Answer:
Wet and sandy soil as it does not provide a sturdy structure
Calculate the specific heat of a substance given that 49 joules of heat is required to raise the temperature of 25.0 g of the substance from 92.6 ºC to 99.4 ºC.
Answer:
0.29 J/g.°C
Explanation:
Step 1: Given data
Added heat (Q): 49 JMass of the substance (m): 25.0 gInitial temperature: 92.6 °CFinal temperature: 99.4 °CStep 2: Calculate the temperature change (ΔT)
ΔT = 99.4 °C - 92.6 °C = 6.8 °C
Step 3: Calculate the specific heat of the substance (c)
We will use the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0L flask with 4.5 atm of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be 1.1 atm. Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
Kp = 7.4727
Explanation:
Let's write the balanced equilibrium reaction:
2NH₃ <-------> N₂ + 3H₂ Kp = ??
Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:
2NH₃ <-------> N₂ + 3H₂
I. 4,5 0 0
C. -2x +x +3x
E. 4,5-2x x 3x
According to this chart, the Kp expression should be:
Kp = (PH₂)³ * (PN₂) / (PNH₃)² (1)
The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:
Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²
Kp = 39.5307 / 5.29
Kp = 7.4727Hope this helps
When calcium forms an ion that has the same number of outer electrons as which noble gas?
1. neon
2. helium
3. argon
4. krypton
BRAINLIEST FOR HELP ASAP!!!!
1. Alexa and her family travelled 5 hours south east on 1-45 to crystal
beach this summer for vacation. If the trip was a total of 340 miles,
what was her average speed?
EQUATION
PLUG N NUMBERS
INTO THE EQUSTION
ENALANSWER WITH
UNTS
Answer:
Average speed = 68 mph
Explanation:
Given that,
Total distance traveled by the family, d = 340 miles
The family traveled 5 hours southeast.
We need to find her average speed. The speed of an object is given by the total distance covered divided by time taken. So,
[tex]v=\dfrac{d}{t}[/tex]
Put all the values,
[tex]v=\dfrac{340}{5}\\\\v=68\ mph[/tex]
So, her average speed is equal to 68 mph.
Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4
Answer:
2.35x10²³ molecules of C2Cl4 are present
Explanation:
To solve this question we must convert, as first, the mass of C2Cl4 to moles using its molar mass (C2Cl4 = 165.83g/mol). Then, using Avogadro's number we can find the number of molecules:
Moles C2Cl4:
73.1g * (1mol / 165.83g) = 0.441 moles C2Cl4
Molecules:
0.441 moles C2Cl4 * (6.022x10²³molecules / 1mol) =
2.35x10²³ molecules of C2Cl4 are presentAt which temperature is water in its gas phase (water vapor)?
Group of answer choices
-40
40
140
How many mL of a 6 M NaOH stock solution is needed in order to prepare 500 mL of a 0.2 M NaOH solution?
Answer:
The right answer is "16.67 mL".
Explanation:
Given:
Molarity of NaOH,
[tex]M_1=6 \ M[/tex]
[tex]M_2=0.2 \ M[/tex]
Volume of NaOH,
[tex]V_1=V \ mL[/tex]
[tex]V_2=500 \ mL[/tex]
As we know, the equation,
⇒ [tex]M_1V_1=M_2V_2[/tex]
On putting the values, we get
⇒ [tex]6\times V=0.2\times 500[/tex]
⇒ [tex]6\times V=100[/tex]
⇒ [tex]V=\frac{100}{6}[/tex]
⇒ [tex]=16.67 \ mL[/tex]
When 1 mol of a nonvolatile, nondissociating solute is dissolved in 3 mol of volatile solvent, the ratio of vapor pressure of the solution to that of the pure solvent (at the same temperature) is approximately:________
Answer:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Explanation:
Hello there!
In this case, since the solvation of a nonvolatile-nondissociating solute in a volatile solvent is modelled via the Raoult's law:
[tex]P_{solution}=x_{solvent}P_{solvent}^{vap}[/tex]
Thus, we can calculate the ratio of the vapor pressure of the solution to that of the pure solvent, mole fraction, as shown below:
[tex]x_{solvent}=\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{n_{solvent}}{n_{solute}+n_{solvent}}[/tex]
Thus, we plug in the moles of solvent and solute to obtain:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{3}{3+1}\\\\ \frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Regards!
1. What would happen to an inflated balloon it were to be placed in a cold environment?
The balloon would inflate more
The balloon would pop
The balloon would float away
The balloon would deflate
Answer:
The balloon would deflate
Explanation:
A newborn blue whale measures 6.0 to 7.9 m long and weighs up to 3003 kg. The blue whale produces the loudest sound by any living animal, 188 dB and can be detected as far as 850 000 m away. What is the total number of significant figures in all these trivia?
