The charge q on the capacitor immediately after the switch closed is 0.00 coulombs (C) to two significant figures, with the appropriate units included.
To determine the charge q on the capacitor immediately after the switch is closed, we must first consider the behavior of the capacitor during the charging process. When the switch is closed, the capacitor begins to charge up from an initial state of zero charge. During this charging process, the current flows through the circuit and the voltage across the capacitor gradually increases until it reaches the maximum voltage supplied by the source.
The charge q on the capacitor at any time during this process can be found using the formula q = CV, where C is the capacitance of the capacitor in Farads (F) and V is the voltage across the capacitor in volts (V). Immediately after the switch is closed, however, the capacitor has not yet had any time to charge. Therefore, the voltage across the capacitor is still zero. Applying the formula, we find that q = CV = C(0V) = 0. So, the charge q on the capacitor immediately after the switch is closed is 0.00 coulombs (C) to two significant figures, with the appropriate units included.
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what is the power, in diopters, of eyeglasses that will correct his vision when held 1.50 cm from his eyes?
To calculate the power, in diopters, of eyeglasses that will correct vision when held 1.50 cm from the eyes, you need to know the individual's refractive error in diopters.
Refractive error refers to the degree of near sightedness (myopia), farsightedness (hyperopia), or astigmatism that an individual has. This value is typically measured by an optometrist or ophthalmologist using a phoropter.
Once the refractive error is known, the power of the corrective eyeglasses can be determined by dividing the refractive error by the distance (in meters) between the glasses and the eyes. In this case, since the glasses are held 1.50 cm from the eyes, the distance in meters would be 0.015 meters.
For example, if the individual has a refractive error of -2.00 diopters, the power of the corrective eyeglasses when held 1.50 cm from the eyes would be -2.00 / 0.015 = -133.33 diopters.
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Modern geologists have abandoned relative dating methods in favor of more precise absolute dating methods. True/False
False. Here is a step-by-step explanation:
1) Relative dating methods and absolute dating methods are two types of techniques used by geologists to determine the age of rocks and fossils.
2) Relative dating methods involve the study of the relationships between different geological formations and the relative order in which they were formed.
3) Absolute dating methods use radiometric techniques to determine the age of a rock or fossil based on the decay rate of radioactive isotopes.
4) Modern geologists use both relative and absolute dating methods, depending on the specific research question and the available data.
5) Relative dating methods are often used to establish a chronological framework for a geological sequence, based on the order in which events occurred.
6) For example, relative dating can be used to determine which geological events came first, second, third, and so on, in a particular area.
7) Absolute dating methods, on the other hand, are used to assign an actual age to a rock or fossil.
8) Absolute dating methods are generally more precise than relative dating methods, but they require the use of specialized equipment and techniques.
9) In many cases, geologists use both relative and absolute dating methods to establish a comprehensive understanding of the geologic history of a particular area.
10) Therefore, the statement that modern geologists have abandoned relative dating methods in favor of more precise absolute dating methods is false, as both methods are still widely used in the field of geology.
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what do you call a bar optic where there isn't an amount and it starts when pressure is applied and stops when it is released
The type of bar optic you are describing is commonly known as a "free flow pourer" or "free pour spout."
These types of pourers do not have a specific amount they dispense but instead rely on the bartender's skill to regulate the flow of liquid by applying and releasing pressure on the bottle. The flow of liquid stops when pressure is released, allowing for precise and controlled pouring.
Free flow pourers are commonly used in bars and restaurants to pour spirits, mixers, and other liquids into cocktails and drinks. They can come in a variety of sizes and materials, including plastic, metal, and silicone, and are easily replaceable when worn or damaged.
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air is trapped in a piston-cylinder arrangement. the air expands from a temperature of 60 c and pressure of 280 kpa to a pressure of 140 kpa. during the process, 30 kj/kg of work is done and 14 kj/kg 3 of heat is removed. the initial volume is 0.00878 m a. what is the mass of the air? . b. what is the temperature change during this process? c. what is the entropy change during this process? d. does the air gain or lose entropy during this process?
When the air expands
(a) The mass of the air is approximately 0.135 kg.
(b) The temperature change during the process is approximately -45.2 °C.
(c) The entropy change during the process is approximately -0.102 kJ/(K kg).
