URGENT!! ANSWER GETS 100 POINTS AND BRAINLIEST The dot plots show the heights of boys and girls at a summer camp. Heights of Boys and Girls at Camp 2 dot plots with number lines going from 40 to 60. A plot is titled Boy's Heights. There are 0 dots above 40, 1 above 41, 3 above 44, 3 above 46, 2 above 48, 3 above 50, 4 above 52, 4 above 54, and 0 above 56, 58, and 60. A plot is titled Girl's Heights. There are 0 dots above 40 and 41, 2 dots above 44, 3 above 46, 1 above 48, 3 above 50, 4 above 52, 3 above 54, 4 above 56, and 0 above 58 and 60. Which is a true statement for most of the data in each plot?
Most of the data in each plot are greater than 48.
Most of the data in each plot are less than 48.
Most of the data in each plot are around 52.
Most of the data in each plot are around 54.

Answer:

576 (square yards)

Step-by-step explanation:

length of slanted height of triangle = √(6² + 8²)

= √100

= 10.

surface area = area of 2 triangle faces + area of 3 lengths

= 2 (1/2 X 12 X 8) + 3 (10 X 16)

= 576 (square yards)

The probability that Ali misses 4 shots out of 25, given that he has a 3-point shooting percentage of 9/10 or 0.9, is approximately 0.1394, or about 13.94%.

The probability of an event occurring is defined by probability. There are numerous real-life scenarios in which we must forecast the outcome of an occurrence.

We can use the binomial distribution to find the probability that Ali misses 4 shots out of 25, given that he has a 3-point shooting percentage of 9/10 or 0.9.

Let X be the number of missed shots out of 25 attempts. Since each shot is either a miss or a make, this is a binomial distribution with n = 25 and p = 1 - 9/10 = 1/10. We want to find P(X = 4), which is:

P(X = 4) = (25 choose 4) * (1/10)⁴ * (9/10)²¹

where "25 choose 4" is the number of ways to choose 4 shots out of 25.

Using a calculator, we can evaluate this expression to find:

P(X = 4) ≈ 0.1394

Therefore, the probability that Ali misses 4 shots out of 25, given that he has a 3-point shooting percentage of 9/10 or 0.9, is approximately 0.1394, or about 13.94%.

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The perimeter of the isosceles trapezoid is equal to 456 feet which makes the option c correct.

This is a trapezoid in which the base angles are equal and therefore the left and right side lengths are also equal. The opposite angles are supplementary which implies they sum up to 180°.

We shall first find the length of the left and right sides which are of same length as follows:

3x - 2 = 2x + 3

3x - 2x = 3 + 2

x = 5

PQ = 6(25) - 10 = 140

QR = 3(25) - 22 = 53

RS = 9(25) - 15 = 210

PS = 2(25) + 3 = 53

perimeter of the Isosceles trapezoid = 140ft + 53ft + 210ft + 53ft

perimeter of the Isosceles trapezoid = 456ft.

Therefore, the perimeter of the isosceles trapezoid is equal to 456 feet which makes the option c correct.

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Corresponds to the equation 84 - 8x = 52 is one where there is a total of 84 items and each item costs 8 dollars less than the previous one. The goal is to determine how many items can be purchased with a budget of 52 dollars. Therefore, In this situation, you gave marbles to 4 friends, with each friend receiving 8 marbles.

Situation, You have 84 marbles in a jar. You want to divide the marbles into equal groups to give away to your friends. After distributing the marbles, you have 52 marbles remaining in the jar. How many friends did you give the marbles to....

Equation , The equation representing this situation is 84 - 8x = 52, where x represents the number of friends you gave the marbles to, and 8 represents the number of marbles in each group.

1. Write down the equation: 84 - 8x = 52

2. To find the value of x, we will first isolate the term containing x. To do this, we need to move the constant term (84) to the other side of the equation by subtracting it from both sides: -8x = 52 - 84

3. Perform the subtraction: -8x = -32

4. Now, to solve for x, we will divide both sides of the equation by -8: x = -32 / -8

5. Perform the division: x = 4

Therefore, In this situation, you gave marbles to 4 friends, with each friend receiving 8 marbles.

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The cost of a CD is $5.94 more than the cost of a DVD. Let's assume that the cost of a DVD is "x" dollars, then the cost of a CD is "x+5.94" dollars.

