Two physics students are arguing about superconductors and their discovery, Jeffe says that he can use a
thermometer and a plug that generates electric current to mimic the experiment and make a superconductor since the
thermometer contains mercury. Sigorne says that he is wrong. Who should win the argument?
O Sigorne, because Jeffe can't use mercury to create a superconductor
O Sigorne, because Jeffe would have to cool the mercury as well
O Jeffe, because he has all of the materials to make a superconductor
O Jeffe, because superconductors are simple to make as long as there is a metal and a current

Answer:yeah it A

Explanation:

This question is incomplete, the complete question is;

People who do very detailed work close up, such as jewelers, often can see objects clearly at much closer distance than the normal 25 cm.

a) What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 8.50 cm? (Assume the lens-to-retina distance is 2.00 cm.)

b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.)  __ mm

Answer:

1) the power in D of the eyes of a woman is 61.7647 D

2) the size in mm of an image of a 8.00 mm object is -1.882 mm

Explanation:

Given the data in the question;

a) power in D of the eyes of woman who can see an object clearly at a distance of only 8.5 cm and the lens-to-retina distance is 2.00 cm,

so

u = 8.5 cm = ( 8.5 / 100 )m = 0.085 m

v = 2.00 cm = ( 2 / 100 )m =  0.02 m

Now, we know that power of lens p = 1 / u + 1 / v

so we substitute

p = ( 1 / 0.085 ) + ( 1 / 0.02 )

p = 11.7647 + 50

p = 61.7647 D

Therefore,  the power in D of the eyes of a woman is 61.7647 D

b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.)

we know that;

m = -v / u

we substitute

m = -0.02 / 0.085

m = -0.2353

since H₀ = 8.0 mm

H[tex]_i[/tex] = m × H₀

H[tex]_i[/tex] = -0.2353 × 8.0

H[tex]_i[/tex] = -1.882 mm

the size in mm of an image of a 8.00 mm object is -1.882 mm

Answer:

[tex]E=4.5*10^-^9J[/tex]

Explanation:

From the question we are told that:

Capacitor [tex]C=1.0nf[/tex]

Induction [tex]I=3.0mH[/tex]

Voltage [tex]V=3.0[/tex]

Generally the equation for Max charge on Capacitor  is mathematically given by

[tex]Q_{max}=C*V[/tex]

[tex]Q_{max}=1*10^{-9}*3[/tex]

[tex]Q_{max}=3*10^{-9}C[/tex]

Generally the equation for Energy in  magnetic field of the coil  is mathematically given by

Since

Energy stored in capacitor = Energy in magnetic field of the coil

Therefore

 [tex]E = (1/2)* C * V^2[/tex]

 [tex]E= 0.5 * 1*10^{-9} *3^2[/tex]

 [tex]E=4.5*10^-^9J[/tex]

Answer:

39.40 MeV

Explanation:

Determine the minimum possible Kinetic energy

width of region = 5 fm

From Heisenberg's uncertainty relation below

ΔxΔp ≥ h/2 , where : 2Δx = 5fm ,  Δpc = hc/2Δx = 39.4 MeV

when we apply this values using the relativistic energy-momentum relation

E^2 = ( mc^2)^2 + ( pc )^2 = 39.4 MeV ( right answer ) because the energy grows quadratically in nonrelativistic approximation,

Also in a nuclear confinement ( E, P >> mc )

while The large value will portray a Non-relativistic limit  as calculated below

K = h^2 / 2ma^2 = 1.52 GeV

Answer:

In some situations, matter demonstrates wave behavior rather than particle behavior. This is best illustrated by which phenomenon is:

C. Interference patterns of electrons.

Answer:

C. Interference patterns of electrons

Answer:

The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

Explanation:

Given;

speed of the faster car, v₁ = 60 mi/h

speed of the slower car, v₂ = 55 mi/h

Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles

[tex]\frac{x}{55} - \frac{x}{60} = \frac{15}{60}[/tex]

Note: divide 15 mins by 60 to convert to hours for consistency in the units.

