what is the volume in liters at 422K if n and P does not change?

Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles[/tex]  

[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]  

According to stoichiometry :

2 moles of [tex]K[/tex] produce = 2 moles of [tex]KOH[/tex]

Thus 0.57 moles of [tex]K[/tex] will produce=[tex]\frac{2}{2}\times 0.57=0.57moles[/tex]  of [tex]KOH[/tex]

Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g[/tex]

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

Answer:

1085° C

Explanation:

From the phase diagram of Ag-Cu shown below:

The minimum value of the high-temp required to be selected for the furnace is: 1085° C

This is on the grounds that the furnace should be chosen to such an extent that it should melt any sort of possible material including pure Cu that melts and liquefies at the temperature of 1085° C.

Answer: Your balanced equation is 2Al + 3S --> Al_2S_3. In two separate equations, first use the 48.5g of Al to find the amount (in moles) of Al_2S_3. Then use the 62.8g of S to find the amount (in moles) of Al_2S_3. By doing these, you find which reactant (the Al or the S) produces the least amount of Al_2S_3. Since it's the S, that's the limiting reactant: you then use that 62.8g of S to find how many grams of Al will be used in the reaction. (Use the same balanced equation.) You find that 35.2g of Al will be used, then find the excess by subtracting that 35.19 from the original 48.5g. Your excess amount is 13.3g of Al!

Explanation:

hopefully this is what you were looking for <3 :)

The amount of excess reactant that left over the chemical reaction between aluminum and ammonium perchlorate is 0.9 moles.

Mass into moles (n) will be converted by using the below equation as:

n = W/M, where

W = given mass

M = molar mass

Moles of 45g of Aluminum = 45g / 27g/mol = 1.66 mol

Moles of 301g of ammonium perchlorate = 301g / 117.4g/mol = 2.56 mol

Both reactants are reacted with each other and one of the reactant is fully consumed, so the excess reactant will be calculated as:

Excess reactant = 2.56mol - 1.66mol = 0.9 moles

Hence amount of excess reactant is 0.9 moles.

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Answer: D

Explanation:

The radioactive dating is also called the radiometric dating. It involves the use of several radioactive substances like Argon, uranium, etc. The correct option is D.

The method of dating rocks and minerals using the radioactive isotopes is defined as the radioactive dating. This method is very helpful to determine the age of igneous and metamorphic rocks which cannot be measured using correlation method.

Many different radioactive isotopes and methods can be used for dating. The elements like uranium and potassium contain a number of different isotopes whose half life is known exactly and thus the concentration of these isotopes within a rock or mineral can measure the age.

The method radiocarbon dating is also used for determining the age of archaeological carbonaceous objects such as wood samples or animal fossils by measuring the radioactivity of ¹⁴C present in them.

Thus the correct option is D.

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Answer:

Empirical formula: CH

Molecular formula: C₆H₆

Explanation:

Based on the combustion of a hydrocarbon, the moles of CO₂ = Moles of Carbon in the hydrocarbon and the moles of H₂O = 1/2 moles of hydrogen in the hydrocarbon.

The empirical formula is the simplest whole number of atoms present in a molecule. With the moles of C and H we can find empirical formula:

Moles C -Molar mass CO₂ = 44.01g/mol-:

13.82g * (1mol / 44.01g) = 0.314 moles C

Moles H -Molar mass H₂O = 18.01g/mol-:

2.829g H₂O * (1mol / 18.01g) = 0.157 moles H₂O * (2mol H / 1mol H₂O) = 0.314 moles of H

The ratio of moles H: moles C:

0.314 moles / 0.314 moles = 1

That means empirical formula is:

With the molecular weight and empirical formula we can find the molecular formula:

Molar mass CH = 12.01g/mol+1.01g/mol = 13.02g/mol

As the molecular weight of the molecule is 78.11amu = 78.11g/mol, there are:

78.11g/mol / 13.02g/mol = 6 times the empirical formula in the molecular formula

That means molecular formula is:

Answer:

Phototropism.

Explanation:

Phototropism is the phenomenon of plants growing in response to light. This is a response to the plants to align or steer towards the source of sunlight, thereby becoming the 'path' to their growth.

The term "photo" means light and "tropism" means "growth" or movement towards". So, we can safely say that phototropism is the scientific and natural phenomenon of plants growing towards or in response to the sunlight.

Thus, the correct answer is phototropism.

Answer:

the bond b/w oxygen and hydrogen atom

Answer: A, the bonds between the two hydrogen atoms and between the two oxygen atoms.

Answer:

14.91 mL

Explanation:

Assuming the weak acid is monoprotic, we can solve this problem using the equation:

Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.

We input the data:

And solve for V₂:

The volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.

Volume for the given solution will be calculated from the below equation:

M₁V₁ = M₂V₂, where

M₁ = Molarity of weak acid = 0.1084 M

V₁ = volume of weak acid = 25 mL

M₂ = molarity of NaOH = 0.1817 M

V₂ = volume of NaOH = to find?