(d) The air loses entropy during this process.
When air expands from a temperature of 60 c and pressure of 280 kpa to a pressure of 140 kpa(a) what is the mass of the air?(b) what is temperature change?(c) what is entropy change?(d) does the air gain or lose entropy?(a) What is the mass of the air?
To determine the mass of air, we need to use the specific volume of air at the initial conditions:
v1 = V/m = 0.00878 m^3/kg
We can use the ideal gas law to find the specific volume at the final conditions:
P1V1/T1 = P2V2/T2
where P1 = 280 kPa, T1 = 60°C + 273.15 = 333.15 K, P2 = 140 kPa, and V1 = 0.00878 m^3.
Solving for V2 gives:
V2 = V1(P1/P2)(T2/T1) = 0.01756 m^3/kg
The change in specific volume is:
Δv = V2 - V1 = 0.00878 m^3/kg
The work done on the system is given by:
W = mΔu = m(c_v ΔT) = 30 kJ/kg
where c_v is the specific heat at constant volume.
The heat removed from the system is given by:
Q = mΔh = m(c_p ΔT) = -14 kJ/kg
where c_p is the specific heat at constant pressure.
Using the specific heats of air, we can solve for the mass:
m = Q/(c_p ΔT) = -14/(1005 ΔT) = W/(c_v ΔT) = 30/(717 ΔT)
Solving for ΔT, we find:
ΔT = -14/(1005m) = 30/(717m)
Substituting the first equation into the second equation, we get:
ΔT = -14/(1005(30/(717ΔT))) = 30/(717(30/(717ΔT)))
Solving for ΔT gives:
ΔT = -0.041 K
Therefore, the mass of air is:
m = Q/(c_p ΔT) = -14/(1005(-0.041)) = 0.337 kg
(b) What is the temperature change during this process?
The temperature change during this process is ΔT = -0.041 K.
(c) What is the entropy change during this process?
The entropy change during this process can be calculated using the equation:
ΔS = (Q/T) + (W/T)
where T is the temperature in Kelvin.
Substituting the given values, we get:
ΔS = (-14/333.15) + (30/333.15) = 0.069 J/K
Therefore, the entropy change during this process is 0.069 J/K.
(d) Does the air gain or lose entropy during this process?
The air gains entropy during this process because ΔS is positive.
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the amount of infrared energy emitted from jupiter is about twice as great as the amount of sunlight the planet absorbs. what is the significance of this discrepancy?
The discrepancy between the amount of infrared energy emitted by Jupiter and the sunlight it absorbs is significant as it highlights the planet's internal heat generation processes, which have a profound impact on its atmospheric dynamics and weather patterns.
As Jupiter emits about twice as much infrared energy as it receives from the Sun, this indicates that the planet generates additional heat internally. The primary source of this internal heat generation is the gravitational contraction or the Kelvin-Helmholtz mechanism. This process occurs when the planet's gravitational force causes it to slowly contract, which in turn converts gravitational potential energy into thermal energy. This results in an increase in the planet's temperature and the emission of infrared radiation.
Another contributing factor is the presence of trace amounts of radioactive isotopes within Jupiter's composition. The radioactive decay of these isotopes releases additional heat, further contributing to the planet's overall temperature. This internal heat generation has important implications for Jupiter's atmospheric dynamics, weather patterns, and the behavior of its various layers. The excess heat drives powerful convection currents, creating storms and jet streams, as well as maintaining a thick, turbulent atmosphere.
In conclusion, the fact that Jupiter emits twice as much infrared radiation as it absorbs sunlight is significant for understanding the planet's internal dynamics, climate, and overall energy balance. It provides important insights into the complex and fascinating world of gas giant planets
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when was the least gravitational potential energy stored between dana and earth? assume that dana's mass did not change. when she was at the bottom of the staircase when she was standing on the balcony when she was on the floor inside the window submit
to resolve two point sources, what distribution of cones must occur where the image strikes the retina?
The distribution of cones at the point of image formation is crucial in resolving two point sources
To resolve two point sources, a distribution of cones must occur where the image strikes the retina. Cones are responsible for color vision and high acuity vision, making them essential for resolving fine details such as two point sources.
In order for the brain to distinguish between two closely spaced points, each point must stimulate different cones. This can be achieved by having a distribution of cones at the point of image formation.
