Weather balloons are filled with hydrogen and released at various sites to measure and transmit data about conditions such as air pressure and temperature. A weather balloon is filled with hydrogen at the rate of 0.5 ft^3/s. Initially, the balloon has 4 ft^3 of hydrogen. Initially, the balloon has 2 ft^3 of hydrogen.

Required:
a. Find a linear function V that models the volume of hydrogen in the balloon at any time t.
b. If the balloon has a capacity of 15 ft^3, how long does it take to completely fill the balloon?

======================================================

Explanation:

3/7 = 0.42857 approximately

Pick a number between that value and 5, not including either endpoint. Let's say we pick x = 2

Plug x = 2 into the f(x) function

f(x) = (x - 5)(2x + 7)(7x-3)

f(2) = (2 - 5)(2*2 + 7)(7*2-3)

f(2) = (2 - 5)(4 + 7)(14-3)

f(2) = (-3)(11)(11)

f(2) = -363

The actual result doesn't matter. All we're after is whether the result is positive or negative. We see the result is negative. This means f(x) is negative when 3/7 < x < 5. The f(x) curve is below the x axis on this interval.

Answer:

The 95% confidence interval for the proportion of participants who have SLD among the children with ASD is (0.1437, 0.1813).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Out of a sample of 1,483 participants, a total of 241 were found to have SLD.

This means that [tex]n = 1483, \pi = \frac{241}{1483} = 0.1625[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1625 - 1.96\sqrt{\frac{0.1625*0.8375}{1483}} = 0.1437[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1625 + 1.96\sqrt{\frac{0.1625*0.8375}{1483}} = 0.1813[/tex]

The 95% confidence interval for the proportion of participants who have SLD among the children with ASD is (0.1437, 0.1813).

Answer:

Last Option

Step-by-step explanation:

Last one because the dot on top of the 4 is filled in and that means it can also equal 4. The rest of the line is going to the right of the 4 so x will be more than 4. The little line below the more than sign means it can also equal 4. Hope this helped :)

Answer:

Option D, x ≥ 4

Step-by-step explanation:

Rule 1: Closed circle: the inequality sign with a line at the bottom, its called greater than or equal to (≥), and less than or equal to (≤), that means that the number 4 is included in the data set.

Rule 2: Since the line is going to the right of 4, there are values greater than 4 in the data set which means x (any value) has to be greater than 4.

So bringing both rules together the equation would be: x ≥ 4

Hope this helps!

Answer:

528 square inches

Step-by-step explanation:

SA = 2(10·16) + 2(10·4) +2(4·16)

= 2(160)+2(40)+2(64)

= 320 + 80 + 128

= 528 square inches

Answer:

2/5

Step-by-step explanation:

3/8 = 375/1000

1/2 = 500/1000

2/5 = 400/1000

Answer:

Step-by-step explanation:

9. disagree;

error: he should have divided 60 by 4, not subtracted. So the correct answer is x = 15.

10. disagree;

error: it should be 3x + 2 = 127 (opposite angles)

so x = 125/3

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Answer:

  A, F

Step-by-step explanation:

Points A(-1, 0) and F(-3, 8) lie on the 2nd line. (Its equation is 4x+y=-4.)

Answer:

This is an impossible question. tan(0) = 0 If this means that you are supposed to just add 3/4 to each of these, then sin(20) = 1.09

Hope that this helps!

Answer:

a) The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b) A sample of 408 is required.

c) A sample of 20465 is required.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Of 1600 randomly selected aircraft, eight were found to have wiring errors that could display incorrect information to the flight crew.

This means that [tex]n = 1600, \pi = \frac{8}{1600} = 0.005[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 - 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0005[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 + 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0095[/tex]

The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b. Suppose we use the information in this example to provide a preliminary estimate of p. How large a sample would be required to produce an estimate of p that we are 99% confident differs from the true value by at most 0.009?

The margin of error is of:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

A sample of n is required, and n is found for M = 0.009. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.009 = 2.575\sqrt{\frac{0.005*0.995}{n}}[/tex]

[tex]0.009\sqrt{n} = 2.575\sqrt{0.005*0.995}[/tex]

[tex]\sqrt{n} = \frac{2.575\sqrt{0.005*0.995}}{0.009}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.575\sqrt{0.005*0.995}}{0.009})^2[/tex]

[tex]n = 407.3[/tex]

Rounding up:

A sample of 408 is required.

c. Suppose we did not have a preliminary estimate of p. How large a sample would be required if we wanted to be at least 99% confident that the sample proportion differs from the true proportion by at most 0.009 regardless of the true value of p?

Since we have no estimate, we use [tex]\pi = 0.5[/tex]

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.009 = 2.575\sqrt{\frac{0.5*0.5}{n}}[/tex]

[tex]0.009\sqrt{n} = 2.575*0.5[/tex]

[tex]\sqrt{n} = \frac{2.575*0.5}{0.009}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.575*0.5}{0.009})^2[/tex]

[tex]n = 20464.9[/tex]

Rounding up:

A sample of 20465 is required.

Answer:

1) y = 17

2) w = 20

Step-by-step explanation:

Answer:

y= 17

w= 20

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

the constant is the y-intercept

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Answer:

  [tex]\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right][/tex]

Step-by-step explanation:

The system of equations can be written in standard form as ...

  x + 0y = 2

  0x +2y = 2

The augmented matrix representation of these is ...

  [tex]\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right][/tex]

Answer:

-1 = 7 - 8

Step-by-step explanation:

length+ breadth and 2×side

Step-by-step explanation:

4÷2 =2

5×2=10

10+2=12

12 ans

Answer:

It is 603 units greater

Step-by-step explanation:

Given

See attachment for table

Average rate of change over (a,b) is calculated as:

[tex]Rate = \frac{f(b) - f(a)}{b-a}[/tex]

For interval [7,9], we have:

[tex][a,b] = [7,9][/tex]

So, we have:

[tex]Rate = \frac{f(9) - f(7)}{9-7}[/tex]

[tex]Rate = \frac{f(9) - f(7)}{2}[/tex]

From the table:

[tex]f(9) = 3878[/tex]

[tex]f(7) = 1852[/tex]

So:

[tex]Rate = \frac{f(9) - f(7)}{2}[/tex]

[tex]Rate = \frac{3878 - 1852}{2}[/tex]

[tex]Rate = \frac{2026}{2}[/tex]

[tex]Rate = 1013\\[/tex]

For interval [4,6], we have:

[tex][a,b] = [4,6][/tex]

So, we have:

[tex]Rate = \frac{f(6) - f(4)}{6-4}[/tex]

[tex]Rate = \frac{f(6) - f(4)}{2}[/tex]

From the table:

[tex]f(6) = 1178[/tex]

[tex]f(4) = 358[/tex]

So:

[tex]Rate = \frac{f(6) - f(4)}{2}[/tex]

[tex]Rate = \frac{1178 - 358}{2}[/tex]

[tex]Rate = \frac{820}{2}[/tex]

[tex]Rate = 410[/tex]

Calculate the difference (d) to get how much greater their rate of change is:

[tex]d = 1013 - 410[/tex]

[tex]d = 603[/tex]

Answer:

603

Step-by-step explanation:

i took it

Answer:

(5x+7) (5x-7)

Step-by-step explanation:

you can look up the answer on symbolab if needed

Answer:

false

Step-by-step explanation:

[tex] \rm \dashrightarrow \: {x}^{2} - 6x + 5 = 0 \\ \rm \dashrightarrow \: {( - 1)}^{2} - 6( - 1) + 5 = 0 \\ \rm \dashrightarrow \: 1 + 6 + 5 = 0 \\ \rm \dashrightarrow \: 7 + 5 = 0 \\ \rm \dashrightarrow \: 12 \cancel{ = }0[/tex]

Answer:

(0.25 ; 21.75)

8.7 (1 decimal place)

Step-by-step explanation:

Net change in scores : X = 6,14,12,23,0

Sample mean, xbar = (6 + 14 + 12 + 23 + 0) /5 = 55 /5 = 11

Sample standard deviation, s = 8.66 ( from calculator)

Sample standard deviation = 8.7( 1 decimal place)

Sample size, n = 5

The 95% confidence interval; we use t, because n is small

Tcritical at 95%, df = 4 - 1 = 3 ; Tcritical = 2.776

Xbar ± standard Error

Standard Error = Tcritical * s/√n

Standard Error = 2.776 * 8.66/√5

Standard Error = 10.751086 = 10.75

Lower boundary = (11 - 10.75) = 0.25

Upper boundary = (11 + 10.75) = 21.75

(0.25 ; 21.75)

The

Answer: Choice D)

(-1.5, -1) and (0, 1)

=============================================================

Explanation:

Exponents can be a bit clunky if you have too many of them, and if they're nested like this. Writing something like e^(x^2) may seem confusing if you aren't careful. I'm going to use a different notation approach. I'll use "exp" notation instead.

So instead of writing something like e^(x^2), I'll write exp(x^2).

The given derivative is

f ' (x) = exp(x^4-2x^2+1) - 2

and this only applies when -1.5 < x < 1.5

Apply the derivative to both sides and we'll find the second derivative

f ' (x) = exp(x^4-2x^2+1) - 2

f '' (x) = d/dx[ exp(x^4-2x^2+1) - 2 ]

f '' (x) = exp(x^4-2x^2+1)*d/dx[ x^4-2x^2+1 ]

f '' (x) = exp(x^4-2x^2+1)*(4x^3-4x)

f '' (x) = (4x^3-4x)*exp(x^4-2x^2+1)

From here, we need to find the roots of f '' (x).

Set f '' (x) equal to zero and solve to get...

f '' (x) = 0

(4x^3-4x)*exp(x^4-2x^2+1) = 0

4x^3-4x = 0  ..... or .... exp(x^4-2x^2+1) = 0

4x(x^2-1) = 0

4x(x+1)(x-1) = 0

4x = 0 or x+1 = 0 or x-1 = 0

x = 0 or x = -1 or x = 1

Those are the three roots. We ignore the equation exp(x^4-2x^2+1) = 0 because it doesn't have any real number solutions.

---------------------

The three roots of x = 0 or x = -1 or x = 1 represent possible locations of points of inflection (POI). Recall that a POI is where the function changes concavity. To determine if we have a POI or not, we'll need to a sign test.

Draw out a number line. Plot -1, 0, and 1 in that order on it. Pick something to the left of -1 but larger than -1.5, lets say we pick x = -1.2. Plugging this into the second derivative function leads to...

f '' (x) = (4x^3-4x)*exp(x^4-2x^2+1)

f '' (-1.2) = (4(-1.2)^3-4(-1.2))*exp((-1.2)^4-2(-1.2)^2+1)

f '' (-1.2) = -2.563    

That value is approximate. The actual value itself doesn't matter. What does matter is the sign of the result. The negative second derivative value tells us we have a concave down region. So we just found that f(x) is concave down for the interval -1.5 < x < -1, which converts to the interval notation (-1.5, -1)

Repeat the process for something between x = -1 and x = 0. I'll pick x = -0.5 and it leads to f '' (-0.5) = 2.63 approximately. The positive result tells us that we have a concave up region. Therefore, -1 < x < 0 is not part of the answer we're after.

Repeat for something between x = 0 and x = 1. I'll pick x = 0.5 and it produces f '' (0.5) = -2.63 approximately. So the region 0 < x < 1 is also concave down. Meaning that the interval notation (0,1) is also part of the answer.

So far we have the interval notation of (-1.5, -1) and (0,1) as part of our solution set.

Lastly, we need to check something to the right of x = 1, but smaller than 1.5; let's go for x = 1.2

You should find that f '' (1.2) = 2.563 which allows us to rule out the region on the interval 1 < x < 1.5

Overall, the final answer is (-1.5, -1) and (0, 1)

Answer:

-1

Step-by-step explanation:

Answer:

The functions are:

f(x) = $14.75*x + $2

s(x) = $12.25*x + $17

Both iSpice and Spice Magic charge $90.50 for 6 pounds of paprika.

Step-by-step explanation:

A linear equation has the general shape:

y = a*x + b

Where a is the slope and b is the y-intercept.

If we know that the function passes through the points: (x₁, y₁) and (x₂, y₂) then the slope is:

a = (y₂ - y₁)/(x₂ - x₁)

Ok, knowing this, let's look at the first table, we need to work with only two points, so let's use the first one (1, $16.75) and the second one (2, $31.50)

Then the slope of the equation is:

a = ($31.50 - $16.75)/(2 - 1) = $14.75

Then the equation is something like:

y = f(x) = $14.75*x + b

To find the value of b, we can use one of the two points. For example, the point (1, $16.75) means that when x = 1, we must have y = $16.75

Replacing these values in the equation we get:

$16.75 = f(1) = $14.75*1 + b

$16.75 - $14.75 = b = $2

Then the function f(x) is:

f(x) = $14.75*x + $2

Now let's go to the other function, again we can choose two points, let's use the first one (1, $29.25) and the third one (3, $53,75).

Then the slope is:

a = ($53.75 - $29.25)/(3 - 1) = $12.25

Then the equation is something like:

y = s(x) = $12.25*x + b

To find the value of b we do the same as before, if we use the first point (1, $29.25) we get:

$29.25 = s(1) = $12.25*1 + b

$29.25 - $12.25 = b = $17

Then this equation is:

y = s(x) = $12.25*x + $17

The two equations are:

f(x) = $14.75*x + $2

s(x) = $12.25*x + $17

b) now we want to find the value x such that the price is the same in both cases, then we need to solve:

f(x) = g(x)

$14.75*x + $2 =  $12.25*x + $17

$14.75*x - $12.25*x = $17 - $2

$2.5*x = $15

x = $15/$2.5 = 6

This means that for 6 pounds of paprika the price is the same on both companies, and the price is:

f(6) = g(6) = $14.75*6 + $2 = $90.50

Answer:

The cost for 4 snacks is 18 dollars.

Cost for x snacks: 4.5x

Step-by-step explanation:

4 x 4.5 = 18

Answers:

The algebraic expression shown above is the same as writing 52+4.50x

You may not need to type in "dollars" or a dollar sign, as your teacher may just want the numbers and algebraic symbols.

=====================================================

Explanation:

There are four people going to the movies, and each ticket costs $13 a piece, so that means the total so far is 4*13 = 52 dollars.

If we want to include snacks, then it costs $4.50 per snack. Buying 4 packages will cost an additional 4.50*4 = 18 dollars. In total, if Kiran wants to buy four snacks, then he'll need 52+18 = 70 dollars.

---------------------

Instead of computing 4.50*4 to get 18, we can leave the "4.50*4" like it is. Adding it onto the 52 found earlier leads to the expression 52+4.50*4

Now imagine that instead of "4", we just had a generic placeholder x take over. The x is standing in for any positive real number, or it could stand in for 0 if Kiran decides to not buy any snacks at all.

If we replace that "4" with x, then the expression

52+4.50*4

is the same as

52+4.50*x

Often times, you'll see the multiplication symbol omitted and the expression could look like 52+4.50x

Because we can add two numbers in any order, that expression above is the same as 4.50x+52

-------------------

Extra info (optional section):

The useful thing about something like 4.50x+52 is that we can graph y = 4.50x+52 and/or set up a table to be able to quickly determine how much money it will cost for buying any amount of snacks.

For example, let's say he wants to buy 10 snacks. That means we replace x with 10 and evaluate like so

4.50x+52 = 4.50*10+52 = 45+52 = 97

Buying 10 snacks, on top of the 4 movie tickets, cost $97 in total.

Answer:

Step-by-step explanation:

2x+10x=12x

12x=-21

x=-1.75

Answer:

x=-7,-3

Step-by-step explanation:

x2+10x+21

(x+7)(x+3)

x=-7,-3

Answer:

Step-by-step explanation:

1). Given equation is,

   2x² - 3x = 6

   2x² - 3x - 6 = 0

   To find the solutions of the equation we will use quadratic formula,

   x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

   Substitute the values of a, b and c in the formula,

   a = 2, b = -3 and c = -6

   x = [tex]\frac{3\pm\sqrt{(-3)^2-4(2)(-6)}}{2(2)}[/tex]

   x = [tex]\frac{3\pm\sqrt{9+48}}{4}[/tex]

   x = [tex]\frac{3\pm\sqrt{57}}{4}[/tex]

   x = [tex]\frac{3+\sqrt{57}}{4},\frac{3-\sqrt{57}}{4}[/tex]

   Therefore, there are two real solutions.

2). Given equation is,

    x² + 1 = 2x

    x² - 2x + 1 = 0

    (x - 1)² = 0

     x = 1

     Therefore, there is one real solution of the equation.

3). 2x² + 3x + 2 = 0

     By applying quadratic formula,

     x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

      x = [tex]\frac{-3\pm\sqrt{3^2-4(2)(2)}}{2(2)}[/tex]

      x = [tex]\frac{-3\pm\sqrt{9-16}}{4}[/tex]

      x = [tex]\frac{-3\pm i\sqrt{7}}{4}[/tex]

      x = [tex]\frac{-3+ i\sqrt{7}}{4},\frac{-3- i\sqrt{7}}{4}[/tex]

      Therefore, there are two complex (non real) solutions.

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Answer:

  1,570,000

Step-by-step explanation:

The sum is approximately ...

  1,260,000 +310,000 = 1,570,000

_____

Additional comment

It is a good idea to estimate the error associated with an estimate. Here, both numbers are rounded up by about 4000 each, so the estimate is around 8000 high.

Answer:

yes

Step-by-step explanation:

lets use a significance level of = 0.1

Determine if the sequence indicates randomness

First step :

H0 : pattern is random

H1 : pattern not random

n1 ( number of true answers ) = 10

n2 ( number of false answers ) = 10

also number of runs for T = 5

       number of runs for F = 5

Total number of runs = 5+ 5 = 10

Given that critical value at 0.05 = 23

we will reject the null hypothesis ( i.e the sequence departs from randomness )

Answer:

report me !!! dont ask why or how

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

A=wl=4·8=32

Answer:

2 days

Step-by-step explanation:

0.12x 400=48.00+33.00=81×2=162.00 for 2 days