What is the ph of a HCl solution with a concentration of 2.51x10^-5M
Answer:
pH = 4.6
Explanation:
As hydrochloric acid (HCl) is a strong acid, the molar concentration of H⁺ species is the same as the molar concentration of the HCl solution. In other words:
[H⁺] = 2.51x10⁻⁵ MWith the information above in mind we can calculate the pH:
pH = -log[H⁺]pH = -log(2.51x10⁻⁵ M)pH = 4.6How do you calibrate an electronic analytical balance
Explanation:
For the calibration process, use a weight that is 50% of the scale's capacity for accurate calibration. Weights less than 10% can result in inaccuracy. Make sure that the scale doesn't have any weights placed on it and nothing is rubbing against the scale or the platform.
2. According to decreasing ionization energy
Cr
со
Fe
V
Mn
Answer: V, Mn, Cr, Fe, Co
Explanation: all elements belong to 4th period. Ionization energy increases from
Left to right
WHAT CAN YOU LEARN OR (LEARNING GOAL) ABOUT MITOSIS AND CELL CYCLE?
Explanation:
At the end of mitosis, the new daughter cells contain the same number of chromosomes as the parent cell. Mitosis enables cellular growth and repair in multicellular organisms.
What is the hydrogen ion concentration of a solution with pH=7.75 ?
Answer:
[tex][H^+]=1.78x10^{-8}M[/tex]
Explanation:
Hello there!
In this case, according to the given information about the pH, it is firstly necessary for us to remember that the pH is defined as the potential of the hydrogen ions in the solution and the concentration of those ions represents how many of them are present in the solution; in such a way, it is possible for us use:
[tex]pH=-log([H^+])[/tex]
Whereas the concentration of hydrogen ions can be calculated as follows:
[tex][H^+]=10^{-pH}[/tex]
So we plug in the given pH to obtain:
[tex][H^+]=10^{-7.75}=1.78x10^{-8}M[/tex]
Regards!
What answer is it and how ? please help !!!!!! ill mark brainlyest if right
Answer:
The answer is B
Brainliest please!
The titration of HCl with NaOH is an example of:
A. a weak acid-weak base titration,
B. a weak acid-strong base titration.
c. a strong acid-strong base titration.
D. a strong acid-weak base titration.
Answer:
I’m pretty sure it’s C
Explanation:
AP Ex
how much corn syrup should be added to water to make 200 mL of a 10% by volume solution
To make 200 mL of a 10% by volume solution, add 20 mL corn syrup to water.
What is volume solution?Volume percent of a solution is defined as the ratio of the volume of solute present in a solution to the volume of the solution as a whole. It means that the volume of a closed figure determines how much three-dimensional space it can occupy. In terms of numerical value, volume is the amount of three-dimensional space enclosed by a closed surface. For example, a substance's space can be solid, liquid, gas, or plasma, or any other space-occupying shape. The volume percentage of a solution can be calculated by dividing the volume of solute by the volume of solution and multiplying the result by 100. The basic formula for volume is length width height, whereas the basic formula for area of a rectangular shape is length width height. The calculation is unaffected by how you refer to the various dimensions: you can, for example, use 'depth' instead of 'height.'To learn more about volume solution, refer to:
https://brainly.com/question/27030789
#SPJ2
Write the structure of all possible peptides containing these amino acids: Asp, Glu, Gln Use single letter abbreviations and capital letters only; i.e. GYR, not Gly-Tyr-Arg. If there are fewer than 6 peptides, leave an appropriate number of answer boxes empty. fill in the blank 1 , fill in the blank 2 , fill in the blank 3 , fill in the blank 4 , fill in the blank 5 , fill in the blank 6
Answer:
QED, EDQ, DQE, EQD, DEQ, QDE
Explanation:
The structure of all possible peptides that contain the given amino acids are :
QED, EDQ, DQE, EQD, DEQ, QDE
where : Asp is represented by the letter code D
Glu is represented by the letter code E
Gln is represented by the letter code Q
Note : when three amino acids combine they form what is known as tripeptide ( i.e. contains two peptide linkages ) while a peptide linkage is been formed by the combination of a carboxyl group of an amino acid and the amino group of different amino acid
12 moles of sodium into grams
Answer:
12 moles sodium= 275.87724000000003 grams
Explanation:
1 moles sodium = 0.043497607849056.
What volume is occupied by 2.0 mol of gas at 3.0 atm
and 27 °C?
1. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -CH3
b) -CH2OH
c) -CH2NH2
d) -CH2BR2. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -F
b) -CH2OH
c) -CHO
d) -CH3
Answer:
1. CH₂Br > CH₂OH > CH₂NH₂ > CH₃
2. -F > -CHO > - CH₂OH > CH₃
Explanation:
The arrangement of the above atom is due to their atomicity and electronegativity of the given compounds.
From (1) we will realize that Bromine (Br) possesses the greatest priority because its atomic number is the highest. This is followed by oxygen (O) in CH₂OH since atomic no 8 is higher than that of Nitrogen N(7). Lastly, CH₃ has the only hydrogen attached to it with the atomic no of (1)
In the second part of the question>
The electronegativity of an element increases across the period and down the group. Fluorine is highly electronegative and contains the highest atomic number of oxygen in -CHO. The oxygen (O) in -CHO has a double bond which gives an edge over the (O) in CH₂OH. Lastly, CH₃ contains a substituted hydrogen atom
Se prepara una concentración molar 0.5M de hidróxido de sodio (NaCH) con la finalidad de determinar el grado de acidez de una bebida embotellada. Calcula la cantidad de gramos de hidróxido de sodio (NaCH) que se requiere para preparar 5 litros de dicha solución.
Answer:
100 g
Explanation:
Primero hay que calcular el número requerido de moles de NaOH, usando la definición de molaridad:
Molaridad = moles / litros0.5 M = moles / 5 Lmoles = 2.5 molesAhora hay que convertir 2.5 moles de NaOH en gramos, usando su masa molecular:
2.5 mol * 40 g/mol = 100 gSe requieren 100 gramos de NaOH.
How many L of 3.0M solution
can be made with 78g of
NaCl?
Answer:
Need to find moles NaCl.
526 grams NaCl (1 mole NaCl/58.44 grams)
= 9.0 moles NaCl
----------------------------------------------------
now,
Molarity = moles of solute/Liters of solution
or, for our purposes
Liters of solution = moles of solute/Molarity
Liters of solution = 9.0 moles NaCl/3.0 M
= 3.0 liters in volume
To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).
Answer: 2.20 g Pb
They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88
What is all the colors in a rainbow
Answer:
Red, orange, yellow, green, blue, indigo, violet.
Explanation:
Answer:
Red, orange, yellow, green, blue, purple, violet.
Explanation:
In the acetylene torch, acetylene gas (C2H2) burns in oxygen to produce carbon dioxide water and energy. How many moles of CO2 are formed from the reaction with 1.20 moles of C2H2?
Given the following equation
2C2H2(g) + 502(g) = 4CO2(g) + 2H2O(g)
Answer: 2.40 moles of [tex]CO_2[/tex] will be formed in the reaction.
Explanation:
Given values:
Moles of [tex]C_2H_2[/tex] = 1.20 moles
The given chemical equation follows:
[tex]2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O[/tex]
By the stoichioemetry of the reaction:
If 2 moles of [tex]C_2H_2[/tex] produces 4 moles of carbon dioxide
Then, 1.20 moles of [tex]C_2H_2[/tex] wil produce = [tex]\frac{4}{2}\times 1.20=2.40mol[/tex] of carbon dioxide
Hence, 2.40 moles of [tex]CO_2[/tex] will be formed in the reaction.
Please help will give brainliest to right answer!!
You add 1.5 moles of HF to 6 liters of water. The concentration is at equilibrium when [H+] is at 0.10 M. What is the Ka of HF? HF -> H+ + F-.
A) 0.067
B) 0.10
C) 0.25
D) 1.5
Answer:
C
Explanation:
NP
PLEASEEE HELPPP WILL MARK BRAINLIEST FOR RIGHT ANSWER!!!
You have an unknown concentration of 0.035 L of HCl acid and added 0.033 L of 0.3 M NaOH before the equivalence point was reached. What is the concentration of the HCl?
HCl + NaOH -> H2O + NaCl
A) 0.28 M HCl
B) 0.11 M HCl
C) 0.035 M HCl
D) 3.14 M HCl
Answer:
A
Explanation:
Answer:
C
Explanation:
Pretty sure!
concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature (a) what volume (mL) of this solution is needed to make a 1.00L solution of 1.00M phosphoric acid?
Answer:
82.0 mL
Explanation:
Step 1: Given data
Concentration of concentrated acid (C₁): 12.2 MVolume of concentrated acid (V₁): ?Concentration of dilute acid (C₂): 1.00 MVolume of dilute acid (V₂): 1.00 LStep 2: Calculate the required volume of the concentrated acid
We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL