URGENT PLEASE HELP ME I NEED TO PASS!!! I WILL GIVE SOMEONE BRAINLIEST!
What is the slope of the line passing through the points (1, 2) and (5, 4)?
A: -2
B: 1/2
C: 1
D: 2

The dimensions will minimize the cost of fence 3555C, armer needs a fenced-in 1 square kilometer rectangular region.

Let the length of the rectangular region be 'l' and the width be 'w'. The area of the rectangular region is given by:

A = lw = 1 sq. km = 1000 x 1000 sq. m

We need to minimize the cost of the fence, which consists of three sides with fencing of cost C and one side with fencing of cost 3C. The total cost of the fence is given by:

Cost = 3Cw + C(2l + w) = 2C(l + w) + Cw

To minimize the cost, we take the derivative of the cost function with respect to w and set it equal to zero:

dCost/dw = 2C - C[tex]w^{(-2)}[/tex]l = 0

Solving for l, we get:

l = 2w

Substituting this value of l in the area equation, we get:

w(2w) = 1000000

2w² = 1000000

w² = 500000

w = √(500000) m = 707.1 m

So, the width of the rectangular region is 707.1 m and the length is 2w = 2 x 707.1 m = 1414.2 m.

Therefore, the dimensions that minimize the cost of the fence are 707.1 m x 1414.2 m and the minimum cost of the fence is:

Cost = 2C(l + w) + Cw = 2C(1414.2 + 707.1) + C(707.1) = 3555C.

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The number of valid ways to construct the cube is [tex]4096 - 48 = 4048[/tex]

Each corner of the cube is formed by three wires coming together. Since the wires are soldered together at the ends, each corner must have either 3 silver wires or 3 copper wires coming together.

There are two choices for each wire: it can be silver or copper. Since there are 12 edges in a cube, there are 2 choices for each edge, giving a total of [tex]2^12 = 4096[/tex] possible arrangements of the edges.

However, not all of these arrangements are valid. We must eliminate the arrangements where at least one corner has two silver wires and one copper wire

There are 8 corners in a cube, and for each corner, there are 3 ways to choose which wire is different from the other two. Once we choose which wire is different, there are 2 choices for its color (silver or copper). Thus, there are [tex]8 x 3 x 2 = 48[/tex] invalid arrangements.

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The substance's half-life in days is 5 days.

What is exponential decay?

If a quantity declines at a pace proportionate to its current value, exponential decay may be present. The following differential equation, where N is the quantity and (lambda) is a positive rate known as the exponential decay constant, disintegration constant, rate constant, or transformation constant, can be used to represent this process symbolically.

Here, we have

Given: A 46-gram sample of a substance that's a by-product of fireworks has a k-value of 0.1394.

We have to find the substance's half-life in days.

Using the formula for the exponential decay that is N = N₀e⁻ⁿˣ,

we have N = 46/2, N₀ = 46, and n = 0.1374.

N = N₀e⁻ⁿˣ

23 = 46e⁻⁰°¹³⁹⁴ˣ

23/46 = e⁻⁰°¹³⁹⁴ˣ

1/2 = e⁻⁰°¹³⁹⁴ˣ

Taking logs on both sides, we get

㏑(1/2) = -0.1394x

x = ㏑(1/2)/(-0.1394)

x = -0.6931/(-0.1394)

x = 4.9720

Hence, the substance's half-life in days is 5 days.

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The chance/

probability

is

16/33

, or roughly 0.485 that 1 and 2 are in the

same set.

Let's say we divide the range of numbers from

1 to 15

into two sets, each containing seven and eight numbers, respectively. Finding the likelihood that the numbers 1 and 2 are included in the same

set

is our goal.

We can determine the

total number

of ways to divide the numbers into the two sets of

7

and

8

in order to begin solving this issue. Calculating this yields the result 6435 using a formula.

The number of ways in which the pairs 1 and 2 can be found in the same set must then be determined. Considering that there are

seven numbers

in the set, we must select six more from the remaining thirteen to complete the set, presuming that one is among the seven .There are

1716

ways to do this. The number of methods remains the same, 1716, even if we suppose that 2 is among the set of 7 numbers.

Hence, there are

3432

different ways to combine the numbers 1 and 2 into one set. The chance is 16/33, or roughly 0.485, when we divide this number by the total number of possible

divisions

of the numbers.

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The dimensions of the poster be so that the least amount of poster is used are A = 6L + 4W + 412.

Let the length and width of the printable area of the poster be L and W, respectively. Then, the total dimensions of the poster can be expressed as L + 2(2) and W + 2(1), since there are 2-inch margins at the top and bottom, and 1-inch margins on the left and right.

We know that the area of the printable area of the poster is 392 square inches. Therefore, we can write the equation: LW = 392

We want to minimize the total area of the poster, which is given by:

A = (L + 2(2))(W + 2(1)) = (L + 4)(W + 2)

Expanding this expression, we get:

A = LW + 2L + 4W + 8

Substituting the equation for LW, we get:

A = 392 + 2L + 4W + 8

Simplifying, we get:

A = 2L + 4W + 400

To minimize this expression, we can take the partial derivatives with respect to L and W and set them equal to zero:

[tex]∂A/∂L = 2 = 0 => L = 0[/tex]

[tex]

∂A/∂W = 4 = 0 => W = -100[/tex]

These values do not make sense in the context of the problem. Therefore, we can conclude that the dimensions of the poster that minimize the amount of poster used cannot be found using this method.

Instead, we can use the fact that the printable area of the poster has a fixed area of 392 square inches, and that the margins have fixed dimensions. We can express the area of the poster as:

A = (L + 4)(W + 2) = LW + 4L + 2W + 8

Substituting the equation for LW, we get:

A = 392 + 4L + 2W + 8

Simplifying, we get:

A = 4L + 2W + 400

To minimize this expression, we can again take the partial derivatives with respect to L and W and set them equal to zero:

[tex]∂A/∂L = 4 = 0 => L = 0[/tex]

[tex]∂A/∂W = 2 = 0 => W = -200[/tex]

These values do not make sense in the context of the problem. Therefore, we can conclude that the dimensions of the poster that minimize the amount of poster used cannot be found using this method either.

We can try a different approach. We can use the fact that the printable area of the poster has a fixed area of 392 square inches, and that the total area of the poster is given by:

A = (L + 4)(W + 2) + 2(L + 4) + 2(W + 2)

Expanding this expression, we get:

A = LW + 6L + 4W + 20

Substituting the equation for LW, we get:

A = 392 + 6L + 4W + 20

Simplifying, we get: A = 6L + 4W + 412

To minimize this expression, we can take the partial derivatives with respect to L and W and set them equal to zero:

[tex]∂A/∂L = 6 = 0 => L = -2/3[/tex]

[tex]∂A/∂W = 4 = 0 => W = -3/2[/tex]

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As a result, Alex should use a circle graph to display his data set because it can effectively convey to his manager the percentage of each flower kind that was planted.

To visualise information and data, use a circle graph or pie chart. Typically, a circle graph is used to quickly and proportionately display the findings of an investigation.

A pie chart, often known as a circle chart, is a visual representation of the various values of a given variable or a means to summarise a set of nominal data. This kind of diagram consists of a circle with numerous segments.

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A reasonable prediction for the number of times a sixth or seventh grader will be chosen is 24 out of the 40 games.

What is reasonable prediction?

A reasonable prediction is a prediction made with a reasonable degree of accuracy or likelihood, based on available information and knowledge. It is based on facts, past events, and logical assumptions, and is not based on conjecture or guesswork. Reasonable predictions can be made about future events, trends, and outcomes, and can be used to inform decisions, plans, and strategies.

The total number of sixth and seventh graders on the team is:

10 sixth graders + 14 seventh graders = 24 students

The total number of students on the team is:

10 sixth graders + 14 seventh graders + 16 eighth graders = 40 students

To find the expected number of times a sixth or seventh grader will be chosen in the coin toss, we can use the proportion of sixth and seventh graders to the total number of students:

(expected number of times) = (proportion of sixth and seventh graders) * (total number of coin tosses)

(expected number of times) = (24/40) * 40

(expected number of times) = 24

Therefore, a reasonable prediction for the number of times a sixth or seventh grader will be chosen is  24.

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Answer:

-23. In my explanation I will include in my picture how this will look in your final answer

Step-by-step explanation:

So to solve this, I first set x + 3 = 0. This means that x = -3, which we will use soon. Now, here's how you would work out this problem. It would be confusing if I explained over text, so I included a picture of my work.

You would first set up your problem like it is in the picture. Then, bring 2 down. Next, multiply 2 by -3 (for future problems, you would multiply the number you brought down by whatever number is on the side). -3 × 2 = -6, so you would put that under 3 (as shown in the picture). Now, add 3 and -6 (which = -3). Repeat this step each time.

I hope this made sense! Please let me know if you have any questions.

The accumulated amount in the account at the end of the second period will be 8,829.71.

We can use the formula for compound interest to solve this problem. The formula is,

A = P(1 + r/n)^(nt)

where A is the accumulated amount, P is the principal (initial amount invested), r is the interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time (in years) for which the money is invested.

Let's use this formula to find the initial principal, P

7,365 = P(1 + 0.08/12)^(12*number of years)

We can solve for P by dividing both sides by the right-hand side and simplifying,

P = 7,365 / (1 + 0.08/12)^(12*number of years)

Now we know that the initial principal was P, and it earned R2 000.00 in interest during the first period. Therefore, the accumulated amount at the end of the first period was,

A1 = P + R2 000.00

A1 = P + P(0.08/12)

A1 = P(1 + 0.08/12)

Now, we want to find the accumulated amount at the end of the second period, which is one year longer than the first period. We can use the same formula as before, but with a time of (number of years + 1),

A2 = P(1 + 0.08/12)^(12*(number of years + 1))

We know that A1 = P(1 + 0.08/12), so we can substitute this into the formula for A2,

A2 = A1(1 + 0.08/12)^(12)

A2 = (P(1 + 0.08/12))(1 + 0.08/12)^(12)

A2 = P(1 + 0.08/12)^13

Now we can substitute the expression we found for P earlier,

A2 = (7,365 / (1 + 0.08/12)^(12*number of years))(1 + 0.08/12)^13

A2 = 7,365(1 + 0.08/12)^(12*number of years + 13)

A2 = 7,365(1.007)^((12*number of years) + 13)

A2 = 8,829.71

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Applying the right triangle altitude theorem and the leg rule, we have:

5. x = 6; y ≈ 6.7; z ≈ 13.4       6. x = 32; y ≈ 35.8; z ≈ 17.9

The right triangle altitude theorem states that the altitude drawn on the hypotenuse of a right triangle is equal to the geometric mean of the two line segments into which the altitude divides the hypotenuse.

5. To find x, apply the right triangle altitude theorem, which is:

x = √(3*12)

x = √36

x = 6

Using the leg rule, we can find y and z. It is expressed as:

hypotenuse/leg = leg/part

Therefore, substitute and find y:

(3 + 12) / y = y / 3

Cross multiply:

y² = 15 * 3

y = √45

y ≈ 6.7

Find z using the leg rule:

15/z = z/12

z² = 180

z = √180

z ≈ 13.4

6. Use the same theorem and leg rule as done in question 5:

Find x:

16 = √(8 * x)

16² = 8x

256 = 8x

x = 256/8

x = 32

Find y using the leg rule:

(8 + 32) / y = y/32

y² = 40 * 32

y = √1,280

y ≈ 35.8

Find z:

40/z = z/8

z² = 40 * 8

z = √320

z ≈ 17.9

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Assuming a two-tailed test with 9 degrees of freedom (10 stores minus 1), the p-value for a t-value of 2.3 is approximately 0.040.

In order to calculate the p-value, we need to know the specific test being used and the significance level of the test. Let's assume that the test is a two-tailed t-test with a significance level of 0.05.

Since the test statistic is 2.3, we need to find the probability of getting a t-value of 2.3 or greater (in absolute value) under the null hypothesis. We can use a t-distribution table or a statistical software to find the corresponding p-value.

Assuming a two-tailed test with 9 degrees of freedom (10 stores minus 1), the p-value for a t-value of 2.3 is approximately 0.040. Therefore, if the significance level of the test is 0.05, we would reject the null hypothesis and conclude that there is a significant difference between the ratings given by the three reviewers.

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A significant point biserial correlation does not directly indicate whether the t-test for mean differences is significant or not.

To determine the significance of the mean differences, you would need to perform a separate t-test analysis.

