What is the slope of a line perpendicular to one with a slope of {-2}{3}.

Answer:

y=3

Step-by-step explanation:

10=2y+4

10-4=2y

6=2y

3=y

Answer:

Null hypothesis: Policy B remains more effective than policy A.

Alternate hypothesis: Policy A is more effective than policy B.

Step-by-step explanation:

Remember, a hypothesis is a  usually tentative (temporary until tested) assumption about two variables– independent and the dependent variable.

We have two types of hypothesis errors:

1. A type I error occurs when the null hypothesis (H0) is wrongly rejected.

That is, rejecting the assumption that policy B remains more effective than policy A when it is actually true.

2. A type II error occurs when the null hypothesis H0, is not rejected when it is actually false. That is, accepting the assumption that policy B remains more effective than policy A when it is actually false.

Answer:

1 = 90°, 2 = 66°

Step-by-step explanation:

Since the diagonals of a rhombus are perpendicular, ∠1 = 90°. Using the Exterior Angles Theorem (exterior angle = sum of remote interior angles, we see that ∠2 = 90 - 24 = 66°.

Answer: -1.8

Step-by-step explanation:

Start at -5.5 and move the point on the number line up 3.7 spaces.

Hope it helps <3

Answer:

Your correct answer is -1.8

Step-by-step explanation:

−5.5 + 3.7

= −5.5+3.7

= −1.8

Answer:

19

Step-by-step explanation:

Inscribed Angle = 1/2 Intercepted Arc

< DBG = 1/2 ( DG)

< DBG = 1/2 ( 360 - BD - BG)

           = 1/2 ( 360 - 172 - 150)

           = 1/2 (38)

           = 19

Answer:

Susan and 4 quests

5 people

Step-by-step explanation:

Take 9/10 and divide by 1/6

9/10 ÷1/6

Copy dot flip

9/10 * 6/1

54/10

50/10 + 4/10

5 4/10

We can only serve whole numbers

5 people

Susan and 4 quests

Answer:

C

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 4 and (a, b) = (- 3, - 4) , thus

y - (- 4) = 4(x - (- 3)) , that is

y + 4 = 4(x + 3) → C

Answer:

B. 6sqrt(2).

Step-by-step explanation:

Since the two legs of the right triangle are congruent, this is a 45-45-90 triangle. That means that the hypotenuse will measure xsqrt(2) units, and each leg will measure x units.

In this case, x = 6.

So, the hypotenuse is B. 6sqrt(2).

Hope this helps!

Answer:

[tex]\boxed{3520\ ft/min}[/tex]

Step-by-step explanation:

1 miles per hour = 88 feet per minute

Multiplying both sides by 40

40 miles per hour = 88*40 ft/min

40 mi./hr = 3520 ft/min

Answer:

3520 feet/min

Step-by-step explanation:

the speed of the car in feet per minute:

first convert miles to feet ( 1 mile =5280 feet) and hours to minutes(1hr=60min.)

(40*5280)/1*60=3520 feet/min

Answer:

Yes, it would be statistically significant

Step-by-step explanation:

The information given are;

The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%

Number of jawbreakers in the sample, n = 800

The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = [tex]\mu _ {\hat p}[/tex] =p

The formula for the standard deviation of a proportion is [tex]\sigma _{\hat p} =\sqrt{\dfrac{p(1-p)}{n} }[/tex]

Solving for the standard deviation gives;

[tex]\sigma _{\hat p} =\sqrt{\dfrac{0.6 \cdot (1-0.6)}{800} } = 0.0173[/tex]

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4  in the sample of 800 = 800*0.6 = 480

For statistical significance the difference from the mean = 2×[tex]\sigma _{\hat p}[/tex] = 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7

The z-score of 494 jawbreakers is given as follows;

[tex]Z=\dfrac{x-\mu _{\hat p} }{\sigma _{\hat p} }[/tex]

[tex]Z=\dfrac{494-480 }{0.0173 } = 230.94[/tex]

Therefore, the z-score more than 2 ×[tex]\sigma _{\hat p}[/tex] which is significant.

Answer:

Step-by-step explanation:

min 452, max 507, so 494 is not unusual.

Answer:

log 12 = 1.0761

Step-by-step explanation:

log 12

=log(3*2*2)

= log 3 +log 2+ log 2

=0.4771+0.3010+0.3010

=1.0761

Answer:

Log 12 = 1.0791

Step-by-step explanation:

=> log (12)

Prime Factorizing 12

=> log (2×2×3)

Using log rule : [tex]log (a*b) = log a+logb[/tex]

=> Log 2 + log 2 + log 3

Given that log 2 = 0.3010 , log 3 = 0.4771

=> 0.3010 + 0.3010 + 0.4771

=> 1.0791

Answer: The concentration of the mixture is 0.5 p % .

Step-by-step explanation:

Given: 5 gallons of p% boric acid is mixed with 5 gallons of water.

Amount of boric acid = p% of 5 gallons

[tex]=\dfrac{p}{100}\times5\text{ gallons}= 0.05p\text{ gallons}[/tex]

Total solution : 5 +5 = 10 gallons

then, the concentration of the mixture = [tex]\dfrac{\text{Amount of boric acid in solution}}{\text{Total solution}}\times100[/tex]

[tex]=\dfrac{0.05p}{10}\times100\\\\=0.5p[/tex]

Hence, the concentration of the mixture is 0.5 p % .

Answer:

0.5p% is the answer

Answer:

The correct option is

This is a polynomial function of degree 7 with a leading coefficient of -1

Step-by-step explanation:

Functions that consist of a variable such as x raised to positive integer powers which are equal to or larger than zero added together to make the function are known as polynomial functions

Therefore, the function in the question which is f(X) = x⁴ × (2 - x³) + 1

Which can be expanded as follows

f(x) = 2·x⁴ - x⁷ + 1, which is the same as given as follow equation;

f(x) = -x⁷ + 2·x⁴ + 1

Which is  polynomial function with a leading coefficient of -1 as it consists of only whole number positive powers of x including the powers of x 4 and 7  

Therefore, the correct option is that f(x) is a polynomial function of degree 7 with a leading coefficient of -1.

Answer:

Step-by-step explanation:

m∠UTV = 112°  ⇒  m∠WTV = 180° - 112° = 68°

sin(68°) ≈ 0.9272

sin(∠WTV) = WV/TV

WV/10 ≈ 0.9272

WV ≈ 9.272

WV ≈ 9.3

Answer:

P(X ≤ 94) =  0.09012

From what we observe; There is a probability  of less than 94 people who voted for the referendum is 0.09012

Comment:

The result is unusual because the probability that p is equal to or more extreme than the sample proportion is greater than 5%. Thus, it is not unusual for a wrong call to be made in an election if the exit polling alone is considered.

Step-by-step explanation:

From the information given :

An exit poll of 200 voters finds that 94 voted for the referendum.

How likely are the results of your sample if the population proportion of voters in the town in favor of the referendum is 0.52​? Based on your​ result, comment on the dangers of using exit polling to call elections.

This implies that ;

the Sample size n = 200

the probability p = 0.52

Let X be the random variable

So; the Binomial expression can be represented as:

X [tex]\sim[/tex] Binomial ( n = 200, p = 0.52)

Mean [tex]\mu[/tex] = np

Mean [tex]\mu[/tex]  = 200 × 0.52

Mean [tex]\mu[/tex]  = 104

The standard deviation [tex]\sigma[/tex] = [tex]\sqrt{np(1-p)}[/tex]

The standard deviation [tex]\sigma[/tex] = [tex]\sqrt{200 \times 0.52(1-0.52)}[/tex]

The standard deviation [tex]\sigma[/tex] = [tex]\sqrt{200 \times 0.52(0.48)}[/tex]

The standard deviation [tex]\sigma[/tex] = [tex]\sqrt{49.92}[/tex]

The standard deviation [tex]\sigma[/tex] = 7.065

However;

P(X ≤ 94) because the discrete distribution by the continuous normal distribution values lies in the region of 93.5 and 94.5 .

The less than or equal to sign therefore relates to the continuous normal distribution of X < 94.5

Now;

x = 94.5

Therefore;

[tex]z = \dfrac{x- \mu}{\sigma}[/tex]

[tex]z = \dfrac{94.5 - 104}{7.065}[/tex]

[tex]z = \dfrac{-9.5}{7.065}[/tex]

z = −1.345

P(X< 94.5) = P(Z < - 1.345)

From the z- table

P(X ≤ 94) =  0.09012

From what we observe; There is a probability  of less than 94 people who voted for the referendum is 0.09012

Comment:

The result is unusual because the probability that p is equal to or more extreme than the sample proportion is greater than 5%. Thus, it is not unusual for a wrong call to be made in an election if the exit polling alone is considered.

Answer:

The slope is 1/3 and the y intercept is 6

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

3y -x =18

Add x to each side

3y = x+18

Divide each side by 3

3y/3 = x/3 +18/3

y = 1/3x +6

The slope is 1/3 and the y intercept is 6

We need to solve for y (y = mx + b):

3y - x = 18

~Add x to both sides

3y = 18 + x

~Divide 3 to everything

y = 6 + x/3 or y = 6 + 1/3/x

So... 1/3 is the slope and 6 is the y-intercept.

Best of Luck!

Constant of variation = number of chairs/ spacing.

80/16 = 5

The answer is B.5

Answer:

-30

Step-by-step explanation:

7m + 2n - 8p/n

Let  m = –4, n = 2, and p = 1.5

7(-4) + 2 ( 2) -8*(1.5)/2

-28 + 4 - 4*1.5

-28+ 4 - 6

-30

Answer:

-30

Step-by-step explanation:

Hey there!

Well given,

m = -4

n = 2

p = 1.5

We need to plug those number into,

7m + 2n - 8p/n

7(-4) + 2(2) - 8(1.5)/(2)

-28 + 4 - 12/2

-28 + 4 - 6

-24 - 6

-30

Hope this helps :)

Answer:

C = 35 + 0.08t

Step-by-step explanation:

The equation is:

35 + 0.08t = C

C = Cost by month

t = cost for each additional message

Answer:

2.

Step-by-step explanation:

The slope is calculated by doing rise over run.

The rise is: 6 - 0 = 6.

The run is: 0 - (-3) = 0 + 3 = 3.

6 / 3 = 2 / 1 = 2.

Hope this helps!

Answer:

2x-(3x+5) = -x-5

Step-by-step explanation:

     2x + 0

-

     3x + 5

-———————-

     -x - 5

Answer:

3.9

Step-by-step explanation:

Pythagorean theorem:

a^2 + b^2 = c^2

a^2 + 1^2 = 4^2

a^2 + 1 = 16

a^2 = 15

a = sqrt(15)

a = 3.9

Answer a = 3.9 yards

Answer:

[tex]\boxed{3.9}[/tex]

Step-by-step explanation:

The triangle is a right triangle.

Apply Pythagorean theorem.

[tex]a^2 + b^2 = c^2[/tex]

[tex]a^2 + 1^2 = 4^2[/tex]

[tex]a^2 + 1 = 16[/tex]

[tex]a^2 = 15[/tex]

[tex]a=\sqrt{15}[/tex]

[tex]a \approx 3.872983[/tex]

Answer with explanation:

Two or more Algebraic expressions are said to be equivalent, if both the expression produces same numerical value , when variable in the expressions are replaced by any Real number.

The two expressions are

1. 7 x +4

2. 3 x +5 +4 x =1

Adding and subtracting Variables and constants

→7 x +5=1

→7 x +5-1

→7 x +4

→ When x=2,

7 x + 4 =7×2+4

=14 +4

=18

So, Both the expression has same value =18.

→So, by the definition of equivalent expression, when ,you substitute , x by any real number the two expression are equivalent.

Correct options among the given statement about the expressions are:

1.When x = 2, both expressions have a value of 18.

2.The expressions have equivalent values for any value of x.

3.The expressions have equivalent values if x = 8.

Answer:

Hey there!

Sine is equal to opposite/hypotenuse

Tangent is equal to opposite/adjacent

opposite=a

hypotenuse=b

adjacent=c

Thus, tangent x= a/c.

Hope this helps :)

Answer:

tan x = a/sqrt(b^2 - a^2)

Step-by-step explanation:

sin x = a/b = opp/hyp

tan x = opp/adj

adj^2 + opp^2 = hyp^2

adj^2 + a^2 = b^2

adj = sqrt(b^2 - a^2)

tan x = a/sqrt(b^2 - a^2)

Answer:

  £531.52

Step-by-step explanation:

We are given the profit in week 1 and information about week 2. We are asked for the difference between week 2 profit and week 1 profit.

__

In week 2, pizza is sold 4 ways. The diagram shows the numbers of pizzas sold each way. The table shows the profit made for each way the pizza was sold. We need to add up the profits from each of the sales to find the profit for week 2.

Then the total profit in week 2 is ...

  £1514.04 -175.42 +888.94 -5.68 = £2221.88

So, profit in week 2 exceeds profit in week 1 by ...

