What is the mass of H2SO4 in a 38.2-cm3 sample of concentrated sulfuric acid that has a density of 1.84 g/cm3 and consists of 98.3% H2SO4

Answers

Answer 1

Answer:

69.09 g

Explanation:

First we calculate the mass of the sample of concentrated H₂SO₄, using the given volume and density:

Mass = density * volumeMass = 1.84 g/cm³ * 38.2 cm³ = 70.288 g

There are 70.288 grams of solution, of which 98.3% is H₂SO₄. Thus the H₂SO₄ mass is:

70.288 g * 98.3/100 = 69.09 g
Answer 2

Taking into account the definition of density and percentage by mass, the mass of H₂SO₄ in a 38.2 cm³ sample of concentrated sulfuric acid is 69.09 grams.

Definition of density

But first you must know the definition of density. Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

Mass of solution

In this case, you know that:

Density= 1.84 [tex]\frac{g}{cm^{3} }[/tex]

Volume= 38.2 cm³

Replacing in the definition of density:

[tex]1.84 \frac{g}{cm^{3} }=\frac{mass}{38.2 cm^{3} }[/tex]

Solving:

mass= 1.84 [tex]\frac{g}{cm^{3} }[/tex]×38.2 cm³

mass= 70.288 g

So, the mass of the solution is 70.288 grams.

Definition of percentage by mass

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

[tex]percentage by mass=\frac{mass of solute}{mass of solution}x100[/tex]

Mass of H₂SO₄

In this case, you know:

percentage by mass=98.3%

mass of solute= ?

mass of solution= 70.288 grams

Replacing in the definition of percentage by mass:

[tex]98.3=\frac{mass of solute}{70.288 grams}x100[/tex]

Solving:

[tex]\frac{98.3}{100} =\frac{mass of solute}{70.288 grams}[/tex]

[tex]0.983=\frac{mass of solute}{70.288 grams}[/tex]

0.983× 70.288 grams= mass of solute

69.09 grams= mass of solute

The mass of H₂SO₄ in a 38.2 cm³ sample of concentrated sulfuric acid is 69.09 grams.

Learn more about

density:

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percentage by mass:

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Answers

Answer:

0.49 mol HCl

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic TableUsing Dimensional Analysis

Explanation:

Step 1: Define

18 g HCl

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar mass of HCl - 1.01 + 35.45 = 36.46 g/mol

Step 3: Convert

[tex]18 \ g \ HCl(\frac{1 \ mol \ HCl}{36.46 \ g \ HCl} )[/tex] = 0.493692 mol HCl

Step 4: Check

Round our answer to 2 decimal places.

0.493692 mol HCl ≈ 0.49 mol HCl

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Answer:

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Explanation:

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Answers

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This question is incomplete, the complete question is;

A 1.00 g sample of NH4NO3 is decomposedin a bomb calorimeter. The temperature increases by 6.12°C. What is the molar heat of decomposition for ammonium nitrate?

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Answer:

the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol

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Answers

Answer:

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Explanation:

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Explanation:

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Further explanation

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[tex]\tt \dfrac{54.5}{12}=4.54[/tex]

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