Which of the following correctly expresses the value of 0.0149 in scientific notation AND in the SI unit for density?

I think it is Ba since the radius increases along the group.but decreases along the period

Answer:

Ba

Explanation:

Ba

A compound formed between two or more non-metal elements that share electrons is called a covalent compound or a molecular compound.

In covalent compounds, the atoms share electrons in order to achieve a full outer shell of electrons and become more stable. Covalent compounds typically have low melting and boiling points, are often gases or liquids at room temperature, and are poor conductors of electricity. Examples of covalent compounds include water (H2O), carbon dioxide (CO2), and methane [CH4].

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463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.

Mass of one mole of substance is referred to as the molar mass. The molar mass of a substance can be calculated by adding up the atomic masses of all the atoms in a molecule.

Balanced chemical equation for the reaction between calcium carbonate (CaCO₃) and hydrochloric acid (HCl) is: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

6.35 mol CaCO₃ * 2 mol HCl / 1 mol CaCO₃ = 12.7 mol HCl

Now, we use the molar mass of HCl (36.46 g/mol) to convert from moles to grams: 12.7 mol HCl * 36.46 g/mol = 463.5 g HCl

Therefore, 463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.

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Explanation: the answer is 3840 because 2950+890=3840

Answer: Oxygen (??)

Explanation: Im not sure but smth like H2O (my brain is not braining T-T)

A. The mass (in grams) of SnF₂ that can be produced theoretically from the reaction is 13.20 g

B. The percentage yield of the reaction is 83.3%

The mass of SnF₂ produced theorethically, can be obtained as shown below:

Sn + 2HF ->  SnF₂ +  H₂

From the balanced equation above,

118.71 g of Sn reacted to produce 156.71 g of SnF₂

Therefore,

10 g of Sn will react to produce = (10 × 156.71) / 118.71 = 13.20 g of SnF₂

Thus, the mass of SnF₂ produced is 13.20 g

The percentage yield for the reaction can be obtained as follow:

Percentage yield = (Actual /Theoretical) × 100

Percentage yield of SnF₂ = (11 / 13.20) × 100

Percentage yield of SnF₂ = 83.3%

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Complete question:

See attached photo

We need 2.59 × 10⁷ g or 25.9 metric tons of SO₂ to treat 3.00 × 10⁸ L of 4.50×10⁻² mM Cr(VI).

Solution in which the solvent is water (H₂O) is known as an aqueous solution.

Balanced equation for the reaction is: Cr₂O₇²⁻ + 3SO₂ + 2H₂O → 2CrO₄²⁻ + 3H₂SO₄

Cr₂O₇²⁻ = 2 × 52 + 7 × 16 = 252 g/mol

n(Cr₂O₇²⁻) = [Cr₂O₇²⁻] × V

n(Cr₂O₇²⁻) = (4.50 × 10² mM) × (3.00 × 10⁸ L) × (1 mM / 1000 mM)

n(Cr₂O₇²⁻) = 1.35 × 10⁵ mol

n(SO₂) = 3 × n(Cr₂O₇²⁻)

n(SO₂) = 3 × 1.35 × 10⁵ mol

n(SO₂) = 4.05 × 10⁵ mol

mass(SO₂) = n(SO₂) × MM(SO2)

mass(SO₂) = (4.05 × 10⁵ mol) × (64.06 g/mol)

mass(SO₂) = 2.59 × 10⁷ g

Therefore, we need 2.59 × 10⁷ g or 25.9 metric tons of SO₂ to treat 3.00 × 10⁸ L of 4.50×10⁻² mM Cr(VI).

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C and O since their electronegativity differs by quite a lot

Answer:

The speed of sound in diamond is about **12,000 metres per second (39,000 ft/s)** which is about **35 times** its speed in air³. To convert this to feet per hour (ft/hr), we can use the following conversion factors:

1 meter = 3.28084 feet

1 second = 3600 hours

Therefore, the speed of sound in diamond in feet per hour (ft/hr) is:

12,000 m/s x 3.28084 ft/m x 3600 s/hr = 141,732,480 ft/hr

The number of mole of H₃PO₄ that can be formed from the reaction of 2 moles of P₄O₁₀ and 8 moles of H₂O is 5.33 moles

First, we shall determine the limiting reactant. Details below

P₄O₁₀ + 6H₂O -> 4H₃PO₄

From the balanced equation above,

1 mole of P₄O₁₀ reacted with 6 moles of H₂O

Therefore,

2 moles of P₄O₁₀ will react with = 2 × 6 = 12 moles of H₂O

From the above calculation, we can see that a higher amount of H₂O is needed to react completely with 2 moles of P₄O₁₀

Thus, H₂O is the limiting reactant.

Now, we shall determine the mole of H₃PO₄ formed from the reaction. Details below:

P₄O₁₀ + 6H₂O -> 4H₃PO₄

From the balanced equation above,

6 moles of H₂O reacted with 4 moles of H₃PO₄

Therefore,

8 moles of H₂O will react with = (8 × 4) / 6 = 5.33 moles of H₃PO₄

Thus, the mole of H₃PO₄ formed is 5.33 moles

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The amount that would remain, given that 3 half-lives has pass when you started with 20.0 g is 2.50 grams (1st option)

The following data were obtained from the question:

The amount remaining can be obtained as shown below:

N = N₀ / 2ⁿ

N = 20 / 2³

N = 20 / 8

N = 2.50 grams

Thus, we can conclude from the above calculation that the amount that would remain after 3 half-lives to pass is 2.50 grams (1st option)

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Answer:

2.50g

Explanation:

When 3 g of a petroleum are burned with more oxygen than is required, 8.8 g of Atmospheric carbon dioxide plus 5.4 g liquid [tex]H_{2}O[/tex] are produced.

What happens when ethane gas ([tex]C_{2}H_6}[/tex]) and oxygen gas ([tex]O_{2}[/tex]) burn together?

Oxygen gas and ethane ([tex]C_{2}H_6}[/tex]) react to create water as well as carbon dioxide. Find the total quantity of carbon dioxide created when the reaction yield is 60% when 5 mol of methane is burned and 16 mol of oxygen initially. 2[tex]C_{2}H_4}[/tex]+7[tex]O_{2}[/tex] →4[tex]CO_{2}[/tex]+6[tex]H_{2}O.[/tex]

How many tumours of CO2 are created when 2.2 blackheads of [tex]C_{2}H_4}[/tex]are burned?

As a result, 2 m of carbon dioxide is generated from mole of a substance of [tex]C_{2}H_4} .[/tex] Thus, multiply 2.2 over 2 by 1 pot to get 2.2 moles for c into h or just a cross. It consists of 4.4 moles of carbon.

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Answer:

Explanation:

Ρ=6.17g/L

m=20*6.17

m=123.4g

n=m/M

n=123.4 mol/138

n= 0.89mol

Due to the nature of the reactants and the balanced chemical equations, the calculated solutions will be acidic, neutral, and neutral, respectively.

Neutrality is represented by 7 on the scale, which ranges from 0 to 14. pH levels below 7 signify acidity, whereas pH values over 7 suggest baseness. The pH scale is really used to determine how much free hydrogen and hydroxyl ions are present in water.

This process of neutralising acid is known as. A basic solution goes away from being basic and towards the middle of the pH scale when an acid is introduced. It is known as neutralising.

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four score and seven years ago (our father) brought this continent, a new nation,

The Two Aspects of Science: Control over nature and understanding of nature must both be held in equal honor.

Answer:

strength in ionic compounds.

Explanation:

:)

Lattice energy is an estimate of the bond of strength. It denotes the amount of energy required to break down one mole of a solid ionic compound into its constituent gaseous ions.

The strength of an ionic compound's ionic bonds is measured by lattice energy. It explains several properties of ionic solids, including their volatility, solubility, and hardness. An ionic solid's lattice energy cannot be measured directly.

The higher an ionic compound's lattice energy, the more difficult it is to disassemble the crystal lattice structure and dissolve it in water. As a result, compounds with high lattice energies are less soluble in water than those with low lattice energies.

The value of lattice energy is determined by the charges on the two ions as well as the distance between them. The distance between the ions is directly proportional to their size.

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Complete question:

Lattice energy is an estimated bond of the bond:

A. conductivity

B. group

C. length

D. strength

Choose the correct option.

The compound's boiling point is around 73.65 °C.

Unexpected Responses. Favorable reactions are those that cause the system's enthalpy to drop while its entropy rises. The reaction happens naturally when both of these conditions are true. Both endothermic and exothermic reactions, which absorb heat and release it, can occur spontaneously.

We can use the Gibbs-Helmholtz equation to solve for the boiling point:

ΔG = ΔH - TΔS

At boiling point, ΔG = 0, so we can solve for T:

T = ΔH/ΔS

Substituting the given values:

T = (32.77 kJ·mol−1) / (94.72 J·mol−1·K−1)

T = 346.8 K

Converting to Celsius:

Boiling point = 346.8 K - 273.15 = 73.65 °C

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Under the given circumstances, the pressure difference between methane and an ideal gas is 58.5 atm.

An ideal gas is a theoretical gas composed of a large number of small particles that have zero volume, do not interact with each other, and are in constant random motion. The behavior of an ideal gas is described by the ideal gas law, which relates the pressure, volume, temperature, and number of moles of the gas.

The van der Waals equation can be used to figure out the pressure difference between methane and an ideal gas under these circumstances:

(P + a n² / V²)(V - n b) = n R T

where P is the pressure, n is the number of moles, V is the volume, T is the temperature in Kelvin, R is the ideal gas constant (0.08206 L·atm/K·mol), a and b are the van der Waals constants for methane.

First, we can calculate the pressure of an ideal gas under these conditions using the ideal gas law:

P = n R T / V

P = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K) / (6.00 L)

P = 299.8 atm

Next, we can use the van der Waals equation to calculate the pressure of methane under these conditions:

(P + a n² / V²)(V - n b) = n R T

(P + (2.300 L²·atm/mol²) (15.0 mol)² / (6.00 L)²) ((6.00 L) - (15.0 mol) (0.0430 L/mol)) = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K)

Simplifying the equation gives:

P + 1.319 atm = 359.6 atm

P = 358.3 atm

As a result, under these circumstances, the pressure difference between methane and an ideal gas is:

ΔP = P (methane) - P (ideal gas) = 358.3 atm - 299.8 atm = 58.5 atm.

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The reaction [tex]2NH_3=N_2H_4+H_2[/tex] has a standard reaction free energy of -62.4 kJ/mol.

Energy is the capacity to carry out tasks or affect change. It comes in a variety of shapes and sizes, including kinetic energy (energy of motion), potential energy (stored energy of position), thermal energy (heat), electrical, chemical, and nuclear energy. Energy is required for the survival and growth of all living things. Additionally, it is necessary for the operation of industries and equipment.

Equation can be used to get a reaction's standard reaction free energy.

ΔG°rxn = ΣΔG°f (products) - ΣΔG°f (reactants).

For the reaction [tex]2NH_3=N_2H_4+H_2[/tex], the ΔG°f values are as follows:

ΔG°f ([tex]2NH_3[/tex]) = -46.2 kJ/mol

ΔG°f ([tex]N_2H_4[/tex]) = -20.8 kJ/mol

ΔG°f ([tex]H_2[/tex]) = 0 kJ/mo

The equation yields the average reaction free energy (ΔG°rxn) of the reaction is:

ΔG°rxn = (2 x -20.8) - (-46.2)

            = -62.4 kJ/mol

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Since 2 moles of KI produce 1 mole of I2, then 7.0 moles of KI will produce 7.0/2 moles of I2. In other words, 3.5 moles of I2 will be produced

The new volume [tex]V_{2}[/tex]) of the gas is approximately 1710 L when the temperature changes from 42 ∘C to 94 ∘C, assuming no change in pressure or amount of gas.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance, such as a gas, liquid, or solid. It is commonly measured in Celsius (°C), Fahrenheit (°F), or Kelvin (K) scales. Temperature determines the direction of heat transfer, which is the movement of energy between substances due to a temperature difference.

To use the ideal gas law, we need to convert the temperatures to Kelvin by adding 273.15 to each:

[tex]T_{1}[/tex] = 42 + 273.15 = 315.15 K

[tex]T_{2}[/tex]= 94 + 273.15 = 367.15 K

Since the pressure, amount of gas, and ideal gas constant remain constant in this problem, we can set up the following ratio:

([tex]V_{1}[/tex] / [tex]T_{1}[/tex]) = ([tex]V_{2}[/tex]/ [tex]T_{2}[/tex])

Plugging in the values:

(1.47 ×[tex]10^{3}[/tex]L / 315.15 K) = ([tex]V_{2}[/tex] / 367.15 K)

Now we can solve for [tex]V_{2}[/tex]:

[tex]V_{2}[/tex] = 1.47×[tex]10^{3}[/tex] L * 367.15 K / 315.15 K

[tex]V_{2}[/tex]≈ 1710 L (rounded to three significant figures)

Therefore, the new volume (V2) of the gas is approximately 1710 L when the temperature changes from 42 ∘C to 94 ∘C, assuming no change in pressure or amount of gas.

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The molality of the solution is 1.080 mol/kg of a 48 grams of MgCl2 is dissolved in 500g of water, density of water = 1 kg/1L.

Taking the moles of solute and dividing it by the kilograms of solvent yields the molality of a solution.

Molality is calculated as follows: kg of solvent/kg of solute

500 g, or 0.500 kg, is the mass of the solvent.

MgCl2 molecular weight divided by its mass gives the amount of moles.

48 g / 95.2 g m o l 1 equals the quantity of moles of magnesium chloride.

0.504 moles of MgCl2 are present in one mole.

Molality is calculated as 0.504moles per kilogram.

Molality is equal to 1.080 mol k g 1.

As stated in the definition, molality is the "total moles of a solute contained in a kilogram of a solvent." The terms "molality" and "molal concentration" are synonymous. It is a measurement of a solvent.

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Answer:  the temperature of the gas is approximately 16.1°C.

Explanation: PV=nRT Rearranging the equation gives us T = PV/(nR), with all variables defined as before. Convert mL to L: V = 4191 mL = 4.191 L. Use equation: T = (89.9 atm) x (4.191 L) / (2.6 mol x 0.08206 L atm/(mol K)). Simplify to get T = 289.2 K. Convert Kelvin to Celsius: T = 289.2 K - 273.15 = 16.1°C.

Statement A is correct: Mary is right because there will be fewer successful collisions between reactants in the dilute solutions.

A reactant is a substance that undergoes a chemical reaction with another substance to form a new substance. In a chemical reaction, one or more reactants are transformed into one or more products, which are the end result of the reaction.

Reactants are typically written on the left side of a chemical equation, while the products are written on the right side. For example, in the chemical equation for the reaction between hydrogen gas and oxygen gas to form water:

2H2 + O2 → 2H2O

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Answer: The units for molarity are moles/liter.

Similarly, the equation to find molarity is moles divided by liters.

Explanation:  

mol / L is a unit of molar concentration. These are the number of moles of dissolved material per liter of solution. 1 mol / L is also called 1M or 1molar. Mol / m3 is also a unit of molar concentration.

Molarity is expressed in units of moles per liter (mol / L). This is a very common unit, so it has its own symbol, which is the uppercase M. A solution with a concentration of 5 mmol / l is called a 5 M solution or has a concentration value of 5 mol.

The molar concentration of the solution is equal to the number of moles of the solute divided by the mass of the solvent (kilogram), and the molar concentration of the solution is equal to the number of moles of the solute divided by the volume of the solution (liter). increase.

A concentrated saltwater solution weighing 29.97 g and fitting into a flask to the mark of 25.0 ml has a density of about 1199.2 g/L.

By dividing the solution's mass by its volume, we may get its density: density = mass/volume

We need to know the density of water at the solution's temperature as well as the capacity of the flask up to the 25.0 ml level in order to calculate the volume of the solution.

Since 1 mL = 0.001 L, volume is equal to 25.0 mL, or 0.0250 L.

Now, we may determine the solution's density as follows:

1199.2 g/L or 29.97 g/0.0250 L is what is referred to as density.

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The reactions with a positive Δrxn are:

A(g) + B(g) ⟶ 3C(g)

A(s) + B(s) ⟶ C(g)

The entropy change (Δrxn) of a reaction indicates the change in the degree of randomness or disorder of the system during the reaction. If the number of product molecules is greater than the number of reactant molecules, the disorder of the system usually increases, resulting in a positive Δrxn. Therefore, we can determine the answer by analyzing the stoichiometry of each reaction:

A(g) + B(g) ⟶ C(g)

In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δrxn.

A(g) + B(g) ⟶ 3C(g)

In this reaction, the number of product molecules is greater than the number of reactant molecules, so the disorder of the system increases. Therefore, this reaction has a positive Δrxn.

A(s) + B(s) ⟶ C(g)

In this reaction, the solid reactants are combining to form a gaseous product. The disorder of the system is expected to increase, resulting in a positive Δrxn.

2A(g) + B(g) ⟶ C(g)

In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δ rxn.

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The volume of [tex]SO_{3}[/tex] would be produced by complete reaction of 100cm3 of [tex]H_{2}O[/tex]with [tex]O_{2}[/tex] is at STP is 60.03L.

22.4 L divided by 2.68 moles per mole yields 60.03 L [tex]SO_{3}[/tex].

describing the elements contributing to the response,

[tex]2SO_{2(g)}+ O_{2} = 2SO_{3}[/tex]

In this instance, [tex]SO_{3}[/tex] and [tex]O_{2}[/tex] have a mole ratio of 2:1. Assume the reaction takes place at STP, where 1 mole of any gas has a volume of 22.4 L. Consequently, 30 [tex]dm^{3}[/tex]of [tex]O_{2}[/tex] (1 dm3 = 1 L) equals 30 L of [tex]O_{2}[/tex] and 30 L/22.4 L times 1 mole equals 1.34 moles of [tex]O_{2}[/tex].

According to stoichiometry, when 1.34 moles of [tex]O_{2}[/tex]are reacted with [tex]SO_{2}[/tex], 2.68 moles of [tex]SO_{3}[/tex] are created, or 2/1 x 1.34 moles of [tex]SO_{3}[/tex].

This means that the amount of [tex]SO_{3}[/tex]produced will be (2.68 moles/1 mole) x 22.4 L = 60.03 L [tex]SO_{3}[/tex].

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