what is 72% written in a deciamal

The resultant value of the given expression x² + 10x + 24 when x = 3 is (C) 63.

A finite collection of symbols that are properly created in line with context-dependent criteria is referred to as an expression, sometimes known as a mathematical expression.

Expressions in writing are made using mathematical operators such as addition, subtraction, multiplication, and division.

For instance, "4 added to 2" will have the mathematical formula 2+4.

So, we have the expression:

= x² + 10x + 24

Now, solve when x = 3 as follows:

= x² + 10x + 24

= 3² + 10(3) + 24

= 9 + 30 + 24

= 63

Therefore, the resultant value of the given expression x² + 10x + 24 when x = 3 is (C) 63.

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Correct question:

Evaluate the expression when x = 3.

x² + 10x + 24

a. 81

b. 86

c. 63

d. 60

The directionality of the alternative hypothesis and the support offered by the sample data determine whether the null hypothesis is likewise rejected at the 5% level of significance for a related one-tailed test.

When the two-tailed test rejects the null hypothesis, it means that the sample data, regardless of how we look at it, support the null hypothesis.. A one-tailed test, however, simply considers the evidence in one way. As a result, the null hypothesis should be used if the sample data only show evidence that the alternative hypothesis is true in one direction (for example, greater than).

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Answer:

The value of x is 2.

Step-by-step explanation:

5(2x -1) + 3(x -3) = -(4x - 6) + 2(13 -3x)

Expand both sides of the equation to remove parenthesis

10x - 5 + 3x - 9 = -4x + 6 + 26 - 6x

Transpose all terms with x as the coefficient on the left side of the equation and transpose the constants to the right.

10x + 3x + 4x + 6x = 6 + 26 + 5 + 9

Simplify

23x = 46

Divide both sides of the equation by 23

23x/23 = 46/23

x = 2

Therefore, the company made $48.3 million (written in scientific notation as 4.83 x 10⁷) that year from selling new cars.

An equation is a mathematical statement that shows that two expressions are equal. It consists of two sides, the left-hand side (LHS) and the right-hand side (RHS), separated by an equals sign (=). The expressions on both sides of the equals sign must have the same value for the equation to be true. Equations can involve a wide range of mathematical operations such as addition, subtraction, multiplication, division, exponents, and roots. They are used to solve problems in various fields such as physics, engineering, economics, and many others.

Here,

To find the total revenue generated by the company, we need to multiply the number of new cars sold by the average price per car. We can do this as follows:

Total revenue = number of new cars sold x average price per car

Total revenue = 2.3 million x $21,000

To multiply these two numbers, we can use the distributive property:

Total revenue = (2.3 x 10⁶) x ($21,000)

Total revenue = 2.3 x $21 x 10⁶

Multiplying 2.3 by 21 gives us 48.3, which we can write in scientific notation as 4.83 x 10¹. We can then add the exponents to get:

Total revenue = 4.83 x 10¹ x 10⁶

Total revenue = 4.83 x 10⁷

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The missing angles of the diagram are:

∠1 = 118°

∠2 = 62°

∠3 = 118°

∠4 = 30°

∠5 = 32°

∠6 = 118°

∠7 = 30°

∠8 = 118°

Supplementary angles are defined as two angles that sum up to 180 degrees. Thus:

∠1 + 62° = 180°

∠1 = 180 - 62

∠1 = 118°

Now, opposite angles are congruent and ∠2 is an opposite angle to 62°. Thus: ∠2 = 62°.

Similarly: ∠3 = 118° because it is congruent to ∠1

Alternate angles are congruent and ∠5 is an alternate angle to 32°. Thus:

∠5 = 32°

Sum of angle 4 and 5 is a corresponding angle to ∠2 . Thus:

∠4 + ∠5 = 62

∠4 + 32 = 62

∠4 = 30°

This is an alternate angle to ∠7 and as such ∠7 = 30°

Sum of angles on a straight line is 180 degrees and as such:

∠8 = 180 - (30 + 32)

∠8 = 118° = ∠6 because they are alternate angles

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It depends on the rotational speed of the wheel. To calculate this speed, we need to know the angular velocity of the wheel.

The maximum speed of a point on the outside of the wheel, 15 cm from the axle, if we assume that the wheel is rotating at a constant rate, we can use the formula v = rω, where v is the speed of the point on the outside of the wheel, r is the radius of the wheel (15 cm in this case), and ω is the angular velocity of the wheel. Therefore, the maximum speed of a point on the outside of the wheel would be directly proportional to the angular velocity of the wheel.
The formula to calculate the maximum linear speed (v) is:
v = ω × r
where v is the linear speed, ω is the angular velocity in radians per second, and r is the distance from the axle (15 cm, or 0.15 meters in this case).
Once you have the angular velocity (ω) of the wheel, you can plug it into the formula and find the maximum speed of a point on the outside of the wheel.

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The section for piano will have 60 degrees in the circle graph.

To find out how many degrees the section for piano will have in the circle graph, we first need to find the fraction of the circle that the piano represents.

The total degrees in a circle is 360 degrees. We can use the given fraction of piano (1/6) and multiply it by 360 degrees to find out the degrees of the section for piano.

Degrees for piano = (Fraction of piano) × 360

Degrees for piano = (1/6) × 360

Now, multiply the fraction by 360:

Degrees for piano = 60

So, the section for piano will have 60 degrees in the circle graph.

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→ 60° ( btw, ° means degrees )

— if a WHOLE circle is 360° and the piano is 1/6 of the circle, then all you have to do is multiply 1/6 by 360° which gives you 60 OR 60°

HEY- you look hungry, eat up !! →

Answer:

Add 1 1/4 x 1 1/4

Step-by-step explanation:

Answer: This situation involves choosing a group of 5 players out of a total of 12 players, where the order in which the players are chosen does not matter. Therefore, this is an example of a combination problem.

The number of ways to choose a group of 5 players out of 12 is given by the formula for combinations:

n C r = n! / (r! * (n-r)!)

where n is the total number of players, r is the number of players being chosen, and "!" represents the factorial operation.

In this case, we have n = 12 and r = 5, so the number of different choices of starters is:

12 C 5 = 12! / (5! * (12-5)!)

= 792

Therefore, there are 792 different choices of starters that the coach can make from the team of 12 players.

Step-by-step explanation:

The measure of the unknown side from the given triangle is 14.48.

The given triangle is a right triangle with the following sides;

Hypotenuse = 15

Adjacent = x

Acute angle = 52 degrees

We are to determine the measure of the unknown side using trigonometry identity

Cos 15 = Adjacent/Hypotenuse

Cos 15 = x/15

x = 15cos15

x = 15(0.9659)

x = 14.48

Hence the measure of the unknown side is 14.48

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The value of the length marked x is 61.5

Trigonometric ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle.  The basic trigonometric ratios are sine, cosine, and tangent ratios.  The other important trig ratios, cosec, sec, and cot can be derived using the sin, cos and tan respectively.

First using left hand side

Cos = Adj/Hypo

Cos22 = Adj/50

Adj = 50 * Cos 22

The adj = 50*0.9272

The adj = 46.4

The to find x, using

Cos 41 = 46.4/x

xCos41 =46.4

x = 46.4/Cos41

x = 46.4/.0755

Therefore the value of x = 61.5

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Rotate triangle △C'D'E' counterclockwise by approximately -0.785 radians about the origin:

[tex]x1' = 1 \times cos(-0.785) - (-4) \times sin(-0.785) \approx 0.436[/tex]

[tex]y1' = 1 \times sin(-0.785) + (-4) \times cos(-0.785) \approx -3.678[/tex]

[tex]x2' = -7 \times cos(-0.785) - 8[/tex]

The given point [tex]s C(2, -8), D(-6, 4),[/tex] and [tex]E(0, 4)[/tex] form the triangle △CDE, and the points U(1, -4), V(-3, 2), and W(0, 2) form the triangle △UVW, with △CDE being the preimage of △UVW.

To represent the transformation algebraically, we can use a combination of translations and rotations.

Translation:

To translate a point (x, y) by a vector (h, k), we add h to the x-coordinate and k to the y-coordinate of the point.

To transform triangle △CDE to triangle △UVW, we can first translate triangle △CDE by a vector (h, k) to obtain triangle △C'D'E', where C' = C + (h, k), D' = D + (h, k), and E' = E + (h, k).

Since the coordinates of C are (2, -8) and the coordinates of U are (1, -4), we can calculate the translation vector (h, k) as follows:

[tex]h = 1 - 2 = -1[/tex]

[tex]k = -4 - (-8) = 4[/tex]

So the translation vector is [tex](-1, 4).[/tex]

Rotation:

To rotate a point (x, y) by an angle θ counterclockwise about the origin, we use the following formulas:

[tex]x' = x \times \cos(\theta) - y times \sin(\theta)[/tex]

[tex]y' = x \times \sin(\theta) + y \times \cos(\theta)[/tex]

To transform triangle △C'D'E' to triangle △UVW, we can apply a rotation of angle θ counterclockwise about the origin to triangle △C'D'E', where C' = (x1', y1'), D' = (x2', y2'), and E' = (x3', y3'). Since the coordinates of C' are (2, -8) after translation, and the coordinates of U are (1, -4), we can calculate the rotation angle θ as follows:

[tex]\theta = atan2(y1' - y2', x1' - x2') - atan2(y1 - y2, x1 - x2)= atan2((-8 + 4) - (-4), (2 + 1) - (-6 + 3)) - atan2((-8) - (-4), 2 - (-6))[/tex]

Using a calculator, we can find θ to be approximately -0.785 radians.

So, the algebraic representation of the transformation that maps triangle [tex]\triangle CDE[/tex] to triangle [tex]\triangle UVW[/tex]  is:

Translate triangle △CDE by the vector (-1, 4) to obtain triangle △C'D'E':

[tex]C' = (2, -8) + (-1, 4) = (1, -4)[/tex]

[tex]D' = (-6, 4) + (-1, 4) = (-7, 8)[/tex]

[tex]E' = (0, 4) + (-1, 4) = (-1, 8)[/tex]

Therefore, Rotate triangle △C'D'E' counterclockwise by approximately -0.785 radians about the origin:

[tex]x1' = 1 \times cos(-0.785) - (-4) \times sin(-0.785) \approx 0.436[/tex]

[tex]y1' = 1 \times sin(-0.785) + (-4) \times cos(-0.785) \approx -3.678[/tex]

[tex]x2' = -7 \times cos(-0.785) - 8[/tex]

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By performing these statistical computations, you can analyze and interpret the central tendency of your dataset, which helps in understanding the overall pattern and distribution of the data.

It looks like you're seeking information on further statistical computation related to mean, mode, and median.

To calculate the mean, mode, and median of a dataset, follow these steps:

1. Mean: The mean is the average of all data points in a dataset.
  - Step 1: Add up all the data points.
  - Step 2: Divide the sum by the total number of data points.

2. Mode: The mode is the data point that occurs most frequently in a dataset.
  - Step 1: Count the frequency of each data point.
  - Step 2: Identify the data point(s) with the highest frequency.

3. Median: The median is the middle value in a dataset when the data points are arranged in ascending order.
  - Step 1: Arrange the data points in ascending order.
  - Step 2: If there is an odd number of data points, the median is the middle value. If there is an even number of data points, the median is the average of the two middle values.

By performing these statistical computations, you can analyze and interpret the central tendency of your dataset, which helps in understanding the overall pattern and distribution of the data.

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a. The most typical case is desired: Mode. The mode is a useful measure of central tendency when the most typical or common value is of relevance since it denotes the value or category that occurs most frequently in a data collection.

b. The distribution is open-ended: Median. The median is the middle value in a data set when arranged in ascending or descending order. It is a suitable measure of central tendency when the distribution is open-ended or skewed, as it is less affected by extreme values compared to the mean.

c. The data collection has an extreme value: the median. The median is less sensitive to extreme values compared to the mean, making it a better measure of central tendency in data sets with extreme values or outliers.

d. The data are categorical: Mode. The mode is appropriate for categorical data, as it represents the most frequently occurring category or value in the data set.

e. Further statistical computations will be needed: This statement does not indicate a specific measure of central tendency. Further statistical computations may be needed to determine the appropriate measure of central tendency depending on the characteristics of the data and the specific objectives of the analysis.

f. The numbers should be split into two roughly equal groups, one of which should contain the higher values and the other should contain the smaller values: Median.  The median is the value that separates a data set into two equal halves, making it suitable for dividing data into two approximately equal groups based on their values.

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COMPLETE QUESTION-

For these situations, state which measure of central tendency - mean, median, or mode-should be used.

a. The most typical case is desired.

b. The distribution is open-ended.

c. There is an extreme value in the data set.

d. The data are categorical.

e. Further statistical computations will be needed.

f. The values are to be divided into two approximately equal groups, one group containing the larger values and one containing the smaller values.

In the given triangle the 3 trigonometric ratios are:

(A) Sinθ = 3/5, (B) Cosθ = 4/5, and (Tanθ = 3/4)

The trigonometric functions in mathematics are real functions that connect the right-angled triangle's angle to the ratios of its two side lengths.

They are extensively employed in all fields of geometry-related study, including geodesy, solid mechanics, celestial mechanics, and many others.

In general, arcsine, arccosine, tangent, cotangent, secant, and cosecant functions are used to express the inverses of sine, cosine, tangent, cotangent, secant, and cosecant functions.

So, according to t the given triangle, the 3 trigonometric ratios would be:

Sinθ = B/H

Sinθ = 27/45

Sinθ = 3/5

Cosθ = P/H

Cosθ = 36/45

Cosθ = 4/5

Tanθ = B/P

Tanθ = 27/36

Tanθ = 3/4

Therefore, in the given triangle the 3 trigonometric ratios are:

(A) Sinθ = 3/5, (B) Cosθ = 4/5, and (Tanθ = 3/4)

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Answer:

C

Step-by-step explanation:

3x - 9y = 9 → (1)

- 2x +2y = 8 ( subtract 2y from both sides )

- 2x = - 2y + 8 ( divide through by - 2 )

x = y - 4

substitute x = y - 4 into (1)

3(y - 4) - 9y = 9

3y - 12 - 9y = 9

- 6y - 12 = 9 ( add 12 to both sides )

- 6y = 21 ( divide both sides by - 6 )

y = [tex]\frac{21}{-6}[/tex] = - [tex]\frac{7}{2}[/tex]

Step-by-step explanation:

hope this will help you Thanks

It will take John approximately 17 months to pay off the balance.

What is simple interest?

Simple Interest (S.I.) is the method of calculating the interest amount for a particular principal amount of money at some rate of interest.

Assuming that John does not use the credit card for any other purchases and that the credit card company uses a simple interest calculation method, we can use the following steps to calculate the number of months it will take John to pay off the balance:

Calculate the monthly interest rate by dividing the annual percentage rate (APR) by 12:

Monthly interest rate = 19% / 12 = 0.01583

Calculate the monthly finance charge by multiplying the outstanding balance by the monthly interest rate:

Monthly finance charge = $2000 x 0.01583 = $31.66

Subtract the monthly payment from the monthly finance charge to get the amount that will be applied to the outstanding balance:

Payment applied to balance = $150 - $31.66 = $118.34

Divide the outstanding balance by the payment applied to balance to get the number of months it will take to pay off the balance:

Number of months to pay off balance = $2000 / $118.34 = 16.9

(rounded up to the nearest whole number)

Therefore, it will take John approximately 17 months to pay off the balance.

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The cube roots of 216 written in the rectangular (standard) form are 3 + 3√3, -3+3√3, and 6.

In mathematics, the cube root formula is used to represent any number as its cube root, for example, any number x will have the cube root 3x = x1/3. For instance, 5 is the cube root of 125 as 5 5 5 equals 125.

3√216 = 3√(2x2x2)x(3x3x3)

= 2 x 3 = 6

the prime factors are represented as cubes by grouping them into pairs of three. As a result, the necessary number, which is 216's cube root, is 6.

Therefore, the cube roots of 216 are 3 + 3√3, -3+3√3, and 6.

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Since BC = 12 and AB = 16, segment BF must be 9, which is one-half of 16.

A triangle is a three-sided polygon that is one of the basic shapes in geometry. It is defined by three points that are connected by three line segments. Triangles have three angles, which add up to 180 degrees, and three sides, which add up to the sum of the lengths of the other two sides. The three sides of a triangle are typically referred to as the base, the height, and the hypotenuse. Triangles come in a variety of forms, from the equilateral triangle, which has three sides of equal length, to the isosceles triangle, which has two sides of equal length, to the scalene triangle, which has three sides of different lengths.

The correct answer is: Segment BF = 9. This can be proved true using the given theorem, since segment DE is parallel to segment BC and segment EF is parallel to AB. Therefore, since BC = 12 and AB = 16, segment BF must be 9, which is one-half of 16.

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Step-by-step explanation:

Again, using similar triangle ratios

7.2 m  is to 2.4 m  

     as   AB is to  12.0 m

7.2 / 2.4  = AB/12.0    Multiply both sides of the equation by 12

12 *   7.2 / 2.4   = AB = 36.0 meters

If $18,000 is invested at 5. 2% compounded then the full sum of the investment after 7 long years is roughly $24,810.89.

we are able to utilize the equation for compound intrigued:

A = P(1 + r/n)[tex]^{nt}[/tex]

where A is the entire sum of the venture after t a long time, P is the foremost speculation sum, r is the yearly intrigued rate as a decimal, n is the number of times the intrigued is compounded per year, and t is the number of a long time.

In this case, P = $18,000, r = 0.052 (since the intrigued rate is 5.2%), n = 1 (since the intrigued is compounded every year), and t = 7 (since we need to discover the full sum after 7 a long time). Substituting these values into the equation, we get: A = 18000(1 + 0.052/1)[tex]^{1*7}[/tex]

= 18000(1.052)[tex]^{7}[/tex]

= $24,810.89 (adjusted to the closest cent)

thus, the full sum of the venture after 7 a long time is roughly $24,810.89.

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The MAD of the hourly wages given would be $ 0.48. The range would be $ 2.00. Q1 would be $8.25. Q3 would then be $9.25. The IQR would be $1.00

Calculate the MAD:

First, find the mean of the data set:

mean = (sum of all values) / (number of values)

mean = (8.25 + 8.50 + 9.25 + 8.00 + 10.00 + 8.75 + 8.25 + 9.50 + 8.50 + 9.00) / 10

mean = 88.00 / 10 = 8.80

Then, find the mean of these absolute deviations:

MAD = (sum of absolute deviations) / (number of values)

MAD = (0.55 + 0.30 + 0.45 + 0.80 + 1.20 + 0.05 + 0.55 + 0.70 + 0.30 + 0.20) / 10

MAD = 4.10 / 10 = 0.41

Calculate the range:

range = maximum value - minimum value

range = 10.00 - 8.00 = 2.00

Find Q1 and Q3:

{8.00, 8.25, 8.25, 8.50, 8.50, 8.75, 9.00, 9.25, 9.50, 10.00}

Q1 is the median of the lower half, and Q3 is the median of the upper half.

Lower half: {8.00, 8.25, 8.25, 8.50, 8.50}

Upper half: {8.75, 9.00, 9.25, 9.50, 10.00}

Q1 = median of lower half = 8.25

Q3 = median of upper half = 9.25

Calculate the IQR:

IQR = Q3 - Q1

IQR = 9.25 - 8.25 = 1.00

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To compute the covariance matrix of the variables in the data, the "matrix-operation" which should be used is ([tex]X^{t}[/tex] × X)/n.

The "Covariance" matrix is defined as a symmetric and positive semi-definite, with the entries representing the covariance between pairs of variables in the data.

The "diagonal-entries" represent the variances of individual variables, and the off-diagonal entries represent the covariances between pairs of variables.

Step(1) : Compute the transpose of the centered data matrix X, denoted as [tex]X^{t}[/tex]. The "transpose" of a matrix is found by inter-changing its rows and columns.

Step(2) : Compute the "dot-product" of [tex]X^{t}[/tex] with itself, denoted as [tex]X^{t}[/tex] × X.

The dot product of two matrices is computed by multiplying corresponding entries of the matrices and summing them up.

Step(3) : Divide the result obtained in step(2) by the number of samples in the data, denoted as "n", to get the covariance matrix.

This step scales the sum of the products by 1/n, which is equivalent to taking the average.

So, the covariance matrix "C" of variables in "centered-data" matrix X can be expressed as: C = ([tex]X^{t}[/tex] × X)/n.

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The given question is incomplete, the complete question is

Let X be a matrix of centered data with a column for each field in the data and a row for each sample. Then, not including a scalar multiple, how can we use matrix operations to compute the covariance matrix of the variables in the data?

The size of the square to cut is 5/3 inches and the maximum volume of the box is 266.67 cubic inches.

To find the size of the square to cut and the maximum volume, we can follow these steps:

Let's call the length of each side of the square to be cut x inches. So the dimensions of the base of the box would be (16-2x) inches by (10-2x) inches.

The height of the box would be x inches since we are folding up the sides.

The volume of the box can be found by multiplying the length, width, and height: V = (16-2x)(10-2x)x.

To find the maximum volume, we can take the derivative of V with respect to x and set it equal to zero, since the maximum volume occurs at a critical point.

After taking the derivative and simplifying it, we get the equation 24x^2 - 520x + 1600 = 0.

Solving this quadratic equation, we get x = 5/3 or x = 20/3. Since x must be less than 5 (the length of the shorter side), the only feasible solution is x = 5/3 inches.

Plugging this value of x back into the equation for the volume, we get V = (16-2(5/3))(10-2(5/3))(5/3) = 266.67 cubic inches.

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We need approximately 12 servings of Designer Whey and 2 servings of Muscle Milk to obtain a 7-day supply that provides exactly 262 grams of protein and 54 grams of carbohydrates.

Let x be the number of servings of Designer Whey and y be the number of servings of Muscle Milk needed to obtain a 7-day supply that provides exactly 262 grams of protein and 54 grams of carbohydrates.

From the information given, we know that each serving of Designer Whey provides 20 grams of protein and 3 grams of carbohydrates, and each serving of Muscle Milk provides 16 grams of protein and 9 grams of carbohydrates.

Therefore, we can set up the following system of equations:

20x + 16y = 262

3x + 9y = 54

To solve for x and y, we can use any method of solving a system of equations. For example, we can use substitution:

From the second equation, we can solve for x in terms of y:

x = (54 - 9y)/3 = 18 - 3y

Substituting this into the first equation, we get:

20(18 - 3y) + 16y = 262

Simplifying, we get:

80y = 182

Solving for y, we get:

y = 2.275

Substituting this into the equation x = 18 - 3y, we get:

x = 12.175

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In the 8 Axioms, 4 and 6 axioms fails to holds and S is not a vector space. Rest of the axioms try to hold the vector space.

To demonstrate that S is not a vector space, we must demonstrate that at least one of the eight vector space axioms fails to hold. Let us examine each axiom in turn:

Therefore, axioms 4 and 6 fail to hold, and S is not a vector space.

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The correct question:

Let S be the set of all ordered pairs of real numbers. Define scalar multiplication and addition on S by α(x₁, x₂) = (αx₁, αx₂); (x₁, x₂) ⊕ (y₁, y₂) = (x₁ + y₁, 0). We use the symbol ⊕ to denote the addition operation for this system in order to avoid confusion with the usual addition x + y of row vectors. Show that S, together with the ordinary scalar multiplication and the addition operation ⊕, is not a vector space. Which of the eight axioms fail to hold?

Answer:

[tex]\large\boxed{\tt x \approx 95.6}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to solve for x by using \underline{Trigonometric Identities}.}[/tex]

[tex]\large\underline{\textsf{What are Trigonometric Identities?}}[/tex]

[tex]\boxed{\begin{minipage}{20 em} \\ \underline{\textsf{\large Trigonometric Identities;}} \\ \\ \textsf{Trigonometric Identities are trigonometric ratios determined with what's given in order to find a missing value. For a Right Triangle, the Trigonometric Identities are Sine, Cosine, and Tangent. These are used to find missing sides.} \\ \\ \tt Sine = \tt $ \tt \frac{Opposite}{Hypotenuse} \\ \\ Cosine = \frac{Adjacent}{Hypotenuse} \\ \\ Tangent = \frac{Opposite}{Adjacent} \end{minipage}}[/tex]

[tex]\textsf{We should determine whether Sine, Cosine, or Tangent will actually help us}[/tex]

[tex]\textsf{determine x. We are given a Right Triangle that has 1 15}^{\circ} \ \textsf{angle, and a side with}[/tex]

[tex]\textsf{a length of 99. Because this side is opposite of the right angle, this side is called}[/tex]

[tex]\textsf{the \underline{Hypotenuse}.}[/tex]

[tex]\textsf{The side labeled x is \underline{Adjacent}, which means that it's touching the given angle.}[/tex]

[tex]\textsf{Using what was given to us, we should use Cosine since we are asked for the}[/tex]

[tex]\textsf{Adjacent Angle when given the Hypotenuse.}[/tex]

[tex]\large\underline{\textsf{Solving;}}[/tex]

[tex]\textsf{Remember that;}[/tex]

[tex]\tt \cos(15^{\circ}) =\frac{Adjacent}{Hypotenuse}[/tex]

[tex]\textsf{We're given;}[/tex]

[tex]\tt \cos(15^{\circ}) =\frac{x}{99}[/tex]

[tex]\textsf{To find the value of x, we first should remove the fraction using cancellation.}[/tex]

[tex]\textsf{We are able to use the \underline{Multiplication Property of Equality} to prove that the}[/tex]

[tex]\textsf{equation remains equal.}[/tex]

[tex]\underline{\textsf{Multiply both expressions by 99;}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) =\not{99} \frac{x}{\not{99}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) =x[/tex]

[tex]\underline{\textsf{Evaluate;}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) \approx \boxed{\tt 95.6}[/tex]

[tex]\large\boxed{\tt x \approx 95.6}[/tex]