Which example illustrates Newton's second law?
A. A wheelbarrow remains stationary when no one pushes on it.
B. More mass is added to a wheelbarrow, and a larger force is
required to move it.
C. A person pushes a wheelbarrow, causing it to move forward.
D. The force of a wheelbarrow on the ground is equal to the force of
the ground on the wheelbarrow.

Answers

Answer 1

Answer:B

Explanation:

Mass

Answer 2

More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.

What is force?

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."

Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.

To find more about force, refer the link:

https://brainly.com/question/13191643

#SPJ2


Related Questions

What is the Net Force acting
on the box below?

Answers

The Net Force would be 2 N to the left.

21 N is being used to push the box to the right and 23 N is used to push it left. There is a stronger force pushing the box towards the left. The different in the two numbers would give you the net force acting on the box and the direction of the arrow with the greatest force will tell you the direction.

Is Time and Light both connected in anyway?​

Answers

Answer:

It is not connected by any way

1. Some penguins are playing turtle hockey on the frictionless ice. Ramona the penguin hits the turtle

with a force of magnitude F, and the turtle experiences an acceleration of magnitude a (Fand a are of

unknown size). Francisco the penguin hits the same turtle with a force of magnitude three times

greater than Ramona's force (3F). What will the resulting acceleration of the turtle be? Answer in

terms of a. Support your answer with reasoning and reference to Newton's Second Law.

Answers

Answer:

a' = 3a

Explanation:

Newton's Second Law gives the magnitude of the unbalanced force applied to an object as follows:

F = ma

where,

F = Force Applied

m = Mass of Object

a = acceleration

FOR RAMONA'S PUSH:

F = F

m = m

a = a

Therefore,

F = ma  

a = F/m   ---------------- equation (1)

FOR FRANSICO'S PUSH:

F = 3F

m = m  (mass of turtle will be same)

a = a'

Therefore,

3F = ma'  

a' = 3F/m

using equation 1

a' = 3a

What happens to the minerals as gneiss forms from schist?

Answers

Answer:

Explanation:

Gneiss is a high grade metamorphic rock, meaning that it has been subjected to higher temperatures and pressures than schist. However, unlike slate and schist, gneiss does not preferentially break along planes of foliation because less than 50% of the minerals formed during the metamorphism are aligned in thin layers.

PLS HELP THIS IS DUE IN TWO HOURS

Answers

I think C orrrrrrr A

Answer:

C

Explanation:

Which part of a DC generator keeps the electric current flowing in only one
direction?
A. The permanent magnets
B. The commutator
o
C. The power source
D. The wire coil

Answers

it’s the commutator

Which of the following is a characteristic of a base?
A. pH greater than 7
B. pH between 4 and 13
C. pH between 4 and 9
D. pH less than 7

Answers

Answer:

A. pH greater than 7

Explanation:

Because a base has a pH scale of 8 to 14

An insulated rigid tank initially contains 1.4-kg saturated liquid water and water vapor at 200°C. At this state, 25 percent of the volume is occupied by liquid water and the rest by vapor. Now an electric resistor placed in the tank is turned on, and the tank is observed to contain saturated water vapor after 20 min. Determine:


(a) the volume of the tank

(b) the final temperature

(c) the electric power rating of the resistor

Answers

Solution:

Mass of liquid water and water vapor in the insulated tank initially = 1.4 kg

Temperature = 200 °C

And 25% of the volume by liquid water is steam.

State 1

[tex]$m=\frac{V}{v}$[/tex]

[tex]$m=m_f+m_g$[/tex]

[tex]$1.4=\frac{0.25V}{v_f}+\frac{0.75V}{v_g}$[/tex]

[tex]$1.4=\frac{0.25V}{1.1565 \times 10^{-3}}+\frac{0.75V}{0.1274}$[/tex]       (taking the value of [tex]$v_g$[/tex] and [tex]$v_g$[/tex] at 200°C  )

[tex]$V=6.304 \times 10^{-3}$[/tex]

Now quality of vapor

[tex]$x=\frac{m_g}{m}$[/tex]

  [tex]$=3.377 \times 10^{-3}$[/tex]

Internal energy at state 1 can be found out by

[tex]$u_1=u_f+xu_{fg}$[/tex]

    [tex]$=850.65+3.377\times10^{-3}\times 1744.65$[/tex]

    = 856.54 kJ/kg

After heating with the resistor for 20 minutes, at state 2, the tank contains saturated water vapor [tex]$v_2=v_g \text { and }\ x=1$[/tex]

Tank is rigid, so volume of tank is constant.

[tex]$v_g=v_2=\frac{V}{m}$[/tex]

[tex]$v_g=\frac{6.304\times 10^{-3}}{1.4}$[/tex]

[tex]$v_g=4.502 \times 10^{-3} \ m^3 /kg$[/tex]

Now interpolate the value to get temperature at state 2 with specific volume value to get final temperature

[tex]$T_2=360+(374.14-360)\left(\frac{0.004502-0.006945}{0.003155-0.006945}\right)$[/tex]

   = 369.11° C

Internal energy at state 2

[tex]$u_2=2154.9 \ kJ/kg$[/tex]

Now power rating of the resistor

[tex]$P=\frac{m(u_2-u_1)}{t}$[/tex]

[tex]$P=\frac{1.4(2154.9-856.54)}{20 \times 60}$[/tex]

  = 1.51 kW

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