what is 3141 times X. x=5783978

Answer:

D.$80

Step-by-step explanation:

$5.26 x 15.5= $81.53

The closest amount to $81.53 is D.$80

Answer:

8lb of the cheaper Candy

17.5lb of the expensive candy

Step-by-step explanation:

Let the cheaper candy be x

let the costly candy be y

X+y = 25.5....equation one

2.2x +7.3y = 25.5(5.7)

2.2x +7.3y = 145.35.....equation two

X+y = 25.5

2.2x +7.3y = 145.35

Solving simultaneously

X= 25.5-y

Substituting value of X into equation two

2.2(25.5-y) + 7.3y = 145.35

56.1 -2.2y +7.3y = 145.35

5.1y = 145.35-56.1

5.1y = 89.25

Y= 89.25/5.1

Y= 17.5

X= 25.5-y

X= 25.5-17.5

X= 8

Answer:

7/44

Step-by-step explanation:

First find the total number of presidents.

2 + 7 + 13 + 12 + 7 + 3 = 44

There were 7 presidents that were 45-49 when elected.  Divide this number by the total number of presidents to find the fraction.

7/44 ≈ 0.159

Answer:

[tex]\boxed{x = 9}[/tex]

Step-by-step explanation:

m = -1/3

b = 7

And y = 4 (Given)

Putting all of the givens in [tex]y = mx+b[/tex] to solve for x

=> 4 = (-1/3) x + 7

Subtracting 7 to both sides

=> 4-7 = (-1/3) x

=> -3 = (-1/3) x

Multiplying both sides by -3

=> -3 * -3 = x

=> 9 = x

OR

=> x = 9

Answer:

x = 9

Step-by-step explanation:

m = -1/3

b = 7

Using slope-intercept form:

y = mx + b

m is slope, b is y-intercept.

y = -1/3x + 7

Solve for x:

Plug y as 4

4 = 1/3x + 7

Subtract 7 on both sides.

-3 = -1/3x

Multiply both sides by -3.

9 = x

Answer:

12/13

Step-by-step explanation:

First we must calculate the hypotenus using the pythagoran theorem

Now let's calculate sin0

So the exact value is 12/13

Answer:

C.) 12/13

Step-by-step explanation:

In a right angle triangle MN = 12, ON = 5 and; angle N = 90°

Now,

For hypotenuse we will use Pythagorean Theorem

(MO)² = (MN)² + (ON)²

(MO)² = (12)² + (5)²

(MO)² = 144 + 25

(MO)² = 169

MO = √169

MO = 13

now,

Sin O = opp÷hyp = 12÷13

Answer:

the probability that one parachute of the  five parachute is damaged is 0.156

Step-by-step explanation:

From the given information;

Let consider X to be the altitude above the  ground that a parachute opens

Then; we can posit that the probability that the parachute is damaged is:

P(X ≤ 100 )

Given that the population mean μ = 155

the standard deviation σ = 30

Then;

[tex]P(X \leq 100 ) = ( \dfrac{X- \mu}{\sigma} \leq \dfrac{100- \mu}{\sigma})[/tex]

[tex]P(X \leq 100 ) = ( \dfrac{X- 155}{30} \leq \dfrac{100- 155}{30})[/tex]

[tex]P(X \leq 100 ) = (Z \leq \dfrac{- 55}{30})[/tex]

[tex]P(X \leq 100 ) = (Z \leq -1.8333)[/tex]

[tex]P(X \leq 100 ) = \Phi( -1.8333)[/tex]

From standard normal tables

[tex]P(X \leq 100 ) = 0.0334[/tex]

Hence; the probability of the given parachute damaged is 0.0334

Let consider Q to be the dropped parachute

Given that the number of parachute be n= 5

The probability that the parachute opens in each trail be  p = 0.0334

Now; the random variable Q follows the binomial distribution with parameters n= 5 and p = 0.0334

The probability mass function is:

Q [tex]\sim[/tex] B(5, 0.0334)

Similarly; the event that one parachute is damaged is :

Q ≥ 1

P( Q ≥ 1 ) = 1 - P( Q < 1 )

P( Q ≥ 1 ) = 1 - P( Y = 0 )

