Answer:
29.16 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 18 × 1.62
We have the final answer as
29.16 NHope this helps you
A 13561 N car traveling at 51.1 km/h rounds
a curve of radius 2.95 × 102 m.
The acceleration of gravity is 9.81 m/s
a) Find the centripetal acceleration of the
car. Answer in units of m/s
Find the force that maintains circular motion.
Answer in units of N.
c) Find the minimum coefficient of static friction between the tires and the road that will
allow the car to round the curve safely.
Answer:
a) The centripetal acceleration of the car is 0.68 m/s²
b) The force that maintains circular motion is 940.03 N.
c) The minimum coefficient of static friction between the tires and the road is 0.069.
Explanation:
a) The centripetal acceleration of the car can be found using the following equation:
[tex] a_{c} = \frac{v^{2}}{r} [/tex]
Where:
v: is the velocity of the car = 51.1 km/h
r: is the radius = 2.95x10² m
[tex] a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2} [/tex]
Hence, the centripetal acceleration of the car is 0.68 m/s².
b) The force that maintains circular motion is the centripetal force:
[tex] F_{c} = ma_{c} [/tex]
Where:
m: is the mass of the car
The mass is given by:
[tex] P = m*g [/tex]
Where P is the weight of the car = 13561 N
[tex] m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg [/tex]
Now, the centripetal force is:
[tex] F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N [/tex]
Then, the force that maintains circular motion is 940.03 N.
c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:
[tex] F_{c} = F_{\mu} [/tex]
[tex] F_{c} = \mu N = \mu P [/tex]
[tex] \mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069 [/tex]
Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.
I hope it helps you!
how much power is used for machine does 28J of work and 7 seconds
Answer:
3N
Explanation:
Why it is some times possible to loosen caps on screw
top bottles by dipping the cap briefly in hot water?
Answer:
Solids expand when they are heated.
Explanation:
It is possible to loosen caps on the screw top bottles by dipping the cap briefly in hot water due to the fact that whenever a solid is heated, it expands. This means that the size of the solid Screw cap (in this our case) increases as the temperature does.
This increase in size causes it to slide off easily from the mouth of the bottle when a little twisting effort is applied.
If a bag of pretzels says it contains 10 servings, and each serving is 150 calories, how many calories would you consume if you ate the entire bag?
300, adding extra healthy calories
1,000, adding extra unnecessary calories
1,500, adding extra unnecessary calories
2,000, adding extra healthy calories
Answer:
5400
Explanation:
i calculated it
Big brain
The quantity of matter in an object. More specifically, it is the measure of the inertia that an object exhibits in response to any effort made to start it, stop it, or change in any way its state of motion
Answer:
Mass
Explanation:
The mass of an object expresses the amount of matter it comprises. Which implies that objects with higher mass contains higher matter compared to objects with lesser masses. Thereby it determines the measure of inertia experienced by an object when a force is applied to change its direction of motion, or to set it in motion when at rest, or bring it to rest when in motion.
The mass of an object the same no matter its location, and it is measured in kilograms.
What is the supply voltage?
Answer:
[sə′plī ‚vōl·tij] (electricity) The voltage obtained from a power source for operation of a circuit or device.
Explanation:
hope this helps :)
How much kinetic energy does an 80 kg man have while running at 3 m/s?
Hello!
[tex]\large\boxed{KE = 360 J}[/tex]
Use the equation KE = 1/2mv² to solve for the kinetic energy of the man.
We are given the mass and velocity, so plug these values into the equation:
KE = 1/2(80)(3²)
KE = 1/2(720)
KE = 360 J
Please answer the circled questions, I will give you brainliest
Answer:
yo so if nobody helps ill gladly take the brainliest
Explanation:
Cars, trucks, and SUVS use seatbelts as safety devices. Roller coasters use
bars. Use Newton's 1* Law of Motion to explain how the seatbelt or restraint
bar help keep you safe ina collision. Be sure to identify forces and velocity.
sorry
Explanation:
Sorry
6. You are holding a rock with a mass of 0.30 kg. You let the rock drop from your hand. It hits the ground 0.75
seconds later. How fast was the rock moving right before it hit the ground? For credit, show work in detail.
