Which features are created by groundwater erosion and deposition? Check all that apply. stalagmites sinkholes rills stalactites gullies rivers

Answer:

just lose it then lol

Explanation:

Answer:

no similarities but if that's so it's temperature

Answer:

London Dispersion

Answer:

K₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2KOH(aq)  

Explanation:

The type of reaction is Double Displacement (Metathesis)

Answer:

b. .28 M KCI

Explanation:

Use the dilution formula.

C₁V₁ = C₂V₂

C₂ = C₁V₁/V₂

C₂ = 1.6*0.175 / 1.0

C₂ = 0.28

The new concentration of the solution of KCl which is diluted to a new volume of 1.0 L is  0.28 M KCI.

Concentration is the abundance of substance or constituent divided by the volume of the mixture.

By the dilution formula

C₁V₁ = C₂V₂

C₂ = C₁V₁/V₂

The concentration is 1.6 M

The volume of KCl is 0.175

The new volume v2 is 1.0 l

Putting the values in the equation

C₂ = 1.6 × 0.175 / 1.0

C₂ = 0.28

Thus, the correct option is b. 0.28 M KCI.

Learn more about concentration

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Answer:

Using the drop down Menu

Proton : Possessing a Charge of +1. It is found in the Nucleus and has a Mass of "A"

Neutron; Possesses a charge of 0. It is situated in the Nucleus and Has a Mass of "B"

Electron: Has a charge of -1. Found in the Orbitals of the atom and has a mass of "C"

Answer:

cis-2-pentene

Explanation : The stereoisomers are the compound which differs only in the spatial arrangement of the atoms across the stereogenic centers.

There are mainly two forms of stereoisomers cis and trans. Cis-isomers are those where the two bulky or functional groups are arranged on the same side across the stereogenic center; whereas, in trans-isomers the two bulky groups or functional groups are arranged in the opposite sides of stereogenic center.

Answer:

385.6cm³

Explanation:

Using Charles law equation as follows;

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 355cm³

V2 = ?

T1 = 325K

T2 = 353K

Using V1/T1 = V2/T2

355/325 = V2/353

1.092/1 = V2/353

Cross multiply

1.092 × 353 = V2

V2 = 385.6cm³

Explanation:

HCl(aq)+ NaOH(aq)→NaCl(aq)+H2O(l) ..

Answer:

V = 50.77 L

Explanation:

Given that,

No. of moles, n = 2

Pressure, P = 0.947 atm

Temperature, T = 20°C = 293 K

We need to find the volume occupies by Nitrogen gas. Using gas law,

[tex]PV=nRT\\\\V=\dfrac{nRT}{P}[/tex]

Where

R is gas constant

Put all the values,

[tex]V=\dfrac{2\times 0.08205\times 293}{0.947}\\\\V=50.77\ L[/tex]

So, the volume occupied by the gas is equal to 50.77 L.

Answer:

2KMnO₄ + 4SO₂ + H₂ ⟶ K₂SO₄ + 2MnSO₄ + H₂SO₄

Explanation:

KMnO₄ + SO₂ + H₂ ⟶ K₂SO₄ + MnSO₄ + H₂SO₄

Balanced Equation

2KMnO₄ + 4SO₂ + H₂ ⟶ K₂SO₄ + 2MnSO₄ + H₂SO₄

-TheUnknownScientist

Answer:

C

Explanation:

Usa test prep.

Answer:

To walk or run, and to wake up.

Answer:

False

Explanation:

chemically stable compounds are stable so they do not break down quickly.

Answer:

I think False

As

stable compounds are of lower energy and have a balanced charge. ... So, very loosely, a compound could be said to be stable when it is low in potential energy, has a neutral or spread out charge, and can be used in regular conditions.

THAT'S WHY THEY DO NOT BREAK DOWN EASILY

if wrong correct me pls

have a nice day

#Captainpower

Answer:

2.5

Explanation:

The given costs for the purchase and delivery of the cupcakes are;

The cost of 10 cupcakes and the delivery fee = $30

The cost of 25 cupcakes and the delivery fee = $67.50

Let 'c' represent the fixed cost of delivery of the cup cakes, and let 'x' represent the cost of each cup cake, we have;

30 = 10·x + c...(1)

67.50 = 25·x + c...(2)

Subtracting equation (1) from equation (2) gives;

67.50 - 30 = 37.50 = 25·x - 10·x + c - c = 15·x

∴ x = 37.50/15 = 2.5

The cost of each cupcake, x = 2.5

(∴ The delivery fee = 30 - 10 × 2.5 = 5)

The cost of each cupcake is 2.5.

Answer:

Explanation:

it should be more electro-negative  

than hydrogen and  it should be small sized atom  

The molecules who fulfill these needs are  

oxygen, nitrogen and fluorine.

Answer:1.59

Explanation: For every mol of Ca(OH)2 there are two moles of OH so the concentration of OH is .013 x2 =.026 M OH

pOH = - log [OH] so -log .026 = 1.59

pOH is the negative logarithm of hydroxide ion concentration. 1.59 is the pOH of a 0.013 M Ca(OH)₂ solution.

The term pOH is defined as the negative of the logarithm of the OH− ion concentration. It is represented by the formula  pOH = - log [OH−].

pOH is the activity of acidity or alkalinity of a solution by determining the concentration of OH− ions.

If the pOH value is less than 7, the solution is basic. If the pOH value is equal to 7, the solution is neutral. If the pOH value is more than 7, the solution is acidic.

For every mol of Ca(OH)₂ there are two moles of hydroxide therefore, the concentration of OH is 0.013 x 2 = 0.026 M OH

According to the formula of pOH

pOH = - log [OH]

-log .026 = 1.59

Thus, the pOH of a 0.013 M Ca(OH)₂ solution is 1.59.

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The complete question is: Is the compound [tex]FeCl_{3}[/tex] ionic or covalent ?

Answer: Compound  [tex]FeCl_{3}[/tex] is an ionic in nature.

Explanation:

When a metal atom combines with a non-metal atom then transfer of electrons take place from metal towards the non-metal. As a result, an ionic bond is formed between the atom and compound formed is called an ionic compound.

For example, [tex]FeCl_{3}[/tex] compound contains Fe atom which is a metal and Cl atom which is a non-metal. Hence, electrons will be transferred from Fe atom to the Cl atom forming an ionic bond.

Hence, [tex]FeCl_{3}[/tex] is an ionic compound.

Thus, we can conclude that [tex]FeCl_{3}[/tex] is an ionic compound.

Answer: 2

Bc when you subtract 12 from 14 you get 2

Answer:

This illustrates Boyle's law, which states that a gas expands if the pressure decreases while all other variables are kept constant. When heating a marshmallow in a microwave, some moisture inside the marshmallow evaporates, adding gas to the bubbles. In addition, a warmer gas pushes outward with more force.

Explanation:

Answer:

12 g/mol

Explanation:

From Avogadro's law;

V1/n1 = V2/n2

V1 =  5.0 dm^3

n1 = 15 g/26 g/mol = 0.6 moles

V2 = 1.0 dm^3

n2 = ?

V1n2 = V2n1

n2 = V2n1/V1

n2 = 1 * 0.6/5

n2 = 0.12 moles

Molar mass= mass of gas D/number of moles of gas D

Molar mass= 1.4 g/0.12 moles

Molar mass= 12 g/mol

D. A town has started a new recycling and composting program

Answer:

D  A town has started a new recycling and composting program

Explanation:

Answer:

2. Solute

3. Suspension

4. Colloid

5. Compound

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 0.0014 \ mol \ Cu}}[/tex]

Explanation:

We are asked to convert particles to moles.

1 mole of any substance contains the same number of particles (atoms, molecules, formula units). This is Avogadro's Number or 6.022*10²³.

In this problem, the particles are atoms of copper. So, 1 mole of copper contains 6.022*10²³ atoms of copper

Use Avogadro's Number to make a ratio.

[tex]\frac{ 1 \ mol \ Cu}{ 6.022*10^{23} \ atoms \ Cu}[/tex]

We are trying to convert 8.3*10²⁰ atoms of copper to moles, so we multiply that value by the ratio.

[tex]8.3*10^{20} \ atoms \ Cu*\frac{ 1 \ mol \ Cu}{ 6.022*10^{23} \ atoms \ Cu}[/tex]

The units of "atoms Cu" will cancel.

[tex]8.3*10^{20}\frac{ 1 \ mol \ Cu}{ 6.022*10^{23} }[/tex]

Condense the expression into 1 fraction.

[tex]\frac{8.3 *10^{20}}{ 6.022*10^{23} } \ mol \ Cu[/tex]

[tex]0.001378279641 \ mol \ Cu[/tex]

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we calculated that is the ten-thousandths place.

The 7 in the hundredth thousandth place tells us to round the 3 up to a 4.

[tex]0.0014 \ mol \ Cu[/tex]

8.3*10²⁰ atoms of copper are equal to 0.0014 moles of copper.

Answer:

[tex]P_2=7.09atm[/tex]

Explanation:

Hello!

In this case, given the change in volume and pressure of the gas, it is possible for us to recall the Boyle's law as way to understand the inversely proportional relationship between pressure and volume:

[tex]P_1V_1=P_2V_2[/tex]

Thus, when solving for the final pressure, P2, given the initial pressure and volume and the final volume, we obtain:

[tex]P_2=\frac{P_1V_1}{V_2}\\\\P_2=\frac{2.27atm*2.50L}{0.80L}\\\\P_2=7.09atm[/tex]

Best regards!

Answer:

7.1 atm

Using Boyle’s law, P1 V1=P2 V2.