What is the wavelength of a photon with energy 8.87x10-28J? Answer to 3 significant figures: ___ ___ ___?

Answers

Answer 1

Answer: the wavelength of the photon is approximately 3.58 × 10^-18 meters.

Explanation: where E is the energy of the photon, h is Planck's constant, f is the frequency of the photon, c is the speed of light, and λ is the wavelength of the photon.

We can rearrange this equation to solve for the wavelength:

λ = hc/E

where all variables have their previously defined meanings.

First, we need to convert the energy from joules to electronvolts (eV), which is a more commonly used unit for photon energy:

8.87 × 10^-28 J = 8.87 × 10^-28 J / 1.602 × 10^-19 J/eV = 5.53 × 10^-10 eV

Next, we can substitute the given values into the equation:

λ = (6.626 × 10^-34 J s) × (2.998 × 10^8 m/s) / (5.53 × 10^-10 eV)

Simplifying, we get:

λ = 3.580 × 10^-18 m

Finally, we can express the wavelength in scientific notation with three significant figures:

λ = 3.58 × 10^-18 m


Related Questions

For the reaction: N₂(g) + 3H₂(g) + 2NH3(g) AH = -76.4 KJ/mol. Determine the heat energy when 5.0g of hydrogen burns.​

Answers

Answer:

-191 kJ

Explanation:

The given reaction is:

N₂(g) + 3H₂(g) → 2NH₃(g) ΔH = -76.4 kJ/mol

From the balanced equation, we can see that the stoichiometric ratio between hydrogen (H₂) and ammonia (NH₃) is 3:2. This means that 3 moles of hydrogen react to produce 2 moles of ammonia.

To determine the heat energy when 5.0 g of hydrogen (H₂) burns, we need to follow these steps:

Step 1: Calculate the moles of hydrogen (H₂)

Using the molar mass of hydrogen (H₂), which is 2 g/mol, we can calculate the moles of hydrogen (H₂) in 5.0 g of hydrogen:

Moles of H₂ = Mass of H₂ / Molar mass of H₂

Moles of H₂ = 5.0 g / 2 g/mol

Moles of H₂ = 2.5 mol

Step 2: Use the stoichiometry of the reaction

Based on the stoichiometry of the reaction, we know that 3 moles of hydrogen (H₂) react to produce 2 moles of ammonia (NH₃), and the enthalpy change (ΔH) is -76.4 kJ/mol.

Step 3: Calculate the heat energy

The heat energy for 2.5 moles of hydrogen (H₂) can be calculated using the given enthalpy change (ΔH) and the stoichiometry of the reaction:

Heat energy = Moles of H₂ x ΔH

Heat energy = 2.5 mol x -76.4 kJ/mol

Heat energy = -191 kJ (rounded to three significant figures)

So, the heat energy when 5.0 g of hydrogen (H₂) burns is -191 kJ (rounded to three significant figures), and the negative sign indicates that the reaction is exothermic, releasing heat.

How many grams of Aluminum Sulfate are produced when 4 g of Aluminum Nitrate react with 3 g of Sodium Sulfate?

Al(NO3)3 + Na2SO4 ---------> Al2(SO4)3 + NaNO3

Answers

3.21 grams of Aluminum Sulfate are got when 4 g of Aluminum Nitrate reacts chemcially with 3 g of Sodium Sulfate.

WHat is the balanced equation for this reaction? How many grams of Aluminum Sulfate are produced?

The equation given is not balanced. Thus,  when balanced the equation becomes:

2 Al(NO₃)₃ + 3 Na₂SO₄ → Al₂(SO₄)₃ + 6 NaNO₃

The molar mass of Al(NO₃)₃ is:

Al(NO₃)₃ = 1(Al) + 3(N) + 9(O) = 213 g/mol

The molar mass of Na₂SO₄ is:

Na₂SO₄ = 2(Na) + 1(S) + 4(O) = 142 g/mol

From the balanced equation, we can see that 2 moles of Al(NO₃)₃ react with 3 moles of Na2SO4 to produce 1 mole of Al₂(SO₄)₃. Therefore, we can calculate the number of moles of Al(NO₃)₃ and Na₂SO₄ that react:

Number of moles of Al(NO₃)₃ = 4 g / 213 g/mol = 0.0188 mol

Number of moles of Na₂SO₄ = 3 g / 142 g/mol = 0.0211 mol

From the balanced equation, we can see that 2 moles of Al(NO₃)₃ produce 1 mole of Al₂(SO₄)₃. Therefore, the number of moles of Al₂(SO₄)₃ produced is:

Number of moles of Al₂(SO₄)₃ = 0.0188 mol / 2 * 1 = 0.0094 mol

The molar mass of Aluminum Sulfate (Al₂(SO₄)₃) is:

Al₂(SO₄)₃ = 2(Al) + 3(S) + 12(O) = 342 g/mol

Therefore, the mass of Aluminum Sulfate produced is:

Mass of Al₂(SO₄)₃ = Number of moles of Al₂(SO₄)₃ * Molar mass of Al₂(SO₄)₃

= 0.0094 mol * 342 g/mol

= 3.21 g

Hence, 3.21 grams of Aluminum Sulfate are liberated when 4 g of Aluminum Nitrate change state with 3 g of Sodium Sulfate.

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. Mercury is the only metal which is a liquid at room temperature. The density of mercury is 13.6 g/cm3. What is the mass, in pounds, of 1.00 quart of mercury? [1 liter = 1.057 quart; 1 pound = 453.6 grams]

Answers

According to the question the 1.00 quart of mercury has a mass of 0.0283 lb.

What is mercury?

Mercury is the smallest and innermost planet in the Solar System. It is a terrestrial planet with a thin atmosphere composed mostly of oxygen, sodium, and helium. It is one of four rocky planets on the inside of the Solar System, the other three being Venus, Earth and Mars. Mercury is named after the Roman deity Mercury, the messenger of the gods. It is a very dense planet due to its large iron core and its small size.

1 quart = 0.946 liters
1.00 quart of mercury has a mass of 13.6 g/cm³ x 0.946 liters = 12.8 g
To convert the mass of mercury from grams to pounds, divide 12.8 g by 453.6 g/lb.
12.8 g / 453.6 g/lb = 0.0283 lb
Therefore, 1.00 quart of mercury has a mass of 0.0283 lb.

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Ascorbic acid ( H2C6H6O2 ) is a diprotic acid with a1=8.00×10−5 and a2=1.60×10−12. Determine the pH of each solution.

A 0.190M ascorbic acid ( H2C6H6O2 ) solution.
pH=

A 0.190M sodium ascorbate ( Na2C6H6O2) solution.
pH=

Answers

Ascorbic acid, also known as Vitamin C, is a water-soluble vitamin that plays an important role in many biological processes in the human body

How do you find out the pH of the given ascorbic acid solution?

For the first part

Step 1: Write the dissociation reactions of H₂C₆H₆O₂ in water:

H₂C₆H₆O₂ ⇌ H⁺ + HC₆H₆O²⁻

HC₆H₆O²⁻ ⇌ H⁺ + C₆H₆O₂²⁻

Step 2: Write the equilibrium expressions for each dissociation reaction:

Kₐ₁= [H⁺][HC₆H₆O²⁻ ] / [H₂C₆H₆O₂]

Kₐ₂= [H⁺][C₆H₆O₂²⁻] / [ HC₆H₆O²⁻]

Step 3: Use the given values of Kₐ₁ and Kₐ₂ to set up an ICE table and solve for [H⁺] and pH.

Kₐ₁  = 8.00×10⁻⁵

Kₐ₂ = 1.60×10⁻¹²

[H₂C₆H₆O₂] = 0.190 M

Let x be the concentration of [H⁺] from the dissociation of H₂C₆H₆O₂

[H⁺] = x M

[HC₆H₆O²⁻] = x M

[C₆H₆O₂²⁻] = x(Kₐ₁/Kₐ₂) M

Now, we can substitute the values into the equilibrium expressions to get:

Kₐ₁ = (x)(x) / (0.190-x)

Kₐ₂ = (x)(x(Ka1/Ka2)) / x

Simplifying and solving for x, we get:

x = 7.62 × 10⁻⁴ M

pH = -log[H⁺] = 3.12

Therefore, the pH of a 0.190 M ascorbic acid solution is 3.12.

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The most common nosocomial infection in patients admitted to the hospital?
Rationale: Harding, M., Kwong, J., Roberts, D., Hagler, D., & Reinisch, C. (2020). Lewis’s Medical-surgical nursing : Assessment and management of clinical problems (11th ed.,). Elsevier, Inc.

Answers

Urinary tract infection is the most common nosocomial infection in patients admitted to the hospital. Surgical site wound infections, bacteremia, and gastrointestinal and skin infections are among the most common nosocomial infections.

What is nosocomial infection after hospitalization?

A hospital-acquired infection, also known as a nosocomial infection, occurs in a hospital or other healthcare setting. It is sometimes referred to as a healthcare-associated infection to emphasize both hospital and nonhospital settings.

Is a nosocomial infection defined as an infection acquired during a hospital stay?

Nosocomial infections, also known as healthcare-associated infections (HAI), are infections acquired while receiving healthcare that was not present at the time of admission.

What is the term for a patient's hospital-acquired infection?

Healthcare-Acquired Infections (HAIs), also known as Healthcare-Associated Infections, are infections contracted while receiving treatment at a healthcare facility, such as a hospital, or from a healthcare professional, such as a doctor or nurse.

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what is the amount of power produced if 35Nm of work is done in 5 seconds

Answers

Answer:

70 watts

Explanation:

Question
In which of the following processes will ΔS°
be negative?

a) C2H5OH(l)→C2H5OH(g)

b) NaCl(s)→NaCl(l)

c) CO2(s)→CO2(g)

d) Cl2(g)→Cl2(l)

Answers

The right response is (b).

The entropy of a framework is a proportion of its problem or irregularity. A framework with more confusion has a higher entropy. By and large, processes that include a lessening all together or an expansion in the quantity of potential states for the framework will have a negative ΔS°.

During the time spent dissolving sodium chloride (NaCl) in water, the strong NaCl breaks up into individual Na+ and Cl-particles. This outcomes in a lot more prominent number of potential states for the framework, as the particles can move around uninhibitedly in the arrangement. Hence, the entropy of the framework increments, and ΔS° is positive.

During the time spent freezing water (H2O), the fluid water particles organize themselves into a normal precious stone design. This outcomes in a diminishing in the quantity of potential states for the framework, as the particles are currently bound to a particular area in the gem. In this way, the entropy of the framework diminishes, and ΔS° is negative.

During the time spent sublimation, strong carbon dioxide (CO2) changes straightforwardly into vaporous carbon dioxide (CO2). This doesn't include an adjustment of the quantity of moles of gas, however it includes an adjustment of the condition of issue. Gases have a higher entropy than solids, so the entropy of the framework increments, and ΔS° is positive.

During the time spent gathering chlorine gas (Cl2) into fluid chlorine (Cl2), the vaporous chlorine particles orchestrate themselves into an ordinary fluid design. This outcomes in a reduction in the quantity of potential states for the framework, as the particles are currently restricted to a particular area in the fluid. Subsequently, the entropy of the framework diminishes, and ΔS° is negative.

Cl2(g)→Cl2(l): ∆S° will be negative because the disordered gas is converted to the ordered liquid. Therefore, option (D) is correct.

What is The entropy change (∆S°)?

The entropy change (∆S°) refers to the change in the degree of disorder or randomness of a system in a chemical reaction or physical change that occurs at a constant temperature and pressure. It is a thermodynamic function that measures the amount of energy that is unavailable to do useful work in a system.

If ∆S° is positive, it indicates an increase in entropy, which means that the system becomes more disordered, chaotic, and random. In contrast, if ∆S° is negative, it indicates a decrease in entropy, which means that the system becomes more ordered, organized, and predictable.

The ∆S° value is affected by several factors, such as the physical state of the reactants and products, the number of particles involved, and the temperature and pressure at which the reaction occurs. A negative ∆S° value suggests that the reaction favors the reactants, whereas a positive ∆S° value indicates that the reaction favors the products.

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A balloon ascends at a constant rate V in an atmosphere that is exponentially stratified so that the variation of temperature with altitude is given by T(z) -Toe". The balloon carries a thermocouple temperature sensor having a time constant t. Determine the sensor temperature as a function of time. Sketch the sensor temperature and the actual temperature versus time

Answers

We can plug them into the equation above and plot the temperature of the sensor and the actual temperature against time on a graph to visualize how they change over time during the ascent of the balloon.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance, such as a solid, liquid, or gas. It is a scalar quantity that reflects the hotness or coldness of a substance. In other words, temperature indicates how much thermal energy is present in a substance.

This equation describes an exponential decay of the temperature with time. As time goes on, the temperature of the sensor decreases exponentially towards zero.

To sketch the sensor temperature and the actual temperature versus time, we would need additional information, such as the initial temperature T0, the time constant tc, and the rate of ascent V of the balloon.

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Which amount of sodium hydroxide is would react exactly with 7.5g of a diprotic acid,H2A(Mr = 150)?

Answers

0.1 mol of sodium hydroxide (NaOH) would react exactly with 7.5 g of the diprotic acid [tex]H_{2}[/tex]A.

What is Molar Mass?

Molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule or the formula mass of all the ions in an ionic compound.

The balanced chemical equation for the reaction between diprotic acid, [tex]H_{2}[/tex]A, and sodium hydroxide, NaOH, can be represented as follows:

2[tex]H_{2}[/tex]A + 2 NaOH -> [tex]Na_{2}[/tex]A + 2 [tex]H_{2}[/tex]O

From the balanced equation, we can see that 2 moles of [tex]H_{2}[/tex]A react with 2 moles of NaOH to produce 1 mole of [tex]Na_{2}[/tex]A and 2 moles of water ([tex]H_{2}[/tex]O).

First, we need to calculate the number of moles of [tex]H_{2}[/tex]A in 7.5g using the formula:

moles = mass / molar mass

moles of [tex]H_{2}[/tex]A = 7.5g / 150 g/mol = 0.05 mol

Since diprotic acid, [tex]H_{2}[/tex]A, reacts in a 1:2 ratio with NaOH, we need to multiply the moles of [tex]H_{2}[/tex]A by 2 to determine the moles of NaOH required for complete reaction:

Moles of NaOH = 2 * Moles of [tex]H_{2}[/tex]A

Moles of NaOH = 2 * 0.05 mol

Moles of NaOH = 0.1 mol

0.1 mol of sodium hydroxide (NaOH) would react exactly with 7.5 g of the diprotic acid [tex]H_{2}[/tex]A.

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A headline for a newspaper in a small town reads: "Sheriff Killed by a Poison that has Killed More People Than Any
Other Poison." How was the sheriff poisoned?
thallium
cyanide
arsenic
strychnine

Answers

The sheriff was poisoned by the use of the arsenic poison.

How does arsenic poison  work?

Arsenic is a toxic substance that can be deadly if ingested or inhaled in high concentrations. It works by disrupting important cellular processes and functions within the body.

When arsenic is ingested, it is absorbed through the digestive system and enters the bloodstream. From there, it is transported to various organs and tissues throughout the body, including the liver, kidneys, and lungs.

Arsenic interferes with the enzymes and proteins that are essential for cellular metabolism, DNA synthesis, and other important cellular processes. This disruption can cause a range of symptoms, including abdominal pain, diarrhea, vomiting, and dehydration.

Arsenic can also cause damage to the nervous system, leading to neurological symptoms such as confusion, seizures, and numbness or tingling in the extremities.

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Students are planning to conduct some tests on two substances: candle wax and sulfur crystals
Which property of the wax and the sulfur should be investigated to provide evidence of the relative strengths of their intermolecular forces?
A. Mass
B. Color
C. Texture
D. Melting point

Answers

The answer should be A
I did this and I pretty sure it’s A mass cuh

Melting point is the property of the wax and the sulfur should be investigated to provide evidence of the relative strengths of their intermolecular forces. Therefore, the correct option is option D.

What is intermolecular forces?

The electrical forces of attraction and repulsion that act between atoms along with other types of nearby particles, such as atoms or ions, are examples of intermolecular forces (IMFs), also known as secondary forces. In comparison to intramolecular forces, which bind a molecule together, intermolecular forces are weak.

For instance, the forces between adjacent molecules are substantially weaker than the covalent bond, which involves sharing pairs of electrons between atoms. Both types of forces are crucial components of the force fields that molecular mechanics typically use. Melting point is the property of the wax and the sulfur should be investigated to provide evidence of the relative strengths of their intermolecular forces.

