What is the perimeter, in terms of x, of the triangle shown here?
(7x2 - 12)
(-5x + 30)
(3x2 + 4x)

Answers

Answer 1

Answer:

The perimeter of triangle is: [tex]\mathbf{10x^2-x+18}[/tex]

Step-by-step explanation:

We need to find perimeter, in terms of x, of the triangle shown here.

The length of side 1: [tex](7x^2 - 12)[/tex]

The length of side 2: [tex](-5x + 30)[/tex]

The length of side 3: [tex](3x^2 + 4x)[/tex]

The formula used to find perimeter of triangle is: [tex]Perimeter\: of\: triangle=Sum\:of\:length\:of\:all\:sides[/tex]

Putting values and finding perimeter:

[tex]Perimeter\: of\: triangle=Sum\:of\:length\:of\:all\:sides\\Perimeter\: of\: triangle=(7x^2 - 12)+(-5x + 30)+(3x^2 + 4x)\\Perimeter\: of\: triangle= 7x^2-12-5x+30+3x^2+4x\\Perimeter\: of\: triangle=7x^2+3x^2-5x+4x-12+30\\Perimeter\: of\: triangle=10x^2-x+18[/tex]

So, The perimeter of triangle is: [tex]\mathbf{10x^2-x+18}[/tex]


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Answer:

-20

Step-by-step explanation:

First, you divide both sides by -2/5, which would get you c = 8 * -5/2 (Because when you divide, you multiply by the reciprocal). 8 * -5/2 is equal to -20. The answer is -20.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answers

Answer:

y = 42

Step-by-step explanation:

Since QT is a midsegment then it is half of RS , that is

QT = [tex]\frac{1}{2}[/tex] RS, substitute values

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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