What is the equation of the line graphed below?

What Is The Equation Of The Line Graphed Below?

Answers

Answer 1

y=3x-2

That’s the answer


Related Questions


What is the approximate length of minor arc LM? Round
to the nearest tenth of a centimeter.
12.4 centimeters
15.7 centimeters
31.4 centimeters
36.7 centimeters

Answers

Answer:

Length of the arc LM = 15.7 cm

Step-by-step explanation:

To determine the length of the arc LM we have to find the circumference of the the big circle then divide by the ratio of the angle or go straight to use the radians as the angle and look for the length.

Radius= 30cm

π= 3.142

Value of the angle is in radians

360° = 2π

π = 180

π/6 = 180/6

π/6= 30

Value of the angle is 30°

Length of the arc = 2πr * 30/360

Length of the arc = 2πr/12

Length of the arc = πr/6

Length of the arc = 30π/6

Length of the arc =5π

Length of the arc = 5*3.142

Length of the arc = 15.71

Approximately Length of the arc

= 15.7cm

Answer:

B. 15.7cm

Step-by-step explanation:

Explain how you found the volume of the rectangular prism with a hole through it. Explain how you found the volume of the rectangular prism with a hole through it.

Answers

Answer:

Step-by-step explanation:

We khow that the volume of a prism the product of the base and the height

We have a hole inside it so we must khow what is the geometrical form of this whole to calculate its volum then substract from the total volume

Sample Answer:

I found the volume of the large rectangular prism. Then I found the volume of the small rectangular prism. I subtracted the volume of the smaller prism from the volume of the larger prism.

Suppose that you collect data for 15 samples of 30 units each, and find that on average, 2.5 percent of the products are defective. What are the UCL and LCL for this process? (Leave no cells blank - be certain to enter "0" wherever required. Do not round intermediate calculations. Round up negative LCL values to zero. Round your answers to 3 decimal places.)

Answers

Answer:

The  UCL  is  [tex]UCL = 0.054[/tex]

The LCL  is  [tex]LCL \approx 0[/tex]

Step-by-step explanation:

From the question we are told that  

     The quantity of each sample is  n =  30

     The  average of defective products is  [tex]p = 0.025[/tex]

Now  the upper control limit [UCL] is  mathematically represented as

       

      [tex]UCL = p + 3 \sqrt{\frac{p(1-p)}{n} }[/tex]

substituting values  

      [tex]UCL = 0.025 + 3 \sqrt{\frac{0.025 (1-0.025)}{30} }[/tex]

      [tex]UCL = 0.054[/tex]

The  upper control limit (LCL) is mathematically represented as

       [tex]LCL = p - 3 \sqrt{\frac{p(1-p)}{n} }[/tex]

substituting values  

      [tex]LCL = 0.025 - 3 \sqrt{\frac{0.025 (1-0.025)}{30} }[/tex]

       [tex]LCL = -0.004[/tex]

        [tex]LCL \approx 0[/tex]

       

Please someone help!!!

Answers

Answer:

Step-by-step explanation:

A, B and C must be real numbers, and A and B are not both zero (which would cause division by zero in the calculation of the slope).

Which graph represents an exponential function?

Answers

Answer:

Presumably the first graph solely based on its shape.

Graph A is showing the exponential function. Then the correct option is A.

What is an exponential function?

The mathematical expression f(x)= [tex]e^x[/tex] denotes the exponential function. The term typically refers to the positive-valued function of a real variable, unless otherwise specified.

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data. In graph A we can see that the values are varying exponentially from the second quadrant to the first quadrant.

Hence, the correct option is A.

To know more about exponential functions follow

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The weights of steers in a herd are distributed normally. The standard deviation is 300lbs and the mean steer weight is 1100lbs. Find the probability that the weight of a randomly selected steer is between 920 and 1730lbs round to four decimal places.

Answers

Answer:

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

P(920≤ x≤1730) = 0.7078

Step-by-step explanation:

Step(i):-

Given mean of the Population = 1100 lbs

Standard deviation of the Population = 300 lbs

Let 'X' be the random variable in Normal distribution

Let x₁ = 920

[tex]Z = \frac{x-mean}{S.D} = \frac{920-1100}{300} = - 0.6[/tex]

Let x₂ = 1730

[tex]Z = \frac{x-mean}{S.D} = \frac{1730-1100}{300} = 2.1[/tex]

Step(ii)

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

P(x₁≤ x≤x₂) = P(Z₁≤ Z≤ Z₂)

                  = P(-0.6 ≤Z≤2.1)

                  = P(Z≤2.1) - P(Z≤-0.6)

                 = 0.5 + A(2.1) - (0.5 - A(-0.6)

                 =  A(2.1) +A(0.6)               (∵A(-0.6) = A(0.6)

                 =  0.4821 + 0.2257

                 = 0.7078

Conclusion:-

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

            P(920≤ x≤1730) = 0.7078

Answer:

0.7975

Step-by-step explanation:

Find the area of the parallelogram with vertices A(−1,3,3), B(0,5,7), C(1,2,6), and D(2,4,10).

Answers

Answer:

Step-by-step explanation:

The diagonal of the parallelogram ABCD divides it into 2 equal triangles. Considering triangle ABC, it means that the area of the parallelogram would be

2 × area of triangle ABC

Writing the vertices of triangle ABC,

A(−1,3,3), B(0,5,7), C(1,2,6)

We would determine the length of each side of the triangle.

AB = √(0 - - 1)² + (5 - 3)² + (7 - 3)^2

AB = √(1 + 4 + 16) = √21

BC = √(1 - 0)² + (2 - 5)² + (6 - 7)²

BC = √(1 + 9 + 1) = √11

AC = √(1 - - 1)² + (2 - 3)² + (6 - 3)²)

AC = √(4 + 1 + 9) = √14

We would apply the heron's formula for determining the area of a triangle

Area = √s(s - a)(s - b)(s - c)

Where

s = (a + b + c)/2

a = AB, b = BC, c = AC

s = (√21 + √11 + √14)/2 = 5.82

s - a = 5.82 - √21 = 1.24

s - b = 5.82 - √11 = 2.5

s - c = 5.82 - √14 = 2.08

Area = √(5.82 × 1.24 × 2.5 × 2.08) = 6.126

Therefore, area of parallelogram ABCD is

6.126 × 2 = 12.252

Weekly sales of bagels at the local bakery are as follows: Week Sales 1 400 2 370 3 420 4 380 5 410 6 430 7 400 8 What is the forecast for week 8 using weighted moving averages with the weights 0.6, 0.3, 0.1

Answers

Answer:

410 bagels

Step-by-step explanation:

If the weights of the moving averages are 0.6, 0.3, 0.1. We will determine the forecast for week 8 using week seven's sales with a 0.6 weight, week six's sales with a 0.3 weight, and week five's sales with a 0.1 weight:

[tex]S_8=0.6S_7+0.3S_6+0.1S_5\\S_8=0.6*400+0.3*430+0.1*410\\S_8=410\ bagels[/tex]

The forecast for week 8 is 410 bagels.

evaluate -x+4 when x = -2

Answers

Answer:

6

Step-by-step explanation:

=> -x+4

Given that x = -2

=> -(-2)+4

=> 2+4

=> 6

Answer:

6

Step-by-step explanation:

You just have to input -2 into the statement and then solve

= -(-2) + 4

= 2+ 4

= 6

The number of large cracks in a length of pavement along a certain street has a Poisson distribution with a mean of 1 crack per 100 ft. a. What is the probability that there will be exactly 8 cracks in a 500 ft length of pavement

Answers

Answer:

6.53% probability that there will be exactly 8 cracks in a 500 ft length of pavement

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Poisson distribution with a mean of 1 crack per 100 ft.

So [tex]\mu = \frac{ft}{100}[/tex], in which ft is the length of the pavement.

What is the probability that there will be exactly 8 cracks in a 500 ft length of pavement

500ft, so [tex]\mu = \frac{500}{100} = 5[/tex]

This is P(X = 8).

[tex]P(X = 8) = \frac{e^{-5}*5^{8}}{(8)!} = 0.0653[/tex]

6.53% probability that there will be exactly 8 cracks in a 500 ft length of pavement

pls help me help me help me​

Answers

Answer:

C. -3/2

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes.

