Answer:
SUPONIENDO QUE NO HAY FRICCIÓN
Explanation:
F = 66 kg([tex]2 m/s^{2}[/tex]) = 132 N
A high surface tension results from _____.
Answer:
Capillary Action.
Explanation:
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.
AS WE CLIMB UP, THE PRESSURE INSIDE OUR BODY WILL BE.................. *
1 )low
2)high
3)very high
4)same
A lamp hangs from the ceiling at a height of 2.6 m. The lamp has a mass of 3.8 kg. The screws holding the lamp break, and it falls to the ground. a. How much gravitational potential energy does the lamp have before it falls? b. How much kinetic energy does the lamp have when it reaches the ground? c. How fast is the lamp moving when it hits the ground?
Whoever answers will get the Brainliest.
Answer:
Explanation:
Given height of lamp from the ceiling = 2.6m
mass of the lamp = 3.8kg
acceleration due to gravity = 9.81m/s²
As the body falls to the ground, it falls under the influence of gravity.
Gravitational potential energy = mass*acc due to gravity * height
Gravitational potential energy = 3.8*2.6*9.81
Gravitational potential energy = 96.923 Joules
b) Kinetic energy = 1/2 mv²
m = mass of the body (in kg)
v = velocity of the body (in m/s²)
To get the velocity v, we will use the equation of motion [tex]v^{2} = u^{2}+2gh[/tex]
[tex]v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s[/tex]
Since mass = 3.8kg
[tex]K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules[/tex]
c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s
ASAP! HELP!
A 66.4 kg person sits on the right end of a seesaw, 2.35m from the fulcrum. On the other end, how far from the fulcrum should a 84.2kg person sit to balance the seesaw?
1: 1.92 m
2: 1.85m
3: 2.08m
4: 1.61 m
Answer:
2. 1.85
Explanation:
the equations weight * distance / other persons weight = distance from fulcrum. so 66.4*2.35/84.2=1.8532 round down to 1.85
The length of a wooden rod is 25.5 cm. What is this length in:
(a) millimetres?
(b) metres?
Answer:
[tex](a)255mm \\ (b)0.255m[/tex]
Explanation:
[tex](a)1cm = 10mm \\ 25.5cm = x[/tex]
Cross multiply
[tex]1x = 25.5 \times 10 \\ x = 255mm[/tex]
[tex](b)100cm = 1m \\ 25.5cm = x[/tex]
cross multiply
[tex]100x = 25.5 \\ \frac{100x}{100} = \frac{25.5}{100} \\ x = 0.255m[/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
Answer:
A. 255
B. 0.255
Explanation:
10mm = 1cm
100cm = 1m
<a href="https://en.wikiafripedia.org/wiki/Centimetre">Learn more</a>
https://en.wikiafripedia.org/wiki/Centimetre
Amina has a mass of 48.4kg, what is her weight.please show calculation
G=m×g
since g=10N,
G=48.4×10
G=484
I hope it's true .d
good luck
If a truck if it is accelerating at a rate of 5m/s2 and hits a parked car with a force of 16,000 newtons what is its mass?
Answer:
3200kg
Explanation:
F=ma
16000=5m
m=3200kg
Hope this helps!
The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
What is mass?A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.
It is given that:
If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons
As we know,
Newton's second law:
F = ma
Here F is the force acting on an object.
m is the mass of the object
a is the acceleration of the object.
a = 5 m/s²
F = 16,000 N
m = 3200kg
16000 = 5m
3200 kg
Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
Learn more about the mass here:
https://brainly.com/question/15959704
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