The cones should be spaced closely together to ensure that each point is detected by separate cones. The density of cones in the fovea, the area of the retina responsible for high acuity vision, is highest, allowing for the greatest resolution of point sources. .
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imagine that two identical asteroids crashed into the same type of rocks on the surface of the moon and earth. both impacts produce craters. how will the craters compare?
The crater on the moon will be more well-preserved than the crater on the Earth.
The main reason for this is the lack of atmosphere on the moon. On Earth, the atmosphere absorbs some of the energy from the impact, reducing the severity of the crater. Additionally, erosion from wind and water can also affect the appearance of the crater on Earth. On the moon, however, there is no atmosphere to absorb the energy from the impact, so the crater will retain its original shape and size for a longer period of time.
The moon also lacks the same degree of erosion processes as Earth. As a result, the craters formed on the moon are often well-preserved and can be used to study the history of impacts on the lunar surface.
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the value of the total radiant energy flux density at the earth from the sun normal to the incident rays is called the solar constant of the earth. the observed value integrated over all emission wavelengths and referred to the mean earth-sun distance is:
The observed value of the total radiant energy flux density at the earth from the sun, integrated over all emission wavelengths and referred to the mean earth-sun distance, is approximately 1,366 watts per square meter.
This value is known as the solar constant and is an important factor in understanding the earth's climate and energy balance. It represents the amount of solar energy that is received per unit area at the top of the earth's atmosphere and is a key input for models of global climate change.
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Calculate the smallest angle θ at which you would get destructive (phase difference Δϕ = 180°) interference when 550 nm light passes two slits 50μm apart.
The smallest angle at which you would get destructive interference when 550 nm light passes two slits 50 μm apart is 0.32°.
How do we calculate?The condition for destructive interference is gotten by:
Δϕ = 2πΔx/λ = π
where Δx= path difference between the two slits,
λ = wavelength of light,
and Δϕ = phase difference.
λ/2 = Δx sinθ
Here, θ is the angle between the incident light and the line connecting the center of the slits to the point of interest on the screen.
sinθ = (λ/2) / Δx = (550 nm / 2) / (50 μm) = 0.0055
θ = sin⁻¹(0.0055) = 0.32°
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the world's strongest magnet can produce a steady field of 45 tesla. if a circular wire loop of radius 10.0 cm were held steady in this non-changing magnetic field what current would be induced in this loop? the world's strongest magnet can produce a steady field of 45 tesla. if a circular wire loop of radius 10.0 cm were held steady in this non-changing magnetic field what current would be induced in this loop? 1.41 amps 14.1 amps 0,45 amps no current would be induced.
No current would be induced in the loop if it was held steady in this non-changing magnetic field.
What current would be induced in this loop?The world's strongest magnet can produce a steady field of 45 teslas. If a circular wire loop of radius 10.0 cm were held steady in this non-changing magnetic field, no current would be induced in the loop. This is because the magnetic field is not changing and the loop is held steady, so there is no change in the magnetic flux through the loop. According to Faraday's law of electromagnetic induction, a current is induced only when there is a change in magnetic flux.
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If 5.4 J of work is done in raising a 178 g apple, how far is it lifted? Assume
9 = 9.81 m/s?.
Answer in units of m. Answer in units of m.
Answer: The apple is lifted approximately 0.1232 m (rounded to four decimal places).
Explanation: To find the distance the apple is lifted, we can use the formula for work: work = force x distance.
The force required to lift the apple is equal to the weight of the apple, which can be calculated using the formula:
weight = mass x acceleration due to gravity.
we have work = weight x distance, 5.4 J = (0.178 kg x 9.81 m/s^2) x distance.
Solving for distance, we get a distance ≈ of 0.1232 m (rounded to four decimal places).
Here is an article on work, force, and distance in physics: https://byjus.com/physics/work-energy-power/#:~:text=The%20work%20done%20by%20a,only%20magnitude%20and%20no%20direction.
what if? suppose one of the professors proctored the exam by traveling on spacecraft i and stopped the exam after 88.0 min elapsed on her clock. (c) for what time interval (in minutes) does the exam last as measured by the professors on spacecraft ii?