Therefore, the correct option is option D.

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The volume of a sample of oxygen is 200.0 mL when the pressure is 3.000 atm and the temperature is 37.0 C. What is the new temperature if the volume increases to 400.0 mL and the pressure decreases to 2.000 atm?

Answers

Answer:

140.3 *C

Explanation:

(P1 * V1) / T1 = (P2 * V2) / T2

where P1 = 3.000 atm, V1 = 200.0 ml, T1 = 37.0°C + 273.15 = 310.15 K, P2 = 2.000 atm, V2 = 400.0 ml.

Substituting these values into the formula gives:

(3.000 atm * 200.0 ml) / 310.15 K = (2.000 atm * 400.0 ml) / T2

Solving for T2 gives:

T2 = (2.000 atm * 400.0 ml * 310.15 K) / (3.000 atm * 200.0 ml)

T2 ≈ 413 K or 140°C.

Calculate %m/v composition of 0.022 Kg ammonium nitrate in 587g solution (d=1.07 g/mL)

Answers

[tex]V_{tot} = \frac{587 g}{1,07 g/mL} = 549 mL[/tex]

0,022 kg = 22 g

[tex]\frac{m}{V} = \frac{22 g × 100}{549 mL} = 4,0 % [/tex]

What mass of solution is formed when 9g of salt is added to 50g water?​

Answers

59g

Amount of salt (solute) = 9g amount of solvent = 50g mass of solution= Mass of solute + mass of solvent=

50+9=59g

CAN SOMEONE HELP WITH THIS QUESTION?

Answers

The percent transmittance (%T) and absorbance (A) of a solution are related by an equation which can be used to solve this question.

What is the absorbance of this solution?

The percent transmittance (%T) and absorbance (A) of a mixture are associated by the following equation:

%T = 100 x 10^(-A)

We are given that the %T value of the solution is 51.6% at a wavelength of 550 nm. To find the absorbance (A), we can rearrange the equation above:

A = -㏒(%T / 100)

On substituting the value in the given %T value, we get:

A = -㏒(51.6 / 100) = -㏒(0.516) = 0.286

Therefore, the absorbance of the solution at a wavelength of 550 nm is 0.286.

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If a molecule has a triple bond, what can be assumed about the bond compared to a molecule with a double bond?

The length is more than a double bond
The strength is more than a double bond
The strength is less than a double bond
The length is the same as a double bond

Answers

While the length is less than a double bond, the strength exceeds that of a double bond.

Within the same molecule, how do triple bonds differ from double bonds?

Due to the presence of two bonds rather than one, triple bonds are stronger than double bonds. An sp-sp sigma bond is created when one of each carbon atom's two sp hybrid orbitals intersects with the corresponding orbital from the other carbon atom.

Compared to double bonds, are triple bonds more durable and longer?

Six electrons are shared by a sigma bond, two bonds, and a triple bond. Double bonds are more powerful than single bonds, and triple bonds are more powerful than double bonds, according to experiments.

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Answer: third

Explanation:

Calculate The PH After 15.0 ML Of 0.210 KOH Is Added In The Titration Of 55.0 ML Of .210 M HClOThe Ka Of HClO Is 4.0x10^-8

Answers

The pH after 15.0 mL of 0.210 KOH is added in the titration of 55.0 mL of 0.210 M HClO is 4.56.

To solve this problem, we need to use the balanced chemical equation for the reaction between KOH and HClO:

HClO + KOH → KClO + H2O

We can see that for every mole of KOH added, one mole of HClO will react. Therefore, the number of moles of HClO in 55.0 mL of 0.210 M HClO is:

n(HClO) = M(HClO) x V(HClO) = 0.210 mol/L x 0.0550 L = 0.0116 mol

When 15.0 mL of 0.210 M KOH is added, the number of moles of KOH added is:

n(KOH) = M(KOH) x V(KOH) = 0.210 mol/L x 0.0150 L = 0.00315 mol

Since the reaction is a neutralization reaction, the moles of HClO left after the reaction will be:

n(HClO) = n(HClO)initial - n(KOH) = 0.0116 mol - 0.00315 mol = 0.00845 mol

We can now use the equilibrium expression for the ionization of HClO in water to calculate the pH of the solution:

HClO + H2O ⇌ H3O+ + ClO-

Ka = [H3O+][ClO-]/[HClO]

At equilibrium, the concentrations of H3O+ and ClO- can be assumed to be equal to the concentration of HClO that remains unreacted, since HClO is a weak acid and does not dissociate completely in water. Therefore:

[H3O+] = [ClO-] = [HClO] = 0.00845 mol / (0.0550 L + 0.0150 L) = 0.105 M

Substituting these values into the equilibrium expression for Ka:

Ka = [H3O+][ClO-]/[HClO] = (0.105 M)² / 0.00845 M = 1.31 x 10⁻⁶

pKa = -log(Ka) = -log(1.31 x 10⁻⁶) = 5.88

pH = 1/2(pKw - pKa) = 1/2(14.00 - 5.88) = 4.56

Therefore, the pH after 15.0 mL of 0.210 KOH is added in the titration of 55.0 mL of 0.210 M HClO is 4.56.

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Calculate the cell potential, Ecell, for the following reaction at 298k.
Co(s)+2Ag+(0.010M)=Co+2(0.015M)+2 Ag(s)

Answers

To calculate the cell potential, Ecell, for the given reaction at 298K, we need to use the Nernst equation. The Nernst equation relates the cell potential to the standard cell potential, temperature, and the concentrations of the reactants and products. The Nernst equation is given as follows:

Ecell = E°cell - (RT/nF) ln(Q)

where,

Ecell = cell potential

E°cell = standard cell potential

R = gas constant (8.314 J/K.mol)

T = temperature (298 K)

n = number of electrons transferred in the balanced redox reaction

F = Faraday constant (96,485 C/mol)

Q = reaction quotient

The given reaction is a redox reaction, which involves the transfer of two electrons from Co to Ag+. The balanced half-reactions are as follows:

Co(s) → Co2+(aq) + 2 e-

Ag+(aq) + e- → Ag(s)

The standard reduction potentials for these half-reactions are:

Co2+(aq) + 2 e- → Co(s) E°red = -0.28 V

Ag+(aq) + e- → Ag(s) E°red = +0.80 V

The overall standard cell potential can be calculated by subtracting the standard reduction potential of the anode from that of the cathode:

E°cell = E°red,cathode - E°red,anode

= +0.80 V - (-0.28 V)

= +1.08 V

Now we need to calculate the reaction quotient Q using the concentrations of the reactants and products. According to the given information, [Ag+] = 0.010 M and [Co2+] = 0.015 M.

Q = ([Co2+][Ag+]^2)/([Ag+]^2)

= ([0.015][0.010]^2)/([0.010]^2)

= 0.015 M

Substituting the values in the Nernst equation, we get:

Ecell = E°cell - (RT/nF) ln(Q)

= 1.08 - (8.314 x 298 / (2 x 96485)) ln(0.015)

= 0.829 V

Therefore, the cell potential, Ecell, for the given reaction at 298K is 0.829 V.

what is the concentration of a 250 mL aqueous solution with 54 grams of KNO3

Answers

Concentration of the 250 mL aqueous solution with 54 grams of KNO₃ is 216 g/L or 216 g/1000 mL.

What is an aqueous solution?

An aqueous solution is a solution in which the solvent is water (H₂O). In an aqueous solution, one or more substances, called solutes, dissolve in water to form a homogeneous mixture.

Concentration (in units of g/mL or g/L) = amount of solute / volume of solution

Given the amount of solute (54 grams) and the volume of the solution (250 mL); volume of solution = 250 mL = 0.250 L

So, concentration = 54 g / 0.250 L

concentration = 216 g/L

Therefore, concentration of the 250 mL aqueous solution with 54 grams of KNO₃ is 216 g/L or 216 g/1000 mL.

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Determine the molarity (M) of 0.2074 g of calcium hydroxide, Ca(OH)₂ (74.09 g/mol), in 40.00 mL of solution.

Answers

Answer:

M=0.06998 mol/L

Explanation:

Question 4 of 10
How much energy is required to vaporize 2 kg of gold? Use
the table below and this equation: Q = mLvapor
Substance
Aluminum
Copper
Gold
Helium
Lead
Mercury
Water
Latent Heat
Fusion
(melting)
(kJ/kg)
400
207
62.8
5.2
24.5
11.4
335
Melting
Point
(°C)
660
1083
1063
-270
327
-39
0
Latent Heat
Vaporization
(boiling) (kJ/kg)
1100
4730
1720
21
871
296
2256
Boiling
Point
(°C)
2450
2566
2808
-269
1751
357
100

Answers

It requires 10.15 kilojoules of energy.

What is vaporization?

The term "vaporisation" (or "evaporation") often refers to the transformation of a liquid's condition into a vapour phase below its boiling point. The phrase, however, can also refer to the process of removing a solvent, independent of the temperature used.

What is energy?

When a body moves to exert force, it is said to be exerting work. Energy is the capacity to accomplish work. Energy is something we always need, and it can take many different forms.

If the gold is present in the liquid state, you only have to determine the latent heat of vaporization, or lvap. The empirical data for gold is 330 kJ/mol.

Q = mlvap

Q = (2 kg)(1 kmol/197 kg)(1,000 mol/1 kmol)

Q = 10.15 kJ

It needs an energy of 10.15 kilojoules

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What is the value of for this aqueous reaction at 298 K?

A+B↽−−⇀C+D
Δ°=17.32 kJ/mol

K= ?

Answers

K has a value of 6.09 105. 6.09 × 10 − 5 . The aqueous reaction for the 298 K reaction is:

The results of substituting the aforementioned variables are: 6.09 10 5.

What exactly are aqueous reactions?

Water-based reactions are known as aqueous reactions. It is crucial to comprehend how substances behave in water in order to comprehend them. Some substances are electrolytes; in water, they split into different ions. The behavior of electrolytes varies, though.

How can you tell when a reaction is water-based?

If a problem involves ions or precipitates, you can tell when a solution is aqueous since it has been dissolved in water.

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how do I convert 0.063 m to centimeters

Answers

Answer:

6.3

Explanation:

multiply the length value by 100

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"A certain object's mass is desired to be found after four weighings. If the obtained values are 2.744g, 2.756g, 2.751g, and 2.758g, find the uncertainty in the mass of the object."

Answers

Answer: the uncertainty in the mass of the object is 0.007 g.

Explanation:

The uncertainty in the mass of the object can be calculated using the formula for absolute uncertainty:

Absolute uncertainty = Maximum measured value - Minimum measured value / 2

In this case, the maximum measured value is 2.758 g and the minimum measured value is 2.744 g.

Plugging these values into the formula, we get:

Absolute uncertainty = (2.758 g - 2.744 g) / 2

= 0.014 g / 2

= 0.007 g

So, the uncertainty in the mass of the object is 0.007 g.
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How much time does it take light to travel 6.03 billion km? (billion=109)

Answer to 3 sig figs.

Answers

Light takes 20,100 seconds or 5.583 hours to travel 6.03 billion km.

How to calculate total time taken using distance and speed?

To calculate the time it takes for light to travel 6.03 billion km, we can use the formula:

time = distance / speed of light

where distance is 6.03 x 10^9 km and the speed of light is approximately 299,792,458 meters per second (m/s).

First, we need to convert the distance from kilometers to meters:

distance = 6.03 x 10^9 km x 10^3 m/km = 6.03 x 10^12 m

Now we can calculate the time:

time = distance / speed of light

= 6.03 x 10^12 m / 299,792,458 m/s

= 20,107.394 seconds

To 3 significant figures, the answer is 20,100 seconds or 5.583 hours (since there are 3600 seconds in an hour).

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To answer this question, you may need access to the periodic table of elements.

Which of these pairs of atoms would experience an ionic bond?

a.)
K and Br
b.)
S and O
c.)
H and S
d.)
Cl and Cl

Answers

K and Br since an halogen and a metal make a salt

A gaseous mixture contains O₂ and another unknown gas in he molar
ratio of 4:1 effuses through a hole in 245 sec. Under similar conditions,
same volume of O, takes 220 sec to effuse. Find the molar mass of the
gas. (in g/mol)

Answers

The molar mass of the unknown gas is 28 g/mol.

What is Graham's law of effusion?

Graham's law of effusion states that the rate of effusion (the escape of gas molecules through a tiny hole) of a gas is inversely proportional to the square root of its molar mass, at constant temperature and pressure. This means that lighter gases effuse (escape through a hole) faster than heavier gases, all other factors being equal.

We can use Graham's law of effusion to solve this problem:

Rate of effusion is inversely proportional to the square root of molar mass.

Thus, we can write:

(rate of effusion of O₂) / (rate of effusion of the unknown gas) =

sqrt(molar mass of the unknown gas) / sqrt(molar mass of O₂)

Let's call the molar mass of the unknown gas "M". We can set up the following system of equations using the information given in the problem:

4/1 = (rate of effusion of O₂) / (rate of effusion of the unknown gas)

(rate of effusion of O₂) = 1/220

(rate of effusion of the unknown gas) = 1/245

Plugging in these values, we get:

4/1 = (1/220) / (1/245)

4/1 = 49/44

Solving for the rate of effusion of the unknown gas, we get:

(rate of effusion of the unknown gas) = (1/245) / (49/44) = 4/539

Now we can use Graham's law of effusion to find the molar mass of the unknown gas:

(rate of effusion of O₂) / (rate of effusion of the unknown gas) =

sqrt(molar mass of the unknown gas) / sqrt(molar mass of O₂)

(1/220) / (4/539) = sqrt(M) / sqrt(32)

Solving for M, we get:

M = 28 g/mol

Therefore, the molar mass of the unknown gas is 28 g/mol.

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For the equilibrium mixture:
NH4Cl(s) + heat <=> NH4+(aq) + Cl-(aq)

A) What change do you observe when you add concentrated hydrochloric acid, HCl, solution. Give complete explanation.

Answers

The addition of concentrated HCl to the equilibrium mixture will result in the precipitation of more NH₄Cl(s) as the equilibrium shifts towards the left. This can be observed as cloudiness or precipitation forming in the solution.

When concentrated hydrochloric acid (HCl) solution is added to the equilibrium mixture of NH₄Cl(s) + heat <=> NH₄+(aq) + Cl-(aq), the equilibrium will shift towards the left, meaning more solid NH₄Cl will be formed.

This is because HCl is a strong acid that will react with NH₄+ ion to form NH₄Cl(s) and H+ ion:

NH₄+(aq) + Cl-(aq) + HCl(aq) → NH₄Cl(s) + H₂O(l)

The increase in H+ ion concentration due to the addition of HCl will result in the shift of the equilibrium to the left to reduce the excess H+ ion concentration. This will favor the formation of more solid NH₄Cl.

Therefore, the addition of concentrated HCl to the equilibrium mixture will result in the precipitation of more NH₄Cl(s) as the equilibrium shifts towards the left. This can be observed as cloudiness or precipitation forming in the solution.

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35.0 ml. of a 0.250 M solution of /OH is titrated with 0.150 M HCI. After 35.0 mL of the HCl has been added, the resultant

Answers

Determine the amount of KOH present in the resulting solution. KOH was initially 0.00875 mol, then 0.00525 mol of it interacted with HCl. As a result, 0.00875 mole - 0.00525 mol (= 0.00350 mol of KOH is left. The resulting solution has a volume of 70.0 mL (35.0 mL plus 35.0 mL).

Is HCl directly titrated with NaOH?

The titrant (NaOH), which is added gradually throughout the course of a titration, is added to the unknown substance. The equivalency point is the moment at which precisely the right quantity of titrant (NaOH) has indeed been added that react to the entire analyte (HCl).

What happens when you titrate NaOH to HCl?

What took place during titration: One mole of NaOH interacts with one mole of HCl inside the reaction between the two substances. NaOH with HCl equals NaCl plus H2O. (NaOH and HCl have a mole ratio of 1:1.) • The NaOH concentration is 0.1 M, or 0.1 molecules per litre.

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Which sub atomic particles are similar in size

Answers

Answer:

Neutrons and Protons

Explanation:

Different elements can have subatomic particles of varying sizes. The size of an atom is defined by the size of its electron cloud, which is composed of electrons, and the size of its nucleus, which is composed of protons and neutrons. The atomic number and subsequently the identity of an element are determined by the number of protons in the nucleus. The quantity of protons and neutrons in the nucleus determines its size. The quantity of electrons in the electron cloud and the energy levels they are located at define its size. The size of atoms can differ depending on the element due to differences in the amount of protons, neutrons, and electrons.

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