Using this information, we can write the following equations:

5(x+5.94) + 2x = 113.63 (cost of 5 CDs and 2 DVDs)

6(x+5.94) + 2x = ? (cost of 6 CDs and 2 DVDs)

Solving the first equation for "x", we get x = 12.21. Substituting this value in the second equation, we get the cost of 6 CDs and 2 DVDs as $83.64.

Therefore, the cost of 6 CDs and 2 DVDs would be $83.64 at All Bets Are Off Electronics if 5 CDs and 2 DVDs cost $113.63, and CDs cost $5.94 more than DVDs.

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Answer:

4 pizzas

Step-by-step explanation:

first of all, subtract parking fee from total:

52 - 4 = 48.

now divide by 12:

48/12

4.

so he he pays for 4 pizzas at $12 each (4 X 12 = 48).

and he pays $4 for parking.

48 + 4 = 52.

Answer: y=−(x−5/2)^2−3/4

Answer:

  -1572864

Step-by-step explanation:

You want the 19th term of the geometric sequence with first term -6 and common ratio -2.

The n-th term of a geometric sequence is ...

  an = a1·r^(n-1)

where a1 is the first term, and r is the common ratio.

Using the given values of a1 and r, the 19th term is ...

  a19 = (-6)·(-2)^(19-1) = -1572864

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The probability of getting all three tosses to head is 1/8.

We have,

When a coin is tossed, there are two possible outcomes:

heads (H) or tails (T).

Since there are three tosses, the total number of possible outcomes.

2³ = 8.

The probability of getting heads on one toss is 1/2.

The probability of getting heads on all three tosses is the product of the probabilities of getting heads on each individual toss:

P(HHH) = P(H) x P(H) x P(H) = (1/2) x (1/2) x (1/2) = 1/8.

Therefore,

The probability of getting all three tosses to head is 1/8.

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Answer:

A. 24 inches

Step-by-step explanation:

A cube is defined by having all three lengths being of equal size,

[tex]V = L^3[/tex]

so to find length from the volume of a cube, you must take the cube root of the volume.

[tex]\sqrt[3]{V} = L[/tex]

[tex]\sqrt[3]{216} = 6[/tex]

That means each side of the cube has a length of 6 inches.

The formula for the perimeter is give below the cube diagram.

[tex]P = 4L[/tex]

Which means we just take the length we found above and multiply it by 4.

[tex]4*6 =24[/tex] inches

Therefore 24 inches is your answer.

A value of r greater than 0.40 indicates a stronger correlation than 0.40.

The correlation coefficient, denoted as "r," measures the strength and direction of the linear relationship between two variables. The value of r ranges from -1 to 1. When the absolute value of r is closer to 1, it indicates a stronger correlation. In this case, a value of r greater than 0.40 suggests a stronger positive correlation than 0.40.

This means that as one variable increases, the other variable tends to increase as well, and the relationship between the variables is more pronounced. For example, if the correlation coefficient is 0.60, it indicates a stronger positive correlation than 0.40. Similarly, if the correlation coefficient is 0.90, it indicates an even stronger positive correlation. On the other hand, if the correlation coefficient is negative, such as -0.60 or -0.90, it indicates a stronger negative correlation.

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The area lying outside r=4sinθ and inside r=2+2sinθ is approximately 10.81 square units.

To find the area lying outside r=4sinθ and inside r=2+2sinθ, we need to first graph these two polar curves.

r=4sinθ is a cardioid, while r=2+2sinθ is a limacon with an inner loop.

The area we are looking for is the shaded region between these two curves.

To find the area, we need to integrate the difference between the outer curve (r=4sinθ) and the inner curve (r=2+2sinθ) from θ=0 to θ=2π:

Area = ∫(4sinθ)^2 - (2+2sinθ)^2 dθ from θ=0 to θ=2π

This simplifies to:

Area = ∫(16sin^2θ - 4 - 8sinθ - 4sin^2θ) dθ from θ=0 to θ=2π

Area = ∫(12sin^2θ - 8sinθ - 4) dθ from θ=0 to θ=2π

Using trigonometric identities and integration techniques, we can solve for the area:

Area = 4π - 8/3

Therefore, the area lying outside r=4sinθ and inside r=2+2sinθ is approximately 10.81 square units.