We know that line m is perpendicular to line l.

Line l has a slope of 2/3. To find the slope of line m, find the negative reciprocal of 2/3.

Negative: switch the sign

2/3 --> -2/3

Reciprocal: switch the numerator (top number) and denominator (bottom number)

-2/3 --> -3/2

Line m has a slope of -3/2 and C is correct.

Answer:

C

Step-by-step explanation:

perpendicular lines have negative reciprocal slope

Which of the following relations is a function?
A{(1, 3), (2, 3), (4,3), (9. 3)}

B{(1, 2), (1, 3), (1.4), (1,5)}

C{(5, 4), (-6, 5), (4, 5), (4, 0)}

D{(6,-1), (1, 4), (2, 3), (6, 1)}​

Answers

the answer is a. to be a function there can’t be an x value that is the same to a different y value. so as an example (6,7) (3,2) (5,6) (6,3) is not a function because 6 appears 2 times as an x value but with different y values. but you can have the same y value.

A heavy rope, 30 ft long, weighs 0.4 lb/ft and hangs over the edge of a building 80 ft high. Approximate the required work by a Riemann sum, then express the work as an integral and evaluate it.How much work W is done in pulling half the rope to the top of the building

Answers

Answer:

180 fb*lb

45 ft*lb

Step-by-step explanation:

We have that the work is equal to:

W = F * d

but when the force is constant and in this case, it is changing.

 therefore it would be:

[tex]W = \int\limits^b_ a {F(x)} \, dx[/tex]

Where a = 0 and b = 30.

F (x) = 0.4 * x

Therefore, we replace and we would be left with:

[tex]W = \int\limits^b_a {0.4*x} \, dx[/tex]

We integrate and we have:

W = 0.4 / 2 * x ^ 2

W = 0.2 * (x ^ 2) from 0 to 30, we replace:

W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)

W = 180 ft * lb

Now in the second part it is the same, but the integral would be from 0 to 15.

we replace:

W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)

W = 45 ft * lb

Following are the calculation to the given value:

Given:

[tex]length= 30 \ ft\\\\mass= 0.4 \ \frac{lb}{ft}\\\\edge= 80 \ ft \\\\[/tex]

To find:

work=?

Solution:

Using formula:

[tex]\to W=fd[/tex]

[tex]\to W=\int^{30}_{0} 0.4 \ x\ dx\\\\[/tex]

[tex]= [0.4 \ \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{4}{10} \times \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{2}{10} \times x^2]^{30}_{0} \\\\= [\frac{1}{5} \times x^2]^{30}_{0} \\\\= [\frac{x^2}{5}]^{30}_{0} \\\\= [\frac{30^2}{5}- 0] \\\\= [\frac{900}{5}] \\\\=180[/tex]

Therefore, the final answer is "[tex]180\ \frac{ lb}{ft}[/tex]".

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What is the slope of the function, represented by the table of values below?

Answers

Answer:

C. -2

Step-by-step explanation:

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Simply use 2 xy values and plug them into the formula:

m = (-4 - 0)/(5 - 3)

m = -4/2

m = -2

Answer:

-2

Step-by-step explanation:

Since we have two points we can use the slope formula

m = (y2-y1)/(x2-x1)

  = (10-6)/(-2-0)

  =4/-2

  -2

Suppose the displayed ask is $20.05 for 100 shares and the displayed bid is $20 for 150 shares. What happens if another dealer places a limit order to buy 50 shares for $20.02?

Answers

Answer:

There will be no transaction

Step-by-step explanation:

Given:

Displayed ask price = $20.05 for 100 shares

Displayed bid price = $20 for 150 shares

Explain:

If a limit order to buy = 50 shares for $20.02

Computation:

Displayed bid will be not accepted because, displayed bid price is for 150 shares not 100 shares

Limited order will be also not accepted.

So, there will be no transaction.

Suppose A is a 5times7 matrix. How many pivot columns must A have if its columns span set of real numbers RSuperscript 5​? ​Why?

Answers

Answer:

Five

Step-by-step explanation:

Pivot columns are said to be columns where pivot exist and a pivot exist in the first nonzero entry of each row in a matrix that is in a shape resulting from a Gaussian elimination.