P( Q ≥ 1 ) = 1 - b(0;5; 0.0334 )

P( Q ≥ 1 ) = [tex]1 -(^5_0)* (0.0334)^0*(1-0.0334)^5[/tex]

P( Q ≥ 1 ) = [tex]1 -( \dfrac{5!}{(5-0)!}) * (0.0334)^0*(1-0.0334)^5[/tex]

P( Q ≥ 1 ) = 1 -  0.8437891838

P( Q ≥ 1 ) = 0.1562108162

P( Q ≥ 1 ) [tex]\approx[/tex] 0.156

Therefore; the probability that one parachute of the  five parachute is damaged is 0.156

Answer:

a. Total amount after 65 years = $1179415.39

b. The total contribution to the account  = $288000

Step-by-step explanation:

Given annuity amount = $1800

Total number of years for contribution = 65 – 25 = 40 years

Interest rate  = 6%

a. Total amount after 65 years = Annuity[((1+r)^n -1) / r]

Total amount after 65 years = 1800×((1+.06/4)^(4 × 40) - 1)/(.06/4)

Total amount after 65 years = $1179415.39

b. The total contribution to the account =1800 × 4 Quarter × 40 Years

        The total contribution to the account  = $288000

Answer:

5x 10 ^-5

Step-by-step explanation:

UHM that would be

NaN × [tex]10^{0}[/tex]

I hope this helps!

so my reasoning...  Any number that can be written in the decimal form between 1.0 to 10.0 multiplied by the power of 10.  

Answer:

AB = 2 sqrt(35)   (or 11.83 to two decimal places)

Step-by-step explanation:

Refer to diagram.

ABO'P is a rectangle (all angles 90)

=>

PO'  =  AB

AB = PO' = sqrt(12^2-2^2) = sqrt(144-4) = sqrt(140) = 2sqrt(35)

using Pythagoras theorem.

Answer:

The required probability = 0.144

Step-by-step explanation:

Since the probability of making money is 60%, then the probability of losing money will be 100-60% = 40%

Now the probability we want to calculate is the probability of making money in the first two days and losing money on the third day.

That would be;

P(making money) * P(making money) * P(losing money)

Kindly recollect;

P(making money) = 60% = 60/100 = 0.6

P(losing money) = 40% = 40/100 = 0.4

The probability we want to calculate is thus;

0.6 * 0.6 * 0.4 = 0.144

Answer:

$435,000

Step-by-step explanation:

$760 per month * 12 months = $9,120

The minimum rent requires an annual rental cost of $9,120.

The annual rent was $20,520.

The excess was $20,520 - $9,120 = $11,400.

The amount of $11,400 of the rent was due to the gross sales in excess of $150,000.

$11,400 is 4% of the amount in excess of $150,000.

Let the amount in excess of $150,000 = x.

$11,400 = 4% of x

0.04x = 11,400

x = 285,000

$285,000 is the amount in excess of $150,000.

Total gross sales volume = $285,000 + $150,000 = $435,000

Answer: Monomial.

Step-by-step explanation:

Ok, when we have a polynomial with only one term, this is a monomial.

If the polynomial has two terms, this is a binomial.

If the polynomial has 3 terms, this is a trinomial.

And so on.

In this particular case we have:

52*c^2*y^4

Where c and y may be variables.

We can see that here we have only one term, so this would be a monomial.

(notice that the number of variables does not affect the type of polynomial in this case, only the number of terms)

Answer:

binomial.

Step-by-step explanation:

The polynomial −50c3z3−41y220z4 has 2 terms, so it is a binomial.

Answer:

j < 2

Step-by-step explanation:

Simplify both sides of the inequality and isolating the variable would get you the answer

Answer:

In Table C, y vary inversely with x.

1×18 = 18

2×9 = 18

3×6 = 18

18 = 18 = 18

Step-by-step explanation:

We are given four tables and asked to find out in which table y vary inversely with x.

We know that an inverse relation has a form given by

y = k/x

xy = k

where k must be a constant

Table A:

x     |      y

1     |      3

2     |     9

3     |    27

1×3 = 3

2×9 = 18

3×27 = 81

3 ≠ 18 ≠ 81

Hence y does not vary inversely with x.

Table B:

x     |      y

1     |     -5

2     |     5

3     |    15

1×-5 = -5

2×5 = 10

3×15 = 45

-5 ≠ 10 ≠ 45

Hence y does not vary inversely with x.

Table C:

x     |      y

1     |      18

2     |     9

3     |     6

1×18 = 18

2×9 = 18

3×6 = 18

18 = 18 = 18

Hence y vary inversely with x.

Table D:

x     |      y

1     |      4

2     |     8

3     |    12

1×4 = 4

2×8 = 16

3×12 = 36

4 ≠ 16 ≠ 36

Hence y does not vary inversely with x.

Answer:

2 inches

Step-by-step explanation:

x= smallest

3x=largest

2x=medium

x+3x+2x=12

6x=12

x=2

so smallest is 2

largest is 6 (3x)

medium is 4 (2x)

2+6+4=12

Answer:

D) Fail to reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than $100.

Step-by-step explanation:

We are given that the owner of a shoe store randomly selected 10 receipts and identified the total spent by each customer. The totals (rounded to the nearest dollar) are given below;

X: 125, 99, 219, 65, 109, 89, 79, 119, 95, 135.

Let [tex]\mu[/tex] = average customer bought worth of shoes.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $100      {means that the mean is smaller than or equal to $100}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $100      {means that the mean is greater than $100}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

                            T.S.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean = [tex]\frac{\sum X}{n}[/tex] = $113.4

             s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = $42.78

             n = sample of receipts = 10

So, the test statistics =  [tex]\frac{113.4-100}{\frac{42.78}{\sqrt{10} } }[/tex]  ~  [tex]t_9[/tex]

                                    =  0.991

The value of t-test statistics is 0.991.

Now, at a 0.05 level of significance, the t table gives a critical value of 1.833 at 9 degrees of freedom for the right-tailed test.

Since the value of our test statistics is less than the critical value of t as 0.991 < 1.833, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean is smaller than or equal to $100.

Answer:    The loss is 4%  

Step-by-step explanation:

Lets call litches that are 20 pcs per Rs 100  - litches A

that are 30 pcs per Rs 100- litches B

So a man can buy 2 pcs A per Rs 10

and 3 pcs B per Rs 10

OR

6x  pcs  A per  Rs  30x  

and 6x  pcs  B  per  Rs  20x

Now he gonna sell the 12x  litches  for y Rs

Lets find y from the proportion

12x  cost y

25   cost 100

y/12=100/25

y=48  Rs

So the man bought 6x A + 6x B  for 20x+30x=50 Rs

And then he sold them for 48 Rs

Obviously the man gonna loose the money.

Lets find the losses in %

(50-48)/50*100=200/50=4%

The loss is 4%  

Answer:

a) $3700

b) $555

Step-by-step explanation:

The length of the loan is 3 years.

The interest after 3 years is $444.

The rate of the Simple Interest is 4%.

Simple Interest is given as:

I = (P * R * T) / 100

where P = principal (amount borrowed)

R = rate

T = length of years

Therefore:

[tex]444 = (P * 3 * 4) / 100\\\\444 = 12P / 100\\\\12P = 444 * 100\\\\12P = 44400\\\\P = 44400 / 12\\[/tex]

P = $3700

She borrowed $3700

b) If the simple interest was 5%, then:

I = (3700 * 5 * 3) / 100 = $555

The interest would be $555.

The area of the surface above the region R is 4096π square units.

Given that:

The function: [tex]f(x, y) = 64 + x^2 - y^2[/tex]

The region R is the disk with a radius of 8 units [tex]x^2 + y^2 \le 64[/tex].

To find the area of the surface given by z = f(x, y) that lies above the region R, to calculate the double integral over the region R of the function f(x, y) with respect to dA.

The integral for the area is given by:

[tex]Area = \int\int_R f(x, y) dA[/tex]

To evaluate this integral, we need to set up the limits of integration for x and y over the region R, which is the disk cantered at the origin with a radius of 8 units.

Using polar coordinates, we can parameterize the region R as follows:

x = rcos(θ)

y = rsin(θ)

where r goes from 0 to 8, and θ goes from 0 to 2π.

Now, rewrite the integral in polar coordinates:

[tex]Area =\int\int_R f(x, y) dA\\Area = \int_0 ^{2\pi} \int_0^8(64 + r^2cos^2(\theta) - r^2sin^2(\theta)) \times r dr d \theta[/tex]

Now, we can integrate with respect to r first and then with respect to θ:

[tex]Area = \int_0^{2\pi} \int_0^8] (64r + r^3cos^2(\theta) - r^3sin^2(\theta)) dr d \theta[/tex]

Integrate with respect to r:

[tex]Area = \int_0^{2\pi}[(32r^2 + (1/4)r^4cos^2(\theta) - (1/4)r^4sin^2(\theta))]_0^8 d \theta\\Area = \int_0^{2\pi} (2048 + 256cos^2(\theta) - 256sin^2(\theta)) d \theta[/tex]

Now, we can integrate with respect to θ:

[tex]Area = [2048\theta + 128(sin(2\theta) + \theta)]_0 ^{2\pi}[/tex]

Area = 2048(2π) + 128(sin(4π) + 2π) - (2048(0) + 128(sin(0) + 0))

Area = 4096π + 128(0) - 0

Area = 4096π square units

So, the area of the surface above the region R is 4096π square units.

Learn more about Integration here:

https://brainly.com/question/31744185

#SPJ4

Answer:

Step-by-step explanation:

The class interval is simply the difference between the lower or upper class boundary or limit  of a class and the lower or upper class boundary or limit of the next class.

In this case for the class

$4 up to $7 18 and

$7 up to $10 36

The lower class boundary of the first class is $4 and the lower class boundary of the second class is $7

Answer:

Standard form: [tex]12x+3y-2=0[/tex]

A = 12, B = 3 and C = -2

Step-by-step explanation:

Given:

The equation:

[tex]y= -4x + \dfrac{2}3[/tex]

To find:

The standard form of given equation and find A, B and C.

Solution:

First of all, let us write the standard form of an equation.

Standard form of an equation is represented as:

[tex]Ax+By+C=0[/tex]

A is the coefficient of x and can be positive or negative.

B is the coefficient of y and can be positive or negative.

C can also be positive or negative.

Now, let us consider the given equation:

[tex]y= -4x + \dfrac{2}3[/tex]

Multiplying the whole equation with 3 first:

[tex]3 \times y= 3 \times -4x + 3 \times \dfrac{2}3\\\Rightarrow 3y=-12x+2[/tex]

Now, let us take all the terms on one side:

[tex]\Rightarrow 3y+12x-2=0\\\Rightarrow 12x+3y-2=0[/tex]

Now, let us compare with [tex]Ax+By+C=0[/tex].

So, A = 12, B = 3 and C = -2

Answer:

The elevation of the airplane decreases by 9 km.

Step-by-step explanation:

We use the distance-rate-time formula: d = rt.

Here, the rate is r = 0.15 km/min and the time is t = 60 min. Simply plug these into the formula:

d = rt

d = 0.15 * 60 = 9 km

So, the change in elevation in the last 60 minutes is 9 km. However, note that the rate is negative (-0.15 km/min), which means that the elevation actually is decreasing.

Thus, the answer is: the elevation of the airplane decreases by 9 km.

~ an aesthetics lover

Answer:

The elevation of the airplane _decrease_ by __9____ km

Step-by-step explanation:

Take the rate and multiply by the time to get the distance traveled

-.15 km per minute * 60 minutes

- 9 km

The plane will go down 9 km in that 60 minutes

Answer: 680

Step-by-step explanation:

When order doesn't matter,then the number of combinations of choosing r things out of n = [tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]

Given: Total participants = 17

From these, a group of 3 participants is to be tested under a special condition.

Number of groups of 3 participants chosen = [tex]^{17}C_3=\dfrac{17!}{3!(17-3)!}\[/tex]

[tex]^{17}C_3=\dfrac{17!}{3!(17-3)!}\\\\=\dfrac{17\times16\times15\times14!}{3\times2\times14!}\\\\=680[/tex]

Hence, there are 680 groups of 3 participants can  be chosen,.

Answer:

3

Step-by-step explanation:

let's call X the length of the bedroom, Y the wide of the bedroom, A the length of the living room and B the wide of the living room

A living room is two times as long as the bedroom, so:

A = 2X

A living room is one and one-half times as wide as a bedroom, so:

B = 1.5Y

The amount of carpet needed for the living room is A*B and the amount of carpet needed by the bedroom is X*Y

So, AB in terms of XY is:

A*B = (2X)*(1.5Y) = 3(X*Y)

It means that the amount of c arpet needed for the living room is 3 times greater than the amount of carpet needed for the  bedroom.

Answer:

The probability that no more than 70% would prefer to start their own business is 0.1423.

Step-by-step explanation:

We are given that a Gallup survey indicated that 72% of 18- to 29-year-olds, if given choice, would prefer to start their own business rather than work for someone else.

Let [tex]\hat p[/tex] = sample proportion of people who prefer to start their own business

The z-score probability distribution for the sample proportion is given by;

                               Z  =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]  ~ N(0,1)

where, p = population proportion who would prefer to start their own business = 72%

            n = sample of 18-29 year-olds = 600

Now, the probability that no more than 70% would prefer to start their own business is given by = P( [tex]\hat p[/tex] [tex]\leq[/tex] 70%)

       P( [tex]\hat p[/tex] [tex]\leq[/tex] 70%) = P( [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] [tex]\leq[/tex] [tex]\frac{0.70-0.72}{\sqrt{\frac{0.70(1-0.70)}{600} } }[/tex] ) = P(Z [tex]\leq[/tex] -1.07) = 1 - P(Z < 1.07)

                                                                       = 1 - 0.8577 = 0.1423

The above probability is calculated by looking at the value of x = 1.07 in the z table which has an area of 0.8577.

I hope this will help uh.....

Answer:

Step-by-step explanation:

Firstly let us calculate the amount of hours you will have to work in a week.

Since you will have to work Mondays through Fridays, hence you will be working 5 days in a week.

Hence in a week you will work 8.5*5= 42.5 hours in a week

Since in 1 hours you are mandated to pick 45 units

Hence in 42.5 hours you will pick 42.5*45= 1912.5 units

Answer:

third option

Step-by-step explanation:

We just have to calculate 2x² - 4x - (x² + 6x). 2x² - x² = x² and -4x - 6x = -10x so the answer is x² - 10x.

Answer:

x^2-10x

Step-by-step explanation:

f(x)-g(x)

(2x^2-4x)-(x^2+6x)

carry through the negative

2x^2-4x-x^2-6x

x^2-10x

Answer: 97

Step-by-step explanation:

Formula to compute the required sample size :

[tex]n= (\dfrac{\sigma\times z_{\alpha/2}}{E})^2[/tex]

, where [tex]\sigma[/tex] = standard deviation

E= Margin of error

[tex]z_{\alpha/2}[/tex] = Two tailed z-value.

Here, E= 20

[tex]\sigma[/tex] = 100

For 95% confidence level: [tex]z_{\alpha/2}[/tex] =1.96

Required sample size:

[tex]n=(\dfrac{100\times1.96}{20})^2\\\\=(5\times1.96)^2\\\\=96.04\approx97[/tex]

Hence, the required sample size : 97

Answer:

z(c)  = - 1,64

We reject the null hypothesis

Step-by-step explanation:

We need to solve a proportion test ( one tail-test ) left test

Normal distribution

p₀ = 63 %

proportion size  p = 51 %

sample size  n = 114

At 5% level of significance   α = 0,05, and with this value we find in z- table z score of z(c) = 1,64  ( critical value )

Test of proportion:

H₀     Null Hypothesis                        p = p₀

Hₐ    Alternate Hypothesis                p < p₀

We now compute z(s) as:

z(s) =  ( p - p₀ ) / √ p₀q₀/n

z(s) =( 0,51 - 0,63) / √0,63*0,37/114

z(s) =  - 0,12 / 0,045

z(s) = - 2,66

We compare z(s) and z(c)

z(s) < z(c)      - 2,66 < -1,64

Therefore as z(s) < z(c)  z(s) is in the rejection zone we reject the null hypothesis