium and potassium contain a number of different isotopes whose half life is known exactly and thus the concentration of these isotopes within a rock or mineral can measure the age.
The method radiocarbon dating is also used for determining the age of archaeological carbonaceous objects such as wood samples or animal fossils by measuring the radioactivity of ¹⁴C present in them.
Thus the correct option is D.
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Given this slope equation, calculate the x-intercept (the point at which y = 0).
y = 0.523x + 16.8
Answer:
The answer is (-31.58, 0) when rounded to 2 decimal places.
What is total distance traveled?
What is the displacement (change in positions)
Answer:
Exercise 1
a) 140 m
b) 100 m
c) 180 m
d) 140 m
Exercise 2
a) 20 yards
b) 30 yards
c) 20 yards
d) 55 yards
Exercise 3
a) 11 Kilometers
b) 7 Kilometers
Explanation:
Exercise 1
Distance from B to C = 140 m
Distance from to D = 100 m
Total distance = 100+40+40 = 180 m
Total displacement i.e. distance between A and D is 140 m
Exercise 2
a) Distance from B to C = 35 -15 = 20 yards
b) Distance from C to D = 5 + 35 = 30 yards
c) Distance from B to D = 5 + 15 = 20 yards
d) Displacement = 5 + 50 = 55 yards
Exercise 3
a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers
b) Displacement = 5-2 + 4 = 7 Kilometers
Our most recent mass extension happened about 65million years ago. Describe the effects of this event.
Answer:
To explain what caused this mass extinction, scientists have focused on events that would have altered our planet's climate in dramatic, powerful ways. The leading theory is that a huge asteroid or comet slammed into Earth 65 million years ago, blocking sunlight, changing the climate and setting off global wildfires.
Look at the diagram of a fuel cell below.
Which part of the fuel cell does A represent?
A. air
B. anode
C. cathode
D. electrolyte
Answer:
It is a electrolyte.
Explanation:
I took the test.
It represents an electrolyte.
What happens if electrolytes are low in the body?
A level under three can cause muscle weakness, spasms, cramps, paralysis, and respiratory problems. If it continues, kidney problems may occur.
What do electrolytes do for your body?Electrolytes are substances that have a natural positive or negative electrical charge when dissolved in water. They help your body regulate chemical reactions, maintain the balance between fluids inside and outside your cells, and more.
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If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?
Answer: 31.9 g of KOH can be produced from 22.2 g of KOH
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles[/tex]
[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]
According to stoichiometry :
2 moles of [tex]K[/tex] produce = 2 moles of [tex]KOH[/tex]
Thus 0.57 moles of [tex]K[/tex] will produce=[tex]\frac{2}{2}\times 0.57=0.57moles[/tex] of [tex]KOH[/tex]
Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g[/tex]
Thus 31.9 g of KOH can be produced from 22.2 g of KOH
What is the main difference between rain and hail?
Answer:
Rain is a liquid and hail is a solid.
_______is the division of the cytoplasm at the end of mitosis.
A
Gamete
B
Anaphase
C Prophase
D Cytokinesis
Answer: D. CYTOKINESIS
Explanation:
Mitosis ends with telophase, or the stage at which the chromosomes reach the poles. ... Telophase is followed by CYTOKINESIS, or the division of the cytoplasm into two daughter cells.
Based on this information which of the following conclusions can be drawn about the growth rate of grass? hurry
Calculate the percent mass of hydrogen in ethane (C2H6).
Answer:
80.% carbon and 20.% hydrogen
Explanation:
Ethane has molecular formula C2H6. So What is the composition of carbon and hydrogen in ethane. its alot to explain but yea thats wht i got
What is the empirical formula for a compound that is 7.70 % carbon and 92.3 % chlorine?
Answer:
Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.
Explanation:
You want to produce a casting of sterling silver that is silver plus 13 atomic% copper. Pure silver is too soft for many applications and adding 13 atomic% copper strengthens the silver without significantly changing the color. To produce the sterling silver casting, you are going to melt commercially available pure silver and copper in a furnace, and then you will pour the liquid metal mixture into a mold. The following questions relate to this alloy. (a) In selecting a furnace, what must be the minimum value of the high-temperature capability of your selected furnace
Answer:
1085° C
Explanation:
From the phase diagram of Ag-Cu shown below:
The minimum value of the high-temp required to be selected for the furnace is: 1085° C
This is on the grounds that the furnace should be chosen to such an extent that it should melt any sort of possible material including pure Cu that melts and liquefies at the temperature of 1085° C.
or the formula C6H14 , calculate the index of hydrogen deficiency (IHD) and select all the types of unsaturation that might be present in the molecule based on the IHD. The IHD is Which types of unsaturation might be present
Answer:
See explanation
Explanation:
The term IHD means index of hydrogen deficiency. It tells us the number of missing hydrogen atoms from a given chemical formula. This number of missing hydrogen atoms corresponds to the number and type of multiple bonds in a given compound.
