Answer:
The magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.
Explanation:
Given;
magnitude of the charge, q = 4 mC = 4 x 10⁻³ C
distance of the charge, r = 3 cm = 0.03 m
The magnitude of the electric field is calculated as follows;
[tex]E = \frac{F}{q} = \frac{Kq}{r^2} \\\\[/tex]
where;
K is Coulomb's constant, = 9 x 10⁹ Nm²/C²
[tex]E = \frac{Kq}{r^2}\\\\E = \frac{(9\times 10^9)(4 \times 10^{-3})}{0.03^2} \\\\E = 4 \times 10^{10} \ N/C[/tex]
Therefore, the magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.
1. A 2,000-turn solenoid is 65 cm long and has cross-sectional area 30 cm2. What rate of change of current will produce a 600 Volts emf in this solenoid.
Answer:
[tex]\frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]
Explanation:
First, we will calculate the inductance of the solenoid by using the following formula:
[tex]L = \frac{\mu_o AN^2}{l}[/tex]
where,
L = self-inductance of solenoid = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
A = Cross-sectional area = 30 cm² = 3 x 10⁻³ m²
N = No. of turns = 2000
l = length = 65 cm = 0.65 m
Therefore,
[tex]L = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(3\ x\ 10^{-3}\ m^2)(2000)^2}{0.65\ m}\\\\L = 0.0232\ H[/tex]
Now, we will use Faraday's law to calculate the rate of change of current:
[tex]emf = L\frac{dI}{dt}\\\\ \frac{dI}{dt} =\frac{emf}{L} \\\\ \frac{dI}{dt} =\frac{600\ V}{0.0232\ H}\\\\ \frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]
A truck with a mass of 1520 kg and moving with a speed of 16.0 m/s rear-ends a 663 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second. vcar
Answer:
Speed of truck after collision = 6.28 m/s
Speed of car after collision = 22.28 m/s
Explanation:
By law of conservation of momentum
momentum before collision = momentum after collision
[tex]m_1u_1+m_2u_2 = m_1v_1+m_2v_2\\plugging/values\\1520\times16+ 0= 1520\times v_1 + 663\times v_2\\24320= 1520v_1+663v_2[/tex]
Since, collision is elastic
[tex]16 = v_2-v_1///v_2 = v_1+16 ....(b)[/tex]
solving the above two equations we get
v_1 = 6.28 m/s and v_2 = 22.28 m/s
Speed of truck after collision = 6.28 m/s
Speed of car after collision = 22.28 m/s
its un1) It is unofficial, but a strong rumor that the world will end in two years' time due to the arrival of a huge comet and its subsequent impact with Earth. You have two years to live, to get the most out of life. How would you react? What would you do? Discuss.
Answer:
I'll try my utmost best to get the most out of life...I'd do the things have always wanted to do
Sometimes it might get to me knowing fully well that in two years time the world will end but i will shake it off because the time i spend thinking about it...It will be enough to make some memories.
Hope this help anyways
if 36C ofcharge pass through a write in 4s current is it carrying?
Answer:
The current flowing through the wire is 9 A.
Explanation:
Given;
quantity of charge passing through the wire, Q = 36 C
duration of the charge flow, t = 4 s
The current flowing through the wire is calculated as;
Q = It
I = Q / t
where;
I is the current flowing in the wire
I = 36/4
I = 9 A
Therefore, the current flowing through the wire is 9 A.
A 4.50-kg centrifuge takes 200 s to spin up from rest to its final angular speed with constant angular acceleration. A point P located 10.0 cm from the axis of rotation of the centrifuge moves with a speed of 150 m/s when the centrifuge is at full(final) speed. a) [4 points] What was its final angular speed
Answer:
Explanation:
ω = v / R
where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .
Given v = 150 m/s ; R =.10 m
ω = 150 / .10
= 1500 radian /s .
Final angular speed is 1500 radian /s .
1. A ford engine is provided with 80,000 W power by burning its fuel. The engine produces a kinetic energy of 96 kJ for 20 seconds before its cut out.
a. Calculate the output power by the engine in watts.
b. What is the efficiency of the engine?
c. Why is there a considerable difference in the power input and output?