Based on the information provided, you calculated a point biserial correlation and found it to be significant.

The point biserial correlation is a measure of association between a continuous variable and a dichotomous variable.  

The t-test for mean differences, on the other hand, compares the means of two groups to determine if they are significantly different from each other.

Although both the point biserial correlation and the t-test for mean differences involve a continuous variable and a dichotomous variable, they serve different purposes.  

The point biserial correlation measures the strength and direction of association, while the t-test assesses the significance of the difference between the means.

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Based on this information, the t-test for mean differences was also significant.

Based on the information provided, you've calculated a point biserial correlation and found that the correlation is significant. To determine if the t-test for mean differences was significant, follow these steps:

1. First, recall that the point biserial correlation is used to measure the relationship between a continuous variable and a dichotomous (binary) variable. In this case, the significant correlation indicates that there is a meaningful association between the two variables.

2. Now, remember that a t-test for mean differences is used to compare the means of two groups, often based on a dichotomous variable. This means that the t-test is examining whether the differences between the means of the two groups are significant.

3. The point biserial correlation and the t-test for mean differences are related. Since you've found a significant point biserial correlation, it implies that there is a significant difference between the means of the two groups.

4. Therefore, based on this information, the t-test for mean differences was also significant.

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The approximated area Jamie needs to cover is 462.05 ft

From the question, we have the following parameters that can be used in our computation:

The area Jamie needs to cover in the figure is calculated as

Area = Pentagon + Trapezoid + Parallelogram

Using the given dimensions, we have

Area = 1/4 * √[5 * (5 + 2√5)] * 10² + 1/2 * (18 + 20) * 10 + 10 * 10

Evaluate

Area = 462.05

Hence, the area Jamie needs to cover is 462.05 ft

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the sine function that meets the given conditions is:
[tex]y(t) = 3 \times sin ((2\pi / 1200) \times t) + 2[/tex]

Function with the given characteristics.

The terms and their definitions we need to consider:
Amplitude:

The maximum displacement from the midline (in this case, 3)
Midline:

The horizontal line that passes through the center of the wave (y = 2)
Period:

The length of one complete cycle of the wave (1200)
Now, let's write the sine function:
[tex]y(t) = A \times sin (B \times t) + C[/tex]
Where:
y(t) is the sine function with respect to time (t)
A is the amplitude (3)
B is the frequency (to be determined)
C is the midline (2)
First, we need to find the frequency (B).

The period and frequency are related by the following formula:
[tex]Period = 2\pi / B[/tex]
In this case, the period is 1200:
[tex]1200 = 2\pi / B[/tex]
Now, solve for B:
[tex]B = 2\pi / 1200[/tex]
Now, we can plug in the amplitude (A), frequency (B), and midline (C) into our sine function:
[tex]y(t) = 3 \times sin((2\pi / 1200) \times t) + 2[/tex]

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It takes the person 40 minutes to travel 10 miles at a rate of 15 miles per hour

We can use the formula:

time = distance / speed

where "distance" is the distance traveled and "speed" is the speed at which the person is traveling.

In this case, the person rode their bike 10 miles south at a speed of 15 miles per hour.

Plugging these values into the formula, we get:

time = 10 miles / 15 miles per hour

Simplifying, we get:

time = 40 minutes

Therefore, it takes them 40 minutes

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(1) The volume of the prism is therefore 380 cubic units and the  area is 382 square units.(2)The volume of the prism is approximately 1534.99 cubic units and the  area is approximately 812.66 square units.

It is called the volume of the solid figure. Thus, it can be said that the surface area is the measure of the solid figure itself, while volume is the measure of the space region enclosed by the solid figure. Just as area is measured in square units, volume is measured in cubic units.

1) To find the volume and surface area of ​​a prism, we need to know the formula for each. The  formula for the volume of a prism is:

V = Bh

where B is the base area and h is the height. The  formula for the area of ​​a prism is:

A = 2B + Ph

where P is the circumference of the base.  

In this case, we get a prism whose sides are 19/3, 5 and 12. Since the base is a rectangle, we can calculate its area using the formula:

B = lw

where l is the length and w is the width. In this case, the length is 12 and the width is 5, so:

B = 12 * 5

B = 60

To find out the circumference of the base, we add  the lengths of all the sides:

P = 2l + 2w

P = 2 (12) 2 (5)

P = 24 10

P = 34

Now we can calculate the volume and  area using the formulas:

V = Bh

V = 60 * (19/3)

V = 380 cubic units

A = 2B + Ph

A = 2 (60) (34) (19/3)

A = 120 (646/3)

A = 382 square units

The volume of the prism is therefore 380 cubic units and the  area is 382 square units.

2) To find the volume and surface area of ​​a prism, we need to know the formula for each. The  formula for the volume of a prism is:

V = Bh

where B is the base area and h is the height. The  formula for the area of ​​a prism is:

A = 2B + Ph

where P is the circumference of the base.  

In this case, we have a prism with sides of 15.5, 17, 14, and 20. Since the base is a trapezoid, we can calculate its area using the formula:

B = ((a b) / 2) * h

where a and b are the lengths of the parallel sides and h is the height. In this case, a and b are 14 and 20,  and the height can be found using the Pythagorean theorem:

h = square(17² - ((20-14.5)/2)²)

h = square(17² - 6.5²)

h = square (109.75)

h ≈ 10.47

So the area of ​​the base is:

B = ((14 20) / 2) * 10.47

B ≈ 146.58

To find out the circumference of the base, we add  the lengths of all the sides:

P = 15.5 17 14 20

P = 66.5

Now we can calculate the volume and  area using the formulas:

V = Bh

V = 146.58 * h

V ≈ 1534.99 cubic units

A = 2B + Ph

A = 2(146.58)(66.5)(h)

A ≈ 812.66 square units

Therefore, the volume of the prism is approximately 1534.99 cubic units and the  area is approximately 812.66 square units.

3) To find the volume and surface area of ​​a prism, we need to know the formula for each. The  formula for the volume of a prism is:

V = Bh

where B is the base area and h is the height. The  formula for the area of ​​a prism is:

A = 2B + Ph

where P is the circumference of the base.  

In this case, we have a prism whose sides are 7,8, 9, 11 and 9. Since the base is a trapezoid, we can calculate its area using the formula:

B = ((a b) / 2) * h

where a and b are the lengths of the parallel sides and h is the height. In this case, a and b are 9 and 11,  and the height can be found using the Pythagorean theorem:

h = square(7.8² - ((11-9)/2)²)

h = squared (60.84 - 1)

h ≈ 7.79

So the area of ​​the base is:

B = ((9 11) / 2) * 7.79

B ≈ 86.35

To find out the circumference of the base, we add  the lengths of all the sides:

P = 7.8 9 11 9

P = 36.8

Now we can calculate the volume and  area using the formulas:

V = Bh

V = 86.35 * h

V ≈ 674.05 cubic units

A = 2B + Ph

A = 2(86.35)(36.8)(h)

A ≈ 501.51 square units

Therefore, the volume of the prism is approximately 674.05 cubic units and the  area is approximately 501.51 square units.

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The train will have traveled option (C) 450 km from its starting point after 4 more hours at the same average speed.

The average speed of the train is given by the distance traveled divided by the time taken to travel that distance

average speed = distance ÷ time

Using this formula, we can find the average speed of the train:

average speed = 250 km ÷ 5 h = 50 km/h

Now that we know the average speed of the train, we can use it to calculate how far it will have traveled after another 4 hours:

distance = average speed × time

distance = 50 km/h × 4 h = 200 km

Therefore, the train will have traveled 250 km + 200 km = 450 km from its starting point after 4 more hours at the same average speed.

So, the answer is (C) 450 km.

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The slope of the line on this graph is equal to 1/3.

In Mathematics and Geometry, the slope of any straight line can be determined by using the following mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = rise/run

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

By substituting the given data points into the slope formula, we have the following;

Slope (m) = (-2 - (-3))/(-1 - (-4))

Slope (m) = (-2 + 3)/(-1 + 4)

Slope (m) = 1/3

Based on the graph, the slope is the change in y-axis with respect to the x-axis and it is equal to 1/3.

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The slope of the coordinate  line is 1/3.

To find the slope of the line that passes through the points (-4, -3) and (-1, -2), we use the slope formula:

slope = (change in y) / (change in x)

The change in y is -2 - (-3) = 1, and the change in x is -1 - (-4) = 3. Therefore, the slope is:

slope = 1 / 3

So the slope of the line is 1/3.

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Therefore , the solution of the given problem of unitary method comes out to be  Isaac and Isaiah are 182 ounces in total.

Use the tried-and-true fundamental method, the actual variables, and any relevant information gleaned from general and specific questions to complete expression the assignment. Customers may be given another chance to taste the products in response. If these adjustments don't happen, we'll lose out on significant advancements in our understanding of programmes.

Here,

We must first change the weights of Isaac and Isaiah from pounds and ounces to ounces before adding them to determine their combined weight.

Weight of Isaac: six pounds 2 ounces = 6 * 16 + 2

= 96 + 2

= 98 ounces

Isaiah is 5 pounds in weight.

= 5 * 16 + 4

= 80 + 4

= 84 ounces

Together, Isaac and Isaiah weighed

98 ounces + 84 ounces = 182 ounces

As a result, Isaac and Isaiah are 182 ounces in total.

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The expression that represents the total amount that Julian paid at the register in terms of x is 0.84x.

What is Percentage?

Percentage is a way of expressing a proportion or fraction as a quantity out of 100. The word "percent" means "per hundred," so percentages are often denoted by the symbol %, which represents one part in a hundred.

The first step is to find the discounted price after the 20% discount. This can be found by multiplying the original price by (1 - 0.2), which represents a 20% reduction.

Discounted price = x - 0.2x = 0.8x

Next, a 4% tax is added to the discounted price. This can be found by multiplying the discounted price by (1 + 0.04), which represents a 4% increase.

Total amount paid = (0.8x) * (1 + 0.04) = 0.84x

Therefore, the expression that represents the total amount that Julian paid at the register in terms of x is 0.84x.

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The problem steps should be put in the correct order as follows;

Problem ≡ [tex]\frac{2}{x+1} \cdot \frac{3}{x-2}[/tex]

Multiply numerators and multiply denominators ≡ [tex]\frac{2 \cdot 3}{(x+1)(x-2)}[/tex]

Simplify numerator and Simplify denominator ≡ [tex]\frac{6}{(x^2 - x - 2)}[/tex]

In Mathematics and Geometry, a fraction simply refers to a numerical quantity (numeral) which is not expressed as a whole number. This ultimately implies that, a fraction is simply a part of a whole number.

In Mathematics and Geometry, a rational expression simply refers to a type of expression which is expressed as a fraction. In this exercise, we would factorize the numerator and denominator for this rational expression as follows;

Multiply numerators = 2 × 3 = 6

Multiply denominators = (x + 1) × (x - 2) = x² - 2x + x - 2 = x² - x - 2

In conclusion, the required rational expression is given by  [tex]\frac{6}{(x^2 - x - 2)}[/tex]

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Answer:

below

Step-by-step explanation:

58.

(72 + 75 + 68 + 70 + 73 + 72 + 76 + 72 + 69 + 72 ) divided by 10 = 71.9

59.

order- 68, 69, 70, 72 , 72, 72, 72, 73, 75, 76

median = (72 + 72) divided by 2 = 72

61.

I dont know what MAD means

this is all I could do rn

There are different ways to approach this problem, but one common method is to use the fact that in a triangle, the sum of the lengths of any two sides is greater than the length of the third side.

Applying this to triangle STU, we get:

ST + TU > SU (1)

ST + US > TU (2)

TU + US > ST (3)

Substituting the given values, we get:

(-3y+5) + (2y-6) > UW

-y-1 > y-6

-2y > -5

y < 2.5

So we know that y must be less than 2.5 for the triangle to be possible. Now we can check the other sides of the triangle:

ST + TU > SU (1)

(-3y+5) + (2y-6) > ST

-y-1 > ST

ST + US > TU (2)

(-3y+5) + UW > TU

(-3y+5) + (2y-6) > TU

-y-1 > TU

TU + US > ST (3)

UW + (-3y+5) > ST

(2y-6) + (-3y+5) > ST

-y-1 > ST

Since we want to solve for y, we can simplify each inequality by isolating the variable on one side:

-y-1 > ST (4)

-y-1 > TU (5)

-y-1 > ST (6)

Now we can combine the three inequalities:

(-y-1) + (-y-1) + (-y-1) > ST + TU + US

-3y - 3 > ST + TU + US

Substituting the given values, we get:

-3y - 3 > (-3y+5) + (2y-6) + UW

-3y - 3 > -y - 1

Simplifying this inequality, we get:

-2y > 2

y < -1

This contradicts our earlier result that y must be less than 2.5, so there is no solution for y that makes the triangle possible. This means that there must be an error in the given values of SW and UW, or the problem is not well-defined.

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Answer:

2.2

Step-by-step explanation:

The probability of detecting a shift in the fraction nonconforming to 0.04 on the first day after the shift is 0.096

The expected number of nonconforming items out of the 50 items:

0.02 x 50 = 1.

The standard deviation of the number of nonconforming items:

√(50 x 0.02 x (1 - 0.02)) = 0.948.

The expected number of nonconforming items out of the 50 items after the shift:

0.04 x 50 = 2.

The standard deviation of the number of nonconforming items after the shift:

√(50 x 0.04 x (1 - 0.04)) = 1.1.

The Z-score:

(2 - 1) / (1.1 - 0.948) = 0.609.

The probability of detecting a shift in the fraction nonconforming to 0.04 on the first day after the shift:

The probability of detecting a shift in the fraction nonconforming to 0.04 on the first day after the shift is determined by calculating the Z-score. Z-scores measure.

The probability of detecting a shift is calculated using the Z-score and the standard normal distribution.

P(Z > 0.609) = 0.096.

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ok so for the first one I'm im taking a guess I think it's the first one.

the second one plot the point on the line between 14 and 15

I think those should be correct I think

Handling Exponents:

Generally when handling exponents it is necessary to follow the different Law of Exponents

1. Product rule

2.  Quotient rule

3. Power to Power rule

4. Negative exponent rule

5. Zero power rule

In this context we are finding what is equivalent to 6^8 x 6^(-4)

[tex]6^(8-4)=6^4[/tex] - this is equivalent

[tex](6^8)^-4=6^-^3^2[/tex] - not equivalent

[tex]6^2[/tex] -  not equivalent

[tex]6^-^2=\frac{1}{6^2}[/tex] - not equivalent

[tex]6^-^3^2=\frac{1}{6^3^2}[/tex] - not equivalent

[tex]\frac{6^8}{6^4}= 6^(^8^-^4^)=6^4[/tex] -  this is equivalent

The first and last options are equivalent to 6^8 x 6^(-4)

Step-by-step explanation:

vf = vo + at      vo = 0 in this case  ( you dropped it from 'at rest')

4 f/s = 32 t

t = 1/8 s

df = do + vot + 1/2 at^2                  df = final position = 0 ft (on the ground)

0 = do  + 0   + 1/2 (-32)(1/8)^2

   solve for do = 1/4 foot

Answer: C 70%

Step-by-step explanation:

First you need to add up how many students are participating in the study. 4+6+12+8+4=34. There are 24 people who own more than 5 video games. This means that it is 24/34. This equals about 70%

Answer:

The given function is k(t) = cos(2πt/3).

The general form of a cosine function is A*cos(Bx - C) + D, where:

Comparing this form to the given function, we can see that:

Therefore, the amplitude of k(t) is 1, the period of k(t) is 3, the phase shift of k(t) is 0, and the vertical shift of k(t) is 0.

The probability that Abby, Barry, and Sylvia win the first, second, and third prizes, respectively, is 1 in 8,000,000 or 0.0000125%

Assuming that each prize is drawn independently of the others and that any person can win any of the prizes, we can find the probability that Abby, Barry, and Sylvia win the first, second, and third prizes, respectively, by using the multiplication principle of probability.

The probability of Abby winning the first prize is 1/200, since there are 200 people in the contest and only one of them can win the first prize. Similarly, the probability of Barry winning the second prize is also 1/200, and the probability of Sylvia winning the third prize is also 1/200.

Since winning more than one prize is allowed, the probability of all three of these events occurring simultaneously is simply the product of their individual probabilities:

P(Abby wins 1st prize AND Barry wins 2nd prize AND Sylvia wins 3rd prize) = (1/200) * (1/200) * (1/200) = 1/8,000,000

Therefore, the probability that Abby, Barry, and Sylvia win the first, second, and third prizes, respectively, is 1 in 8,000,000 or 0.0000125%

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