The smallest value of the force that will make the block not to slide down is 10 N.
We'll begin by calculating the normal reaction. This can be obtained as follow:
Mass (m) = 8 KgAcceleration due to gravity (g) = 10 m/s²Normal reaction (N) =?N = mg
N = 8 × 10
N = 80 N
Finally, we shall determine the frictional force.
Coefficient of friction (μ) = 0.4Normal reaction (N) = 80 NFrictional Force (F) =?F = μN
F = 0.4 × 80
F = 32 N
Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the block not to slide down.
From the options given above, only option A has a force that is lesser than the frictional force.
Therefore, the correct answer to the question is Option A. 10 N
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An object, initially at rest, moves 475 m in 19 s. What is its acceleration? *
[tex]\\ \sf\Rrightarrow s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \sf\Rrightarrow s=0(19)+\dfrac{1}{2}a(19)^2[/tex]
[tex]\\ \sf\Rrightarrow 475=\dfrac{361a}{2}[/tex]
[tex]\\ \sf\Rrightarrow 950=361a[/tex]
[tex]\\ \sf\Rrightarrow a\approx 2.3m/s^2[/tex]
Fill in the blanks about Newton’s First Law of Motion:
Objects want to ____________ ____________ doing what they’re ____________ ____________ because they are “lazy.” This is called ____________.
Objects want to continue doing what they’re doing because they are “lazy.” This is called law of inertia.
Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that state unless it is being acted upon by an external force. This law is also called the law of inertia because it depends on mass.
From the given question, we can fill gaps as follows;
Objects want to continue doing what they’re doing because they are “lazy.” This is called law of inertia.
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In a car engine, fuel is ignited within a cylinder to cause an explosion that moves a piston. If the explosion exerts 300 Pa of pressure on a piston with a surface area of 80 cm^2?
The force exerted by the explosion on the piston is 2.4 N.
The given parameters:
Pressure of the explosion on piston, P = 300 Pa (N/m²)Surface area of the piston, A = 80 cm²The force exerted on the piston by the explosion is calculated as follows;
F = PA
where;
A is the area of the piston in m²
The surface area of the piston in square meter is calculated as follows;
[tex]A = 80 \ cm^2 \times \frac{(1m)^2}{(100 \ cm)^2} \\\\A = 0.008 \ m^2[/tex]
The force exerted by the explosion on the piston is calculated as follows;
[tex]F = 300 \ (N/m^2)\ \times \ 0.008 \ (m^2)\\\\F = 2.4 \ N[/tex]
The complete question is here:
In a car engine, fuel is ignited within a cylinder to cause an explosion that moves a piston. If the explosion exerts 300 Pa of pressure on a piston with a surface area of 80 cm^2, what is the force exerted on the piston?
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How much energy is needed just to boil 5kg of water at 100◦ C?
what is volume help plz
Answer:
Explanation:
Volume = Length x width x height
Multiply the length, width and, height to get the volume of the question.
What is the sum of 130+125+191? A. 335. B. 456. C. 446. D. 426.
If we minus 712 from 1500, how much do we get? A. 788. B. 778. C. 768. D. 758.
50 times of 8 is equal to: A. 80. B. 400. C. 800. D. 4000.
110 divided by 10 is: A. 11. B. 10. C. 5. D. None of these.
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A gas in a closed container is heated with 10J of energy, causing the lid of the container to rise 2m with 3N of force. What is the total change in energy of the system
Explanation:
For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.
ΔU=Q−W
We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.
W=FΔx
W=3N×2m
W=6J
Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.
ΔU=Q−W
ΔU=10J−6J
ΔU=4J
Answer is 4J
i think this may help you very much
During chemical reactions, bonds between atoms break and form. What does this mean in terms of subatomic particles? (1 point)
O Electrical fields of charged particles interact, bonding those with the same charge.
Electrical fields of neutral particles interact, bonding those with opposite charges.
O Electrical fields of neutral particles interact, bonding those with the same charge.
o Electrical fields of charged particles interact, bonding those with opposite charges
During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.
What is the chemical bonds?During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.
Since we know that every element have electrons in their atoms and every atom have vacant shells.
So during chemical reactions the elements fulfill their vacant shells and form bonds between each other it can be ionic or it can be covalent bond.
But when atoms breaks the bond their will be the positively or negatively charged electrons left in the atoms.
Hence During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.
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Write any three facts in the support of molecular theory
Answer:
Every gas is made up of very small particles called molecules. Molecules of a gas are separated from each other by large distances so that volume is negligible as compared to total volume of gas. The force of gravitation on the molecules is also negligible.
Hope that helps. x
:
A log has a density of. 8 g/cmÂł. What will happen to this log in freshwater, which has a density of 1. 0 g/cmÂł? It will sink. It will float. It will move deeper. It will decrease in density.
When a log of wood is put over the freshwater, the log start to float. Option B is correct.
Density:
It can be defined as the amount of substance per unit volume. It is usually denoted by D. It is measured in the [tex]\bold { kg/m^3}[/tex].
The less dense object always floats over the more dense substance.
For example- Here, The density of the log is 0.8 [tex]\bold{ cm^3}[/tex] and the density of the of water is 1.0 [tex]\bold{ cm^3}[/tex] .
Since, the density of the log is lesser than the density of the water.
Therefore, when a log of wood is put over the freshwater, the log start to float.
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desventajas de la fricción cinética
Answer:
Please translate this into Spanish! Sorry I can't :(
Explanation:
Disadvantages of Friction:
Friction produces unnecessary heat leading to the wastage of energy.
The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects.
Forest fires are caused due to the friction between tree branches.
A car that's initially traveling at 10 m/s acceleration uniformly for 4 seconds at a rate of 2 m/s?in a straight line. How far does the car travel during this time?