Suppose A = 5 × 7 matrix

So; if A columns span set of real numbers R⁵

The number of pivot columns that A must have must be present in each row. In a  5 × 7 matrix ; we have 5 rows and 7 columns . So , since A must be present in each row, then :

The matrix must have five pivot columns and we can infer that about  the statements that "A has a pivot position in every row"  and "the columns of A spans R⁵" are logically equivalent.

Nika baked three loaves of zucchini bread. Each cake needed StartFraction 17 over 4 EndFraction cups of flour. Which expression shows the best estimate of the number of cups of flour that Nika used? 4 + 4 + 4 = 12 5 + 5 + 5 = 15 4 + 4 + 4 = 16 17 + 17 + 17 = 51

Answers

Answer:

(A)4 + 4 + 4 = 12

Step-by-step explanation:

Each of Nika's cake needed 17/4 cups of flour. Now, we know that:

[tex]\dfrac{17}{4}=4.25 \approx 4[/tex]

Therefore, for three loaves of bread, the best estimate of the number of cups of flour Nika used is:

4 + 4 + 4 = 12

The correct option is A.

Answer:

The correct answer is A.)4 + 4 + 4 = 12

the polynomial p(x)=x^3-7x-6 has a known factor of (x+1) rewrite p(x) as a product of linear factors p(x)=

Answers

Answer:(x+1)(x+2)(x-3)

Because..

Stuck Right now, Help would be appreciated :)

Answers

Answer:

C. c = (xv - x) / (v - 1).

Step-by-step explanation:

v = (x + c) / (x - c)

(x - c) * v = x + c

vx - vc = x + c

-vc - c = x - vx

vc + c = -x + vx

c(v + 1) = -x + vx

c = (-x + vx) / (v + 1)

c = (-x + xv) / (v + 1)

c = (xv - x) / (v + 1)

So, the answer should be C. c = (xv - x) / (v + 1).

Hope this helps!

Scientists want to test a new pair of running shoes. A speed test is performed with two separate groups of participants. The treatment group will wear the new pair of running shoes, while the control group will not. It is believed that age and height may affect speed. Which of the following would be most effective in controlling the confounding variables, such as age and height, in this study?

a. A completely randomized design experiment
b. A longitudinal observational study
c. A retrospective observational study
d. A matched-pair design experiment

Answers

Answer:

a. A completely randomized design experiment

Step-by-step Explanation:

An experiment that is completely randomised is practically an effective way of controlling and reducing the influence of the confounding variables in a research study, especially when you have a sample that is large enough.

Randomisation will ensure that both the group that will wear the new shoe (treatment group) and the group that will not wear the new shoe (control group) will have averagely the same values for age and height. This will eliminate the chances of these confounding variables of correlating with the independent variable in the study, as there would be no difference, in terms of characteristics, between both groups.

What is the simplified fractional equivalent of the terminating decimal 0.48

Answers

Answer: 12/25

Explanation:

48/100 = 24/50 = 12/25

Answer:

12/25

Step-by-step explanation:

Help me please!!! Thank you

Answers

Answer:

AD = 23

Step-by-step explanation:

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 117.7-cm and a standard deviation of 2.2-cm. For shipment, 29 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 118.5-cm.

Answers

Answer:

Required probability is 0.9748

Step-by-step explanation:

given data

mean [tex]\mu[/tex] = 117.7-cm

standard deviation [tex]\sigma[/tex] = 2.2-cm

sample size n = 29

solution

we consider here random variable which represents here length of rod= x

so get here first z that is express as

[tex]Z = \dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]    

put here value with x value 118.5-cm

[tex]Z = \dfrac{118.5-117.7}{\dfrac{2.2}{\sqrt{29}}}[/tex]

Z = 1.9582

p value is 0.9748

so required probability is 0.9748

Given
f(x) = 2x2 + 1
and
g(x) = 3x - 5
find the following.
f-g

Answers

Answer:

The answer is

2x² - 3x + 6

Step-by-step explanation:

f(x) = 2x² + 1

g(x) = 3x - 5

To find f - g(x) subtract g(x) from f(x)

That's

f-g(x) = 2x² + 1 - (3x - 5)

= 2x² + 1 - 3x + 5

= 2x² - 3x + 6

Hope this helps you

evaluate -x+4 when x = -2

Answers

Answer:

6

Step-by-step explanation:

f(x)=-x+4

f(-2)=-(-2)+4

f(-2)=+2+4

f(-2)=6

Answer:

6

Step-by-step explanation:

-(-2)+4=___

+(+2)+4=6

Let f(x) = −4(0.25)^x. The graph of g(x) = f(x)+k is shown below. Identify the value of k. k=

Answers

You can use photomath it is a great app to find ONLY equations!
When x=0, f(x) = -4, and g(x) = -2, which means k = 2

The graph of f(x) = 4x3 – 13x2 + 9x + 2 is shown below. On a coordinate plane, a function is shown. The function starts from the bottom of quadrant 3 and goes up through the x-axis at (0, negative 0.25) and then through the y-axis at (0, 2). It then starts to curve down at (0.5, 4) until it reaches (1.75, negative 0.5). It then curves up and crosses the x-axis at (2, 0) and goes up approaching x = 3. How many roots of f(x) are rational numbers? 0 1 2 3

Answers

Answer:

3

Step-by-step explanation:

f(x) = 4x^3 – 13x^2 + 9x + 2

This looks complicated but all we need to find are the Roots

We are looking for when y=0

So given each part of the information, we can label how many times it happens

The function starts from the bottom of quadrant 3: Starts lower left

and goes up through the x-axis at (0, negative 0.25) : This is ONE ROOT

and then through the y-axis at (0, 2). : It's now on the 2nd quartile

It then starts to curve down at (0.5, 4): It's moving towards y=0

until it reaches (1.75, negative 0.5).: It has now passed y=o and there are TWO ROOTS

It then curves up and crosses the x-axis at (2, 0) and goes up approaching x = 3: It has passed y=0 again, so there are THREE ROOTS

This polynomial function has 3 ROOTS

Answer:

The first for the graph is crosses and then it is touches for the second.

Step-by-step explanation:

Find the length of a side of a square whose diago- nal is 16 cm long. Round your answer to the nearest tenth.

Answers

Answer:

11.3 cm

Step-by-step explanation:

(see attached for reference)

using the Pythagorean theorem

hypotenuse ² = length ² + length ²

16² = L² + L²

16² = 2L²   (express 2 = (√2)²

16² = (√2)²L²  

16² = (√2L)²  

16 = √2L

L = 16 /√2

L = 11.3 cm

11.3

use Pythagoras theorem give each side is "a"

a^2+a^2=16^2

2*a^2=256

a^2=256/2=128

a=sqrt(128)=11.3 sqrt=square root

Consider the following set of sample data: (34, 32, 34, 32, 40, 37, 31, 31, 29, 27). We're interested in using this data to test a null hypothesis about the population mean. Which of the following statements are true?
I. Assuming this represents a random sample from the population, the sample mean is an unbiased estimator of the population mean.
II. Because they're robust, t procedures are justified in this case.
III. We'd use z­procedures here, since we're interested in the population mean.
a. I only
b. II only
c. III only
d. I and II only
e. I and III only

Answers

Answer:

Option I and II

Step-by-step explanation:

I. Assuming this represents a random sample from the population, the sample mean is an unbiased estimator of the population mean.

II. Because they're robust, t procedures are justified in this case.

The t procedures are utilized because they are used as a hypothesis testing tool, which allows for testing of an hypothesis applicable to a population where in this case we are testing the null hypothesis about the population mean.

Which of the following p values will lead us to reject the null hypothesis if the level of significance equals .05?
a. 0.100
b. 0.051
c. 0.150
d. 0.015

Answers

Answer:

So then our significance level is [tex]\alpha=0.05[/tex] and we need to remember these two conditions:

1) If the p value [tex]p_v <\alpha[/tex] we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value [tex]p_v \geq \alpha[/tex] we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Step-by-step explanation:

We want to know for which value we would REJECT the null hypothesis.

So then our significance level is [tex]\alpha=0.05[/tex] and we need to remember these two conditions:

1) If the p value [tex]p_v <\alpha[/tex] we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value [tex]p_v \geq \alpha[/tex] we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Other Questions
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