Answer: a) 4800 W b) 6 % c) most of the energy of fuel is converted to heat in combustion engine
Explanation: a) Power P = W/t = 96 000 J / 20 s = 4800 W
b) efficiency η = P(putput) / P(intake) = 4800 W / 80000 W = 0,06
A torsional pendulum has a centroidal mass moment of inertia of 0.40 kg·m2 and when given an initial twist and released is found to have a frequency of oscillation of 200 rpm. Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm, determine the damping constant for the oil. The damping constant for the oil is
Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm,0.00246914 come to the damping of the constant for the oil
what is frequency ?
The frequency can be defined as the number of oscillation per unit time which is used for defining the cyclic process like rotation, oscillation, wave etc.
The SI unit of the frequency is denoted as Hertz and the symbol λ represents it where one hertz means the wave completed one cycle in one second.
The frequency which explains the phenomenon of oscillatory and vibration like the mechanical vibration, sound signals, light, frequency waves etc. The “period” represented as the time required by the wave for one oscillation, i.e., it is inversely proportional to the frequency.
If the flashes, then the period is the time between the two flashes. And the frequency is the total number of flashes per second.
For more details regarding frequency, visit
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how are force and motion related
Just a thought
If you had let’s say two pieces of glass one being much more rudder than the other, and you try to break the tougher glass with the other piece
Example: throwing a glass ball at a glass door
Question: is it possible to break a tougher piece of glass with a weaker piece of glass ?
Suspicion: I’m guessing at high speeds it’s possible but I’m not sure anyone care to put their input ?
Answer:
Explanation:
THE FOURTEEN WEEKS' COURSES
IN
NATURAL SCIENCE,
BY
J. DORMAN STEELE, A.M., PHI.D.
Fourteen Weeks iq Natural Philosophy,
Fourteen Weeks iq Ctlenqistry,
Fourteen Weeks iq Descriptive Astroqonqy,
Fourteel Weeks iq Popular Geology,
Fourteeq Weeks iQ2 Human P1ysiology,
Fourteen Weeks iq Zoology,
Fourteeq Weeks iq Botany,
A Key, containing Answers to the Questions
and Problems in Steele's I4 Weeks' Courses,
4 1ISTORIC4L SERIES,
ON THE PLAN OF STEELE'S 14 WEEKS IN THE SCIENCES.
A Brief History of the Urlited States,
A Brief History of France,
The same publishers also offer the following standard scientific
vworks, being more extended or difficult treatises than those of
Prof. Steele, though still of Academic grade.
Peck's Ganot's Natural Philosophy,
Porter's Principles of Chemistry,
Jarvis' Physiology and Laws of Healtl,
Wood's Botanist and Florist,
Clanlbers' Elenments of Zoology,
lcIqtyre's Astroqomy and tle Globes,
Page's. Elen~ents of Geology,
Entered according to Act of Congress, in the year 1869, by
A. S. BARNES & CO.,
In the Clerk's Office of the District Court of the United States
for the Southern District of New York.
sTERLE'S KEY.
A ball has a mass of 0.046kg. Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.
The mass of a ball is 0.046kg. The ball is released. Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s
Answer:
PE=0.92414J and KE=0.28175J
Explanation:
Gravitational potential energy=mass*gravity*height
PE=mgh
Data,
M=0.046kg
H=2.05m
g=9.8m/s^2
PE=0.046kg * 9.8m/s^2 * 2.05m
PE =0.92414J
KE=1/2mv^2
M=0.046kg
V=3.5m/s
KE=[(0.046kg)*(3.5m/s)^2]\2
KE=0.28175J
How many significant figures are in the number 54,100?
Answer:
3
Explanation:
what makes molecules move. A. covection. B. Radiation. C. Thermal or heat. D. conduction.
Answer:
the answer is C
Explanation:
सत्मार्ग र शान्तिले नै समाजलाई सभ्य बनाउँछ भन्ने विषयमा ५० शब्दसम्मको एउटा अनुच्छेद
लेख्नुहोस्।
Answer:
So you have a question
Explanation:
either way have a nice day
The Hall effect is to be used to find the sign of charge carriers in a semiconductor sample. The probe is placed between the poles of a magnet so that magnetic field is pointed up. A current is passed through a rectangular sample placed horizontally. As current is passed through the sample in the east direction, the north side of the sample is found to be at a higher potential than the south side. Make a sketch of the situation, then decide if the number density of charge carriers is positively or negatively charged.
Answer:
the sign of these carriers is POSITIVE
Explanation:
In the effect, he found the charge carriers that were subjected to two forces, one electric and the other magnetic.
F = F_e + F_m = q E + q v x B
bold indicates vectors
The electric field goes to the east, therefore the current also has this direction, the vector product of the velocity of the charge carriers towards the east and the magnetic field upwards, using the right hand rule a magnetic force is created towards the north if the carriers are positive.
In the exercise they indicate that the north side has a higher potential than the south side, therefore there must be an accumulation of carriers on this side that create an electric field (Hall) that is put to the magnetic force until reaching equilibrium when the total force is zero.
Therefore the sign of these carriers is POSITIVE
. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. The first vehicle collides with a concrete barrier, and stops in a time of approximately 0.1 s. The second vehicle collides with a collapsible barrier, and comes to rest in about 1 second. Which object is subject to a larger force
Answer:
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
Explanation:
For this exercise let's use the relationship between momentum and momentum.
I = F t = Δp
in this case the final velocity is zero
F t = 0 -m v₀
F = m v₀ / t
in order to answer the question we must assume that the two vehicles have the same mass and speed
concrete barrier
F₁ = -p₀ / 0.1
F₁ = - 10 p₀
barrier collapses
F₂ = -p₀ / 1
let's look for the relationship of the forces
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
A 10kg block is Pulled along a horizontal
Surfact by a fores of son at an ansie
of 37° with the horizontal If the
coefficient of sliding friction 6/n the
block ound the surface is 0.2
(8-10 mis? Sin 37=016 and cos 37.2008)
of what frictional for acting on the block
b what is the acceleration of the block?
Answer:
Explanation:
I hate these kinds of problems, luckily I can't understand how much the kinetic friction is for this , the words are all mixed around. and don't read well. Maybe this went through a translator program? My suggestion draw the free body diagram. so you can see where the forces are, and how they are acting. getting the free body diagram right.. usually makes these problems pretty straight forward. just do the steps and you get the answer.
Answer:
I cant understand the question well but i will tell u how to solve it
first apply f = ma eqaulation vertically...then u will get an r = mg which means normal upward force = weight of the object (to find weight multiply mass by 9.81)
[tex]f = ma \\ r - mg = 0 \\ r = mg[/tex]
after that use friction eqaution which is
[tex]f = \mu \times r [/tex]
(mu) is the coefficient of friction and (r) is the vertical normal force then by substituting value you can get an answer for the friction
the use
[tex]f = ma \\ f \cos(37) - fr = ma[/tex]
by using the above eqaution you can get an answer for acceleration...
hope you can understand...
A pair of slits, separated by 0.150 mm, are illuminated by light with a wavelength of 643 nm. An interference pattern is observed on a screen at 140 cm from the slits. Consider a point seen on the screen that is located 1.80 cm to the right of the central bright fringe. Will the point be a minimum (destructive) point, a maximum (constructive) point or somewhere in between
Answer:
Explanation:
slit separation d = .15 mm
screen distance D = 1.4 m
wavelength of light used λ= 643 x 10⁻⁹ m
position of n th bright fringe x
x = n x λ D / d
1.8 x 10⁻² = n x 643 x 10⁻⁹ x 1.4 / .15 x 10⁻³
1.8 x 10⁻² = n x 6 x 10⁻³
n = 3
So 3 rd bright fringe will be formed at a point 1.8 cm from the central bright fringe .
When we experience positive "g forces", it is as if we have become...
Answer:
heavier
Explanation:
A Ring, a solid Cylinder and a solid sphere all having the same mass and the Same radius are held at the top of an inclined plane if the objects are roll without slipping and the (see the picture)between each object and the plane is 0.3 if they are released from an incloed plane at the same time which wal bee reach the bottom first?
Answer:
Since they all have the same mass and radius they all experience the same amount of torque.
Torque = moment of inertia * angular acceleration
The one with the smallest moment of inertia will experience the greatest angular acceleration and thus reach the bottom first.
I = M r^2 ring
I = 1/2 M r^2 cylinder
I = 2/5 M r^2 sphere
The sphere will reach the bottom first.
You throw a tennis ball straight up. Air resistance can be neglected.
(a) The maximum height above your hand that the ball reaches is H. At what speed does the ball leave your hand?
(b) What is the speed of the ball when it is a height H/2 above your hand? Express your answer as a fraction of the speed at which it left your hand.
(c) At what height above your hand is the speed of the ball half as great as when it left your hand? Express your answer in terms of H.
Answer:
(a) [tex]\sqrt{2gH}[/tex]
(b) [tex]\sqrt{gH}[/tex]
(c) [tex]\frac{3u^{2}}{8g}[/tex]
Explanation:
The maximum height = H
(a) Let the speed of the ball as it leaves the hand is u.
Use third equation of motion
[tex]v^{2}=u^{2}+2as\\0 = u^{2}- 2 gH\\u=\sqrt{2 gH}[/tex]
(b) Let the speed of the ball at H/2 is v.
Use third equation of motion
[tex]v^{2}=u^{2}+2as\\v^{2} = u^{2}- 2 g\frac{H}{2}\\v^{2}=2 g H - gH = gH\\v =\sqrt{gH}[/tex]
(c) Let the height is h.
[tex]v^{2}=u^{2}+2as\\\frac{u^{2}}{4} = u^{2}- 2 gh \\\\2 g h = \frac{3u^{2}}{4}\\h =\frac{3u^{2}}{8g}[/tex]
NEED HELP PLZ!!! ASAP
Which of the following happens during a solar eclipse?
The moon appears red.
The moon casts a shadow on Earth.
Earth, the moon, and the sun form a triangle.
Earth comes between the sun and the moon.
Ok so I'm Confused, that last answer- Shouldnt that say the moon comes between the sun and the earth? This is what it says on my test instead..
U r correct mate it's the right answer.
Hope it helps u
Plz mark me brainlest
A vehicle reaches a speed of 7.5 m/s over 15 seconds. What is its acceleration if it
starts from rest?
a. -0.5 m/s2
b. 0.5 m/s?
c. 2 m/s?
d. 22.5 m/s2
[tex]acceleration = \frac{velocity}{time} = \frac{7.5}{15} = 0.5ms^-^2[/tex]
So the answer is option b.
problema de coeficiente de rozamiento
If you take the positive horizontal direction to be to the right (the same direction as F₂), then by Newton's second law, the block has
• a net horizontal force of
∑ F = F₁ cos(-50°) + F₂ - f = m a
• a net vertical force of
∑ F = F₁ sin(-50°) + n - m g = 0
where
• f = µ n = magnitude of friction
• µ = coefficient of kinetic friction
• n = magnitude of the normal force
• m = 20 kg
• a = acceleration of the block
Solve for n :
n = m g + F₁ sin(50°)
n = (20 kg) (9.80 m/s²) + (50 N) sin(50°)
n ≈ 234.302 N
If the block accelerates uniformly from rest with acceleration a, then this acceleration is equal to its average, given by
a = ∆v / ∆t = (9 m/s - 0) / (3 s) = 3 m/s²
Solve for f :
f = F₁ cos(50°) + F₂ - m a
f = (50 N) cos(50°) + 80 N - (20 kg) (3 m/s²)
f ≈ 52.1394 N
Solve for µ :
µ = f / n
µ ≈ (52.1394 N) / (234.302 N)
µ ≈ 0.22253 ≈ 0.22
If a team of workers comes to a consensus, what probably happened in the meeting?
A. They compromised with each other to reach an agreement.
B. They disagreed and were unable to come to a decision.
OC. They were forced by their manager to follow a new policy.
O D. They all turned in their letters of resignation.
Answer:
A
Explanation:
A consensus is when you come to an agreement
If unlike magnetic poles attract, how does a magnet attract an un-magnetized piece of metal such as a piece of iron?
A
It does this via a process called magnetic induction which temporarily makes a magnet of the metal.
B
It can only do this if the piece of metal already is a magnet internally.
C
What actually happens is that the un-magnetized metal attracts the magnet rather than the other way around.
D
Only powerful electro-magnets, such as are found in wrecking yards, can attract unmagnetized metals.