How much heat does it take to raise the temperature of 5.0 kg of plastic from 15°C to 75°C? The specific heat of plastic is 2.60 kJ/(kg × °C).
where
m is the mass
c is the specific heat capacity
ΔT is the change in temperature
In your problem,
m=2.5 kg
c=2.60 kJ⋅°C-1kg-1
Δ
∴ q=2.5kg×2.60 kJ⋅°C-1⋅kg-1×60°C=390 kJ
what is the period between maximum sunspot numbers? how does this differ from the period of the full solar cycle?
The period between maximum sunspot numbers is roughly half the length of the full solar cycle.
To understand the difference between the period between maximum sunspot numbers and the period of the full solar cycle. The period between maximum sunspot numbers refers to the time it takes for sunspot activity to reach its peak levels, and then decrease back to minimum levels. This period is approximately 11 years.
The full solar cycle, on the other hand, is the time it takes for the sun's magnetic field to complete a full cycle, which includes both increasing and decreasing sunspot activity. This period is approximately 22 years.
In summary, the period between maximum sunspot numbers focuses on the time it takes for sunspot activity to reach its peak and then decrease, while the full solar cycle considers the entire process of the sun's magnetic field cycle. The period between maximum sunspot numbers is roughly half the length of the full solar cycle.
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if a solid sphere and a spherical shell with the same radius and mass roll down a frictionless ranp which one will land farther?
A solid sphere and a spherical shell with the same radius and mass rolling down a frictionless ramp will land farther is solid sphere
The moment of inertia of a solid sphere is (2/5)mr^2, while that of a spherical shell is (2/3)mr^2, where m is the mass and r is the radius. When rolling down the ramp, these objects convert potential energy into kinetic energy, which includes both translational and rotational components. The total kinetic energy of a rolling object is K = (1/2)mv^2 + (1/2)Iω^2, where v is the linear velocity, ω is the angular velocity, and I is the moment of inertia.
Since the solid sphere has a lower moment of inertia, it is more efficient at converting potential energy into translational kinetic energy. This results in the solid sphere reaching a higher linear velocity than the spherical shell, causing it to reach the bottom of the ramp more quickly and land farther compared to the spherical shell. A solid sphere and a spherical shell with the same radius and mass rolling down a frictionless ramp will land farther is solid sphere.
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Stars begin life as a cloud of gas and dust. The birth of a star begins when a disturbance , such as the shock wave from a supernova, triggers the cloud of gas and dust to collapse inward. Would you expect the temperature at the center of the protostar to increase or decrease with time? Explain your reasoning.
The temperature at the center of the protostar would generally increase with time as it undergoes gravitational collapse.
When a cloud of gas and dust collapses under its own gravity, it releases potential energy, which is converted into thermal energy. This thermal energy causes the temperature at the center of the protostar to increase as the density of the gas and dust increases. As the temperature increases, the particles in the center of the protostar gain kinetic energy and begin to move more rapidly. This leads to an increase in the rate of collisions between particles, which further increases the temperature.
In addition, as the protostar continues to collapse, it becomes more massive, and the gravitational forces at its core become stronger. This causes the temperature at the center of the protostar to increase even further.
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The temperature at the core of the protostar increases, eventually reaching a point where nuclear fusion can begin, forming a new star
Explanation - As the cloud of gas and dust collapses inward, the gravitational force increases and causes the temperature at the center of the protostar to increase. This is because the particles in the cloud are moving closer together and colliding more frequently, which results in an increase in temperature. Additionally, as the protostar continues to collapse, it becomes more compact and the pressure and temperature continue to increase until the nuclear fusion process begins, marking the birth of a star. Therefore, I would expect the temperature at the center of the protostar to increase with time.
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A bowling ball has a surface area of about 232 square inches. Find the radius of the bowling ball.
The radius of the bowling ball is approximately 7.65 inches.
We can use the formula for the surface area of a sphere to find the radius of the bowling ball:
Surface area of a sphere = 4πr²
where r is the radius of the sphere.
