simplify the following
[tex]\sqrt{98][/tex]
[tex]\sqrt{16 b^{5} }[/tex]
[tex]3\sqrt{5m} x 4\sqrt{\frac{1}{5} m3}[/tex]
[tex]\sqrt{26x2}[/tex]

Answers

Answer 1

Step-by-step explanation:

Simplify:

[tex]\sqrt{98} = \sqrt{49*2} = \sqrt{7^2*2} = 7\sqrt{2}[/tex][tex]\sqrt{16b^5} = \sqrt{4^2(b^2)^2b} = 4b^2\sqrt{b}[/tex][tex]3\sqrt{5mx^4} \sqrt{1/5m^3} = 3\sqrt{5*1/5*m^4x^4} = 3\sqrt{(m^2)^2(x^2)^2} = 3m^2x^2[/tex][tex]\sqrt{26x^2} = x\sqrt{26}[/tex]

Answer 2

Answer:

[tex]→ \sqrt{98} = \sqrt{7 \times 7 \times2} = 7 \sqrt{2}✓ [/tex]

[tex]→ \sqrt{ 16{b}^{5} }= \sqrt{4 \times 4 \times {b}^{5} } = 4 {b}^{ \frac{5}{2} } ✓[/tex]

[tex]→3 \sqrt{5 mx^{4} } \sqrt{ \frac{1}{5} {m}^{3}} = 3 \sqrt{5 \times \frac{1}{5} {m}^{4} {x}^{4} } = 3 {m}^{2} {x}^{2} ✓[/tex]

[tex] →\sqrt{26 {x}^{2} } = \sqrt{26} x✓[/tex]


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Answer:

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Step-by-step explanation:

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Answers

Problem:

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Solution:

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[tex] - 8 - ( - 2) = \boxed{ - 6}[/tex]

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[tex] - 4 - ( - 2) = \boxed{ - 2}[/tex]

[tex] - 2 - ( - 2) = \boxed{0}[/tex]

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Answers

Answer:

root 50

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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ovided line. (1 pt. each)
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Meeting now 16:47
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Answers

Answer:

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Step-by-step explanation:

Explanation:-

Given   4x - 2y = -6

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The function form of the given equation

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer: 1928.90

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answer:

Ok I'll help ya out

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Answers

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

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Answers

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Once!

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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