Answer:
A
Explanation:
The lets say the magnet is is facing the north and a piece of iron is near it. The iron will become magnetized since the protons will be repelled leaving only the electrons creating a magnetic field. Or in other words a temporary magnet is made, this is only as long a the actual magnet is close enough to the iron.
g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a distant screen that has been set up behind the slit. The first dark fringe in the diffraction pattern is 4.0 cm from the center point of the pattern. If you replace the orange laser with an unknown laser and observe that the second dark fringe of the diffraction pattern appear at 4.0 cm from the center point, what is the wavelength of the unknown laser
Answer:
λ = 3 10⁻⁷ m, UV laser
Explanation:
The diffraction phenomenon is described by the expression
a sin θ = m λ
let's use trigonometry
tan θ = y / L
as in this phenomenon the angles are small
tan θ = [tex]\frac{sin \ \theta}{cos \ \theta}[/tex] = sin θ
sin θ = y / L
we substitute
a y / L = m λ
let's apply this equation to the initial data
a 0.04 / L = 1 600 10⁻⁹
a / L = 1.5 10⁻⁵
now they tell us that we change the laser and we have y = 0.04 m for m = 2
a 0.04 / L = 2 λ
a / L = 50 λ
we solve the two expression is
1.5 10⁻⁵ = 50 λ
λ = 1.5 10⁻⁵ / 50
λ = 3 10⁻⁷ m
UV laser
a 60 kg pupil runs for 600m in 1 minute uniformly calculate kinetic energy
velocity = traveled distance ÷ time of the traveled distance is seconds
velocity = 600 ÷ 60
velocity = 10 m/s
_________________________________
Kinetic Energy = 1/2 × mass × ( velocity )^2
KE = 1/2 × 60 × ( 10 )^2
KE = 30 × 100
KE = 3000 j
Volcanic process refers to the eruptive and noneruptive activities that occur on a volcano. Volcanic activities usually
results if one of the following happens: A). Deep within the core of the Earth, it is so hot that some rocks melt and
become a thick and sticky substance called (16)_
Magma B) This substance gets hotter and hotter and pressure
builds deep in the (17)
of the volcano. C) Eventually, magma will push up toward the surface of the
Earth through the volcano's crater and escape through vents in the earth. D) When magma erupts from the volcano, it is
called (18)
During an eruption, volcanic asin and ouiet rock pa licies called (19)
alsu escape
violently into the air and can cause major damage to the volcano's surrounding environment. E) (20)
that erupts from the volcano will fall back down onto the Earth like powdery snow that can cover and suffocate
anlants and animals and also contaminate streams and rivers.
In a chemical reaction, substances react in a specific ratio. Chemical reactions are used to make many products, including food. For a company that carries out a chemical reaction to make a product, why would it be important to know the ratio of substances?
Answer: “Chemical equations need to be balanced in order to satisfy the law of conservation of matter, which states that in a closed system matter is neither created nor destroyed. There are some things called mole ratios, which are important because mole ratios allow you change moles of a substance to moles of another substance. The mole ratio is the magic that changes from A to B. The mole ratios come from the chemical formula or equation.”
You need to make sure you have an equal balance so that you don’t make a mistake and mess up the reaction. If anything goes minutely wrong, it may alter the substance. Knowing the ratios of substances can help to make the product as expected.
It is important to know the ratio of substances because:
Mole ratios are important because mole ratios allow you change moles of a substance to moles of another substance. The mole ratio is the magic that changes from A to B. The mole ratios come from the chemical formula or equation.The mole ratios are determined using the coefficients of the substances in the balanced chemical equation. Mole ratios are used as a means of comparison of substances in a balanced chemical equation in order to determine amounts.Example: 2H₂ + O₂ → 2 H₂O
Learn more:
brainly.com/question/14197404
Bob uses a wheelbarrow to move soil from his garden to a new flowerbed. He exerts an average force of 185 N while pushing the wheelbarrow, and he does 6.1 kJ of work while moving each load of soil. How far is he moving the soil?
A. 0.026 m
B. 0.039 m
C. 26 m
B. 39 m
Answer:
A. reduce the amount of soil by one-half and apply the same amount of force
Explanation: