Answer:
b
Explanation:
What is the momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s?
Answer:
p = 17500 kg*m/s
Explanation:
p = mv
p = 35.0 kg * 500.0 m/s = 17500 kg*m/s
The momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s will be equal to 17500 [tex]\dfrac{kg.m}{s}[/tex]
What is momentum ?
When any body which is having a mass and is in the motion carry momentum with it.
The formula for finding the momentum of any body is given by
[tex]Momentum = Mass\times Velocity[/tex]
Given that-
[tex]Mass = 35 kg[/tex]
[tex]Velocity = 500[/tex] [tex]\dfrac{m}{s}[/tex]
[tex]Momentum = 35\times500[/tex]
[tex]momentum= 17500 \dfrac{kg.m}{s}[/tex]
Hence The momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s will be equal to 17500 [tex]\dfrac{kg.m}{s}[/tex]
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For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of product is given by which set of expression?
Answer: [tex]-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}[/tex]
Explanation:
Rate of a reaction is defined as the rate of change of concentration per unit time.
Thus for reaction:
[tex]2Br^.\rightarrow Br_2[/tex]
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
[tex]Rate=-\frac{d[Br^.]}{2dt}[/tex]
or [tex]Rate=+\frac{d[Br_2]}{dt}[/tex]
Thus [tex]-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}[/tex]
Assessment started: undefined. Item 1 Which statement accurately describes what happens when ice melts in terms of energy? A:The ice releases energy which causes chemical bonds to break, changing the ice to water.;B:The ice releases energy which causes the water molecules to have less kinetic and potential energy, changing their configuration from solid to liquid. C:The ice absorbs energy which causes the water molecules to have more kinetic and potential energy, changing their configuration from a solid to a liquid. D:The ice absorbs energy which causes chemical bonds to break, changing ice to water.
Answer:
A.
Explanation:
it's needed top release energy due to the breaking of chemical bonds.
Answer:
A: the ice releases energy which causes chemical bonds to break, changing the water to ice.
Explanation:
Jasper made a list of the properties of electromagnetic waves. Identify the mistake in the list. Electromagnetic Wave Properties 1. Are made up of an electric field and a magnetic field 2. Are longitudinal waves 3. Can travel through space 4. All travel at the same speed in a vacuum Line 1 has a mistake. Line 2 has a mistake. Line 3 has a mistake. Line 4 has a mistake.
Answer:
Statement 2 is wrong
Explanation:
To check the statements in this exercise, let's describe the main properties of electromagnetic waves. Let's describe the characteristics
* they are transverse waves
* formed by the oscillations of the electric and magnetic fields
* the speed of the wave is the speed of light
with these concepts let's review the final statements
1) True. Formed by the oscillation of the two fields
2) False. They are transverse waves
3) True. Can travel by vacuum as they are supported by oscillations of the electric and magnetic fields
4) True. They all have the same speed of light
Statement 2 is wrong
A 0.300 kg mass is attached to
a 26.6 N/m spring. It is pulled
0.120 m and released. How much
Kinetic Energy does it have when it
is 0.0600 m from equilibrium?
(Unit = J)
Answer:
0.144 J
Explanation:
From the question above,
Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring
E' = E.k+Ep...................... Equation 1
Ek = E'-Ep......................... Equation 2
Where E' = total elastic energy, E.k = kinetic energy, E.p = potential energy.
E' = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.
Ep = 1/2ke² = 1/2(26.6)(0.06²)
Ep = 0.04788 J
Therefore,
Ek = 0.19152-0.04788
Ek = 0.144 J
I just realized my answer was incorrect but I don’t know how to delete an answer.
A ball is launched upward at an angle from the ground. Which way does its velocity point at the top?
A. Vertical
B. It isn't moving
C. Horizontal
D. Horizontal and Vertical
A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.
Answer:
14.4 mThe distance covered by the body is 14.4 m.
Solution,
Initial velocity(u)= 0 m/s( according to Question, the body starts from rest.that's why initial velocity(u) becomes zero.
Acceleration (a)= 0.2 m/s
Time (t):
[tex] \frac{1}{5} minute = \frac{1}{5 } \times 60 \: seconds[/tex]
[tex] = 12 \: seconds[/tex]
Now,
Applying third equations of motion:
[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times 12 + \frac{1}{2} \times 0.2 \times {(12)}^{2} \\s = 0 + 14.4 \\ s = 14.4 \: metre[/tex]
Thus, the distance covered by the body is 14.4 metre.
Further more information:
Application of equation of motion in different situation:When a certain object comes in motion from rest, in the case, initial velocity(u)= 0 m/sWhen a moving object comes in rest,in the case, final velocity(v)= 0 m/sIf the object is moving with uniform velocity, in the case, (u=v)If any object is thrown vertically upward, in the case, acceleration (a)= -gWhen an object is falling from certain height, in the case, u= 0 m/sWhen an object is thrown vertically upwards in the case, final velocity at maximum height becomes 0.A convex lenses forms a real image of an object magnified two times. The distance between the object and image is 60cm. Find the focal lenth of the lense
Answer:
13.3cm ≈ 13cm
Explanation:
The following data were obtained from the question:
Magnification (M) = 2
Distance between image and object = 60cm
Focal length (f) =..?
Next, we shall determine the image distance (v) and the object distance (u). This can be obtained as follow:
Magnification (M) = image distance (v) / object distance (u)
M = v/u
Magnification (M) = 2
2 = v/u
Cross multiply
v = 2u
From the question,
Distance between image and object = 60cm i.e
v + u = 60
v = 2u
2u + u = 60
3u = 60
Divide both side by 3
u = 60/3
u = 20cm.
v = 2u = 2 x 20 = 40cm
Now, we can obtain the focal length of the lens as follow:
1/f = 1/v + 1/u
u = 20cm.
v = 40cm
1/f = 1/v + 1/u
1/f = 1/40 + 1/20
1/f = (1 + 2)/40
1/f = 3/40
f = 40/3
f = 13.3cm ≈ 13cm
Therefore, the focal lenth of the lens is 13.3cm ≈ 13cm
What us meant by Velocity ratio of simple machine is 4?
100 POINTS! I will mark brainliest! Record your hypothesis as an “if, then” statement for the rate of dissolving the compounds: Record your hypothesis as an “if, then” statement for the boiling point of the compounds:
Answer:
Rate of dissolving compounds:
If we increase the temperature of the solution, then the dissolving compound would dissolve more easily.
Boiling Point of Compounds:
If the inter-molecular forces of any compound is really strong, then the boiling point of the compound would be really high.
Answer: This is just re worded from the other answer to give a different saying to the responce.
Record your hypothesis as an “if, then” statement for the rate of dissolving the compounds: If we increase the temperature then the compound will dissolve easier.
Record your hypothesis as an “if, then” statement for the boiling point of the compounds: If the forces of the compound itself is strong, then the boiling point would be way higher.
an astronaut is said to be weightless when he/she travels in a satellite.does it mean that the earth does not attract him/her?
Answer:
No, gravitational force is a force having infinite range. It only reduces to an extent that astronauts cannot feel it.
Explanation:
In physics what does 7.56 × 5.746 equal ?
Answer:
43.43
Explanation:
5.746 x 7.56 = 43.43976
As the least number of desimal is two so our awnser should contain two digits after the decimal point.
Ans: 43.43.
Answer:
43.4 (Plato/Edmentum)
Explanation:
#1: 7.56 * 5.746
#2: 43.43976
#3: 43.4
The golf club is in contact with the golf ball for 1.8 ms and exerts a force of 1500 N on the golf ball. The mass of the golf ball is 0.045kg Calculate the velocity of the golf ball as it leaves the golf club. Velocity ______________ m/s Thank you :)
Answer:
Force x time = Impulse which is a change in momentum. You can then use this to find the velocity (as you know the ball's initial momentum is 0)
1500 x 1.8 x 10^-3 = 0.045v
v = (1500 x 1.8 x 10^-3)/0.045 = 60 ms^-1
Explanation:
The distance the ball travels is directly related to the force that is applied from the head of the golf club, the angle at which the force is applied, gravity, as well as air and wind resistance. The force of the club head on the ball causes the ball to compress and apply an equal amount of force on the club.
use ke=1/2mv^2 rearrange for V
The golf club is in contact with the golf ball for 1.8 ms and exerts a force of 1500 N on the golf ball. The mass of the golf ball is 0.045kg then the velocity of the golf ball as it leaves the golf club. Velocity 60 m/s
what is velocity ?Velocity can be defined as the rate at which the change in the position of the object with respect to time, it is mainly involve in speeding of the object in a specific direction.
Velocity is a vector quantity which shows both magnitude and direction and The SI unit of velocity is meter per second (ms-1), the change in magnitude or the direction of velocity of a body is said to be accelerating.
Finding the final velocity is simple but few calculations and basic conceptual knowledge are needed.
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What does FAI stand for?
Answer:
Femoroacetabular impingement
It occurs when an area of your hip joint becomes pinched when you move in certain directions. :)
a) Under what circumstances would a constant force result in increasing acceleration on a body? b) Under what circumstances would a constant force result in zero acceleration on a body?
Answer:
Remember the equation:
F = m*a
where F is force, m is mass and a is acceleration.
If we have F constant. and we want that increases, then we can have the case where m decreases.
The mass can decrease in cases like a rocket, where as the fuel of the rocket consumes, the mass of the rocket decreases and the acceleration increases.
b) The cases where a constant force results in a constant acceleration of zero, is when the force is canceled, an example of this is the constant force of the gravity in all the objects. The objects that are in the ground are being affected by this force, but the gravitational force is canceled with the normal force of the ground. Then we have a constant force that does not cause any acceleration.
Answer the following questions regarding the equation:
N₂ + 3H₂ → 2NH₃
1) indicates what type of reaction is
2) what represents the coefficients 3 and 2 in the previous reaction is done for
3) What would be missing in the previous equation to make it more accurate is
Explanation:
1) This is a synthesis reaction (two or more reactants combine to form a single product).
2) The coefficients are added to balance the reaction.
3) Adding the states of matter (solid, liquid, gas) will make the reaction more precise.
A woman is standing on a steep hillside in the rain and is not moving. A
sudden gust of wind blows down the hillside, which makes her start sliding
down the hill. When the wind stops blowing, the woman continues to slide.
Which of the following statements explains why she continues to slide down
the hillside?
A. The component of the woman's weight along the hillside is larger
than the kinetic friction between the woman and the ground.
B. The component of the woman's weight along the hillside is less
than the kinetic friction between the woman and the ground.
C. The component of the woman's weight along the hillside is larger
than the static friction between the woman and the ground.
D. The component of the woman's weight along the hillside is less
than the static friction between the woman and the ground.
SUBMIT
Answer:
The correct option is;
A. The component of the woman's weight along the hillside is larger than the kinetic friction between the woman and the ground
Explanation:
Given that the coefficient of static friction is always larger than the coefficient of kinetic friction, we have that before the wind blew, the component of the woman's weight along the hillside was lesser than the static friction between the woman and the ground, when the wind blew the total force of the wind and the component of the woman's weight put her into motion such that the acting frictional force was then the kinetic frictional force which was lesser than the kinetic frictional force so the woman continues to slide down the hillside without the wind.
An object of mass 800g hangs on a spring. Calculate the force exerted by the object if acceleration due to gravity is 10/s2
Answer:
8 N
Explanation:
Using the equation F=ma (F: force/ m: mass in kg/ a: acceleration),
F = (800/1000)(10)
F = 8 N
What must be included when describing the displacement of an object?
Answer:
the unit must always be indicated
Explanation:
displacement is alway in metre (m)
Answer:
A: measurement and direction
Explanation:
on edge! hope this helps!!~ (≡^∇^≡)
when a 0.622kg basketbll hits the floor its velocit changes from 4.23m/s down to 3.85m/s up. if the averge force was 72.9N how much time was it in contact with the floor?
Answer:
Time, t = 3.2 ms
Explanation:
It is given that,
Mass of basketball, m = 0.622 kg
Initial velocity, u = 4.23 m/s
Final velocity, v = 3.85 m/s
Average force acting on the ball, F = 72.9 N
We need to find the time of contact of the ball with the floor. Let t is the time of contact. So,
[tex]F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{0.622\times (3.85-4.23)}{72.9}\\\\t=0.0032\ s\\\\\text{or}\\\\t=3.2\ ms[/tex]
So, the ball is in contact with the floor for 3.2 ms.
The index of refraction of a clear plastic is listed as 1.89 in the book, but you measured the angle of incidence 63.5° and the angle of refraction 32°. What index of refraction did you calculate and what is the percentage error?
Answer:
index of refraction = 1.69percentage error = 10.58%Explanation:
According to Snell's law, the ratio of the sine of angle of incidence to the sine of angle of refraction is a constant for a given pair of media. The constant is known as the refractive index.
Mathematically [tex]\frac{sin i}{sin r} = n[/tex]
i = angle of incidence measured = 63.5°
r = angle of refraction measured = 32°
n = refractive index
[tex]n = \frac{sin 63.5^{0} }{sin 32^{0} } \\n = \frac{0.8949}{0.5299}\\ n = 1.69[/tex]
The index fraction calculated is approx. 1.69.
If the index of refraction of a clear plastic as listed in the book is 1.89 and the calculated is 1.69, the percentage error will be calculated as thus;
%error = [tex]\frac{1.89-1.69}{1.89} * 100[/tex]
%error = [tex]\frac{0.2}{1.89}*100[/tex]
%error = [tex]\frac{20}{1.89}[/tex]
%error = 10.58%
A 13,500 kg railroad freight car travels on a level track at a speed of 4.5 m/s. It collides and couples with a 25,000 kg second car, initially at rest and with brakes released. What is the speed of the two cars after collision?
Answer:
V = 1.578m/s
Explanation:
(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V
(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V
60750 + 0 = (38500)V
60750 = 38500V
V = 60750/38500
V = 1.578m/s
The speed of the two cars after the collision will be equal to V = 1.578m/s
What is collision?A collision is any event in which two or more bodies exert forces on each other in a relatively short time. Although the most common use of the word collision refers to incidents in which two or more objects collide with great force, the scientific use of the term implies nothing about the magnitude of the force
Now from the perfectly inelastic collision, the conservation of momentum will be
(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V
(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V
60750 + 0 = (38500)V
60750 = 38500V
V = 60750/38500
V = 1.578m/s
Hence the speed of the two cars after the collision will be equal to V = 1.578m/s
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identify units for volts
Answer:
Volts itself is SI Unit of Electric Potential.
Explanation:
A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499cm3499cm 3 of air at atmospheric pressure (1.01×105Pa)(1.01×10 5 Pa) and a temperature of 27.0∘C27.0 ∘C. At the end of the stroke, the air has been compressed to a volume of 46.2cm 346.2cm 3 and the gauge pressure has increased to 2.72×106Pa2.72×10 6Pa. Compute the final temperature.
Answer:
503°C
Explanation:
According to the given situation, the computation of the final temperature is shown below:
In this question we use the law of ideal gas i.e
pV = nRT
i.e
[tex]\frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_2}[/tex]
Therefore
[tex]T_2 = T_1 (\frac{p_2}{p_1}) (\frac{V_2}{V_1})[/tex]
[tex]= 300\ k (\frac{2.72 \times 10^{6} Pa + 1.01 \times 10^{5} Pa}{1.01 \times 10^{5} Pa})(\frac{46.2 cm^3}{499 cm^3})[/tex]
= 776 k
= (776 - 273)° C
= 503°C
Therefore the final temperature is 503°C
We simply applied the above formulas so that the final temperature could arrive
An object has a mass of 785g and a volume of 15cm cubed what is its density
Answer:
we have ,
mass(m)=785g
volume (v)= 15 cm^3
now , density(d)= m/ v
=785/15
=52.33g/cm^3... is anwer
What is the meaning of wwe
Answer:
World Wrestling Entertainment, Inc., d/b/a WWE, is an American integrated media and entertainment company that is primarily known for professional wrestling. WWE has also branched out into other fields, including movies, football, and various other business ventures.
Answer:
This means WORLD WRESTLING ENTERTAINMENT.
Explanation:
This is an american integrated media and entertainment company that is primarily known for PROFESSIONAL WRESTLING.
The wavelength of light is 5000 angstrom. Express it in nm and m.
Answer:
1 angstrom = 0.1nm
5000 angstrom = 5000/1 × 0.1nm
= 500nm[tex]1 \: angstrom = 1 \times {10}^{ - 10} m[/tex]
5000 angstrom = 5000 × 1 × 10^-10
= 5 × 10^-7 mHope this helps you
3. A force of 200 N is applied to an object of area 2 sq.m . the pressure will be
Answer: 100 Pa
Explanation:
P = F / A = 200/ 2 = 100 Pa
Answer:
100 Pa
Explanation:
Pressure = Force/Area
P = 200/2
P = 100
The SI unit is Pa for pressure, one newton per square meter N/m².
The photons of different light waves:
Answer:
(C)
Explanation:
Because the photons being different makes them have different amounts of energy, they both with have a precise and different energy from each other.
Please Help!!! I WILL GIVE BRAINLIEST!!!! An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C and separation between the charged plates is 2.0 cm. a.) Determine the horizontal distance traveled by the electron when it hits the plate. b.)Determine the velocity of the electron as it strikes the plate.
Answer:
a. 9.52 cm b. 4.34 × 10⁶ m/s
Explanation:
a. The horizontal distance traveled by the electron when it hits the plate.
The electric force F on the electron due to the electric field E of mass, m is
F = -eE = ma
a = -eE/m where a = acceleration of electron
The vertical distance moved by the electron is given by
Δy = ut +1/2at²
u = initial vertical velocity = 0. and take the top plate as y = 0 and bottom plate as y
So,
0 - y = 0 × t + 1/2at²
-y = 1/2at²
substituting a = -eE/m
-y = 1/2(-eE/m)t²
y = eEt²/2m
making t subject of the formula,
t = √(2ym/eE) where t is the time it takes to reach the bottom plate.
Since E = 4.0 × 10² N/C, y = distance between plates = 2.0 cm = 0.02 m, m = 9.109 × 10⁻³¹kg and e = 1.602 × 10⁻¹⁹ C
t = √[(2 × 0.02 m × 9.109 × 10⁻³¹kg)/(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C)]
t = √[(0.36436 × 10⁻³¹kgm)/(6.408 × 10⁻¹⁷ N)]
t = √[(0.0569 × 10⁻¹⁴kgm/N)t
t = 0.238 × 10⁻⁷ s
t = 23.8 × 10⁻⁹ s
t = 23.8 ns
The horizontal distance moved when it hits the plates x = vt where v = initial horizontal velocity = 4.0 × 10⁶ m/s
x = 4.0 × 10⁶ m/s × 23.8 × 10⁻⁹ s
= 0.0952 m
= 9.52 cm
b. The velocity of the electron as it strikes the plate.
To find the velocity of the electron as it strikes the plates, we calculate its final vertical velocity V as it strikes the plate. This is gotten from
v' = u + at since u = 0,
v' = at
= -eEt/m
= -(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C × 0.238 × 10⁻⁷ s)/9.109 × 10⁻³¹kg
= -1.525 × 10⁻²⁴ Ns/9.109 × 10⁻³¹kg
= -0.167 × 10⁷ m/s
= -1.67 × 10⁶ m/s
So, the resultant velocity as it strikes the plate v = √(v'² + v²)
= √((-1.67 × 10⁶ m/s)² + (4 × 10⁶ m/s)²)
= √(2.7889 + 16) × 10⁶ m/s
= √18.7889 × 10⁶ m/s
= 4.335 × 10⁶ m/s
≅ 4.34 × 10⁶ m/s