[tex]\frac{x}{55} - \frac{x}{60} = \frac{15}{60}\\\\multiple \ through \ by \ 660\\\\12x - 11x = 165\\\\x = 165 \ miles[/tex]

Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

Answer:

Option 2

Explanation:

The complete question is

A 50 kg child sits on the left side of the bathtub. A small toy boat of 0.5 kg is on the right side of the bathtub. Which part of the bathtub has the greatest pressure

Solution

It is the bottom of the bucket that will high pressure because of the additional weight of 50 Kg boy along with the weight of the water and the tub itself.

Pressure acts in the down ward direction and is equal to the force/weight divided by the area.

Hence, option 2 is correct

The question is incomplete. The complete question is :

Iron β is a solid phase of iron still unknown to science. The only difference between it and ordinary iron is that Iron β forms a crystal with an fcc unit cell and a lattice constant, a = 0.352 nm. Calculate the density of Iron β.

Solution :

The density is given by :

[tex]$\rho = \frac{ZM}{a^3N_0} \ \ g/cm^3$[/tex]         ..................(i)

Here, Z = number of atoms in a unit cell

         M = atomic mass

         [tex]$N_0$[/tex] = Avogadro's number = [tex]$6.022 \times 10^{23}$[/tex]

          a = edge length or the lattice constant

Now for FCC lattice, the number of atoms in a unit cell is 4.

So, Z = 4

Atomic mass of iron, M = 55.84 g/ mole

Given a  = 0.352 nm = [tex]$3.52 \times 10^{-8}$[/tex] cm

From (i),

[tex]$\rho = \frac{ZM}{a^3N_0} $[/tex]      

[tex]$\rho = \frac{4 \times 55.84}{(3.52 \times 10^{-8})^3 \times 6.022 \times 10^{23}} $[/tex]

  [tex]$= 8.51 \ \ g \ cm ^{-3}$[/tex]

Therefore, the density of Iron β is [tex]$ 8.51 \ \ g \ cm ^{-3}$[/tex].

Answer:

The speed of the proton is [tex]v =5.95\times 10^{5} m/s[/tex]

Explanation:

Energy, E = 1.85 keV

mass of proton, m = 1.67 x 10^-27 kg

Let the speed is v.

The kinetic energy is given by

[tex]K = 0.5m\times v^{2}\\\\1.85\times \1.6\times 10^{-16} = 0.5\times 1.67\times 10^{-27}\times v^{2}\\\\v =5.95\times 10^{5} m/s[/tex]

Answer:

Only a decreasing gravitational force that acts downward

Explanation:

The gravitational force is the gravitational pull which attract a mass of smaller size by the mass of a bigger size.  It is the force which attract two masses close to each other.

In the context, when a ball is tossed up from the surface of an asteroid that have no atmosphere, the ball rises up and then falls back to the surface of the asteroid. The ball falls back because the gravitational pull of the asteroid pulls back the ball to its surface. Thus a decreasing gravitational force acts on the ball in the downward direction while the ball is in its way up.  

Answer:

 Q / m = 8.61 10⁻¹¹ C / kg

Explanation:

For this exercise we use the gravitational force of attraction

     [tex]F_g = G \frac{m_1m_2}{r^2}[/tex]

the electric force

     [tex]F_e = k \frac{q1q2}{r^2}[/tex]

indicate that the two forces are equal

     G m₁ m₂ / r² = k q₁ q₂ / r²

they also say that the two masses are equal and the two charges are equal

     G m² = k Q²

     Q / m =  [tex]\sqrt{\frac{G}{k} }[/tex]

we calculate

      Q / m = [tex]\sqrt{\frac{6.67 \ 10^{-11} }{8.99 \ 10^9} }[/tex]

      Q / m = [tex]\sqrt{ 0.7419 \ 10 ^{-20}}[/tex]

       Q / m = 0.861 10⁻¹⁰

       Q / m = 8.61 10⁻¹¹ C / kg

Answer:

-10miles/hr²

Explanation:

a = ∆v/∆t

Where:

a = acceleration (miles/hr²)

∆V = change in velocity (miles/hr)

t = time (hour)

The change in time is from 2:00 - 4:00 ∆t = 2 hours.

The distance covered is as follows: 20miles/hour - 40 miles/hr

∆v = -20miles/hr

Using a = ∆v/∆t

a = -20/2

a = -10miles/hr²

Answer:

efficiency of a machine is less than 100% because some part is energy is utilized to overcome some opposing forces like friction which is wasted as heat ,sound energy etc

Explanation:

Answer: [tex]115.52\ N[/tex]

Explanation:

Given

Length of plank is 1.6 m

Force [tex]F_1[/tex] is applied on the left side of plank

Force [tex]F_2[/tex] is applied 43 cm from the left end O.

Mass of the plank is [tex]m=13.7\ kg[/tex]

for equilibrium

Net torque must be zero. Taking torque about left side of the plank

[tex]\Rightarrow mg\times 0.8-F_2\times 0.43=0\\\\\Rightarrow F_2=\dfrac{13.7\times 9.8\times 0.8}{0.43}\\\\\Rightarrow F_2=249.78\ N[/tex]

Net vertical force must be zero on the plank

[tex]\Rightarrow F_1+W-F_2=0\\\Rightarrow F_1=F_2-W\\\Rightarrow F_1=249.78-13.7\times 9.8\\\Rightarrow F_1=115.52\ N[/tex]

White Dwarf Stage

Answer: b force

Explanation:

yes because the world comin g up with more technique

Answer:

The electric force will also double.

When the test charge q is double the change in magnitude of the electric force is that it also gets doubled.

Electric force is defined as force between the chages which is directly proportional to the product of charges and inversely proportional to the square of the distance between them. The electric force is a vector quantity, It have magnitude as well as direction.

Electric force = k*Q*q/r²

The electric field is defined as the electric force per unit charge. The electric field is a vector quantity.

Electric field = Electric force / test charge

Electric field = k*Q/r²

Given that in question there is the test charge, q for electric field and the source charge Q when the test charge q will become 2q then electric force is,

Electric force = kQ(2q)/r²

So, the magnitude of the electric force is increased by twice when the test charge will become 2q.

To learn more about the electric force refer to the link

brainly.com/question/2526815

#SPJ2

Answer:

I dont. understand the question, maybe insert the picture?

Answer:

Equations of motion relate the displacement of an object with its velocity, acceleration and time. s=vt where s is the displacement, v the (constant) speed and t the time over which the motion occurred. ...

Displacement with negative acceleration: s, equals, v, t, minus, one half, a, t, square...

Displacement with positive acceleration: s, equals, u, t, plus, one half, a, t, squared,s...

Velocity squared: v, squared, equals, u, squared, plus, 2, a, s,v2=u2+2as

Velocity: v, equals, u, plus, a, t,v=u+at

им putins брат, почему вы обманываете нашу систему образования, Это теперь запрещено в России.

Answer: [tex]-4.3\ J,\ 9\ J[/tex]

Explanation:

Given

(a)

Heat transfer [tex]Q=-7.9\ J\quad \text{taken}[/tex]

Work done [tex]W=-3.6\ J\quad \text{on the system}[/tex]

Change in the internal kinetic energy is

[tex]\Delta U=Q-W\\\Rightarrow \Delta U=-7.9-(-3.6)\\\Rightarrow \Delta U=-4.3\ J[/tex]

(b)

Heat transfer [tex]Q=1.5\ J\quad \text{given}[/tex]

Work done [tex]W=-7.5\ J\quad \text{on the system}[/tex]

Change in the internal kinetic energy is

[tex]\Delta U=Q-W\\\Rightarrow \Delta U=1.5-(-7.5)\\\Rightarrow \Delta U=9\ J[/tex]

Answer:

required distance is 233.35 m

Explanation:

Given the data in the question;

Sound intensity [tex]I[/tex] = 1.62 × 10⁻⁶ W/m²

distance r = 165 m

at what distance from the explosion is the sound intensity half this value?

we know that;

Sound intensity [tex]I[/tex] is proportional to 1/(distance)²

i.e

[tex]I[/tex] ∝ 1/r²

Now, let r² be the distance where sound intensity is half, i.e [tex]I[/tex]₂ = [tex]I[/tex]₁/2

Hence,

[tex]I[/tex]₂/[tex]I[/tex]₁ = r₁²/r₂²

1/2 = (165)²/ r₂²

r₂² = 2 × (165)²

r₂² = 2 × 27225

r₂² = 54450

r₂ = √54450

r₂ = 233.35 m

Therefore, required distance is 233.35 m

Answer:

Option C, acting as waves and particles

Explanation:

Light has dual nature  because it acts both as a wave and particle. It has high energy particle i.e photons and it also behave as an electromagnetic wave. This property of light is studied under the quantum mechanics. Einstein also proved that light is a stream of photons possessing both electrical and magnetic properties.