  £2221.88 -1690.36 = £531.52 . . . more profit in week 2

Answer:

Option A is the correct option.

Step-by-step explanation:

As PW is the median.

PW = [tex] \frac{1}{2} [/tex] ( YZ + TM )

Plug the values

x = [tex] = \frac{1}{2} (5.5 + 12.1)[/tex]

Calculate the sum

x = [tex] = \frac{1}{2} \times 17.6[/tex]

Calculate the product

x = [tex] = 8.8[/tex]

Hope this helps...

Best regards!

Answer:

  D.  p + q = 7

Step-by-step explanation:

The slope of AB is ...

  mAB = (y2 -y1)/(x2 -x1) = (1 -4)/(6 -p) = -3/(6 -p)

The slope of BC is ...

  mBC = (q -1)/(9 -6) = (q -1)/3

We want the product of these slopes to be -1:

  mAB·mBC = -1 = (-3/(6 -p))·((q -1)/3)

  -(q-1)/(6 -p) = -1 . . . . cancel factors of 3

  q -1 = 6 -p . . . . . multiply by -(6 -p)

  q + p = 7 . . . . . matches choice D

Answer:

C p+q=7

Step-by-step explanation:

I did it on plato and it was right

Answer:

[tex]\boxed{f^{-1}(x)= \frac{\sqrt{8x+9}+3}{4}}[/tex]

Step-by-step explanation:

[tex]f(x)=2x^2-3x[/tex]

[tex]f(x)=y[/tex]

[tex]y=2x^2-3x[/tex]

Switch variables.

[tex]x=2y^2-3y[/tex]

Solve for y.

Multiply both sides by 8.

[tex]8x=16y^2-24y[/tex]

Add 9 on both sides.

[tex]8x+9=16y^2-24y+9[/tex]

Take the square root on both sides.

[tex]\sqrt{8x+9} =\sqrt{16y^2-24y+9}[/tex]

Add 3 on both sides.

[tex]\sqrt{8x+9}+3 =\sqrt{16y^2-24y+9}+3[/tex]

Divide both sides by 4.

[tex]\frac{\sqrt{8x+9}+3}{4}= \frac{\sqrt{16y^2-24y+9}+3}{4}[/tex]

Simplify.

[tex]\frac{\sqrt{8x+9}+3}{4}= \frac{4y-3+3}{4}[/tex]

[tex]\frac{\sqrt{8x+9}+3}{4}= \frac{4y}{4}[/tex]

[tex]\frac{\sqrt{8x+9}+3}{4}=y[/tex]

Inverse y = [tex]f^{-1}(x)[/tex]

[tex]f^{-1}(x)= \frac{\sqrt{8x+9}+3}{4}[/tex]

Answer:

[tex] f^{-1}(x) = \dfrac{3}{4} \pm \dfrac{1}{4}\sqrt{8x + 9} [/tex]

Step-by-step explanation:

[tex] f^{-1}(x) = 2x^2 - 3x [/tex]

Change function notation to y.

[tex] y = 2x^2 - 3x [/tex]

Switch x and y.

[tex] x = 2y^2 - 3y [/tex]

Solve for y.

[tex] 2y^2 - 3y = x [/tex]

Complete the square on the left side. We must divide both sides by 2 to have y^2 as the leading term on the left side.

[tex] y^2 - \dfrac{3}{2}y = \dfrac{x}{2} [/tex]

1/2 of 3/2 is 3/4. Square 3/4 to get 9/16.

Add 9/16 to both sides to complete the square.

[tex] y^2 - \dfrac{3}{2}y + \dfrac{9}{16} = \dfrac{x}{2} + \dfrac{9}{16} [/tex]

Find common denominator on right side.

[tex] (y - \dfrac{3}{4})^2 = \dfrac{8x}{16} + \dfrac{9}{16} [/tex]

If X^2 = k, then [tex] X = \pm \sqrt{k} [/tex]

[tex] y - \dfrac{3}{4} = \pm \sqrt{\dfrac{1}{16}(8x + 9)} [/tex]

Simplify.

[tex] y = \dfrac{3}{4} \pm \dfrac{1}{4}\sqrt{8x + 9} [/tex]

Back to function notation.

[tex] f^{-1}(x) = \dfrac{3}{4} \pm \dfrac{1}{4}\sqrt{8x + 9} [/tex]

The answer is B. Shooting. Shooting is a sport on dry land, while the other three are aquatic sports, that is, they are on or in the water.