What are two main types of exercise???

Answer:

Antibody molecules that are secreted by plasma cells mediate the humoral immune response. The antigen that binds to the receptor of the B-cell antigen signals B cells and is internalized and transformed into peptides that activate the armed helper at the same time.

Explanation:

Answer:

B cells

Explanation:

Humoral immunity or humoural immunity is the aspect of immunity that is mediated by macromolecules found in extracellular fluids such as secreted antibodies, complement proteins, and certain antimicrobial peptides. Humoral immunity is named so because it involves substances found in the humors, or body fluids. It contrasts with cell-mediated immunity. Humoral immunity is also referred to as antibody-mediated immunity.

Answer:

D

Explanation:

Increasing temperature or pressure some times make the condition favorable to the reaction. Similarly increasing surface area  of reacting mixture also helps to increase the reaction rate.

The rate of  a reaction is the rate of decrease in concentration of reactant or the rate of increase in concentration of the products. The rate of a reaction depends on several factors such as temperature, pressure, surface area etc.

Fir an endothermic reaction, as the temperature increases, reaction rate increases. Similarly, as the pressure increases, the reaction in which the number of moles of gaseous reactants is higher than that in products, rate increases.

The concentration of reactants must be sufficient for the reaction and decreasing the concentration of reactants does not favor an increase in reaction rate. Hence, option D is correct.

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Answer:

my mind cant comprehend a shing word u just said

Explanation:

The probes collect data, they capture the movement in space, therefore, spacecraft that carry instruments to collect data about objects in space are called probes, So the given statement is correct.

Any conductor that is placed into a plasma and gathers current is a probe. Measurements of the current on the probe as a function of the bias potential given to the probe can be used to identify a plasma's properties.

Such probes affect their surroundings while directly detecting electron and ion flows in the plasma. Any conductive material (wire, foil, chamber walls, etc.) can serve as a plasma probe; nevertheless, precise control over the probe's size, shape, and substance is necessary to achieve detectable plasma levels. Astronauts are not present aboard probes. Scientists can analyze the data the probes relay back to Earth. Sputnik 1 was the first spacecraft to launch.

Because probes probably collect data, they capture the movement in space, therefore, spacecraft that carry instruments to collect data about objects in space are called probes.

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Answer:

8) A hanging 7.5 kg object stretches a spring 1.1 m. What is the spring constant? 1 . 1 66. 82 NIMO 9) A spring has a constant of 875 N/m. What hanging mass will cause this spring to stretch 4.5 m? Iouliply then divide 875 X 4. 2- - (4 04. 7919) 10) A spring with a spring constant of 25 N/m is stretched 65 cm. What was the force used? 11) A 25 N force stretches a spring 280 cm. What was the spring constant? 12) A 75 N force stretches a spring 175 cm. What was the proportionality constant? 8) 66.82 N/m 9) 401.79 kg 10) 16.25 N 11) 8.93 N/m 12) 42.86 N/m

Explanation:

A spring has a constant of 875 N/m. and the mass which will cause this spring to stretch 4.5 meters is 401.78 kg.

The spring constant is a characteristic of a spring which is defined as the ratio of the force affecting the spring to the displacement which is caused by that force. The SI unit of spring constant is N.m⁻¹ (Newton per meter).

The spring constant is:

F = -k/ x

where, k is the spring constant

F denotes the force,

and x denotes the change in the length of the spring.

k = 875N/m

x = 4.5m

We know that

Kx = mg

m= kx/ g

m = 875 × 4.5/ 9.8

m = 401.78kg

Therefore, the mass which will cause this spring to stretch 4.5 meters is 401.78 kg.

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Answer:

Final velocity v = 4 m/s

Explanation:

Given:

Initial velocity u = 0 m/s

Acceleration a = 0.16 m/s²

Distance s = 50 m

Find:

Final velocity v

Computation:

Using; v² = u² + 2as

v² = (0)² + 2(0.16)(50)

v² = 16 m/s

v = 4 m/s

Final velocity v = 4 m/s

Answer:12.5

Explanation: Subtract