Hence, option C is correct

Answer:

The answer is C. A change in a substance with no new substances being formed

Explanation:

I did the quiz.

The best definition of physical change is a change in a substance, with no new substances being formed. Hence, option C is correct.

A chemical substance's form, not its chemical composition, can change due to physical changes. In most cases, compounds cannot be separated into chemical components or simpler compounds; instead, mixtures are separated into their constituent compounds through physical changes.

Whenever something changes physically but not chemically, we say that something has changed physically. This is in contrast to the idea of a chemical change, which occurs when a substance's composition changes or when one or more compounds join or fragment to generate new substances. In general, physical means can be employed to undo a physical alteration. For instance, by letting the water evaporate, salt that has been dissolved in it can be reclaimed.

Therefore, this concludes that option C is correct.

To know more about Physical change:

#SPJ2

Answer:

brightness that we observe from a star is related to the energy produced and the distance to the Earth

Explanation:

In stars, the color that we observe is directly related to the temperature of the star by the y of the Wien displacement.

             λ_{max} T = 2,898 10³

the brightness that we observe from a star is related to the energy produced and the distance to the Earth

Answer:

Explanation:

In a Solid sphere; the moment of inertia around its geometrical axis can be expressed by using the formula:

[tex]\mathtt{I_s = \dfrac{2}{5} M_s R^2_s}[/tex]

For the solid disk; the moment of inertia around the central axis is:

[tex]\mathtt{I_D= \dfrac{1}{2}M_DR_D^2}[/tex]

Suppose [tex]M_D = M_S[/tex]; then we can say both to be equal to M

As well as [tex]R_D = R_S[/tex]; then that too can be equal to R

Now;

[tex]\mathtt{I_s = \dfrac{2}{5} M R^2} --- (1)[/tex]

[tex]\mathtt{I_D= \dfrac{1}{2}MR^2}---(2)[/tex]

Multiplying equation (1) by 2, followed by dividing it by 2; we have:

[tex]\mathtt{I_s= \dfrac{2}{5}MR^2} \times \dfrac{2}{2}[/tex]

[tex]I_s = \dfrac{4}{5} \times \dfrac{1}{2}MR^2 \\ \\ I_s = \dfrac{4}{5}\times I_D \\ \\ I_s > I_D[/tex]

Answer:

a)   p = 4.167 cm, b)   m = + 6

Explanation:

a) For this exercise we must use the equation of the constructor

          [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and the image, respectively

In this case the distance to the image q = 25 cm and the focal length is f = 5.0 cm

Since the object and its image are on the same side of the lens, the distance to the image by the sign convention must be negative.

       [tex]\frac{1}{p } = \frac{1}{f} - \frac{1}{q}[/tex]

      [tex]\frac{1}{p} = \frac{1}{5} - \frac{1}{-25}[/tex]

      [tex]\frac{1}{ p}[/tex] = 024

      p = 4.167 cm

b) angular magnification

     m = h ’/ h = - q / p

     m = - (-25) /4.167

     m = + 6

the positive sign indicates that the image is straight and enlarged

Given :

A 0.50-kg mass is attached to a spring of spring constant 20 N/m along a horizontal, frictionless surface.

The object oscillates in simple harmonic motion and has a speed of 1.5 m/s at the equilibrium position.

To Find :

At what location are the kinetic energy and the potential energy the same.

Solution :

Let, at location x from the equilibrium position the kinetic energy and the potential energy the same.

So,

[tex]P.E = K.E\\\\\dfrac{kx^2}{2} = \dfrac{mv^2}{2}\\\\x = v\sqrt{\dfrac{m}{k}}\\\\x = 1.5 \times \sqrt{\dfrac{0.5}{20}}\ m\\\\x = 0.238 \ m[/tex]

Hence, this is the required solution.