On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL

Hence required volume is 14.91 mL.

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Answer:

Fractional distillation is a method for separating a liquid from a mixture of two or more liquids. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points. When the mixture is heated, one liquid evaporates before the other.

Answer:

That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.

Explanation:

If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O

If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O

The question is incomplete, the complete question is;

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with =n10 to an orbital with =n8. Round your answer to 3 significant digits.

Answer:

162 * 10^-7 m

Explanation:

The Rydberg formula is;

1/λ= R(1/n2^2 - 1/n1^2)

R = Rydberg constant = 1.097 * 10^7 m-1

n2 = final state of the electron = 8

n1 = initial state of the electron = 10

Substituting values;

1/λ= 1.097 * 10^7(1/8^2 - 1/10^2)

1/λ= 1.097 * 10^7(1/64 - 1/100)

  1 / λ = 1.097 10⁷ (0.015625 - 0.01)

1 /λ = 0.006170625 10⁷

λ = (0.006170625 10⁷)^-1

λ = 162 * 10^-7 m

Answer:

It is a electrolyte.

Explanation:

I took the test.

It represents an electrolyte.

A level under three can cause muscle weakness, spasms, cramps, paralysis, and respiratory problems. If it continues, kidney problems may occur.

Electrolytes are substances that have a natural positive or negative electrical charge when dissolved in water. They help your body regulate chemical reactions, maintain the balance between fluids inside and outside your cells, and more.

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Answer:

The answer is (-31.58, 0) when rounded to 2 decimal places.

Answer:

See explanation

Explanation:

The term IHD means index of hydrogen deficiency. It tells us the number of missing hydrogen atoms from a given chemical formula. This number of missing hydrogen atoms corresponds to the number and type of multiple bonds in a given compound.

The formula for IHD is; IHD = C + 1 + N/2 – H/2 – X/2

C = Number of carbon atoms

N = Number of nitrogen atoms

H = Number of hydrogen atoms

X = Number of halogen atoms

Since;

N=0, X=0

Then;

IHD = C + 1 – H/2

Hence;

IHD = 6 + 1 - 14/2

IHD = 7 -7

IHD = 0

An IHD of 0 implies that there is no hydrogen deficiency or multiple bond in the molecule. It is purely a saturated compound.

Answer:

80.% carbon and 20.% hydrogen

Explanation:

Ethane has molecular formula C2H6. So What is the composition of carbon and hydrogen in ethane. its alot to explain but yea thats wht i got

Answer:

Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.

Explanation:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

[tex]n = \frac{2.56 \times {10}^{13} }{6.02 \times {10}^{23} } \\ \\ \\ = 4.25 \times {10}^{ - 11} \: \: \: moles[/tex]

Hope this helps you

Answer:

Rain is a liquid and hail is a solid.

Answer: D. CYTOKINESIS

Explanation:

Mitosis ends with telophase, or the stage at which the chromosomes reach the poles. ... Telophase is followed by CYTOKINESIS, or the division of the cytoplasm into two daughter cells.

Answer:

it is a little fuzzy

Explanation:

In general, salts (formed during a neutralization reaction) are ionic compounds that are soluble in water and dissociate in solution into ions that conduct electricity. Out of the six statements given, there are three related statements that rehash the foregoing, and there are three related statements that are collectively incorrect.

Statements A, B, and D are (generally) true regarding salts formed during a neutralization reaction. When you consider that the net ionic equation of many acid-base neutralization reactions is H⁺(aq) + OH⁻(aq) → H₂O(l), the counterions of the H⁺(aq) and OH⁻(aq) are the aqueous spectator ions that comprise the salt. These ions are electrolytes, as they are charged species that can carry a current in solution; they are ionic compounds by definition since they're composed of cations and anions; and, as aqueous species, they're clearly dissolved in water.

Statements C, E, and F, as a whole, generally aren't true of such salts.

Answer:

C

Explanation:

Perfume needs to evaporate in order to smell.  If this perfume didn't evaporate, it would stay as a liquid and never smell.  

It wouldn't be D, as no toxic perfumes is sold.

It's not A because perfume doesn't have to be pressurized in order to not evaporate.

It's not B, as it is a hasty conclusion to the claim.  Plus, if the perfume did have an odor, even while not evaporating, the sales would be low as the product is that good.  

Answer:

Explanation: Reaction of oxygen with chromium(II) and chromium(III) porphyrins and synthesis of a .mu.-oxo chromium porphyrin derivative.

tion:

Answer: polyatomic

Explanation:hope you find helpful

Answer:

69

Explanation:

Answer:

the plane will crash, or if it is usable or not.

Answer: The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.

Explanation:

The basic rules for naming of organic compounds are :

1. First select the longest possible carbon chain. The longest possible carbon chain should include the carbons of double or triple bonds or functional group.For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and ketones by adding the suffix -one.;

3. The numbering is done in such a way that the carbon containing the functional group gets the lowest number. While writing the name, the word root is given first , followed by the position of carbon containing the functional group followed by the suffix.

The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.