what is hummus in biology​

Answer:

Radio waves are able to penetate the earth's atmosphere due to their low frequency and long wavelength.

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Answer:19.6%

Explanation:

From K=0.693/t

0.693/20 =0.03465min^-1

But rate law is K =2.303/t log a/(a-x)

Substitute the value of k

0.03465=2.303/47 log a / (a-x)

Log a/ (a-x) = 0.7071

a/ (a-x) = 5.094

(a-x)/ a = 1/5.094 = 0.196

Percentage of reactants remaining after 47 minutes= 0.196× 100% = 19.6%

Answer:

Living things need nonliving things to survive. Without food, water, and air, living things die. Sunlight, shelter, and soil are also important for living things. ... Plants use water from the soil, carbon dioxide from the air, and energy from sunlight to make their own food.

Explanation:

Answer: yes they do here are is an example a tree depends on water to keep it hydrated.  

Explanation:

Answer:

0.2 mole

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 12.06×10²²

Number of mole =?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

12.06×10²² molecules = 12.06×10²² / 6.02×10²³

12.06×10²² molecules = 0.2 mole

Thus, 12.06×10²² molecules is equivalent to 0.2 mole

Answer:

grams O₂ = 134 grams

Explanation:

PV = nRT => n = PV/RT

P = 8.15atm

V = 12.2 Liters

R = 0.08206L·atm/mol·K

T = 16.0°C + 273 = 289K

n = (8.15atm)(12.2L)/(0.08206L·atm/mol·K)(289K) = 4.2 moles O₂

grams O₂ = 4.2 moles O₂ x 32g/mol = 134 grams O₂

The reaction enthalpy is the heat energy absorbed or evolved from a reaction. The enthalpy of reaction for the given reaction is -432 KJ.

Enthalpy is the heat energy evolved or absorbed by a reaction system. The reaction enthalpy can be negative or positive. A positive enthalpy means the heat is absorbed and a negative enthalpy means that the heat is evolved by the system.

The given two reactions 1 and 2 have to be reversed to get the net reaction as follows. Thus the positive enthalpy  of these reactions becomes negative when reversed.

[tex]2NO_{2} + 4 H_{2} \rightarrow N_{2} +4H_{2}O\\ -92 KJ\\ \\N_{2} + 3 H_{2} \rightarrow 2NH_{3} - -340 J[/tex]

Now, add these two reactions so that  we get the reaction of nitrogen dioxide and hydrogen to give water and ammonia and the enthalpies of the above reactions are also added.

Sum of enthalpies of above two reactions is the enthalpy of the required reaction written as follows:

[tex]2NO_{2} + 4 H_{2} \rightarrow N_{2} +4H_{2}O\\ -92 KJ\\ \\+\\ \\\\N_{2} + 3 H_{2} \rightarrow 2NH_{3} - -340 J\\\\\rightarrow NO_{2} + 7H_{2} \rightarrow 4H_{2}O + 2NH_{3}[/tex]

Enthalpy of net reaction = -92 + -340 = -432 KJ

Therefore, enthalpy of reaction for the given reaction is -432 KJ.

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Answer: 65.28 g of [tex]Al_2O_3[/tex] will be produced from 34.6 g of Al.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Al=\frac{34.6g}{27g/mol}=1.28moles[/tex]

The balanced chemical reaction is

[tex]4Al+3O_2\rightarrow 2Al_2O_3[/tex]  

According to stoichiometry :

4 moles of [tex]Al[/tex] produce =  2 moles of [tex]Al_2O_3[/tex]

Thus 1.28 moles of [tex]Al[/tex] produce=[tex]\frac{2}{4}\times 1.28=0.64moles[/tex]  of [tex]Al_2O_3[/tex]

Mass of [tex][tex]Al_2O_3[/tex]= [tex]moles\times {\text {Molar mass}}=0.64moles\times 102g/mol=65.28g[/tex]

Thus 65.28 g of [tex]Al_2O_3[/tex] will be produced from 34.6 g of Al.

Explanation:

If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.

- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B

Among these options, the correct formula for calcium phosphide is D. [tex]CaP_2[/tex]. Option D

The product formed from a reaction between calcium (Ca) and phosphorus (P) is calcium phosphide, which is represented by the chemical formula [tex]Ca_3P_2[/tex].

In the reaction between calcium and phosphorus, the calcium atom (Ca) donates two electrons to each phosphorus atom (P). This results in the formation of calcium ions (Ca2+) and phosphide ions (P3-). The ions combine to form the compound calcium phosphide ([tex]Ca_3P_2[/tex]).

