Answer:
The reflection and rectilinear propagation of light helps in the formation of shadows and also tells light doesn't penetrate opaque materials.
why do badminton players use rubber shoes while playing
Badminton shoes are specifically designed for badminton footwork and movement. Rubber that is anti-slip and wear-resistant is ideal for the soles of badminton shoes, while the midfoot area requires excellent shock-absorption and resilience
Answer:
It's the perfect shoe to wear on the fields they play on like so they don't slip
A boy stands 190m from a high wall and claps his hands,if he hears an echo 1.3 seconds later. calculate the speed of sound in air.
Answer:
292.31 m/s
Explanation:
If Distance (d) = 190m
Time (t) = 1.3s
Speed of sound in air (v) =?
then
2d=vt
v=2d/t
v= 2×190/1.3
v=292.31 m/s
The force of a hammer drives a nail into wood. This is an example of?
A. An unbalanced force.
B. Gravitational force.
C. Friction.
D. Balanced forces.
Answer:
A. An unbalanced force.
Explanation:
There needs to be a net force in order for the nail to be driven into presumably the wall. Without the net force then the hammer and nail wouldn't move.
Determine
i. the total capacitance for the circuit
ii. the total charge stored in the circuit
iii. the charge stored in C9 (3μF)
(i) The total capacitance for the circuit is 5 μF.
(ii) The total charge stored in the circuit is 1 x 10⁻⁴ C.
(iii) The charge stored in 3μF capacitor is 6 x 10⁻⁶ C.
Total capacitance of the circuit
The total capacitance of the circuit is determined by reolving the series capacitors separate and parallel capacitors separate as well.
C1 and C2 are in series[tex]\frac{1}{C_{12}} = \frac{1}{C_1 } + \frac{1}{C_2} \\\\\frac{1}{C_{12}} = \frac{1}{4 } + \frac{1}{4} \\\\\frac{1}{C_{12}} = \frac{1}{2} \\\\C_{12} = 2 \ \mu F[/tex]
C1 and C2 are parallel to C3[tex]C_{123} = C_{12} + C_3\\\\C_{123} = 2\ \mu F + 2\ \mu F \\\\C_{123} = 4 \ \mu F[/tex]
C(123) is series to C5 and C6[tex]\frac{1}{C_{t} } = \frac{1}{C_{123}} + \frac{1}{C_5} + \frac{1}{C_6} \\\\\frac{1}{C_{t} } = \frac{1}{4} + \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{t} } = \frac{12}{24} \\\\\frac{1}{C_{t} } = \frac{1}{2} \\\\C_t = 2 \ \mu F[/tex]
C7 and C8 are in series[tex]\frac{1}{C_{78}} = \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{78}} = \frac{2}{6} \\\\\frac{1}{C_{78}} =\frac{1}{3} \\\\C_{78} = 3 \ \mu F[/tex]
Total capaciatnce of the circuitCt + C(78) = 2 μF + 3 μF = 5 μF
Total charge stored in the circuitThe total charge stored in the capacitor is calculated as follows;
Q = CV
Q = (5 x 10⁻⁶) x (20)
Q = 1 x 10⁻⁴ C
Charge stored in 3μF capacitorQ = (3 x 10⁻⁶) x (20)
Q = 6 x 10⁻⁶ C
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A magnet gets demagnetized when it is heated.
Answer:
The delicate balance between temperature and magnetic domains is destabilized when a magnet is subjected to high temperatures. If a magnet is exposed to this temperature for an extended length of time or heated over its Curie temperature, it will lose its magnetism and become irreversibly demagnetized.
Explanation:
Which statement best describes the circular flow model?
A satellite with a mass of 45 kg fires its rocket thrusters, which give an impulse of 1035 kg•m/s. What was the total change in the velocity of the satellite - that is, what was the total ΔV?
O 58 m/s
O 23 m/s
O 39 m/s
O 47 m/s
The total change in velocity of the satellite is 23 m/s
What is Impulse?In Physics, Impulse is the product of mass and change in velocity
Given:
mass = 46 kg
Impulse = 1035 kg•m/s
change in velocity = ?
impulse = mass * velocity
change in velocity = Impulse / mass
change in velocity = 1035 / 45
change in velocity = 23 m/s
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explain how a deflection magnetometer can be used to find the horizontal component of the Earth's magnetic field
While cruising on the high sea at speed of v = 22 km/hr, a cargo ship suddenly encounters a problem with its propeller shaft leading to the main engine being shut down. This causes the vessel to slow down to 12 km/hr over the next 14 minutes. Assuming that its deceleration profile is following a correlation of as a = -0.85ct², where c is the acceleration constant for any time t, determine; i) The magnitude for constant c from the two boundary limits of deceleration profile given above, and ii) Plot against the timescale for same interval above, a total distance covered by the vessel as it's slowing down from 22 km/hr to 12 km/hr. Also plot the speed profile for the vessel during that 14 minutes' span.
Answer:
how can you support to leprosy victims?
What type of heat transfer occurs in your stomach when you eat hot soup and an ice cold beverage
The type of heat transfer occurs in your stomach when you eat hot soup and an ice cold beverage is Conduction.
What is Conduction?This is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules.
This happens when they are in close contact with each other which was why Conduction was chosen as the most appropriate choice.
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An object absorbs red, orange, yellow, blue, indigo, and violet light. What color is it?
A. blue
B. green
C. indigo
D. red
Answer: B. Green
Explanation:
Since the object absorbs all the other options listed here, it will reflect green light. This makes the object appear green to our eyes.
Blue (A), indigo (C), and red (D) are listed in red, orange, yellow, blue, indigo, and violet. Green is not, so this is our answer.
Fun fact:
An example of this is grass!
Answer:
green
Explanation:
How far back into the universe are we able to see? Explain.
Answer:
About 46 billion light years Because space expands so what we didn’t see before is what we could see now. An example could be how everyone thought Pluto was a regular sized planet but once you get a look at the bigger picture and compare it to other thing in space we now know Pluto is a dwarf planet.
. A rope is being used to pull a mass of 10 kg vertically upward. Determine the tension on the rope, if starting from rest, the mass acquires a velocity of 4 ms-1 in 8s [g= 10ms-2]
[tex]\text{Given that,}\\\\\text{Mass, m =10 kg}\\\\\text{Time, t = 8 sec}\\\\\text{Velocity, v = 4~m/s}\\\\\text{When a body is moving upwards,}\\\\\text{Tension,}~ T=mg +ma\\\\~~~~~~~~~~~~~~~=mg+m\left(\dfrac{v-u}t \right)\\\\~~~~~~~~~~~~~~~=10(10)+10\left(\dfrac{4-0}8\right)\\\\~~~~~~~~~~~~~~~=100+10\left(\dfrac 12\right)\\\\~~~~~~~~~~~~~~~=100+5\\\\~~~~~~~~~~~~~~~=105~N[/tex]
What is the force of the drag for a 65 kg bicyclist, initially at rest at the top of a hill coasts down the hill, reaching a speed of 15.5 m/s at the bottom of the hill. The distance is 60M. neglect any friction impeding the motion and the rotational energy of the wheels.
Height is 19M
Intial GPE is 12350J
KE is 7808J and loss is 4542 J
If an object accelerates from rest, with a constant acceleration of
10 m/s2, what will its velocity be after 2 s?
The velocity of the body affter 2 seconds is 20 m/s
What is acceleration?Acceleration, a is the change of velocity with time. this is represented mathematically as
a = ( v - u ) / t
where:
u = intial velocity
v = final velocity
t = time
Given:
a = 10 m/s2
t = 2s
u = 0 ( from rest means initial velocity is zero )
therefore
a = v / t
v = a t
v = 10 * 2
v = 20 m/s
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Does every light source emit only one type of light?
Yes it is possible. Spectrum of emitted light depends upon the chemical composition of the source. and the way of its excitation. a clear example to us is that of sun.
Suppose a grower sprays (2.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water when it freezes?
There is no temperature change which drives heat flow, thus no heat will be released by the water.
Heat released by the water when it freezesThe heat released by the water when it freezes is calculated as follows;
Q = mcΔФ
where;
m is mass of waterc is specific heat capacity of waterΔФ is change in temperature = Фf - ФiInitial temperature of water, Фi = 0 °C
when water freezes, the final temperature, Фf = 0 °C
Q = 22 x 4200 x (0 - 0)
Q = 0
Since there is no temperature change which drives heat flow, thus no heat will be released by the water.
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A cable with 19.0 N of tension pulls straight up on a 1.50 kg block that is initially at rest. What is the block's speed after being lifted 2.00 m ? Solve this problem using work and energy
The final speed of the block, after being lifted 2.00 m is 3.39 m/s
What is speed?Speed can be defined as the rate of change in the distance of a body.
To calculate the speed of the block after being lifted 2.00 m, first, we need to calculate the acceleration of the block using the formula below
Formula:
T-mg = ma......... Equation 1Where:
T = Tension in the cablem = mass of the cablea = accelerationg = acceleration due to gravityRestructuring the formula above,
a = (T-mg)/m............... Equation 2From the question,
Given:
T = 19 Nm = 1.5 kgg = 9.8 m/s²Substitute these values into equation 2
a = [(19)-(1.5×9.8)]/1.5a = 4.3/1.5a = 2.87 m/s²Finally, to calculate the speed of the block, we use the formula below.
v² = u²+2as.......... Equation 3Where:
v = Final speedu = initial speeda = accelerations = distanceFrom the question,
Given:
u = 0 m/sa = 2.87 m/s²s = 2.00 mSubstitute these values into equation 3
v² = 0²+(2×2×2.87)v² = 11.48v = √11.48v = 3.39 m/sHence, The final speed of the block, after being lifted 2.00 m is 3.39 m/s.
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A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the
same direction at 6 m/s. What is their combined speed if the two balls stick together
when they touch?
Answer:
Given:
m1 = 7 kg
V1 = 12 m/s
m2 = 25 kg
V2 = 6 m/s
To find:
Combined speed of two balls stick together after collision V = ?
Solution:
According to law of conservation of momentum,
m1V1 + m2V2 = (m1+m2)V
7×12 + 25×6 = (7+25)V
84 + 150 = 32V
V = 234/32
V = 7.31 m/s
Combined speed of two ball is 7.31 m/s
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"A ball with a mass of 0.1 kg is rolling at a velocity of 5 m/s. What is its
momentum?" What Given is the 5 in this problem? *
mass
velocity
acceleration
momentum
Answer:
velocity
Explanation:
because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.
A car travels at a speed of 40 m/s for 29.0 s;
what is the distance traveled by the car?
Answer: 1160 m
Explanation:
Speed = distance / time. Plug in 40 m/s for speed and 29 s for time in order to get the distance, 1160 m.
The magnetic field perpendicular to a single wire loop of diameter 10.0 cm decreases from 0.50 T to zero. The wire is made of copper and has a diameter of 2.0 mm and length 1.0 cm. How much charge moves through the wire while the field is changing?
I know how to do the calculations, but can someone please explain what is the 10cm diameter and 2mm diameter? Why is there one wire and two diameters? I understand this problem mathematically but not conceptually.
Hi there!
We can begin by using Lenz's Law:
[tex]\epsilon = -N\frac{d\Phi _B}{dt}[/tex]
N = Number of Loops
Ф = Magnetic Flux (Wb)
t = time (s)
Also, we can rewrite this as:
[tex]\epsilon = -NA\frac{dB}{dt}[/tex]
A = Area (m²)
Since the area is constant, we can take it out of the derivative.
This is a single wire loop, so N = 1.
Now, we can develop an expression for the induced emf.
We can begin by solving for the area:
[tex]A = \pi r^2 \\\\d = r/2 r = 0.05cm \\\\A = \pi (0.05^2) = 0.007854 m^2[/tex]
We can also express dB/dt as:
[tex]\frac{dB}{dt} = \frac{\Delta B}{t} = \frac{0-0.5}{t} = \frac{-0.5}{t}[/tex]
Now, we can create an equation.
[tex]\epsilon = -(1)(0.007854)\frac{-0.5}{t} = \frac{0.003927}{t}[/tex]
To solve the system, we must now develop an expression for current given an emf and resistance.
Begin by calculating the resistance of the copper wire:
[tex]R = \frac{\rho L}{A}[/tex]
ρ = Resistivity of copper (1.72 * 10⁻⁸ Ωm)
L = Length of wire (0.01 m)
A = cross section area (m²)
Solve:
[tex]R = \frac{(1.72*10^{-8})(0.01)}{\pi (0.001^2)} = 5.475 * 10^{-5} \Omega m[/tex]
Now, we can use the following relation (Ohm's Law):
[tex]\epsilon = iR\\\\\epsilon = \frac{Q}{t}R[/tex]
*Since current is equivalent to Q/t.
Plug in the value of R and set the two equations equal to each other.
[tex]\frac{Q}{t}(5.475 * 10^{-5}) = \frac{0.003927}{t}[/tex]
Cancel out 't'.
[tex]Q (5.475 * 10^{-5}) = 0.003927 \\\\Q = \frac{0.003927}{5.475*10^{-5}} = \boxed{71.73 C}[/tex]
When must scientific theories be changed
Answer:
when new information disproving the current theory becomes available.
Explanation:
hope this helps..
Answer:
when new evidence is discovered
Select the correct answer. Based on the law of conservation of energy, which statement is correct? O A. Energy is always being added to all parts of the Universe. O B. Energy is often destroyed in some parts of the Universe. O C. Energy in a closed system cannot change forms. O D. Energy in an isolated system remains constant.
Answer:
d. energy in an isolated system remains constant.
Explanation:
energy can neither be replaced or destroyed
Physics Momentum topic question. I will mark brainliest please help.
Answer:
10 m/s
Explanation:
Given
mass of ball 1, m1 = 1 kgmass of ball 2, m2 = 0.25 kginitial velocity of ball 1, u1 = 10 m/sinitial velocity of ball 2, u2 = 0 m/s [stationary]final velocity of ball 1, v1 = 7.5 m/smomentum of ball 2 after collision = 2.5 kg m/sSolving :
We do not require all of this informationOnly require points 2 and 6Momentum = mass x velocity⇒ velocity = 2.5 / 0.25⇒ velocity = 10 m/sYou are riding a bicycle up a gentle hill. It is fairly easy to increase your potential
energy, but to increase your kinetic energy would be harder.
True or false
The resistance of a 60.-watt lightbulb operated at
120 volts is approximately
Answer:
The resistance of a 60 watt light bulb designed to operate at 120 volts is 240 Ω.
Explanation:
Water of mass, m at 100 ℃ is added to 0.50 kg of water at 20 ℃ in a lagged calorimeter of thermal capacity 105 JK −1 . If the specific heat capacity of water is 4200 kg −1K −1 and the final temperature of the mixture is 70℃, determine the value of m.
The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
Determine the value of mApplying the principle of energy conservation
Heat lost by the hot body = heat absorbed by the cold water + calorimeter
= m * 4200 * ( 100 - 70 ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )
= m * 126000 = 110250
therefore ;
m = 110250 / 126000
= 0.875 kg
Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
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A circular ferris wheel that revolves at a constant rate once every 30 seconds. The
radius of the ferris wheel is 10 m. What is the normal force of the ferris wheel on a 10
kg toddler at the very bottom of the ferris wheel?
The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.
Centripetal force of the Ferris wheelThe normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is calculated as follows;
Fn = Fc + mg
Fn = mω²r + mg
where;
ω is the angular speed = 1 rev/30 s = 2π/30 s = 0.21 rad/sFn = 10(0.21²) 10 + 10(9.8)
Fn = 102.41 N
Thus, the normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.
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What is the angular momentum at a radius of 2 m with an object of 5 kg at a
velocity of 20 m/s?
The angular momentum is 200 kg m^2 s^-1
what is angular momentum?Angular momentum is the product of linear momentum and the perpendicular distance. Linear momentum is the product of mass and velocity, where radius is the perpendicular distance
Angular momentum = mass * velocity * radius
Angular momentum = 5 * 2 * 20
Angular momentum = 200 kg m^2 s^-1
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