What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?

Answer:

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Explanation:

Answer:

v = 8.46 m/s

Explanation:

Given that,

Mass of the object, m = 14.6 g

Spring constant of the spring, k = 15.7 N/m

It is released from rest with an amplitude of 29.8 cm.

We need to find the speed of the mass when it is halfway to the equilibrium position if the surface is frictionless.

We can use the conservation of energy in this case. Let v be the speed of the mass. So,

[tex]EPE_i=\dfrac{1}{2}mv^2+EPE_f\\\\\dfrac{1}{2}kx_i^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx_f^2[/tex]

Substitue all the values in the above expression.

[tex]\dfrac{1}{2}\times 15.7\times (0.298)^2=\dfrac{1}{2}\times 0.0146\times v^2+\dfrac{1}{2}\times 15.7\times (\dfrac{0.298}{2})^2\\\\v=8.46\ m/s[/tex]

So, the speed of the mass is equal to 8.46 m/s.

Answer:

a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]

b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]

c) the magnitude of the net momentum is 54102.5 kgm/s

Explanation:

Given the data in the question;

a) x-component of the net momentum of this system.

the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up

so;

Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]

Px = 44200 kgm/s [tex](-x)[/tex]

Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]

b) y-component of the net momentum of this system

Also, momentum along y-axis is entirely provided by the sedan

Py = 1300 kg × 24.0 m/s [tex](y)[/tex]

Py = 31200 kgm/s [tex](y)[/tex]

Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]

c) magnitude of the net momentum?

magnitude of the net momentum P = √( Px² + Py² )

so we substitute  

P = √( (44200)² + (31200)² )

P = √( 2927080000 )

P = 54102.5 kgm/s

Therefore, the magnitude of the net momentum is 54102.5 kgm/s

Answer:

The answer is "[tex]1155\ \frac{kg}{m^3}[/tex]"

Explanation:

Please find the complete question in the attached file.

[tex]p = p_0 + ?gh[/tex]

pi = pressure only at two liquids' devices

PA = pressure atmosphere.

1 = oil density

2 = uncertain fluid density

[tex]h_1 = 11 \ cm\\\\h_2= 3 \ cm[/tex]

The pressures would be proportional to the quantity [tex]11-3 = 8[/tex] cm from below the surface at the interface between both the oil and the liquid.

[tex]\to p_A + ?2g(h_1 - h_2) = p_A + ? 1gh_1\\\\\to ?2 = \frac{?1h_1}{(h_1 - h_2)} \\\\[/tex]

       [tex]= \frac{840 \frac{kg}{m^3}}{\frac{11}{8}} \\\\= 1155\ \frac{kg}{m^3}[/tex]

Answer:

v₀ = 60.38 mi / h

Explanation:

For this exercise let's start by using Newton's second law

Y axis

        N-W = 0

        N = W

X axis

         fr = m a

the expression for the friction force is

         fr = μ N

we substitute

        μ mg = m a

        μ g = a

calculate us

         a = 0.620   9.8

         a = 6.076 m / s²

now we can use the kinematics relations

          v² = v₀² - 2 a x

suppose v = 0

          v₀ = [tex]\sqrt{2ax}[/tex]

let's calculate

         v₀ = [tex]\sqrt{2 \ 6.075 \ 60.0}[/tex]

         v₀ = 27.00 m / s

let's slow down to the english system

          v₀ = 27.0 m / s (3.28 ft / 1m) (1 mile / 5280 ft) (3600s / 1h)

          v₀ = 60.38 mi / h

With this stopping distance, the starting speed should have been 60.38, which is much higher than the maximum speed allowed.

Answer:

A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.

Explanation:

Answer:

[tex]0.000835\ \text{m}[/tex]

Explanation:

d = Distance between plates = 2 mm

V = Potential difference = 500 V

v = Velocity of proton = [tex]2\times 10^5\ \text{m/s}[/tex]

a = Acceleration

m = Mass of proton = [tex]1.67\times 10^{-27}\ \text{kg}[/tex]

Electric field is given by

[tex]E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{500}{2\times 10^{-3}}\\\Rightarrow E=250000\ \text{V/m}[/tex]

Force balance is given by

[tex]ma=qE\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times 250000}{1.67\times 10^{-27}}\\\Rightarrow a=2.395\times 10^{13}\ \text{m/s}^2[/tex]

We have the relation

[tex]v^2=u^2+2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(2\times 10^5)^2-0}{2\times 2.395\times 10^{13}}\\\Rightarrow s=0.000835\ \text{m}[/tex]

The farthest distance from the negative plate that the proton reaches is [tex]0.000835\ \text{m}[/tex].

The farthest distance from the negative plate that the proton reaches will be s=0.000835 m

The electric field is defined as the force across the charged particles which attract or repel the other charged particles.

Now it is given in the question that

d = Distance between plates = 2 mm

V = Potential difference = 500 V

v = Velocity of proton =   [tex]2\times 10^5\ \dfrac{m}{s}[/tex]

a = Acceleration

m = Mass of proton = [tex]1.67\times10^{-27} kg[/tex]

The Electric field will be calculated as

[tex]E=\dfrac{V}{d}[/tex]

[tex]E=\dfrac{500}{2\times10^{-3}} =250000\ \frac{V}{m}[/tex]

Force balance is given by

[tex]ma=qe[/tex]

[tex]a=\dfrac{qE}{m}[/tex]

[tex]a=\dfrac{1.6\times10^{-19}\times250000}{1.67\times10^{-27}}[/tex]

[tex]a=2.395\times 10^{13}\frac{m}{s^2}[/tex]

Now from equation of motion

[tex]v^2=u^2+2as[/tex]

[tex]s=\dfrac{v^2-u^2}{2a}[/tex]

[tex]s=\dfrac{(2\times10^5)^2-0}{2\times 2.395\times 10^{13}}[/tex]

[tex]s=0.000875 m[/tex]

Thus the farthest distance from the negative plate that the proton reaches will be s=0.000835 m

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Answer:

w = 3.6087 10⁶ rpm

Explanation:

The centripetal acceleration is

         a = v²/r

where r is the distance from the center of rotation and v is the magnitude of the velocity

let's reduce to the SI system

        r = 7.0 cm (1m / 100cm) = 0.070 m

the angular and linear variables are related

         v = w r

we substitute

         a = w² r

         w = [tex]\sqrt{\frac{a}{r} }[/tex]

         w = [tex]\sqrt{ \frac{100000^2}{0.07} }[/tex]

         w = 3.779 10⁵ rad / s

let's reduce to rpm

          w = 3.779 10⁵ rad / s (1rev / 2pi rad) (60 s / 1min)

          w = 3.6087 10⁶ rpm

Answer:

m = 24146.34 kg

Explanation:

The heat of fusion is defined as the amount of heat required to melt a unit mass of a substance completely. Hence, it can be calculated by the following formula:

[tex]H = \frac{Q}{m}\\\\m = \frac{Q}{H}[/tex]

where,

m = mass of copper = ?

Q = Heat absorbed by rod = 4950000000 J

H = Heat of fusion of copper = 205000 J/kg

Therefore,

[tex]m = \frac{4950000000\ J}{205000\ J/kg}[/tex]

m = 24146.34 kg

Answer:

C. both A and B

Explanation:

Sana nakatulong

Answer:

The tension in the horizontal string is 7.2 N

Explanation:

With the assumption that the ice surface has no friction, the tension in the horizontal string is equal to the centripetal force, 'F', acting on the string to keep it in circular motion

[tex]The \ centripetal \ force, \ F = m \times \dfrac{v^2}{r}[/tex]

Where;

m = The mass of the object in the circular

v = The tangential velocity of the object

r= The radius of the circle through whose path the object is moved

The given parameters are;

The mass of the toy that is whirled in a circle by the string, m = 2 kg

The radius of the circle the toy's path turns, r = 2.5 meters

The velocity of the toy at the instant the tension is sought, v = 3 m/s

Therefore, we get;

[tex]The \ centripetal \ force, \ F = 2 \, kg \times \dfrac{(3 \, m/s)^2}{2.5 \, m} = 7.2 \, N[/tex]

The centripetal force, F = 7.2 N = The tension in the horizontal string

∴ The tension in the horizontal string = 7.2 N.

Answer:

5

Explanation:

From the question given above, the following data were obtained:

Proton number = 2

Neutron number = 3

Mass number =.?

The mass number of a given atom is simply the sum of the protons and neutrons in the nucleus of the atom. Mathematically, it is expressed as:

Mass number = proton + neutron

With the above formula, we can obtain the mass number of the atom as follow:

Proton number = 2

Neutron number = 3

Mass number =.?

Mass number = proton + neutron

Mass number = 2 + 3

Mass number = 5

Thus, the mass number the atom is 5.

Answer:

6. 9.4 m

7. 1050 m/s.

Explanation:

6. Determination of the wavelength

Velocity (v) = 30 m/s

Frequency (f) = 3.2 Hz

Wavelength (λ) =?

v = λf

30 = λ × 3.2

Divide both side by 3.2

λ = 30 / 3.2

λ = 9.4 m

Thus, the wavelength of the wave is 9.4 m.

7. Determination of the speed of the wave.

Wavelength (λ) = 350 m

Frequency (f) = 3 Hz

Velocity (v) =.?

v = λf

v = 350 × 3

v = 1050 m/s

Thus, the speed of the wave is 1050 m/s

Answer:

one or two three or four

Explanation:

animals of CO2 gas find the final temperature of gas

The final temperature of the 2 moles of gas has been 0.0014 K.

The gas has been assumed to be the ideal gas. The moles of the has been n. According to the ideal gas equation:

(a) PV= nRT.

For the reversible expansion of 1 mole of gas:

P = [tex]\rm \dfrac{RT}{V - b}\;\times\;\dfrac{a}{V^2}[/tex]

For n moles of gas, the reversible expansion will be:

P = [tex]\rm \dfrac{nRT}{V - b}\;\times\;\dfrac{a}{V^2}[/tex]

The final temperature of the reversible expansion has been:

[tex]\rm T_f\;=\;T_i\;+\;\dfrac{an^2\;[\frac{1}{Vf\;-\;\frac{1}{Vi} } ]}{Cv}[/tex]

(B) The ideal gas equation can be given as:

[tex]\rm \dfrac{P1V1}{nT1}\;=\; \dfrac{P2V2}{nT2}[/tex]

Substituting the values:

[tex]\rm \dfrac{40}{2\;\times\;350}\;=\;\dfrac{80}{2\;\times\;T2}[/tex]

T2 = 0.0014 K.

The final temperature of the 2 moles of gas has been 0.0014 K.

(c) The work done can be given by:

W = nRT In[tex]\rm \dfrac{V2}{V1}[/tex]

The internal energy of the system has been given by:

[tex]\Delta[/tex]U = [tex]\rm C_v[/tex][[tex]\rm T_f\;-\;T_i[/tex]] - a[tex]\rm n^2[/tex] [tex]\rm [\dfrac{1}{Vf}\;-\;\dfrac{1}{Vi} ][/tex]

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Answer:

The answer is D (It reduced his average

force.)

Answer:

Acoustics

Explanation:

It's the one that has a concave line running upward.

Answer:

its the middle one

Explanation:

i did it on edge 2021

Answer:

More than four-fifths of the single points of light we observe in the night sky are actually two or more stars orbiting together. The most common of the multiple star systems are binary stars, systems of only two stars together.o

Answer:

The speed of the knife after passing through the target is 9.33 m/s.

Explanation:

We can find the speed of the knife after the impact by conservation of linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]

Where:

[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg

[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg

[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s

[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s

[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?

[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)

Taking as a positive direction the direction of the knife movement, we have:

[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]  

[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]

Therefore, the speed of the knife after passing through the target is 9.33 m/s.

I hope it helps you!              

On lowering the temperature of the given reaction, H₂ gas and N₂ gas would react to produce more NH₃. Therefore, option (A) is correct.

When the chemical reaction is exothermic then increasing the temperature will cause the backward reaction to occur, decreasing the amounts of the products while increasing the amounts of reactants. Lowering the temperature will produce more reactants and cause the reaction to occur in the forward direction.

The formation of the ammonia is an exothermic reaction that can be represented as:

N₂  (g) +  3 H₂ (g) ⇄  2NH₃ (g)

If the temperature will be decreased, the chemical reaction will proceed forward to produce more heat. The effect of temperature on equilibrium will change the value of the equilibrium constant of the chemical reaction. The production of more ammonia on lowering the temperature.

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Answer:

final velocity = 0

because the train stoped

so,

Answer:

Explanation:

In a standing wave function[tex]\psi (x,t) = A sin(kx)[/tex] characterized for x between (0.a). on the off chance that the amplitude of the wave interchange from positive to negative at the interval. there probably been a node at [tex]x_0[/tex], among 0 and a to such an extent that [tex]0<x_0 <a[/tex]. The reasoning is right that the likelihood of discovering the particle at the node [tex]x_0[/tex] is 0 in light of the fact that by definition, the nodes of the wave are the place where the wave function falls and is equivalent to 0. Since the likelihood of discovering a particle at a position [tex]x_0[/tex] at time [tex]t_0[/tex], is provided by [tex]P=|\psi(x_0,t_0)|^2 dx[/tex], this implies that at the nodes of a standing wave,

[tex]P = | \psi (x_0,t_0)|^2 \ dx \\ \\ P = |0|^2 dx \\ \\ P = 0[/tex]

 So the reasoning that the likelihood of the particle being at [tex]x_0[/tex] is 0 is right.  

However, to examine whether the particle can travel from a position  [tex]x <x_0[/tex] to a position of [tex]x_0>x[/tex]. All together words, can the molecule be found on one or the other side of the node?

The appropriate response is yes.  

Recall that in quantum mechanics. wave functions at most present with the likelihood of discovering a particle at a specific time inside a time frame. The wave function doesn't present with an old classical actual trajectory that a particle should follow to go in space: all things being equal, it simply yields chances of whether a particle can be found in a specific spot at a specific time. So the reasoning that a particle can't get from a position [tex]x <x_0[/tex] to a position of [tex]x>x_0[/tex], is incorrect.

Answer:

The electric field will be decreased by 29%

Explanation:

The distance between point P from the distance z = 2.0 R

Inner radius = R/2

Outer raidus = R

Thus;

The electrical field due to disk is:

[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])

[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]

Similarly;

[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]

However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]

[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]

[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]

Answer:

What is the question on the testtt

Answer:its 2kg

Explanation:

Answer:

D. A lower Voltage into a higher

Answer:

image distance = -8.47 cm

diameter of the image = 0.769 cm