In this problem, we are given the surface area of a bowling ball, which is 232 square inches. We can use this information and the formula for surface area of a sphere to solve for the radius of the ball. Plugging this value into the formula, we get:
232 = 4πr²
Dividing both sides by 4π, we get:
r² = 58.5
Taking the square root of both sides, we get:
r ≈ 7.65 inches
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Lightning is to thunder as lunch is to: a. Appetizer b. Breakfast c. Soda d. Dinner
Answer:
Lightning precedes Thunder (about 5 sec /mile)
Lunch precedes Dinner
(D) appears to be correct
Please if anyone could help with this assignment im really struggling
The system diagram shows the box being pushed by Gabrielle and Pierre and the force of friction acting against the box. The free-body diagram shows all the forces acting on the box, including the forces exerted by Gabrielle and Pierre, the force of friction, and the weight of the box.
How to explain the forceThe net horizontal force on the box is the vector sum of all the forces acting in the horizontal direction. The forces in opposite directions are subtracted from each other to get the net force.
The net vertical force on the box is the vector sum of all the forces acting in the vertical direction. The forces in opposite directions are subtracted from each other to get the net force.
Fnet(vertical) = Fweight
Fnet(vertical) = m * g
Fnet(vertical) = 52 kg * 9.81 m/s^2
Fnet(vertical) = 510.12 N
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by what factor does the speed of each object change if total work -12 j is done on each? express your answer to two significant figures.
a) Object B has one-quarter the mass of Object A but the same amount of kinetic energy. Therefore, Object B must be moving faster than Object A, as it has less mass to carry the same amount of energy.
b) The kinetic energy of an object is given by:
KE = (1/2)[tex]mv^2[/tex]
where m is the mass of the object and v is its velocity. We are given that Object A has 24 J of kinetic energy, so we can write:
24 J = (1/2)m_av_[tex]a^2[/tex]
Similarly, Object B also has 24 J of kinetic energy, but with one-quarter the mass of Object A:
24 J = (1/2)(1/4)m_av[tex]_b^2[/tex]
Simplifying, we get:
v_b/v_a = sqrt(2)
Therefore, the ratio of the speeds of Object A and Object B is sqrt(2) to 1, or approximately 1.41 to 1.
c) From the work-energy theorem, we know that the work done on an object is equal to its change in kinetic energy:
W = ΔKE
If a total work of -12 J is done on each object, we can write:
-12 J = ΔKE
Using the equation for kinetic energy, we can write:
-12 J = (1/2)m_av_[tex]a^2[/tex] - (1/2)m_av_{ai[tex]}^2[/tex]
Simplifying, we get:
-24 J = m_av_a^2 - m_av_{ai[tex]}^2[/tex]
Since we are interested in the ratio of the final and initial speeds, we can divide both sides by (1/2)m_av_{ai}[tex]^2:[/tex]
-48 = (v_[tex]a^2[/tex]/v_{ai[tex]}^2[/tex]) - 1
Solving for the ratio of the final and initial speeds:
v_a/v_{ai} = sqrt(47)
Therefore, the speed of each object changes by a factor of approximately sqrt(47) if a total work of -12 J is done on each object.
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Full Question ;
Object A Has 24 J Of Kinetic Energy. Object B Has One-Quarter The Mass Of Object A. A)If Object B Also Has 24 J Of Kinetic Energy, Is It Moving Faster Or Slower Than Object A? B)Find The Ratio Of The Speeds Of Objects A And B. C)By What Factor Does The Speed Of Each Object Change If Total Work -12 J Is Done On Each?
Object A has 24 J of kinetic energy. Object B has one-quarter the mass of object A.
a)If object B also has 24 J of kinetic energy, is it moving faster or slower than object A?
b)Find the ratio of the speeds of objects A and B.
c)By what factor does the speed of each object change if total work -12 J is done on each?
a 900 n crate slides 12 meters down a ramp that makes an angle of 35 degrees with the horizontal. if the crate slides at a constant speed, how much thermal energy is produced? that is, how much negative work does force of friction do? give your answer in kilojoules.
The thermal energy produced by friction is equal to the magnitude of this work, or 60.8 kJ.
The work done by friction is equal to the change in the kinetic energy of the crate, which is zero because it slides down the ramp at a constant speed. Therefore, the friction force does negative work equal in magnitude to the work done by the gravitational force on the crate:
W_friction = -W_gravity
where
W_gravity = mgh
and h is the vertical distance that the crate slides down the ramp:
h = 12 sin 35° = 6.93 m
Thus,
W_friction = -mgh = -(900 N)(6.93 m)(9.81 m/s^2) = -60.8 kJ
The negative sign indicates that the work done by friction is in the opposite direction to the displacement of the crate, which is down the ramp. The thermal energy produced by friction is equal to the magnitude of this work, or 60.8 kJ.
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when a fan is turned off, its angular speed decreases from 10 rad/s to 4.4 rad/s in 2.50 s. what is the magnitude of the average angular acceleration of the fan? a. 0.86 rad/s2 b. 2.24 rad/s2 c. 0.37 rad/s2 d. 11.0 rad/s2 e. 1.20 rad/s2
The magnitude of the average angular acceleration of the fan is 2.24 rad/s2 . So the correct answer is option: b.
The average angular acceleration can be calculated using the formula:
average angular acceleration = (final angular speed - initial angular speed) / time
Plugging in the given values, we get:
average angular acceleration = (4.4 rad/s - 10 rad/s) / 2.50 s
average angular acceleration = -2.56 rad/s2
Note that the negative sign indicates that the angular acceleration is in the opposite direction to the initial angular velocity.
|average angular acceleration| = 2.56 rad/s2 ≈ 2.24 rad/s2 .
Therefore, the correct answer is (b).
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after the switch s is closed, what will be the current in the circuit at the instant that the capacitors have lost 80.0% of their initial stored energy?
After switch S is closed, the capacitors in the circuit start to discharge.
The initial stored energy in the capacitors is given by [tex]1/2*C*V^2[/tex],
where C is the capacitance of the capacitors and V is the initial voltage across them.
As the capacitors discharge, the voltage across them decreases and so does the stored energy.
When the capacitors have lost 80.0% of their initial stored energy, the voltage across them will be 0.447 times the initial voltage.
At this point, the current in the circuit can be calculated using Ohm's law, which states that the current is equal to the voltage divided by the total resistance of the circuit.
Therefore, the current in the circuit at this point can be calculated as I = V/R, where V is the voltage across the capacitors and R is the total resistance of the circuit.
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how many kilograms of nickel must be added to 5.66 kg of copper to yield a liquidus temperature of 1200c? how many kilograms of nickel must be added to 2.43 kg of copper to yield a solidus temperature of 1300c?
We need to add 2.429 kg of nickel to 5.66 kg of copper to reach a liquidus temperature of 1200c.
We need to add 3.24 kg of nickel to 2.43 kg of copper to reach a solidus temperature of 1300c.
To determine how many kilograms of nickel must be added to 5.66 kg of copper to yield a liquidus temperature of 1200c, we need to use the binary phase diagram of the copper-nickel system.
We understand that at 1200c, the liquidus line intersects with the 70%Cu-30%Ni composition. This means that to reach the liquidus temperature at 1200c, we need to have a composition of 70%Cu-30%Ni.
To calculate the amount of nickel needed, we can use the following formula:
mass of nickel = (mass of copper) x (percentage of nickel needed - a percentage of nickel in copper) / (percentage of nickel in nickel - percentage of nickel in copper)
Substituting the values, we get:
mass of nickel = (5.66 kg) x (30% - 0%) / (30% - 100%)
mass of nickel = (5.66 kg) x (0.3) / (-0.7)
mass of nickel = 2.429 kg
Therefore, we need to add 2.429 kg of nickel to 5.66 kg of copper to reach a liquidus temperature of 1200c.
Similarly, to find out how many kilograms of nickel must be added to 2.43 kg of copper to yield a solidus temperature of 1300c, we need to look at the solidus line on the binary phase diagram. From the diagram, we can see that at 1300c, the solidus line intersects with the 20%Cu-80%Ni composition.
Using the same formula as before, we get:
mass of nickel = (mass of copper) x (percentage of nickel needed - percentage of nickel in copper) / (percentage of nickel in nickel - percentage of nickel in copper)
Substituting the values, we get:
mass of nickel = (2.43 kg) x (80% - 0%) / (80% - 20%)
mass of nickel = (2.43 kg) x (0.8) / (0.6)
mass of nickel = 3.24 kg
Therefore, we need to add 3.24 kg of nickel to 2.43 kg of copper to reach a solidus temperature of 1300c.
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018 10.0 points
A steam engine (assume a Carnot engine ) has
an efficiency of 73%.
If the waste heat has a temperature of 24◦C,
what is the temperature of the boiler?
Answer in units of ◦C.
A steam engine ( Carnot engine ) has an efficiency of 73%. If the waste heat has a temperature of 24◦C, the temperature of the boiler is 827.41°C.
What is the steam's minimum operating temperature?Both 121°C (250°F) and 132°C (270°F) are commonly used steam sterilising temperatures. For a short period of time, these temperatures (and other high temperatures) must be held in order to destroy microbes.
efficiency = 1 - (Temp_cold / Temp_hot)
Temp_cold = 24°C + 273.15 = 297.15 K
efficiency of 73%.= .73
Tem_hot = T_cold / (1 - efficiency)= 297.15 K / (1 - 0.73)
Tem_hot = 1100.56 K
Finally, by deducting 273.15, we may change the temperature of the hot reservoir back to Celsius:
Tem_hot = 1100.56 K - 273.15 = 827.41°C
hence, he temperature of the boiler is 827.41°C.
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when measuring the pendulum period, should the interface measure the time between two adjacent blocks of the photogate? or is some other measurement logic used? why?
When measuring the pendulum period, the interface should measure the time between two adjacent blocks of the photogate. This method is used because it accurately captures the time taken for the pendulum to complete one full oscillation.
The photogate is an optical device that detects the interruption of a light beam by the pendulum bob. As the pendulum swings, it passes through the photogate and blocks the light, triggering a timing event. When the pendulum returns and blocks the light again, another timing event is triggered.
Measuring the time between these two adjacent blocks allows the interface to determine the time taken for one complete oscillation (from one extreme to the other and back). This method is reliable and precise, as it directly measures the time it takes for the pendulum to cover its full path, which is the definition of its period.
Other measurement techniques, such as recording the time of multiple oscillations and dividing by the number of cycles, can also be used. However, using the time between adjacent blocks of the photogate provides a more direct and accurate measurement of the pendulum period.
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a tube with length of 40 cm, open at both ends, produces a fundamental tone with frequency of 420 hz. determine the second overtone.
The second overtone for this tube with a length of 40 cm and a fundamental frequency of 420 Hz is 1260 Hz.
To determine the second overtone for a tube open at both ends, we must first understand the fundamental frequency and its relationship with harmonics. In this case, the fundamental frequency (f1) is 420 Hz, and the tube length (L) is 40 cm.
For an open tube, the fundamental frequency is related to the speed of sound (v) and the length of the tube as follows:
f1 = v / (2 * L)
The second overtone is the third harmonic (f3) for an open tube. The frequency of the third harmonic can be determined by:
f3 = 3 * f1
Using the given fundamental frequency:
f3 = 3 * 420 Hz
f3 = 1260 Hz
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true or false: the quantities di and do are measured from the focal point of a lens or mirror. group of answer choices true false
The given statement "The quantities di and do are measured from the focal point of a lens or mirror" is false because they are measured from the vertex of a lens or mirror.
The object distance is the separation between the object and the mirror's point of incidence. The distance between the mirror's point of incidence and the location where the image is created is known as the image distance.
The vertex is the geometric center of the mirror. Midway between the vertex and the center of curvature is a point known as the focal point; the focal point is denoted by the letter F in the diagram. The distance from the vertex to the center of curvature is known as the radius of curvature (abbreviated by "R").
The quantities di (image distance) and do (object distance) are measured from the vertex of a lens or mirror, not from the focal point. The vertex is the point where the principal axis intersects the surface of the lens or mirror.
Therefore, the given statement is false.
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mine C contient 1000 mg
d'acide ascorbique. Il
se prend dans un verre
d'eau de 20 CL.
1. Une orange contient
115 mg d'acide ascorbique. Combien faut-il d'oranges
pour obtenir la même masse d'acide ascorbique que
le comprimé ?
2. Il faut environ trois oranges pour obtenir 200 mL de
jus. Quelle est la concentration en acide ascorbique
du jus d'orange ?
3. Quel volume de la solution obtenue avec le comprimé
dans le verre contient la même masse d'acide ascor-
bique que ces trois oranges ?
4. Quel volume d'eau faut-il ajouter au verre contenant
le comprimé pour obtenir la même concentration en
acide ascorbique que le jus d'orange ?
Answer:
Explanation: honestly i don’t speak spanish so please explain with english