Answer:
v = 14.7m/s
Explanation:
When the rock was at the top of cliff it had only Potential Energy and no Kinetic Energy but soon as the rock hit the ground all the Potential Energy converted into Kinetic Energy so by the Law of Conservation of Energy
[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]
because all of that potential energy got converted into kinetic energy so we use the following formula as we need to calculate the velocity (v)
[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]
here we know [tex]g = 9.8m/s^2[/tex] because the rock was under free fall motion so it had acceleration of 9.8 but we do not the height which is h but we do know the formula:
[tex]Velocity=\frac{Displacement}{Time}[/tex]
the height h is the displacement so we replace height with the following:
[tex]Velocity=\frac{Displacement}{Time}\\\\Displacement=Velocity*Time\\h=vt[/tex]
now, insert h = vt in the above equation
[tex]v^2=2gh\\\\v^2=2g(vt)\\v^2=2vgt\\\\\frac{v^2}{v} =2gt\\\\v=2gt\\v=2(9.8)(0.75)\\v=14.7m/s[/tex]
What is the velocity of an object moving 10 m in 5 seconds to the right?
Explanation:
The velocity of an object can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex] v = \frac{10}{5} \\ [/tex]
We have the final answer as
2 m/sHope this helps you
A ball is thrown straight off a 150 meter high roof at 20 m/s.
How long does it take for the ball to hit the ground?
What was the ball's final downward velocity?
How far did the ball travel horizontally?
What was the ball's displacement?
Answer:
I'll try and find the answer for you:)
Explanation:
I can't promise you I will though
any three different between of rarefaction and compression
Answer:
credits to the real owner of the answer I just found it here
HELPPPPPPP!!!!!!!!!!!!!!!!
What is the chemical formula for sulfur trioxide? O SO3 O SIO3 8 O SO O SIO
Sulfur trioxide/Formula
SO3
this is what i looked up and got
An airplane is traveling at an altitude of 15,490 meters. A box of supplies is dropped from its cargo hold. What is the cargo's velocity when it hits the ground? (Show your work and do not forget units)
Answer :
556.59 m/s.
Explanation:
Given that,
An airplane is traveling at an altitude of 15,490 meters.
A box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.
The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :
[tex]v^2-u^2=2as[/tex]
Put u = 0 and a = g
[tex]v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s[/tex]
So, when it hits the ground its velocity is 556.59 m/s.
a 3.2 kg durian fruit is pushed across the table.If the acceleration of the durian is 3.1 m/s/s to the right,what is the net force exerted on the fruit?(Fnet=ma)
Answer:
9.92 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 3.2 × 3.1
We have the final answer as
9.92 NHope this helps you
Answer:
9.92
Hope I helped
How is it technically correct to say that a car making a u-turn can have a constant speed but cannot have a constant velocity?
During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.
Define Work And its types
Positive Work.
Negative Work.
Case of zero work done.
Displacement at an angle to the force.
Energy.
Kinetic Energy.
work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement.
Two kids are playing tag. The first kid is running at an unknown speed chasing the other. The first kid has a mass of 25 kg and a KE of 450 J.
How fast is the first kid running?
I really need help
Answer:
1mph
Explanation:
unicellular
organism are
Explanation:
Its organism are one cell I think
In uniform circular motion, the factor that remains constant is.............
Answer:
When a body is in uniform circular motion, its speed remains constant but its velocity, angular acceleration, angular velocity changes due to change in its direction.
12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it
reaches a speed of 900 m/s after 30 s. After this period of uniform acceleration, the rocket
engine cuts out. During the next 90 s, the upward speed of the rocket decreases uniformly to
zero.
speed
m/s
times
plot a speed-time graph for the rocket for the first 120 s of it's flight
Answer:
We kindly invite you to read carefully the explanation and check the image attached below.
Explanation:
According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:
[tex]v_{f} = v_{o}+a\cdot (t-t_{o})[/tex] (1)
Where:
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
[tex]v_{f}[/tex] - Final velocity, measured in meters per second.
[tex]a[/tex] - Acceleration, measured in meters per square second.
[tex]t_{o}[/tex] - Initial time, measured in seconds.
[tex]t[/tex] - Final time, measured in seconds.
Now we obtain the kinematic equations for thrust and free fall stages:
Thrust ([tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 30\,\frac{m}{s^{2}}[/tex], [tex]t_{o} = 0\,s[/tex], [tex]0\,s\le t< 30\,s[/tex])
[tex]v = 30\cdot t[/tex] (2)
Free fall ([tex]v_{o} = 900\,\frac{m}{s}[/tex], [tex]a = -9.807\,\frac{m}{s}[/tex], [tex]t_{o} = 30\,s[/tex], [tex]30\,s \le t \le 120\,s[/tex])
[tex]v = 900-9.81\cdot (t-30)[/tex] (3)
Now we created the graph speed-time, which can be seen below.
A force of 10N is making an angle of 300 with the horizontal. Its horizontal components will be
Answer: 5N
Explanation:
Horizontal component is the force that is applied as a result of the diagonal application of force.
here in this case,
given diagonal force =10N.
angle= 30°
horizontal component is found using trigonometry..
so,
A vector of magnitude 10 N is provided.
It is at an angle of 30° to the + x axis.
To find:
The components along the x and y axis.
Calculation:
Along x axis:
F(x) = F cos(θ)
=> F(x) = 10 × cos(30)
=> F(x) = 10 (√3/2) = 5√3N
Along y axis:
F(y) = F sin(θ)
=> F(y) = 10 sin(30°)
=> F(y) = 10 × ½
=> F(y) = 5 N.
Additional information:
1. A vector is a quantity that can be defined with both magnitude and direction.
2. Since force is a vector, we are able to break it down into components along chosen axis.
Imagine a 0.2 kg ball moving at 5 m/s colliding with a 0.3 kg ball moving at 2 m/s in the same direction. After the collision the 0.2 kg green ball stops moving and the 0.3 kg purple ball continues moving in the same direction.
Answer:
[tex]m1v1 + m2v2 = m1v3 + m2v4[/tex]
[tex](0.2 x 5) + (0.3 x 2) = (0.2 x 0) + (0.3 x v4)[/tex]
[tex]1.0 + 0.6 = 0 + 0.3v4, 0.3v4 = 1.6[/tex]
[tex]v4 = 1.6/0.3 = 5.3 m/s (2 sf)[/tex]
Which does not decrease your chances of being injured
A Warmup
B Overload
C Exercise
D Cooldown
Benny wonders why when he presses his finger against a map nothing happens to the map. However if he presses a thumbtack into the map using the same force the tack will probably poke a hole in the map.
Answer: The pressure exerted on a surface by an object increases as the surface area of contact decreases.
Explanation:
Pressure measures the amount of force exerted per a given area of an object. From this definition, the surface area of the object and force applied, affects the pressure applied.
As Benny presses his finger against a map, nothing happens to the map because the force applied is affected by the increased surface area of his finger. However as he presses a thumbtack into the map using the same force the tack will probably poke a hole in the map because the small( decreased) surface area of the sharp point of the thumbtack produces a much larger pressure on the map than the area of Benny finger. I hope this helps, thanks!
Chris threw a basketball a distance of 27.5 m to score and win his
high school basketball game. If the shot was made at a 50.0° angle
above the horizontal, what was the initial speed of the ball?
Answer:
v₀ = 16.55 m/s
Explanation:
This motion of the ball can be modeled as a projectile motion with following data:
R = Range of Projectile = 27.5 m
θ = Launch Angle = 50°
g = acceleration due to gravity = 9.81 m/s²
v₀ = Initial Speed of Ball = ?
Therefore, using formula for range of projectile, we have:
[tex]R = \frac{v_{0}^2\ Sin2\theta}{g}\\\\v_{0}^2 = \frac{Rg}{Sin2\theta}\\\\v_{0}^2 = \frac{(27.5\ m)(9.81\ m/s^2)}{Sin100^o}\\\\v_{0} = \sqrt{273.93\ m^2/s^2}[/tex]
v₀ = 16.55 m/s
If a 0.8kg ball is thrown with a velocity of 5 m/s,what is its KE?(KE=1/2 x m x v2)
Cuál es la diferencia entre fricción beneficiosa y perjudicial? Pon 5 ejemplos de cada uno.
Answer:
Difference is given below.
Explanation:
The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.