Answer:
tin nitrite Formula:Sn(NO2)2
The formula for tin (II) nitrite Sn(NO2)2.
What is Molecular formula?Two atoms together chemically form a molecule. The chemical formula for a molecular compound's molecular formula lists the variety of atoms that make up the molecule.
A subscript under oxygen in CO2, for instance, indicates that there are two oxygen atoms present, but a subscript under carbon indicates that there is just one carbon atom present.
A nitronium salt is produced when tin(IV) nitrate and trifluoroacetic acid anhydride combine. Trifluoroacetic acid produces a similar molecule when it is solvated with it.
The number of each atom contained in a given molecule is indicated by the molecule's molecular formula. In essence, it is a list of the elements that are present in a molecule and how many of each there are.
Therefore, The formula for tin (II) nitrite Sn(NO2)2.
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how many molecules of sugar are in 4.67 miles of sugar?
How many significant figures
are in this number?
3 x 10^6
Some major contributions to the development of atomic theory are listed. Identify the scientist associated with each contribution. Not all names will be used, and some names will be used more than once. He discovered the electron. He discovered periodic changes in properties of elements when they are listed in order of their atomic weights. He experimented with the deflection of cathode rays by a magnetic field. He carried out experiments that measured the scattering of alpha particles by heavy atoms. His model of the hydrogen atom led to an accurate calculation of the wavelengths of light emitted by an excited hydrogen atom. He proposed the planetary model of the atom with most of the mass of the atom concentrated in a very small nucleus. He modified the planetary model of the atom by suggesting electrons could travel about the nucleus in only a few discrete stable orbits. Answer Bank
Answer:
He discovered the electron - J.J Thompson
He discovered periodic changes in properties of elements when they are listed in order of their atomic weights - Dimitri Mendeleev
He experimented with the deflection of cathode rays by a magnetic field - J.J Thompson
He carried out experiments that measured the scattering of alpha particles by heavy atoms - Ernest Rutherford
His model of the hydrogen atom led to an accurate calculation of the wavelengths of light emitted by an excited hydrogen atom - Neil Bohr
He proposed the planetary model of the atom with most of the mass of the atom concentrated in a very small nucleus - Ernest Rutherford
He modified the planetary model of the atom by suggesting electrons could travel about the nucleus in only a few discrete stable orbits - Neil Bohr
Explanation:
J.J Thompson discovered the electrons. He initially called them cathode rays and he also studied how they are deflected in magnetic fields and by so doing established that they are negatively charged particles.
Ernest Rutherford is renowned for his experiment using the thin gold foil and alpha particles to determine that atoms have a positively charged massive core called the nucleus. This led to the proposition of the planetary model of the atom.
Dimitri Mendeleev discovered periodic changes in properties of elements when they are listed in order of their atomic weights. This led to the discovery of the Mendeleev periodic table.
Neil Bohr model of the atom gave accurate explanation of the emission spectra of the hydrogen atom. His atomic model suggested that electrons could travel about the nucleus in only a few discrete stable orbits.
Answer:
He discovered the electron - J.J Thompson
He discovered periodic changes in properties of elements when they are listed in order of their atomic weights - Dimitri Mendeleev
He experimented with the deflection of cathode rays by a magnetic field - J.J Thompson
He carried out experiments that measured the scattering of alpha particles by heavy atoms - Ernest Rutherford
His model of the hydrogen atom led to an accurate calculation of the wavelengths of light emitted by an excited hydrogen atom - Neil Bohr
He proposed the planetary model of the atom with most of the mass of the atom concentrated in a very small nucleus - Ernest Rutherford
He modified the planetary model of the atom by suggesting electrons could travel about the nucleus in only a few discrete stable orbits - Neil Bohr
Explanation:
Consider the proposed structure of carbon dioxide. Determine whether the structure is correct and justify your decision. Select one: This structure is correct due to the total number of bonds and electrons. This structure is correct due to allowed exceptions to the octet rule for the involved atoms. This structure is incorrect due to the total number of electrons for the involved atoms. This structure is incorrect because the octet rule is not fulfilled for all the atoms.
The question is incomplete, the complete question is found in the image attached to this answer
Answer:
This structure is correct due to the total number of bonds and electrons.
Explanation:
We know that all atoms in a compound are expected to obey the octet rule and we use this rule to ascertain the correctness of any chemical structure.
The structure of carbon IV oxide drawn perfectly satisfies the octet rule for each atom. Each atom in the molecule has eight electrons around its valence shell.
Therefore,since CO2 has sixteen valence electrons, we can conclude that; this structure is correct due to the total number of bonds and electrons.
Phosphorus is commercially prepared by heating a mixture of calcium phosphate, sand, and coke in an electric furnace. The process involves two reactions. 2 Ca3(PO4)2(s) 6 SiO2(s) 6 CaSiO3(l) P4O10(g) P4O10(g) 10 C(s) P4(g) 10 CO(g) The P4O10 produced in the first reaction reacts with an excess of coke (C) in the second reaction. Determine the theoretical yield of P4 if 293.5 g Ca3(PO4)2 and 378.5 g SiO2 are heated. (No Response) g If the actual yield of P4 is 44.9 g, determine the percent yield of P4.
Answer:
76.6% is percent yield of P₄
Explanation:
Percent yield is defined as 100 times the ratio of actual yield and theoretical yield. To solve this quesiton we need to find the theoretical yield of the reaction. Using:
2Ca₃(PO₄)₂(s) + 6SiO₂(s) → 6CaSiO₃(l) + P₄O₁₀(g)
P₄O₁₀(g) + 10C(s) → P₄(g) + 10CO(g)
We need to find the moles of Ca₃(PO₄)₂ and SiO₂ to find limiting reactant. With limiting reactant we can find moles of P₄O₁₀ = Moles of P₄. We must convert the moles of P₄ to mass using Molar mass (P₄ = 123.895g/mol):
Moles Ca₃(PO₄)₂ -Molar mass: 310.1767g/mol-
293.5g * (1mol / 310.1767g) = 0.9462moles
Moles SiO₂ -Molar mass: 60.08g/mol-:
378.5g * (1mol / 60.08g) = 6.30 moles
For a complete reaction of 6.30 moles of SiO₂ there are required:
6.30 moles SiO₂ * (2 moles Ca₃(PO₄)₂ / 6 moles SiO₂) =
2.10 moles Ca₃(PO₄)₂. As there are just 0.9462 moles, Ca₃(PO₄)₂ is limiting reactant
Moles P₄O₁₀ = Moles P₄:
0.9462moles Ca₃(PO₄)₂ * (1mol P₄O₁₀ / 2 mol Ca₃(PO₄)₂) = 0.4731 moles P₄O₁₀ = Moles P₄.
The mass is:
0.4731 moles P₄ * (123.895g / 1mol) = 58.6g = Theoretical yield.
Percent yield is:
44.9g / 58.6g * 100 =
76.6% is percent yield of P₄54.1miles/gallons how many liters of gas will be consumed traveling 132 km
Answer:
5.75 L.
Explanation:
From the question given above, the following data were obtained:
Rate = 54.1 miles/gallons
Distance = 132 km
Volume (in L) consumed =?
Next, we shall convert 132 km to mile. This can be obtained as follow:
1 km = 0.621 mile
Therefore,
132 km = 132 km × 0.621 mile / 1 km
132 km = 81.972 mile
Next, we shall determine the volume (in gallons) of the gas needed. This can be obtained as follow:
Rate = 54.1 miles/gallons
Distance = 81.972 mile
Volume (in gallon) =?
Rate = Distance / volume
54.1 = 81.972 / volume
Cross multiply
54.1 × volume = 81.972
Divide both side by 54.1
Volume = 81.972 / 54.1
Volume = 1.52 gallon.
Finally, we shall convert 1.52 gallon to litre (L). This can be obtained as follow:
1 gallon = 3.785 L
Therefore,
1.52 gallon = 1.52 gallon × 3.785 L / 1 gallon
1.52 gallon = 5.75 L
Therefore, 5.75 L of the gas will be consumed.
Select all of the Earth Systems that contain carbon.
Oa Atmosphere
Ob Geosphere
Oc Biosphere
Od Hydrosphere
Answer:
a, c, d
Explanation:
biosphere atmosphere hydrosphere lithosphere
What is the percent enantiomeric excess (ee) of a mixture that has 86% of one enantiomer and 14% of the other
Answer:
86% - 14% = 72%
Explanation:
Which statement is true about the speed of light? (2 points)
Light travels relatively slowly.
Distance in space is measured using the speed of light.
Time in space is measured using the speed of light.
The speed of light is unknown
Answer:
2nd option is the correct answer of this question
Answer:
yes it is b
Explanation:
Can someone help me with this? And provide an explanation on how they found their answer? Using conversion factors. I'm confused :(
You have used 3.0×102 L of distilled water for a dialysis patient. How many gallons of water is that?
Answer:
This would be 63 gallons :)
Explanation:
The Volume of water = 2.4 × 10² L
The Volume of water in gal = ?
The solution: We know that one gal is equal to 3.785 litter.
So in conclusion, 2.4 × 10²L × 1 gal / 3.785 L
2.4 × 10²L × 0.264 gal. L⁻¹
0.634 × 10² gal
Hopefully this helps :3
63 gal
A chemical equation is balanced when the number of each
type of ____ is the same on both sides of the equation.
Answer:
element
Explanation:
QUICK !!! How many moles are in 3.78 x 1025 molecules of CO?
Answer: 63
Explanation: (3.78/6.022)*100
Nitric acid decomposes in light to form nitrogen dioxide, water, and oxygen, according to the following chemical equation.
4HNO3 (l â 4NO2(g) + 2H2O (l) + O2(g)
If 2.5 g nitric acid decomposes, what is the total volume of gas produced?
a. 0.050L
b. 0.22
c.0.89
d. 1.1L
Answer:
b. 0.22 L
Explanation:
Step 1: Write the balanced equation
4 HNO₃(l) ⇒ 4 NO₂(g) + 2 H₂O(l) + O₂(g)
Step 2: Calculate the moles corresponding to 2.5 g of HNO₃
The molar mass of HNO₃ is 63.01 g/mol.
2.5 g × 1 mol/63.01 g = 0.040 mol
Step 3: Calculate the moles of O₂ produced from 0.040 moles of HNO₃
The molar ratio of HNO₃ to O₂ is 4:1. The moles of O₂ produced are 1/4 × 0.040 mol = 0.010 mol.
Step 4: Calculate the volume corresponding to 0.010 moles of O₂
Assuming the reaction takes place at standard temperature and pressure, the volume of 1 mole of O₂ is 22.4 L.
0.010 mol × 22.4L/1 mol = 0.22 L
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Answer:
Thank you for the free points!!
Explanation:
What can you conclude about the above reaction? * (1 Point)
•It needs air
•It releases heat.
•It releases light
•It absorps heat
In the desert, wind picks up and carries fine particles of sand and dirt. As 5 points
the wind blows against the rocks, the particles rub against the rocks and
wear them down in a process called: *
Weathering
Erosion
Deposition
Compaction/Cementation
What are the four Earth systems that contribute to the rock cycle?
C
It’s wrong I need points
The rock cycle includes the geosphere, hydrosphere, biosphere, and atmosphere. The wearing of the rock particles is called weathering. Thus, option a is correct.
What is weathering?Weathering is the process of sediment formation where the parent rocks and substances get disintegrated through natural biochemical and physical factors.
The parent rocks get deteriorated into smaller fine particles and sediments by the action of the strong wind and water. The movement causes the particles to dissolve the minerals on the surface.
The method of weathering, erosion, deposition, and compaction/ cementation is the part of the rock cycle that comprises the four major spheres including geosphere, hydrosphere, biosphere, and atmosphere.
Therefore, option a. in weathering the particles get disintegrated due to air and water.
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How many atoms are in 34 g of Cu?
Answer:
Babygirl these are double DD'S
Explanation:
OooOOO I'm hurt oh my neck my neck and my back
Which of the following best describes an advantage of genetic engineering?
Can reduce long-term health problems among consumers of GMO
Increases regulation of sale and consumption of healthy food
Reduces harmful impact on natural ecosystem in the future
Can produce crops having high level of nutrition
Answer:
d
Explanation:
d
Answer:
D. Can produce crops having high level of nutrition.
Explanation:
Some benefits of genetic engineering in agriculture are increased crop yields, reduced costs for food or drug production, reduced need for pesticides, enhanced nutrient composition and food quality, resistance to pests and disease, greater food security, and medical benefits to the world's growing population.
Three benefits to genetic engineering are the crops can survive better, leading the farmers to make more money, the crops can grow in more locations, and the plants can be modified to help people
Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 14. g of hydrochloric acid is mixed with 6.55 g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Round your answer to significant digits.
Answer:
8.02 g of HCl could be left over by the chemical reaction
Explanation:
We propose the reaction:
HCl(aq) + NaOH (s) → NaCl (aq) + H₂O (l)
Ratio is 1:1. First of all, we determine the moles of reactants:
14 g . 1mol / 36.45g = 0.384 mol of acid
6.55 g. 1mol / 40g = 0.164 mol of base
If a determined mass of HCl, could be left; this means that the acid is the excess reagent.
For 0.164 moles of NaOH, we need 0.164 moles of HCl.
As we have 0.384 moles, (0.384 - 0.164) = 0.220 moles of acid are left over in the reaction. We convert the moles to mass:
0.220 mol . 36.45 g /1mol = 8.02 g
When you need to produce a variety of diluted solutions of a solute, you can dilute a series of stock solutions. A stock solution has a significantly higher concentration of the given solute (typically 101 to 104 times higher than those of the diluted solutions). The high concentration allows many diluted solutions to be prepared using minimal amounts of the stock solution. What volume of a 6.57 M stock solution do you need to prepare 500. mL of a 0.0490 M solution of HCl
Answer:
3.73 mL
Explanation:
To solve this problem we can use the equation C₁V₁=C₂V₂, where:
C₁ = 6.57 MV₁ = ?C₂ = 0.0490 MV₂ = 500 mLWe input the data:
6.57 M * V₁ = 0.0490 M * 500 mLAnd solve for V₁:
V₁ = 3.73 mLSo 3.73 mL of a 6.57 M stock solution would be required to prepare 500 mL of a 0.0490 M solution.
How much energy is required to remove a neutron from the nucleus of an atom of carbon-13?
Answer:
uh i think 12?
Explanation:
Some hypothetical alloy is composed of 25 wt% of metal A and 75 wt% of metal B. If the densities of metals A and B are 6.17 and 8.00 g/cm3 , respectively, and their respective atomic weights are 171.3 and 162.0 g/mol, determine whether the crystal structure for this alloy is simple cubic, facecentered cubic, or body-centered cubic. Assume a unit cell edge length of 0.332 nm
Answer:
Simple cubic
Explanation:
The density of metal A (ρa) = 6.17 g/cm³, The density of metal B (ρb) = 8 g/cm³, The atomic weight of metal A (Aa) = 171.3 g/mol, The atomic weight of metal B (Ab) = 162 g/mol, the unit cell edge length (a) = 0.332 nm, concentration of metal A (Ca) = 25%, concentration of metal B (Cb) = 75%
The average density is given by:
[tex]\rho_{ave}=\frac{100}{\frac{C_a}{\rho_a} +\frac{C_b}{\rho_b} } \\\\\rho_{ave}=\frac{100}{\frac{25}{6.17} +\frac{75}{8} } =7.45\ g/cm^3\\\\The\ average\ atomic\ weight\ is:\\\\A_{ave}=\frac{100}{\frac{C_a}{A_a} +\frac{C_b}{A_b} } \\\\A_{ave}=\frac{100}{\frac{25}{171.3} +\frac{75}{162} } =164.23\ g/mol\\\\The\ number\ of\ atoms\ per\ unit(n)\ is:\\\\n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} \\\\N_A=Avogadro\ constant=6.02*10^{22} \ mol^{-1},a=0.332\ nm=3.32*10^{-8}cm\\\\Substituting:\\\\[/tex]
[tex]n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} =\frac{7.45*(3.32*10^{-8})^3*6.02*10^{23}}{164.23} \\\\n=0.999\\[/tex]
n≅1
Since n≅1, the crystal structure for this alloy is simple cubic
An irreversible change would be?
A.chipping ice to flakes
B.getting a hair cut
C.condensing steam
D.boiling water
Answer:
A. Chipping ice to flakes
Explanation:
You can't reverse the ice becoming flakes. They will stay like that until they melt
Which mission is not going to explore outside of the solar system?
A. SAFIR
B. Europa Clipper
C. MIRI
D. Kepler
What are metalloids?
A metalloid is a type of chemical element which has a preponderance of properties in between, or that are a mixture of, those of metals and nonmetals.
Answer:
Metalloid, in chemistry, an imprecise term used to describe a chemical element that forms a simple substance having properties intermediate between those of a typical metal and a typical nonmetal. There is no single property which can be used to unambiguously identify an element as a metalloid.
What are the names of the stable forms of oxygen?
Answer:
18 O, 17 O, and 16 O
Explanation:
three naturally stable isotopes
The stable forms of oxygen are molecular oxygen ([tex]O_{2}[/tex]) and ozone ([tex]O_{3}[/tex]). Molecular oxygen is the most common form in the Earth's atmosphere, while ozone is found in the ozone layer of the atmosphere and has a different molecular structure than [tex]O_{2}[/tex].
The most stable type of oxygen in the Earth's atmosphere is [tex]O_{2}[/tex], sometimes referred to as molecular oxygen or dioxygen. It is made up of two oxygen atoms joined by a link.
Another stable form of oxygen is [tex]O_{3}[/tex], also referred to as ozone. It is a molecule made up of three linked oxygen atoms. The ozone layer in the stratosphere of the Earth contains ozone, which is essential for protecting life on the planet by absorbing damaging ultraviolet (UV) radiation from the Sun.
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Copper(II) chloride hydrate, also known as copper chloride hydrate, is the inorganic compound with the chemical formula CuCl2 . x(H2O), where x can range from 1 to 7. A 2.060 g sample of copper (II) chloride hydrate was dissolved in 50.0 mL of deionized water. The concentration of copper (II) ion in the solution was determined spectrophotometrically using the equation from the calibration curve, was 0.200 M. Determine the formula of the copper (II) chloride hydrate.
Answer:
CuCl₂·4H₂O
Explanation:
First we calculate the moles of copper (II) ion in the solution, using the given volume and concentration:
50.0 mL ⇒ 50.0/1000 = 0.05 L0.05 L * 0.200 M = 0.01 mol Cu⁺²For each Cu⁺² mol there's also one CuCl₂ mol.
We convert 0.01 CuCl₂ moles into grams, using its molar mass:
0.01 CuCl₂ mol * 134.45 g/mol = 1.344 gThat means that out of the 2.060 g of the sample, 1.344 g are of CuCl₂. This means that there are (2.060 - 1.344) 0.716 g of water.
We convert those 0.716 g of water to moles:
0.716 g ÷ 18 g/mol = 0.04 mol H₂OThere are four times as many H₂O moles as there are CuCl₂ moles. This means the formula is CuCl₂·4H₂O
Practice Problem Website: https://www3.nd.edu/~smithgrp/structure/workbook.html
1. Click on Do the problems
2. Click on the number for the practice problem to be completed
3. Click on IR
Example of problem 1 from the website:
Formula: C3H5BrO2
IR Peaks:
1717 nm—Strong peak indicates a carbonyl group C=O
2571-2670 nm- medium peak indicates sp3 hybrid C-H.
3067 nm --- Broad medium peak indicates OH group, specifically in a carboxylic acid (Would not be a carboxylic acid without the carbonyl peak as well)
Complete the following problems: 3, 5, 7, 8, 12, 13, 27, 32, 38, and 40.
Be as accurate as possible. I am looking for the frequency and molecular formula to make sense with the functional group you think is represented.
A careless student forgets to label one of their reagent containers. They know it contains one of the following solutions: 0.1 M NaCl, 0.1 M Ca(NO3)2, 0.1 M KCH3COO The student decides to add some 0.1 M Pb(NO3)2 to a sample of the reagent in question. Upon stirring, a white precipitate formed. Which of the possible solutions was present in the unlabeled container based on this observation
Answer:
He kinda lazy ngl
Explanation:
Rgheeghfgufugf
In order to be in a position to manipulate any operation, one has to know all the fine details of the system and where and how one might apply subtle changes to affect the outcome. When looking at chemical reactions, it is from the study of its kinetics that one gleams the insight necessary to be able to do this. The main use of chemical kinetics is to measure the speed of a chemical reaction. But more importantly, in measuring the speed of a reaction, one gains insight as to what part of the reaction imparts this speed (or lack thereof) and thus allows one to propose a specific mechanism that details the critical pathway for the reaction. Measuring the speed of a chemical reaction is very similar to measuring speed in general, except that instead of talking in terms of distance traveled per unit time we are measuring either reactants consumed per unit time or products produced per unit time. There are many factors that affect the speed of a chemical reaction, some of the more common ones being:
Answer:
See explanation
Explanation:
Chemical kinetics, the branch of physical chemistry that is concerned with understanding how fast or how slow chemical reactions occur (Encyclopedia Britannica).
The study of the kinetics of a chemical reaction is helpful in many ways. Most important is the fact that it allows one to propose a specific mechanism that details the critical pathway for the reaction.
The factors that affect the rate of chemical reaction includes; concentration of reactants, temperature, nature of reactants , the solvent used, the presence of a catalyst, presence of light, surface area of reactants and pressure for gaseous reactants.