Answer:
Explanation:
The answer is -2m/s²
pls help me, its just fill in the blank
1. Frequency
2. Reflected
3. Absorbed
4. Black
What is science notation
Answer:
Scientific notation is the way that scientists easily handle very large numbers or very small numbers. For example, instead of writing 0.0000000056, we write 5.6 x 10-9. So, how does this work? We can think of 5.6 x 10-9 as the product of two numbers: 5.6 (the digit term) and 10-9 (the exponential term).
Explanation:
I need help!
A car has a mass of 1,200 kg and the road can provide a maximum force of 24 kN on the car what is the maximum acceleration?
Answer:
The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²
Explanation:
A 1500 kg car travels 50 m north in 20 seconds. What is the magnitude of the average velocity of the car during the 20 second interval?
a. 2.5 m/s
b. 5.0 m/s
c. 6.5 m/s
d. 7.0 m/s
Answer:
a. 2.5 m/s
Explanation:
50 / 20 = 2.5 m/s
A car weighing 8000N is traveling at 45 m/s on a perfectly flat, frictionless road. If the driver slams on the brakes, how far will thw car slide before it comes to a stop?
Without friction, the car cannot stop...
A baseball player at practice is pushing a tackling dummy across the field. He initially has to push the 130 kg dummy with 600 Newton’s of force to get it to start moving and maintain a force of 475 to keep it moving at a steady state. What are the coefficient of friction static and kinetic with the dummy on the ground
.
Answer:
Static= 600/(130*9.8)=0.47
Kinetic=475/(130*9.8)=0.37
Read the picture, please. I am a bit confused about what it means when it says which one supports it.
Answer:
not suppoted
not supported
support
A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000 J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car
The final speed of the car at the given conditions is 30.1 m/s.
The given parameters:
Mass of the car, m = 1700 kgVelocity of the car, v = 21 m/sTime of motion, t = 10 sAdditional energy provided by the engine, E₁ = 22,000 JEnergy used in overcoming friction, E₂ = 3,666.67 JThe change in the energy applied to the car is calculated as;
[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]
The final speed of the car is calculated as follows;
[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]
Thus, the final speed of the car at the given conditions is 30.1 m/s.
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explain the difference between vector and scalar quantities
Answer:
vector quantity have both magnitude and direction but scalar quantities have only magnitude
[tex] \huge \rm༆ question ༄[/tex]
Calculus proof of second equation of motion ~
Newton's second equation of motion :-
S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]
This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.
So let's see what pieces of information (bundles of equations) do we have with us, initially.
We have, a very primary equation with us,
dS/dt = v… (I)
(Considering motion in a straight line only)
And we also have the equation
dv/dt = a…(II)
Simply replacing the v in eqn (II) by eqn (I), we find
d2S/dt^2 = a…(III)
This is what we need to solve. It's easy.
You know,
d2S/dt^2 = d/dt(dS/dt) = a
⟹ dS/dt = ∫adt = at+c1
Since, dS/dt is the velocity of the particle,
Therefore, at t = 0, dS/dt|t = 0 = u
⟹ u = a∗0 + c1 = c1
⟹ c1 = u
Therefore, dS/dt = u + at
Thus, S = ∫(udt + atdt)
⟹ S = ut + 1/2at^2 +c^2
If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0
This makes S = S0 +ut + 1/2at^2
Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),
We get
S = ut + 1/2at^2
Hope it helps :)
A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s
The impulse of the boxers punch is 28 kgm/s.
The given parameters;
applied force by the boxer, F = 1400 Ntime of force action, t = 0.02 sThe impulse of the boxers punch is calculated as follows;
[tex]J = Ft[/tex]
where;
F is the applied force (N)t is the time of force action (s)The magnitude of the impulse is calculated as follows;
[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]
Thus, the impulse of the boxers punch is 28 kgm/s.
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PLEASEE IS FOR A TEST!!!Which ionic compound is BOTH correctly written and named??
A mg0 magnesium oxide
B Mn02 manganese oxide
C N02 nitrogen oxide
D SrBr strontium bromide
Answer:
Letter A
Explanation:
Manganese dioxide- Mn02
Nitrogen Dioxide- n02
Strontium bromide- SrBr
Draw a diagram that represents how a mechanical wave interacts with a particular material.
Create a diagram and include reflection, absorption, and transmission.
Write a brief description (3+ sentences) of the interaction of the mechanical waves and the material. Include an explanation of how the amplitude and frequency of the wave are affected.
85 POINTS!!
When mechanical waves interact with material, it transfer its energy to the material.
What are mechanical waves?Mechanical waves are the type of waves that require a medium for transporting their energy from one region to another. Mechanical waves depend on particle interaction in order to transport their energy.
The amplitude and frequency of the wave are negatively affected due to the striking of mechanical waves with the material.
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Answer:
i have a screenshot just use mine https:/ss27
Explanation:
Why don't atoms get too close?
a.) The electrons from atom repel each other
b.) The protons from each atom repel each other
c.) The neutrons from each atom repel each other
Answer:
This tends not to happen, because atoms are composed of charged particles that interact at a distance. ... Since the electrons are around the outside of the atom, those are the things that first interact, and as they have the same charge, they repel one another.A. The electrons from atom repel each other
I need help with this physics question
Answer:
its B hope you have a good Day
What is the relationship between momentum and speed?
Answer:
Momentum is directly proportional to the object's mass and also its velocity.
Explanation:
Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v.
Help if u can please
Answer:
d
Explanation:
Make a super villain out of these resources
Answer:the super villain would have the ability to control electricity and could take any Metal object or weapons that anyone points at him because he is magnetic
Explanation: