Answer:
A. Continent material
Explanation:
Eruptions of molten material, which results in continent material is a piece of evidence of seafloor spreading.
Continent material is one piece of evidence of seafloor spreading. Option b is correct.
What is seafloor spreading?Seafloor spread is a phenomenon that happens along mid-ocean ridges, when new oceanic crust is generated by volcanic activity and then progressively travels away from the ridge.
The geological activity of seafloor spreading occurs when tectonic plates split apart.
Continent material is one piece of evidence of seafloor spreading.
Hence, option b is correct.
To learn more about the seafloor spreading, refer to the link;
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Hydrogen fuel cells are used on the space shuttle to provide the shuttle with all of its electrical energy. Explain why fuel cells are used instead of batteries.
Answer:
Hydrogen used in fuel cells has the energy to weight ratio ten times greater than lithium-ion batteries. Consequently, it offers much greater range while being lighter and occupying smaller volumes. It can also be recharged in a few minutes, similarly to gasoline vehicles.
an elastic cord 61 cm long when a weight of 75N hangs from it, but 85cm when a weight of 210N hangs from it. what is the spring constant of the cord
Answer:
560 N/m
Explanation:
F = kx
75 N = k (0.61 m − L)
210 N = k (0.85 m − L)
Divide the equations:
2.8 = (0.85 − L) / (0.61 − L)
2.8 (0.61 − L) = 0.85 − L
1.708 − 2.8L = 0.85 − L
0.858 = 1.8L
L = 0.477
Plug into either equation and find k.
75 = k (0.61 − 0.477)
k = 562.5
Rounded to two significant figures, k = 560 N/m.
A physics professor uses an air-track cart of mass m to compress a spring of constant k by an amount x from its equilibrium length. The air-track has negligible friction. When she lets go, the spring launches the cart. What cart velocity should she expect after it is launched by the spring
Answer:
v = √k/m x
Explanation:
We can solve this exercise using the energy conservation relationships
starting point. Fully compressed spring
Em₀ = [tex]K_{e}[/tex] = ½ k x²
final point. Cart after leaving the spring
[tex]Em_{f}[/tex] = K = ½ m v²
Em₀ = Em_{f}
½ k x² = ½ m v²
v = √k/m x
1600cm of fresh water of density 1g/cm are mixed with 1200 cm of sea water of
density 1.2g/cm'. Determine the density of the mixture..
Answer:
[tex]\boxed{\mathrm{Density = 1.1 \ g/cm^3}}[/tex]
Explanation:
Volume of fresh water:
Volume = Mass / Density
Volume = 1600/1
[tex]V_{1}[/tex] = 1600 cm³
Volume of sea water:
Volume = Mass / Density
Volume = 1200/1.2
Volume = 1000 cm³
So,
Total Volume when they are mixed = 1600+1000
Total Volume when they are mixed = 2600 cm³
And,
Total Mass when they are mixed = 1600+1200
Total Mass when they are mixed = 2800 g
Now, Measuring the density of the mixture:
Density = Mass / Volume
Density = 2800/2600
Density = 1.1 g/cm³
Answer:
[tex]\mathrm{1.086 \: g/cm^3 }[/tex]
Explanation:
Volume of fresh water ⇒ 1600 cm³
Density of fresh water ⇒ 1 g/cm³
Volume of sea water ⇒ 1200 cm³
Density of sea water ⇒ 1.2 g/cm³
[tex]density=\frac{mass}{volume}[/tex]
[tex]mass=density \times volume[/tex]
Calculate mass of fresh water.
[tex]m=1600 \times 1[/tex]
[tex]m=1600 \: g[/tex]
Calculate the mass of sea water.
[tex]m=1200 \times 1.2[/tex]
[tex]m=1440 \: g[/tex]
Find the density of the mixture.
[tex]density=\frac{mass}{volume}[/tex]
[tex]\rho = \frac{1600+1440}{1600 + 1200}[/tex]
[tex]\rho = \frac{3040}{2800}[/tex]
[tex]\rho= 1.0857...[/tex]
PLEASE HELP. i will mark brainliest. and do more!
I would suggest an easier route. So for example, I would research light energy, where it comes from, and what causes it. I won't be able to do the work for you though.
The plates of a parallel-plate capacitor are maintained with a constant voltage by a battery as they are pushed together, without touching. How is the amount of charge on the plates affected during this process
Answer:
The amount of charge increases.
Explanation:
For a capacitor that has its plates still connected to a battery, the voltage on the capacitor remains constant. If the distance between the two plates of this capacitor is decreased, the capacitance will increase, and then the charge on the plate will increase in accordance with the relationship
Q =CV
From this relationship, if V is held constant, then Q has to increase for C to increase also.
A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on the cart?
Answer:
The total frictional force equals 60 N
Explanation:
We know that F - f = ma where F is the applied force, f is the frictional force, m the mass of the object and a its acceleration.
Now, since the cart moves with constant velocity, its acceleration is zero. So, a = 0.
So F - f = ma
F - f = m(0) = 0
F - f = 0
So, F = f
From the above, we see that the frictional force equals the applied force which is equal to 60 N.
So, f the total frictional force equals 60 N
Negative ions have _____.
A negaive ion has more electrons bound to it than protons in its nucleus.
A massless, rigid board is placed across two bathroom scales that are separated by a distance of 1.89 m. A person lies on the board. The scale under his head reads 470 N, and the scale under his feet reads 334 N. (a) Find the weight of the person. (b) Locate the center of gravity of the person relative to the scale beneath his head.
Answer:
A. 119kg
B.0.53m from head
Explanation:
A. Weight = 730+340.
=1170N
F= Wg
W = 1170/9.8
= 119kg
If x is distance from head to CG then 1.92–x is the other distance.
Moments must equal
470x = 330(1.89–x)
470x = 623.7 – 330x
1170x = 623.7
x = 0.53m from head
A body is thrown vertically upwards, remaining 4s in the air. Calculate the maximum height that the body reaches.
Answer:
20 m
Explanation:
Given:
v = 0 m/s
a = -10 m/s²
t = 4 s / 2 = 2 s
Find: Δy
Δy = vt − ½ at²
Δy = (0 m/s) (2 s) − ½ (-10 m/s²) (2 s)²
Δy = 20 m
why is string a good force measurer?
Answer:
tension is how much force is being exerted on each end of the string, whereas length is how long the string is. So assuming that the string has finite mass, then the tension on the string should increase proportionally to the string according to Newton's law f=ma.
Explanation:
Average velocity is different than average speed because calculating average velocity involves a)Distance b)Time c)Motion d)Displacemnet
Answer:
D. Displacement
Explanation:
got it right on edge
Average velocity is different than average speed because calculating average velocity involves Displacement, therefore the correct option is option D.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The unit of velocity is meter/second.
The mathematical expression for velocity is given by
velocity= displacement / time taken
In the displacement time graph the slope of the curve represent the velocity of the object ,the rate of change of velocity is known as the acceleration of the object .
In the velocity time graph the slope of the curve represent the acceleration of the body, The unit of acceleration is metre per second Square
The total distance traveled by an object is different than the total displacement covered by it because the displacement is a vector quantity and it is calculated on the basis of the shortest distance traveled by the body or object.
The main difference between the distance and the displacement is that displacement can be positive or negative or zero but distance can never be negative.
Let’s understand understand with example of average velocity ,suppose an object is moving with 200 m displacement covered in a time of 15 seconds then the average velocity of the object is 13.33 m/s.
Thus, average velocity is different than average speed because calculating average velocity involves Displacement, therefore the correct option is option D.
Learn more about Velocity from here
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Please help asap. A soccer player can kick a 0.370 kg football at 55 km/h. How much work does the soccer player have to do on the ball in order to give it that much kinetic energy?
Answer: 43.2 J
Explanation:
Work = change in KE
initial KE = 0
final KE = 1/2mv^2 = 1/2(0.370 kg)(15.2778 m/s)^2 = 43.2 J
i'm not sure about sig figs though
It is nighttime, and you dropped your goggles into a swimming pool that is 3.0m deep. If you hold a laser pointer 1.0m directly above the edge of the pool, you can illuminate the goggles if the laser beam enters the water 2.0m from the edge. How far are the goggles from the edge of the pool
Answer:
The distance of the goggle from the edge of the pool is 4.726 m
Explanation:
The given information are;
The depth of the swimming pool = 3.0 m deep
The height of the laser pointer above the swimming pool edge = 1.0 m
The distance from the pool edge the laser pointer enters the water = 2.0 m
The angle between the pool and the laser = ∅ = tan⁻¹(1/2) = 26.57°
Therefore, the angle of incidence to the vertical [tex]\theta_i[/tex], = θ - ∅ = 90 - 26.57° = 63.43°
By Snell's law we have;
The ratio of the sin of the angle of incidence to the sin of the angle of refraction is a a constant equal to the ratio of the refractive indices as follows;
[tex]\dfrac{sin (\theta_i)}{sin (\theta_r} =\dfrac{n_r}{n_i}[/tex]
Where:
[tex]n_r[/tex] = Refractive index of the refractive medium which is water = 1.33
[tex]n_i[/tex] = Refractive index of the incidence medium which is air = 1.00
Therefore;
[tex]\theta_r = sin^{-1} \left (\dfrac{n_i \times sin (\theta_i)}{n_r} \right) = sin^{-1} \left (\dfrac{1\times sin (63.43)}{1.33} \right) = 42.26 ^{\circ}[/tex]
We have that tan([tex]\theta_r[/tex]) = (Distance of the goggles from the point directly above the point of incidence of the beam)/(The water depth)
tan(42.26) = (The horizontal distance of the goggles from the point of incidence of the laser on the water surface)/(3.0)
∴ The horizontal distance of the goggles from the point of incidence of the laser on the water surface = 3.0 × tan(42.26) = 2.726 m
The distance of the goggle from the edge of the pool = The horizontal distance of the goggles from the point of incidence of the laser on the water surface + The distance from the edge of the water surface the laser enters the water
The distance of the goggle from the edge of the pool = 2.726 + 2 = 4.726 m
The distance of the goggle from the edge of the pool = 4.726 m.
help me helpppp the last words are experience a total
Answer:
False
Explanation:
Total internal reflection is a condition that occurs when light travels from dense medium to less dense medium.
From the table given in the question above,
Refractive Index of Whale oil = 1.460
Refractive Index of vacuum = 1
From the above, we can see that the whale oil has a higher Refractive Index than vacuum. This implies that the whale oil is denser than the vacuum.
Therefore, total internal reflection will occur when light travels from whale oil to vacuum because the whale oil is denser than the vacuum.
(e)
Give an example of a process when electrons behave as:
A.particles.
B.a wave.
Answer:
particles
Explanation:
Find the mass. 10 points. Will give brainliest.
Answer:
3.94 kgExplanation:
Given,
Force ( f ) = 30 N
Acceleration(a) = 7.6 m/s
Now, Let's find the mass of the ball
Using the Newton's second law of motion:
We get:
[tex]force \: = mass \: \times acceleration[/tex]
plug the value
[tex]30 \: = m \: \times 7.6[/tex]
Use the commutative property to reorder the terms
[tex] 30 = 7.6 \: m[/tex]
Swap the sides of the equation
[tex]7.6m = 30[/tex]
Divide both sides of the equation by 7.6
[tex] \frac{7.6 \: m}{7.6} = \frac{30}{7.6} [/tex]
Calculate
[tex]m = 3.94 \: kg[/tex]
Hope this helps..
Best regards!!
Answer:
[tex]\displaystyle \boxed{\mathrm{3.95 \: kg }}[/tex]
Explanation:
[tex]\mathrm{force \: (N) = mass \: (kg) \times acceleration \: (m/s^2)}[/tex]
[tex]\mathrm{force = 30N}[/tex]
[tex]\mathrm{acceleration = 7.6 \: m/s^2 }[/tex]
[tex]\mathrm{Find \: the \: mass.}[/tex]
[tex]\mathrm{30 = m \times 7.6}[/tex]
[tex]\displaystyle \mathrm{m =\frac{30}{7.6} }[/tex]
[tex]\displaystyle \mathrm{m = 3.947... }[/tex]
What is at the very center of our galaxy? This question is difficult to answer because the center is completely obscured to our eyes behind a large amount of dust. On the basis of what you know about dust from previous chapters, what can be done to improve our view of the galaxy’s center?
Answer:
The answer is "Observe it in the infrared"
Explanation:
The infrared observatory is a device, which helps to track but also fix thermal light from sources out and the front of Earth's atmosphere like nebulae, young stars, and dust and gas in several other galaxies.
The very center of our galaxy is like a star cluster is situated in the central of our universe across the Milky Way supermassive, and the central black hole, around 4 million times our sun's mass.
The main super black hole named the Sagittarius A-star has been located in the nucleus of the galaxy, that's why in this question "Observe it in the infrared" is the correct answer.
Theere is more role of the moon than sun to occur tides in oceans why?
Help
Answer:
Because ocean tides are the effect of ocean water responding to a gravitational gradient, the moon plays a larger role in creating tides than does the sun. But the sun's gravitational gradient across the earth is significant and it does contribute to tides as well.
i hope this help i
i try to explain and like i sayed i hope this help u.
Answer:
the moon
Explanation:
ive passed the grade you learned this in
To a stationary observer, a bus moves south with a speed of 12 m/s. A man
inside walks toward the back of the bus with a speed of 0.5 m/s relative to
the bus. What is the velocity of the man according to a stationary observer?
A. 11 m/s south
B. 12.5 m/s south
C. 11.5 m/s south
D. 0.5 m/s south
ANSWER
C 11.5 m/s
EXPLANATION
Answer:
11.5m/s south
Explanation:
Online classes
Question 21 of 25
Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him
O A 352 N
O B. 122 N
C. 1150 N
O D. 813N
Answer:
B. 122N
Explanation:
f = 0.15 x 83 x 9.8 = 122.01
f = 122N
Two kilograms of nitrogen (N2) at 25°C is contained in a 0.62 m3 rigid tank. This tank is connected by a valve to a 0.16 m3 rigid tank containing 0.8 kg of oxygen (O2) at 127°C. The valve is opened, and the gases are allowed to mix, achieving an equilibrium state at 87°C.
initial pressures of N2 is 5.7293 bar and O2 is 5.2 bar.
the final pressure is 6.44 bar.
the magnitude of the heat transfer for the process is 162.8 kJ, and the direction of energy flow is going in.
What is the entropy change for the mixing process, in kJ/K?
Answer:
Explanation:
For entropy change the formula is
ΔS = ΔQ / T
ΔQ = Δ H
ΔS = Δ H / T
Given
Δ H = + 162.8 kJ
We can take equilibrium temperature as average temperature of the whole process
So, T = 273 + 87 = 360 K
ΔS = Δ H / T
= 162.8 kJ / 360
= + 0.508 kJ / K .
When the magnitude of the heat transfer for the process is 162.8 kJ, Then the entropy change for the mixing process, in kJ/K is = + 0.508 kJ / K
What is Entropy change?
For The entropy change, the formula is
Then ΔS = ΔQ / T
After that ΔQ = Δ H
Then ΔS = Δ H / T
Given as per question are:
Then Δ H = + 162.8 kJ
Now We can take equilibrium temperature as average temperature of the whole process are:
So, T is = 273 + 87 = 360 K
Then ΔS = Δ H / T
After that = 162.8 kJ / 360
Therefore, = + 0.508 kJ / K.
Find more information about Entropy change here:
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You work for an advertising company and have been hired to place a blimp above a football stadium. The angle of elevation from a point directly under the goal post is 72° and the blimp will be directly above the 50 yard line. a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line? b. How high above the ground is the blimp? c. In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement? If not, what possible angle of elevation could we use? d. What is the exact angle if the blimp is at 150 feet?
Answer:
a) tangent ; b) 153.88 yds ; c) No , less than or equal to 45° ; D) 45°
Explanation:
Given the following ;
From the triangle sketch :
Base length = 50 yards
Angle of elevation = 72°
a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?
Using trigonometry :
The height of the blimp will be calculated using :
Tangent :
Tan θ = opposite / Adjacent
B.) How high above the ground is the blimp?
Using :
Tan θ = opposite / Adjacent
Θ = 72° ; adjacent = 52, opposite = height(h)
Tan 72° = h / 50
h = 3.0776835 * 50
h = 153.88 yds
C.) In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement?
1 yard = 3 Feets
153.88 yards = 3 * 153.88
= 461.65 feets
No, because the height of the blimp is 461.65 Feets which is greater than 150 Feets.
To make viewing possible, the angle of elevation should be:
50 yards is equivalent to (3 * 50) = 150 feets
Max imum Height of blimp = 150 Feets
From pythagoras ;
Tanθ = 150 Feets / 150 Feets
Tanθ = 1
θ = tan^-1(1)
θ = 45°
To make viewing advertisement possible, angle of elevation should not exceed 45°
d.)If height of blimp is 150 Feets, then the exact angle of elevation will be 45°
(c) An object of mass 100 kg is accelerated uniformly from a velocity of 15m/s to 20 m/s in 10 s.
Calculate the initial and final momentum of the object.
Also, find the magnitude of the force exerted on the object.
Explanation:
momentum = mass x velocity
initial momentum = 100 x 15 = 1500kgm/s
after momentum = 100 x 20 = 2000kgm/s
a =(v-u)/t
a = (20-15)/10
a = 5/10
a = 0.5m/s²
f = ma
f = 100 x 0.5
f = 50N
1. The electric field strength between two parallel plates separated by 6.00 cm is 7.50 × 104 V/m . (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?
Answer:
a)4500V
b)750V
Explanation:
Given:
Distance between the plate=
6.00 cm
We need to convert to m
Then the Distance between the plate=
0.06m
electric field strength between two parallel plates =
7.50 × 104 V/m .
Then E= 7.50 × 104 V/m .
(a) What is the potential difference between the plates?
potential difference between the plates can be calculated using the formula below
Δ Vab=ED
Where E is the given electric field strength
D= The Distance between the plate
ΔVab=7.50 × 10⁴V/m ×
0.06m
= 4500V
(b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?
the potential 1cm from the zero volt plate
Then the 1cm must be converted to m
= 0.01m
Let us say plate A as the plate at 0 volts:
The potential increases linearly going from plate A (0 V) to plate B (4500V).
Therefore,if the potential difference between A and B, separated by 6 cm, is 4500 V, then the potential difference between A and a point located at 1 cm from A is can be calculated also
If the plate with Lowest potential is taken to be zero then
=ΔVab=Vab-Vb=Va-0=Va=ED
Va=7.50 × 10⁴V/m × 0.01=750V
Which statement describes how work and power are similar?
A: You must know time and energy to calculate both.
B: You must know velocity and time to calculate both.
C: You must know force and distance to calculate both.
D: You must know energy and force to calculate both.
Answer:
C: You must know force and distance to calculate both.
Explanation:
A force is said to have done work, when it has succeeded in causing displacement in an object from its starting point.
Power can be defined as the rate of doing work.
The work can be calculated using the following formula:
Work done = Force × Displacement
The power can be calculated using the following formula:
Power = Work \ Time
In order to calculate the work and power, the force and distance should be known. The force and distance will help in the calculating the work, which will in turn help in the calculation of the power of the object.
Hence, the answer is you must know force and distance to calculate both.
Which statement describes dynamic equilibrium? A. The forces on an object in motion are balanced. B. An object is accelerating due to forces acting on it. C. The forces on an object are unbalanced. D. The forces on a stationary object are balanced.
Answer: A. The forces on an object in motion are balanced.
Explanation:
The dynamic equilibrium is defined as the phase when an object moves at a constant velocity such that all forces on the object are balanced.
Simple case of dynamic equilibrium: A horizontal force is applied to an object making it run with a constant velocity across a surface.
Hence, the statement describes dynamic equilibrium is " The forces on an object in motion are balanced. "
So, the correct option is "A".
Answer:
Hope this helps!
Explain the method to measure the external diameter of a sphere
Answer:
Sphere is a geometrical object in dimensional space that surface of a circle and ball.
Explanation:
Sphere is that the circular objects in the two dimensional space (1) circle
(2) disk. Two dimensional space is a set of points and the distance of that point,The two points of Sphere that length and center.
Sphere can constructed as the named of surface form circle about any diameter. circle is the special type of the revolution replacing the circle,
sphere is the distance r is the radius of the ball and circle is the center of mathematical ball,as the center and the radius of the sphere is to respectively.
The ball and sphere has not be maintained mathematical references as a solid references. A sphere of any radius is centered at the number of zero.
There is a Full Moon on September 14th. On which date will the New Moon occur? A.September 21st B.September 28th C.13th D.October 31st
Answer:
the answer B
Explanation:
A plane drops a package for delivery. The plane is flying horizontally at a speed of 120m/s,and the package travels 255 m horizontally during the drop. We can ignore air resistance.What is the package's vertical displacement during the drop?
Answer:
Package's vertical displacement(s) = 22.12 meter
Explanation:
Given:
Speed of plane = 120 m/s
Total distance = 255 m
Find:
Package's vertical displacement(s)
Computation:
Time taken = Distance / Speed
Time taken = Total distance / Speed of plane
Time taken = 255 / 120
Time taken = 2.125 s
Acceleration due to gravity(g) = 9.8 m/s²
Initial velocity (u) = 0
So,
Package's vertical displacement(s) = ut + (1/2)gt²
Package's vertical displacement(s) = (0)(2.125) + (1/2)(9.8)(2.125)²
Package's vertical displacement(s) = 22.12 meter
Answer: -22.1
Explanation:
I just did the Khan Academy and that was the answer, not the one provided by that one person. :)))