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The value of the definite integral (3x-4)²dx is (3b³ - 12b² + 16b + C) - (3a³ - 12a² + 16a + C), since the limits are not mentioned.

To evaluate the definite integral of (3x-4)² dx, we first need to expand the expression and then find the antiderivative. Finally, we need to apply the limits of integration if they are provided.

Expanding the expression:

(3x-4)² = 9x² - 24x + 16
Finding the antiderivative:

∫(9x² - 24x + 16) dx = 3x³ - 12x² + 16x + C
Now, if we have limits of integration (a, b), we would evaluate the antiderivative at those points and subtract the results:
F(b) - F(a) =[tex](3b^3 - 12b^2[/tex] [tex]+ 16b + C[/tex]) - [tex](3a^3 - 12a^2 + 16a + C)[/tex]
However, since no limits of integration were provided, we cannot evaluate the definite integral further.

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The composite function is c(x(t)) = 3(2-6t)^2 - 7, and its derivative with respect to t is dc/dt = -72 + 216t.

To write the composite function, we substitute the expression for x(t) into c(x), giving c(x(t)) = 3(2-6t)^2 - 7.

To find the derivative of this composite function with respect to t, we use the chain rule:

dc/dt = (dc/dx) * (dx/dt)

where (dc/dx) is the derivative of c(x) with respect to x, and (dx/dt) is the derivative of x(t) with respect to t.

Taking the derivative of c(x) = 3x^2 - 7 with respect to x, we get:

dc/dx = 6x

And taking the derivative of x(t) = 2 - 6t with respect to t, we get:

dx/dt = -6

Substituting these values into the chain rule formula, we get:

dc/dt = (6x) * (-6)

Since x(t) = 2-6t, we can substitute that expression for x to get:

dc/dt = (6(2-6t)) * (-6)

Simplifying, we get:

dc/dt = -72 + 216t

So the composite function is c(x(t)) = 3(2-6t)^2 - 7, and its derivative with respect to t is dc/dt = -72 + 216t.

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Answer:

-35.375

Step-by-step explanation:

(-1.5+9.5)=8

5/8 =0.625

7+11=18

0.4*18=36/5

=7.2

7.2/-0.2=

-283/8=

-35.375

The area between the functions f(x) = 2 · x + 6 and g(x) = 2 · x² + 2 is equal to 8.333 square units. (Right choice: C)

In this question we must determine the area between the functions f(x) = 2 · x + 6 and g(x) = 2 · x² + 2, this can be done by using the following definite integral:

A = ∫²₋₁ [f(x) - g(x)] dx

A = ∫²₋₁ f(x) dx - ∫²₋₁ g(x) dx

A = ∫²₋₁ (2 · x + 6) dx - ∫²₋₁ (2 · x² + 2) dx

A = x²|²₋₁ + 6 · x|²₋₁ - (2 / 3) · x³|²₋₁ - 2 · x|²₋₁

A = 2² - (- 1)² + 6 · [2 - (- 1)] - (2 / 3) · [2³ - (- 1)³] - 2 · [2 - (- 1)]

A = 1 + 18 - 14 / 3 - 6

A = 8.333  

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A certain states might not be visited at all while collecting the Statistics. Statistics for certain states might be visited much less often than others leading to very noisy estimates.

Certain states might not be visited at all while collecting the statistics: In the described manner of estimation, there is a possibility that some states may not be visited during the data collection process. This can result in incomplete or biased estimates if those unvisited states have unique characteristics or play an important role in the overall analysis.

Estimates for certain states might be visited much less often than others leading to very noisy estimates: If the data collection process is not balanced or systematic, certain states may be visited less frequently compared to others. As a result, the estimates for these states could be less reliable and prone to higher levels of uncertainty, leading to noisy or inconsistent results.

Therefore, the correct options are:

Certain states might not be visited at all while collecting the statistics.

Estimates for certain states might be visited much less often than others leading to very noisy estimates.

It is likely that certain states might not be visited at all or may be visited much less frequently than others while collecting statistics, leading to very noisy estimates. This is known as the problem of "sparse data." Therefore, the correct options are:

Certain states might not be visited at all while collecting the statistics.

Statistics for certain states might be visited much less often than others leading to very noisy estimates.

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The Taylor polynomial t3(x) for the function f(x) = xe−7x centered at a is:

t3(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)2/2! + f'''(a)(x-a)3/3!

To find the Taylor polynomial t3(x), we need to compute the first three derivatives of f(x):

f(x) = xe−7x

f'(x) = e−7x − 7xe−7x

f''(x) = 49xe−7x − 14e−7x

f'''(x) = −343xe−7x + 147e−7x

Next, we evaluate these derivatives at x = a and simplify:

f(a) = ae−7a

f'(a) = e−7a − 7ae−7a

f''(a) = 49ae−7a − 14e−7a

f'''(a) = −343ae−7a + 147e−7a

Now, we plug these values into the formula for t3(x):

t3(x) = ae−7a + (e−7a − 7ae−7a)(x-a) + (49ae−7a − 14e−7a)(x-a)2/2! + (−343ae−7a + 147e−7a)(x-a)3/3!

We can simplify this expression to obtain the final form of t3(x):

t3(x) = ae−7a + (x-a)e−7a(1-7(x-a)) + (x-a)2e−7a(49a-7) + (x-a)3e−7a(-343a+147)/6

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Answer:

To transform the graph of f(x)=x√ into g(x)=x+9, we need to apply a horizontal shift to the right by 9 units. This can be done by replacing x in f(x) with x-9 to get g(x)=(x-9)√. The resulting graph will be the same as the graph of f(x), but shifted 9 units to the right.

(a) Polar coordinate r for P, with r>0 and ?<θ<3π/2 is r=7cos(π/4-θ). (b) Cartesian coordinates for point P are (x,y)=(-7cos(π/4-θ),-7sin(π/4-θ)). (c) The curve passes through the origin twice when 0<θ<2π.

(a) To find r for P, we plug in θ=16π/14 into r=7(2cosθ) and simplify using the identity cos(π/4-θ)=cos(π/4)cos(θ)+sin(π/4)sin(θ)=√2/2(cos(θ)+sin(θ)) to obtain r=7cos(π/4-θ).

(b) To convert from polar to Cartesian coordinates, we use the formulas x=r cos(θ) and y=r sin(θ) and plug in r=7cos(π/4-θ) to get x=-7cos(π/4-θ) and y=-7sin(π/4-θ).

(c) The curve passes through the origin when r=0, which occurs when θ=π/2 and θ=3π/2. Since 0<θ<2π covers each θ value exactly once, the curve passes through the origin twice.

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if Jeremiah wants to get the most dog food for his money, he should buy the Woofy Waffles.

For Part A,

According to the given data in the table,

To calculate the unit rate for each package,

Simply divide the cost by the size.

So, for Canine Cakes,

The unit rate would be $24 ÷ 16 pounds = $1.50 per pound.

For Bark Bits,

The unit rate would be $82 ÷ 50 pounds = $1.64 per pound.

And for Woofy Waffles,

The unit rate would be $48 ÷ 40 pounds = $1.20 per pound.

For Part B,

To determine the best buy using the unit rates found in Part A.

The best buy is the package with the lowest unit rate,

because that means you're getting the most product for your money.

In this case,

The package with the lowest unit rate is Woofy Waffles,

At $1.20 per pound.

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Answer:

z = 56

Step-by-step explanation:

124 and Z form a straight line so they will add to 180

124+z = 180

z = 180-124

z = 56

Answer:

z = 56°

Step-by-step explanation:

We know that vertically opposite angles are equal.

∴ y = 124°

We know that angles in a straight line are added up to 180°.

∴ y + z = 180

124 + z = 180

z = 180 - 124

z = 56°

x = 56° ( vertically opposite angles ⇒ x = z )

The phasor method involves converting the sinusoidal functions into phasors, which are complex numbers representing the amplitude and phase of the sinusoidal function. The phasor for a sinusoidal function y = A sin(ωt + φ) is A e^(iφ), where A is the amplitude and φ is the phase angle.

(a) To find the amplitude of y, we need to add the phasors of y1, y2, and y3. The phasor for y1 is 11 e^(i0) = 11, the phasor for y2 is 21 e^(i30°), and the phasor for y3 is 7.0 e^(-i50°). Therefore, the phasor for y is:

Y = 11 + 21 e^(i30°) + 7.0 e^(-i50°)

To find the amplitude of Y, we can take the magnitude of this phasor:

|Y| = sqrt[(11)^2 + (21)^2 + (7.0)^2] = 24.2

Therefore, the amplitude of y is 24.2.

(b) To find the phase constant of y, we need to find the angle that the phasor Y makes with the positive real axis. We can write the phasor Y in rectangular form:

Y = (11 + 21 cos 30° - 7.0 cos 50°) + (21 sin 30° - 7.0 sin 50°) i

The angle that the phasor Y makes with the positive real axis is:

tan^(-1)[(21 sin 30° - 7.0 sin 50°) / (11 + 21 cos 30° - 7.0 cos 50°)]

Using a calculator, we find that this angle is approximately -6.5°. Therefore, the phase constant of y is -6.5°, or we can say that the phase angle of the phasor Y is -6.5°.

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The first partial derivatives of f(x,y) at the point (3,1) are:
∂f/∂x(3,1) = 3
∂f/∂y(3,1) = -12

To find the first partial derivatives of f(x,y) at the point (3,1), we need to find the partial derivative with respect to x and y, respectively, and then substitute x=3 and y=1.

So, let's begin with the partial derivative with respect to x:
∂f/∂x = 3 - 0  (since the derivative of 3x with respect to x is 3, and the derivative of 4y with respect to x is 0)

Now, we can substitute x=3 and y=1 into this expression:
∂f/∂x(3,1) = 3 - 0 = 3

So, the partial derivative of f(x,y) with respect to x at the point (3,1) is 3.

Next, let's find the partial derivative with respect to y:
∂f/∂y = 0 - 12y^2  (since the derivative of 3x with respect to y is 0, and the derivative of 4y with respect to y is 12y^2)

Now, we can substitute x=3 and y=1 into this expression:
∂f/∂y(3,1) = 0 - 12(1)^2 = -12

So, the partial derivative of f(x,y) with respect to y at the point (3,1) is -12.

Therefore, the first partial derivatives of f(x,y) at the point (3,1) are:
∂f/∂x(3,1) = 3
∂f/∂y(3,1) = -12

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The points whose distance from (-3,-4) is the square root of 10 and whose distance from (1,0) is the square root of 10 are given by the circle (x+3)^2 + (y+4)^2 = 2, which has center (-3,-4) and radius sqrt(2).

The problem involves finding all points that are equidistant from two given points. These points will lie on the perpendicular bisector of the line segment joining the two given points.

First, we find the midpoint of the line segment joining (-3,-4) and (1,0), which is ((-3+1)/2, (-4+0)/2) = (-1,-2).The line passing through (-1,-2) and perpendicular to the line joining (-3,-4) and (1,0) can be found by finding the negative reciprocal of the slope of that line. The slope of the line joining (-3,-4) and (1,0) is (0-(-4))/(1-(-3)) = 4/4 = 1. So the slope of the perpendicular line is -1/1 = -1.

Now we have the slope and a point on the perpendicular line, so we can find its equation using point-slope form: y - (-2) = (-1)(x - (-1)) => y = -x - 1.

Next, we find the points that are a distance of sqrt(10) from (-3,-4) and also from (1,0). Let (x,y) be a point on the line y = -x - 1. The distance from (-3,-4) to (x,y) is sqrt((x-(-3))^2 + (y-(-4))^2), which simplifies to sqrt(x^2 + y^2 + 6x + 8y + 25). Similarly, the distance from (1,0) to (x,y) is sqrt((x-1)^2 + y^2). Setting these two expressions equal to sqrt(10) and squaring both sides, we get the equation x^2 + y^2 + 6x + 8y + 15 = 0.

We can complete the square to rewrite this equation as (x+3)^2 + (y+4)^2 = 2. This is the equation of a circle centered at (-3,-4) with radius sqrt(2). The coordinates of all points equidistant from (-3,-4) and (1,0) are given by the points on this circle.

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We can conclude that the left-hand side (AU (BoC) - (AUB) A (AUC)) and the right-hand side (∅) have no common elements, which proves the equality AU (BoC) - (AUB) A (AUC) = ∅.

To prove the equality AU (BoC) - (AUB) A (AUC) = ∅, we need to show that the left-hand side is an empty set.

First, let's break down the expression step by step:

AU (BoC) represents the union of A with the intersection of B and C. This implies that any element in A, or in both B and C, will be included.

(AUB) represents the union of A and B, which includes all elements present in either A or B.

(AUC) represents the union of A and C, which includes all elements present in either A or C.

Now, let's analyze the right-hand side:

(AUB) A (AUC) represents the intersection of (AUB) and (AUC), which includes elements that are common to both sets.

To prove the equality, we need to show that the left-hand side and the right-hand side have no common elements, i.e., their intersection is empty.

If an element belongs to the left-hand side (AU (BoC) - (AUB) A (AUC)), it must either belong to A and not belong to (AUB) A (AUC), or it must belong to (BoC) and not belong to (AUB) A (AUC).

However, if an element belongs to (BoC), it implies that it belongs to both B and C. Since it does not belong to (AUB) A (AUC), it means that it cannot belong to either A or B or C. Similarly, if an element belongs to A, it cannot belong to (AUB) A (AUC).

Therefore, we can conclude that the left-hand side (AU (BoC) - (AUB) A (AUC)) and the right-hand side (∅) have no common elements, which proves the equality AU (BoC) - (AUB) A (AUC) = ∅.

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The decimal form of the given number which is 5 3/4 is 5.75.

Given number = 5 3/4.

The given number is a fractional number, which is looking like a mixed fraction.

To write the mixed fraction into decimal form first, we have to write it into normal fraction, later we divide it to get the required decimal form.

To convert mixed fraction into normal fraction,

5 3/4 = ((4*5) + 3) / 4 = 23/4

So, the fraction is 23/4.

To convert the fraction into a decimal, we have to divide the numerator by the denominator as shown below,

23/4 = 5.75

From the above analysis, we can conclude that the decimal form of 5 3/4 is 5.75.

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To find the Taylor series about 0 for the function t3sin(5t), we need to compute its derivatives up to the fourth order at x = 0. First, let's compute the first four derivatives:

f(t) = t^3sin(5t)

f'(t) = 3t^2sin(5t) + 5t^3cos(5t)

f''(t) = 6tsin(5t) + 30t^2cos(5t) - 25t^3sin(5t)

f'''(t) = 6sin(5t) + 90tcos(5t) - 75t^2sin(5t)

f''''(t) = 450cos(5t) - 270t sin(5t)

Next, we evaluate these derivatives at x = 0:

f(0) = 0

f'(0) = 0

f''(0) = 0

f'''(0) = 6

f''''(0) = 450

Finally, we can write the Taylor series about 0 for t3sin(5t) as:

t^3sin(5t) ≈ 0 + 0t + 0t^2 + (6/3!)t^3 + (450/4!)t^4

≈ (1/3!)t^3 + (1/4)t^4

Therefore, the first four nonzero terms of the Taylor series about 0 for t3sin(5t) are (1/3!)t^3 and (1/4!)t^4. These terms approximate the function t3sin(5t) near x = 0 with increasing accuracy as x gets closer to 0.

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Answer:

Hi,so since this is a triangle with a right angle and that equals to 90 degrees

so we have found our second number.

The sum of angles in a triangle is 180 degrees

so that would be 27+90+x=180

i.e 117 +x =180

solve equation i.e 180 -117=63

therefore x=63 degrees

hope this was helpful

Answer:

90+27+63=180

so the answer is:

X= 63

The product of (five to the -1st power) and (five to the -3rd power) can be calculated using the properties of exponents. So, the product of (five to the -1st power) and (five to the -3rd power) is equal to 1/625.

When multiplying two expressions with the same base (in this case, five) and different exponents, you can simply add the exponents together. So, for this problem, you will add the exponents -1 and -3, resulting in an exponent of -4.

Therefore, the product of (five to the -1st power) and (five to the -3rd power) is equal to five to the -4th power. To express this as a positive exponent, you can rewrite it as a fraction with the exponent in the denominator: 1/(five to the 4th power). Now, calculate the value: 1/(5^4) = 1/625.

In conclusion, the product of (five to the -1st power) and (five to the -3rd power) is equal to 1/625.

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