The formula [tex]Ca_3P_2[/tex]indicates that three calcium atoms combine with two phosphorus atoms. The numerical subscripts are determined by the charges of the ions involved. Calcium, being a group 2 element, forms ions with a +2 charge (Ca2+), while phosphorus, being a group 15 element, forms ions with a -3 charge (P3-).

The product options provided are:

A. [tex]Ca_3P_2[/tex]

B. Cap

C. [tex]CazP_2[/tex]

D. [tex]CaP_2[/tex]

Among these options, the correct formula for calcium phosphide is D. [tex]CaP_2[/tex].

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Answer: Ca3P2

This is the answer!

Explanation:

A. Ca3P2

B. CaP2

C. Ca2P3

D. CaP

Answer:

C. One type of atom is oxidized and another is reduced

D. Electrons are transferred from one atom to another

Explanation:

just took the test, i hope this helps!!

have a nice day and take care of yourself!! :))

One type of atom is oxidized and another is reduced and  Electrons are transferred from one atom to another. Therefore, the correct options are options C,D.

Any chemical process in which a participating chemical species' oxidation number changes is known as an oxidation-reduction reaction, often known as a redox reaction. The phrase refers to a broad range of processes. Numerous oxidation-reduction processes are as frequent and well-known as fire, metal corrosion and disintegration, fruit browning, respiration, and photosynthesis—basic life processes.

The combined processes of oxidation and reduction are known as redox reactions due to their complimentary nature. The oxidising agent is the reactant that causes the oxidation, while the reducing agent itself reduces this reagent.  One type of atom is oxidized and another is reduced and  Electrons are transferred from one atom to another.

Therefore, the correct options are options C,D.

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Answer: Mechanical weathering

Explanation:

Mechanical weathering breaks rocks into smaller pieces

Answer:

Both the system and the surroundings are losing 260 J. The system is gaining 260 J, while the surroundings are losing 260 J. Both the system and the surroundings are gaining 260 J. The system is losing 260 J, while the surroundings are gaining 260 J. None of the above is true.

Hi there!

[tex]\large\boxed{4.04g}[/tex]

To solve, we can use dimensional analysis to convert from molecules to grams.

We must use Avogadro's number (6.02 × 10²³) in converting from molecules to moles.

After converting, multiply by the atomic mass, or grams per mole.

[tex]1.204 * 10^{24} moles *\frac{1 mol}{6.02*10^{23}moles}* \frac{2.02g}{1mol }= 4.04g[/tex]

Answer:

1:aerobic

2:anaerobic

3:aerobic

Answer:

Oxidizing Agent - Nitrogen

Reducing Agent - Hydrogen

Explanation:

The equation of the reaction is given as;

N2 + H2  -->  2 NH3

Oxidation Rules:

- The oxidation number of an element in it's free state is Zero. This means oxidation state of N2 and H2 are Zero.

- The oxidation number of a neutral compound is the sum of the oxidation state of the individual elements and is equal to zero.

- Oxidation Number of Hydrogen in a compound/Molecule is 1 except in hydrides where it is -1

This means that oxidation number of H in NH3 = 1

Oxidation state of N in NH3;

x + 3(1) = 0

x = -3

The reducing agent loses electrons. Loss of electrons is represented by increase in oxidation Number. The oxidation number of H increases from 0 to + 1

The Oxidizing agent gains electrons. Gain of electrons is represented by decrease in oxidation Number. The oxidation number of N decreases from 0 to -3

Answer:

Electrical energy

Explanation:

The wind Mill is an example of a device that converts wind energy into electrical energy

Answer:

Explanation:Reaction NaHCO3 + HCl ⇒ NaCl + H2O + CO2

Molar mass M = (22.99+1.008+ 12.01+3·16 ) g/mol. Calculate

Amount of substance n =m/M, n(NaCl) is equal.

M(NaCl) = 58.44 g/mol and mass m= n·M

Answer:

128.4 m

Explanation:

3.604m + 104.29m + 3.1m + 17.41m

Add all the values

= 128.404 m

The significant figure rule for addition is for the sum to have the same number of decimal places as the value with the least number of decimal places. In the addition sentence 3.604m + 104.29m + 3.1m + 17.41m, the value with the least number of decimal places is 3.1, which has 1 decimal place. Therefore, we round our sum so that it also has 1 decimal place.

128.404 m

= 128.4 m

I hope this helps!

Answer:

[PCl₅]  → 4.47×10⁻³ M

[PCl₃]  → 0.0897M

Explanation:

We state the equilibrium: PCl₅ (g) ⇄  PCl₃(g) + Cl₂(g)

Initially we have 0.4192 moles of  PCl₅ so during the reaction, x moles of it have been reacted. In conclussion after the equilibrium we may have x moles of PCl₃ and Cl₂. In order to find the final concentration, we use the Kc, but we need molar concentrations. That's why we divide all the values with the 4.5L, volume for the vessel. The expression for Kc is:

Kc = [PCl₃] . [Cl₂] / [PCl₅]

1.80 = (x/ 4.45) . (x/ 4.45) / ((0.4192-x) /4.45)

1.80 = (x² / 4.45²) / ((0.4192-x) /4.45)

1.80 = x² / 4.45 / (0.4192-x)

1.80 (0.4192-x) = x² / 4.45

1.80 (0.4192-x) . 4.45 - x² = 0

3.36 - 8.01x - x² = 0 → Quadractic

a = -1  b = -8.01  c = 3.36

(-b + √(b² - 4ac)) / (2a)

(-(-8.01) + √((-8.01)² - 4(-1)3.36)) / (2(-1) = 0.3995

[PCl₅] = (0.4192 - 0.3995) / 4.45L → 4.47×10⁻³ M

[PCl₃] = 0.3995 /4.45L → 0.0897M

Answer:

C₃H₃O₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 0.5242 g

Mass of CO₂ = 0.9740 g

Mass of H₂O = 0.1994 g

Empirical formula =?

Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:

For carbon, C:

Mass of CO₂ = 0.9740 g

Molar mass of CO₂ = 12 + (16×2)

= 12 + 32 = 44 g/mol

Mass of C = 12/44 × 0.9740

Mass of C = 0.2656 g

For hydrogen, H:

Mass of H₂O = 0.1994 g

Molar mass of H₂O = (2×1) + 16

= 2 + 16 = 18 g/mol

Mass of H = 2/18 × 0.1994

Mass of H = 0.0222 g

For oxygen, O:

Mass of compound = 0.5242 g

Mass of C = 0.2656 g

Mass of H = 0.0222 g

Mass of O =?

Mass of O = (Mass of compound) – (Mass of C + Mass of H)

Mass of O = 0.5242 – (0.2656 + 0.0222)

Mass of O = 0.5242 – 0.2878

Mass of O = 0.2364 g

Finally, we shall determine the empirical formula. This can be obtained as follow:

Mass of C = 0.2656 g

Mass of H = 0.0222 g

Mass of O = 0.2364 g

Divide by their molar mass

C = 0.2656 /12 = 0.0221

H = 0.0222 /1 = 0.0222

O = 0.2364 /16 = 0.0148

Divide by the smallest

C = 0.0221 / 0.0148 = 1.5

H = 0.0222 / 0.0148 = 1.5

O = 0.0148 / 0.0148 = 1

Multiply through by 2 to express in whole number.

C = 1.5 × 2 = 3

H = 1.5 × 2 = 3

O = 1 × 2 = 2

Empirical formula => C₃H₃O₂

Answer:

Explanation:

CH4 + 2O2 ---> CO2 + 2H2O

moles of methane = 62.8/16 = 3.92

by stotiometry,

3.92 = n

thus mass of co2 = moles× molar mass = 3.92 × ( 12 + 32)

Answer:C

Explanation:

It would be the most visually understandable.It would be easyer to understand what you are modeling.

Answer:

3.34 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

100 g × 1 mol/60.05 g = 1.67 mol

Step 3: Calculate the molarity of acetic acid

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

M = 1.67 mol/0.5000 L = 3.34 M

Answer:

aluminum nitrate

Explanation:

We already know that calcium carbonate is insoluble in water hence it will not even dissolve in the water.

Mercury(I) nitrate is soluble in water, when sodium sulfate (Na2SO4) is added to mercury(I) nitrate (Hg2(NO3)2), a pale yellow precipitate is formed.

Aluminum nitrate is soluble in water and reacts with Na2SO4(aq) solution according to the reaction, 2Al(NO3)3(aq)+3Na2SO4(aq) ---> Al2(SO4)3(s)+6NaNO3(aq). The precipitate, Al2(SO4)3(s) is a white crystalline hygroscopic solid.

Answer:

When solutions of sodium carbonate and hydrochloric acid are mixed, the equation for the hypothetical double displacement reaction is: Na2CO3 + 2 HCl → 2 NaCl + H2CO3 Bubbles of a colorless gas are evolved when these solutions are mixed.