Two protons are on either side of an electron as shown below:
Diagram
The electron is 30 µm away from the proton on its left and 10 µm away from the proton on its right. What is the magnitude and direction of the net electric force acting on the electron? Note that
P=1.6×10(-19) c=-e

Select one:
a. 2.0×10−18N to the right
b. 7.0×10−24N to the right
c. 2.0×10−18N to the left
d. −9.59×10−24N to the right
e. 7.0×10−24N to the

Answers

Answer 1

Answer:

Choice a. approximately [tex]2 \times 10^{-18}\; \rm N[/tex] to the right.  

Explanation:

Look up the Coulomb constant, [tex]k[/tex]:

[tex]k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex].

Coulomb's Law may be used to find the magnitude of the electric force between the electron and each proton.

Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of electric charge on two point charges. Let [tex]r[/tex] denote the distance between these two charges.

By Coulomb's Law, the magnitude of the force between these two point charges would be:

[tex]\displaystyle F = \frac{k\, q_1\, q_2}{r^2}[/tex].

The unit of distance in the Coulomb's constant here[tex]k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex] is meters. However, the distance between the electron and each proton is given in micrometers, [tex]\rm \mu m[/tex]. Note that [tex]1\; \rm \mu m = 10^{-6}\; \rm m[/tex].

Convert these units to meters:

[tex]30 \; \rm \mu m = 30 \times 10^{-6}\; \rm m[/tex].

[tex]10 \; \rm \mu m = 10 \times 10^{-6}\; \rm m[/tex].

The question states that the magnitude of electric charge on each proton and each electron is [tex]1.6\times 10^{-19}\; \rm C[/tex].

Using these information, find the magnitude of the electric force between the electron and each proton:

Between the electron and the proton on the left-hand side of the electron: [tex]\begin{aligned}F &= \frac{k\, q_1\, q_2}{r^2}\\ &\approx \frac{\left(8.987552\times 10^{9}\; \rm N \cdot m^2\cdot C^{-2}\right) \times \left(1.6 \times 10^{-19}\; \rm C\right) \times \left(1.6 \times 10^{-19}\; \rm C\right)}{\left(30 \times 10^{-6}\; \rm m\right)} \\ &\approx 0.26 \times 10^{-18}\; \rm N\end{aligned}[/tex].Between the electron and the proton on the right-hand side of the electron:[tex]\begin{aligned}F &= \frac{k\, q_1\, q_2}{r^2}\\ &\approx \frac{\left(8.987552\times 10^{9}\; \rm N \cdot m^2\cdot C^{-2}\right) \times \left(1.6 \times 10^{-19}\; \rm C\right) \times \left(1.6 \times 10^{-19}\; \rm C\right)}{\left(10 \times 10^{-6}\; \rm m\right)} \\ &\approx 2.56 \times 10^{-18}\; \rm N\end{aligned}[/tex].

The two protons in this question will both attract the electron. Therefore, the force between the electron and the proton on the left-hand side of the electron would point to the left. Similarly, the force between the electron the proton on the right-hand side of the electron would point to the right.

The magnitude of the net electric force on the electron would be:

[tex]2.56 \times 10^{-18}\; \rm N - 0.26\times 10^{-18}\;\rm N \approx 2\times 10^{-18}\; \rm N[/tex].

These two forces act along the same line in opposite direction. Therefore, the resultant force of these two force would be in the direction of the larger force of the two.

In this question, the electric force between the electron and the proton on the right-hand side of the electron is larger. Hence, the net electric force of the protons on the electron should point to the right (towards the proton that is closer to the electron.)


Related Questions

A cement truck when filled weighs 42 000 N. Calculate its mass

Answers

Answer:

Mass = 4281.35 kg

Explanation:

From Newton's law of motion, the weight of an object is given by the formula;

W = mg

Where;

W is weight

m is mass

g is acceleration due to gravity which has a constant value of 9.81 m/s².

We are given weight W = 42000 N.

Thus;

42000 = m × 9.81

m = 42000/9.81

m ≈ 4281.35 kg

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Answer:

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i hope this helps your answer

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Answer:

They would probably not be looking good.. like if u don't sort it out they won't be shaped well and there are many types of plastic and if we combine them together they won't give the correct form..

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Answer:

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Explanation:

I used a calculator.

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that is cool and i have one interesting fact

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A new business should be based on an entrepreneur's individual interests because the entrepreneur must have sufficient confidence to succeed. be willing to take personal responsibility. have enough determination to work alone. dedicate as many hours as needed to the work.

Answers

Answer: D) dedicate as many hours as needed to the work.

Explanation:

edge 2020

If the entrepreneur puts in dedication to duty, responsibility and long hours of work, the new business is more likely to survive.

Who are entrepreneurs?

A business refers to any venture that is set up with the intention of making profit. The proprietors of new businesses are called entrepreneurs. They are saddled with the responsibility of propagating the activities of the new business.

The entrepreneur must be ready to put in:

Long hours of workResponsibilityDedication

If the entrepreneur does all these, his/her new business is more likely to survive than ever.

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1. Newton's third law states that any action will have a(n) and reaction O A. Equal and opposite O B. Greater and opposite C. Equal and similar D. Equal and different​

Answers

Answer: Equal and Opposite

Explanation:

The average swimming speed of a salmon is about 5 ft/s. If a salmon swims at this speed for a full minute, how far will the salmon travel?

Answers

300 feet because 5x60=300 and there is 60 seconds in a min

A hockey puck attached to a horizontal spring oscillates on a frictionless, horizontal surface. The spring has force constant 4.50 N/m and the oscillation period is 1.20 s. What is the mass of the puck

Answers

Answer:

m = 0.164 kg

Explanation:

T (period)

k (force/spring constant)

m (mass)

T = 2*Pi*sqrt(m/k)

T/(2*Pi) = sqrt(m)/sqrt(k)

(T/(2*Pi))*sqrt(k) = sqrt(m)

m = ((T/(2*Pi))*sqrt(k))^2

m = 4.5*((1.2/(2*Pi)))^2

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A black lift of amber is placed in water and a laser beam travels from the water through the amber. The angle of incidence is 35 degrees while the angle of refraction is 24 degrees. What is the index of refraction of amber

Answers

Answer:

Explanation:

refractive index of ember = sin of angle of incidence / sin of angle of refraction

= sin 35 / sin24

= .5735 / .4067

= 1.41

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A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above her head, and the string angles down slightly (11.9° below the horizontal.). The string is massless and 0.75m long.

A coordinate system lies with its origin a the location where the string comes out of the girl's hand. The positive z-axis points vertically. the projection onto the horizontal plane is such that the string makes an angle of 34.6° with the x-axis.

At a certain instant, the rock makes 2.50 revolutions per second (rev/s) in a counterclockwise direction as seen from above.

What is the tangential velocity vector at this instant?

Answers

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is  [tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]

Explanation:

From the question we are told that

   The mass of the rock is  [tex]m = 0.250 \ kg[/tex]

    The length of the string is  [tex]L = 0.75 \ m[/tex]

    The angle the string makes horizontal is  [tex]\theta = 11.9^o[/tex]

     The angle which the projection of the string onto  the xy -plane makes with the positive x-axis is  [tex]\phi = 34.6^o[/tex]

    The angular velocity of the rock is  [tex]w = 2.50 rev/s = 2.50 * 2\pi =15.7 \ rad/s[/tex]

Generally the radius of the circle made by the length of the string is mathematically represented as

               [tex]r = L cos(\theta )[/tex]

=>            [tex]r = 0.75 cos(11.9 )[/tex]

=>            [tex]r = 0.734 \ m[/tex]

Generally the resultant tangential velocity is mathematically represented as

      [tex]v__{R}} = w * r[/tex]

=>  [tex]v__{R}} = 15.7 *0.734[/tex]

=>  [tex]v__{R}} = 11.5 \ m/s[/tex]

Generally the tangential velocity along the x-axis is  

      [tex]v_x = -v__{R}} * sin(\phi)[/tex]

=>   [tex]v_x =- 11.5 * sin(34.6)[/tex]

=>   [tex]v_x = -6.543 \ m/s[/tex]

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is  

      [tex]v_y = v__{R}} * cos(\phi)[/tex]

=>   [tex]v_y = 11.5 * cos(34.6)[/tex]

=>   [tex]v_y = 9.47 \ m/s[/tex]

Generally the tangential velocity along the y-axis is  

      [tex]v_z = v__{R}} * cos(90)[/tex]

=>   [tex]v_z = 0 \ m/s[/tex]

Generally the tangential velocity at that instant is mathematically represented as

       [tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]

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Answers

Answer:

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Fnorm
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Å

Answers

Answer:

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Explanation:

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