Given that,
Initial position of the spring, x₁ = 0.25 m
Final position of the spring, x₂ = 0.1 m
The spring constant of the spring, k = 100 N/m
To find,
The elastic potential energy stored from the spring's compression.
Solution,
The work done in moving a spring from on position to another is stored in the form of elastic potential energy. It can be given as follows :
[tex]E=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 100\times (0.1^2-0.25^2)\\\\=2.62\ J[/tex]
So, the required energy is 2.62 J.
Answer:
1.125 J
Explanation:
The correct answer is 1.125 J
How can you drop two eggs the fewest amount of times, without them breaking?
Answer:
Both eggs are identical. The aim is to find out the highest floor from which an egg will not break when dropped out of a window from that floor. If an egg is dropped and does not break, it is undamaged and can be dropped again. However, once an egg is broken, that's it for that egg.
What happens when plate subducts and reaches the mantle
Answer:
burns
Explanation:
For a given force as time ___
the impulse related to that force increases. *
A. increases
B. decreases
Answer:
Increases
Explanation:
For a given force, as the time increases, the impulse related to that force increases also.
Impulse and time are directly related to one another. Impulse is mathematically given as:
I = F t
I is the impulse
F is the force
t is the time taken
So, as both force and time increases, the value of the impulse must increase.