The formula for IHD is; IHD = C + 1 + N/2 – H/2 – X/2
C = Number of carbon atoms
N = Number of nitrogen atoms
H = Number of hydrogen atoms
X = Number of halogen atoms
Since;
N=0, X=0
Then;
IHD = C + 1 – H/2
Hence;
IHD = 6 + 1 - 14/2
IHD = 7 -7
IHD = 0
An IHD of 0 implies that there is no hydrogen deficiency or multiple bond in the molecule. It is purely a saturated compound.
Molecules on the surface of the ice escaping into the water happen in ————.
A. Boiling
B. Freezing
C. Condensation
D. Melting
E. Sublimation
A ___________ ion is made of 2 or more atoms of different elements
O nuclear
O polyatomic
O magnetic
O mono-atomic
Answer: polyatomic
Explanation:hope you find helpful
b) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
constant pressure?
C2H5OH burning in a simple alcohol lamp is -1277.3kJ/mol
Answer:
Explanation:
You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.
This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.
Formal charge of Cl in CHCl3
When 4.088 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.82 grams of CO2 and 2.829 grams of H2O were produced.
In a separate experiment, the molecular weight of the compound was found to be 78.11 amu. Determine the empirical formula and the molecular formula of the hydrocarbon.
Answer:
Empirical formula: CH
Molecular formula: C₆H₆
Explanation:
Based on the combustion of a hydrocarbon, the moles of CO₂ = Moles of Carbon in the hydrocarbon and the moles of H₂O = 1/2 moles of hydrogen in the hydrocarbon.
The empirical formula is the simplest whole number of atoms present in a molecule. With the moles of C and H we can find empirical formula:
Moles C -Molar mass CO₂ = 44.01g/mol-:
13.82g * (1mol / 44.01g) = 0.314 moles C
Moles H -Molar mass H₂O = 18.01g/mol-:
2.829g H₂O * (1mol / 18.01g) = 0.157 moles H₂O * (2mol H / 1mol H₂O) = 0.314 moles of H
The ratio of moles H: moles C:
0.314 moles / 0.314 moles = 1
That means empirical formula is:
CHWith the molecular weight and empirical formula we can find the molecular formula:
Molar mass CH = 12.01g/mol+1.01g/mol = 13.02g/mol
As the molecular weight of the molecule is 78.11amu = 78.11g/mol, there are:
78.11g/mol / 13.02g/mol = 6 times the empirical formula in the molecular formula
That means molecular formula is:
C₆H₆Is anyone good at chemistry if so can someone help me please ?
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In general, salts (formed during a neutralization reaction) are ionic compounds that are soluble in water and dissociate in solution into ions that conduct electricity. Out of the six statements given, there are three related statements that rehash the foregoing, and there are three related statements that are collectively incorrect.
Statements A, B, and D are (generally) true regarding salts formed during a neutralization reaction. When you consider that the net ionic equation of many acid-base neutralization reactions is H⁺(aq) + OH⁻(aq) → H₂O(l), the counterions of the H⁺(aq) and OH⁻(aq) are the aqueous spectator ions that comprise the salt. These ions are electrolytes, as they are charged species that can carry a current in solution; they are ionic compounds by definition since they're composed of cations and anions; and, as aqueous species, they're clearly dissolved in water.
Statements C, E, and F, as a whole, generally aren't true of such salts.
if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be added to reach the equivalence point
Answer:
14.91 mL
Explanation:
Assuming the weak acid is monoprotic, we can solve this problem using the equation:
C₁V₁=C₂V₂Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.
We input the data:
25.00 mL * 0.1084 M = 0.1817 M * V₂And solve for V₂:
V₂ = 14.91 mLThe volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.
How we calculate the volume?Volume for the given solution will be calculated from the below equation:
M₁V₁ = M₂V₂, where
M₁ = Molarity of weak acid = 0.1084 M
V₁ = volume of weak acid = 25 mL
M₂ = molarity of NaOH = 0.1817 M
V₂ = volume of NaOH = to find?
On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL
Hence required volume is 14.91 mL.
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Give the systematic (IUPAC) name for each molecule. This molecule has the condensed formula C H 3 C O C H 3. The oxygen atom has a double bond to the center carbon. systematic (IUPAC) name: This molecule has the condensed formula C H 3 C H 2 C H 2 C O C H 3. The oxygen atom has a double bond to carbon. systematic (IUPAC) name:
Answer: The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.
Explanation:
The basic rules for naming of organic compounds are :
1. First select the longest possible carbon chain. The longest possible carbon chain should include the carbons of double or triple bonds or functional group.For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
2. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and ketones by adding the suffix -one.;
3. The numbering is done in such a way that the carbon containing the functional group gets the lowest number. While writing the name, the word root is given first , followed by the position of carbon containing the functional group followed by the suffix.
The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.
the maximum amount of copper sulfate that can be dissolved in 45.0g of water at 70C is 20.0g. what is the solubility of copper sulfate at that temperature?
(in grams per 100g water)
Answer:
That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.
Explanation:
If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O
If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O