What is the kinetic energy of a jogger with a mass of 65.0 kg traveling at a speed of 2.5m/s

Answers

Answer 1

Answer:

203.1J

Explanation:

Given parameters:

Mass  = 65kg

Speed  = 2.5m/s

Unknown:

Kinetic energy of jogger  = ?

Solution:

To solve this problem, we use the kinetic energy equation:

    K.E  = [tex]\frac{1}{2}[/tex] m v²  

m is the mass

v is the velocity

 Now insert  the parameters and solve;

  K.E  =  [tex]\frac{1}{2}[/tex] x 65 x 2.5²   = 203.1J


Related Questions

what types of forces can move an object?

Answers

One of them is Gravity

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Acceleration Due to Gravity - Free Fall
V=V;+gt
vir initial velocity (m/s)
=final velocity (m/s)
g=gravity (10 m/s2)
t = time (s)
1. What is the velocity of a dropped object after it has fallen
downward for 3.0s?
V=V;+gt
Vi = 0
8 = 10
t = 3
2. A brick is thrown down off a bridge with a velocity of 5 m/s. What
is its velocity after it has fallen for 2 seconds?
I
3. An arrow is launched straight up from the ground. It reaches its
highest point in 6 s. What velocity was it released at?

Answers

a b c d

A V=V+gt

dhehehdhehdhshehehehehehe

What type of energy is stored in the nucleus of an atom?

Answers

Answer:

Nuclear energy

Explanation:

The nucleus holds the energy together

If a car is traveling forward at 15 M/S, how fast will be going in 1.2 seconds if the acceleration is 10 M/s2?

Answers

Answer:

Vf=27m/s

Explanation:

Vf=Vi+at

Lets substitute the known variables into the equation:

Vf=15+10×1.2

Vf=27m/s

So itll be going 27metres per second

What happens when you call someone using your cell phone?
A. Microwaves travel from your cell phone directly to the cell phone
of the person you are calling.
B. Microwaves reach a cell tower, then fiber optic cables send the
signal to a cell tower near the person you are calling.
C. A system of satellites orbiting Earth receives the microwave
signals and sends them to the person you are calling.
D. Sound waves reach a cell tower, then fiber optic cables send the
signal to a cell tower near the person you are calling.

Answers

Answer: B, Microwaves reach a cell tower, then fiber optic cables send the signal to a cell tower near the person you are calling.

Explanation:

Answer:D. Sound waves reach a cell tower, then fiber optic cables send the

signal to a cell tower near the person you are calling.

Explanation: just got it right

a 950 N skydiver jumps from an altitude of 3000 m. What is the total work performed on the skydiver?

Answers

Answer:

2850000J

Explanation:

Given parameters:

Weight of diver = 950N

Altitude  = 3000N

Unknown:

Total work done by the sky diver = ?

Solution:

To solve this problem, we use the expression:

        Work done  = Weight x height

Now insert the parameters:

        Work done  = 950 x 3000  = 2850000J

A person who is heavier than the standard for the person’s height is _____

A. overweight.
B. obese.
C. hefty.
D. extremely obese.

Answers

Answer:

A. overweight

Explanation:

Answer:

c

Explanation:

since of his lack of growing his body dont know what to do with the needed fat so while he's still growing its in his tummy waiting

List three ways light can be grouped based on how much light shines through or passes through them

Answers

Answer:

Materials can be classified based on the amount of light they transmit. Materials, which allow complete transmission of light, are called transparent. Any object can be seen through a transparent material. One example of transparent material is pure glass.

Explanation:

Does this help ?

Answer:

light, materials, and shadows

Explanation:

hope this helps have a good rest of your day :) sorry if incorrect

Help me plz i'll mark brainliest

Answers

Answer:

a PDF is what u use to upload an assignment to turn it in to get graded

help pls .. Which process produces the energy that powers a solar calculator?

Answers

Answer:

C) Nuclear fusion

Explanation: You had it correct  

Answer:

Nuclear fusion

Explanation: Answer choice C

what is 1=1?????????????????????????????//// HELP

Answers

Answer:

I am pretty sure that it is one

Answer:

Explanation: is 1

Roller coasters accelerates from initial speed of 6.0 M/S2 final speed of 70 M/S over four seconds. What is the acceleration?

Answers

Answer:

[tex]a=16\ m/s^2[/tex]

Explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly in time.

The formula to calculate the change of velocities is:

[tex]v_f=v_o+at[/tex]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The roller coaster moves from vo=6 m/s to vf=70 m/s in t=4 seconds. To calculate the acceleration, solve for a:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

[tex]\displaystyle a=\frac{70-6}{4}=\frac{64}{4}[/tex]

[tex]\boxed{a=16\ m/s^2}[/tex]

What is the direction of the net force when one force is pulling down and one force is pushing to the right?

Answers

Answer:  If the net force on an object is zero, its acceleration will be zero. For example in free fall, the net force on an object equals its weight - the one force pulling on it. If 2 forces push or pull on an object in opposite directions, and the two forces cancel .

Explanation: PLEASE MARK ME AS BRAINLIEST!

We have that the  direction of the net force when one force is pulling down and one force is pushing to the right is given as

[tex]\theta=tan^{-1}(\frac{Down force}{Right force})[/tex]

From the question we are told that:

One force is pulling down and one force is pushing to the right

Generally,

When two or more forces are acting in the same direction we have that the Resultant for or net for is a sum of the forces involved

Therefore

When one force is pulling down and one force is pushing to the right the Net force is in a direction that obeys the law

[tex]\theta=tan^{-1}\frac{y-axis\ force}{x-axis\ force}[/tex]

Therefore

[tex]\theta=tan^{-1}(\frac{Down force}{Right force})[/tex]

 

In conclusion

The direction of the net force when one force is pulling down and one force is pushing to the right is given as

[tex]\theta=tan^{-1}(\frac{Down force}{Right force})[/tex]

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