Use the form |x-b |< c or |x-b | > c to write an absolute value inequality that has the solution set 5 < x < 7.
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
What is inequality?Inequality refers to the state of being unequal, uneven, or unfair in terms of social, economic, political, or other factors. It can be the result of various factors such as discrimination, prejudice, systemic biases, and unequal distribution of resources, opportunities, and power. Inequality can manifest itself in many forms, including income and wealth disparities, unequal access to education, healthcare, and housing, unequal treatment under the law, and marginalization of certain groups based on their race, gender, sexual orientation, religion, or other characteristics. Addressing inequality is an important challenge in creating a more just and equitable society.
to write an absolute value inequality with a solution set of 5 < x < 7, we need to use the form |x - b| < c, where b is the center of the solution set and c is the distance from the center to the edge of the solution set.
In this case, the center of the solution set is (5 + 7)/2 = 6, and the distance from the center to the edge is (7 - 5)/2 = 1.
Therefore, we can write the absolute value inequality as:
[tex]| x - 6 | < 1[/tex]
Alternatively, we can use the form |x - b| > c and write the absolute value inequality as:
[tex]x < 5 or x > 7[/tex]
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
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Find the measure of the line segment indicated, assume that lines which appear tangent, are tangent.
Find FS
Possible answers —>
A. 17
B. 21
C. None of the other answers are correct
D. 18
E. 45
The value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
What is the properties of intersecting chordsThe property of intersecting chords states that in a circle, if two chords intersect, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.
UF × FS = VF × FT
8(10x - 1) = 9 × 16
80x - 8 = 144
80x = 144 + 8 {collect like terms}
80x = 152
x = 152/80 {divide through by 80}
x = 1.9
FS = 10(1.9) - 1 = 18
Therefore, the value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
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Gia made a garden stone shaped like a regular octagon with the dimensions shown. Find the area of the octagon.
5.5 in.
4.6 in
The area of the garden which is same as the shape of an octagon would be = 101.2in².
How to calculate the area of an octagon?To calculate the area of an octagon the formula that can be used is given below;
Area of an octagon = (number of sides × length of one side × apothem)/2
For an octagon = 8 sides
apothem = 5.5in
Length of one side = 4.6in
Area = 8×4.6×5.5/2
= 202.4/2
= 101.2in²
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subtract (c-3d-e) from the sum of (4c+d-e) and (2c-3d+2e)
To subtract (c-3d-e) from the sum of (4c+d-e) and (2c-3d+2e), we can first find the sum of the two polynomials, which is (4c+d-e) + (2c-3d+2e) = 6c - 2d + e. Then, we can subtract (c-3d-e) from this sum by changing the signs of the terms in (c-3d-e) and adding the resulting polynomial to 6c - 2d + e. This gives us:
(4c+d-e) + (2c-3d+2e) - (c-3d-e) = 5c + d + 4e
Therefore, the answer is 5c + d + 4e.
please help me find these 2!! it’s due tmmr and it would help a lot!!
Answer:
the outlier is 37 but for 43 are they asking for the upper and lower quartiles or the lowest and highest number
solve for x please
Choices are..
6
20
140
90
Answer:
Answer is 20
Step-by-step explanation:
When two lines intersect each other as a result of that, every opposite angles are equal
so,
6x+20 = 140
6x = 120
x = 120/6
x = 20
Answer:
x = 20
Step-by-step explanation:
Vertically opposite are equal
therefore
6x + 20 = 140
6x = 140-20
6x = 120
6x/6 = 120/6
x = 20
29. The area of a rectangle is given by the expression +7x² + 11x + 2) in². The length of the rectangle is given by the expression (x + 2) in. What is an expression for the width of the rectangle?
To find an expression for the width of the rectangle, we can use the formula for the area of a rectangle, which is:
Area = length x width
What is an expression for the width of the rectangle?In this case, we know that the area is given by the expression +7x² + 11x + 2 and the length is given by the expression (x + 2). So we can substitute these values into the formula and solve for the width:
+7x² + 11x + 2 = (x + 2) x width
Expanding the right-hand side, we get:
+7x² + 11x + 2 = xwidth + 2width
Rearranging terms, we get:
+7x² + 11x + 2 - xwidth - 2width = 0
Factoring out the width, we get:
width*(x - 2) + 2*(x - 1) = 0
Dividing both sides by (x - 2), we get:
width = -2*(x - 1)/(x - 2)
Therefore, an expression for the width of the rectangle is:
width = -2*(x - 1)/(x - 2)
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Which equation is perpendicular to y= -2/7x - 5 and passes through (2,4)?
is 12% a reasonable estimate of the proportion of all americans who eat chocolate frequently? why or why not?
The reasonableness of the estimate depends on the quality and reliability of the data sources and methodology used to arrive at the estimate.
In order to determine whether 12% is a reasonable estimate of the proportion of all Americans who eat chocolate
frequently, we would need to define what is meant by "frequently."
If we define "frequently" as "at least once a week," then 12% may or may not be a reasonable estimate, depending on
the data source and methodology used to arrive at that estimate.
For example, if the estimate is based on a small sample size or a non-representative sample of the population, then it
may not be a reliable estimate of the true proportion of Americans who eat chocolate frequently. Additionally, if the
estimate is several years old, it may not accurately reflect current trends and habits.
On the other hand, if the estimate is based on a large, nationally representative sample of the population, and is
relatively recent, then 12% could be a reasonable estimate of the proportion of Americans who eat chocolate
frequently.
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Which of the following combinations of side lengths would NOT form a triangle with vertices X, Y, and Z? A. XY = 11 mm , YZ = 12 mm , XZ = 18 mm B. XY = 16 mm , YZ = 12 mm , XZ = 23 mm C. XY = 16 mm , YZ = 17 mm , XZ = 18 mm D. XY = 11 mm , YZ = 12 mm , XZ = 28 mm
the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
How to solve the question?
To determine whether a triangle can be formed using the given side lengths, we need to apply the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side.
Let's check each option:
A. XY = 11 mm, YZ = 12 mm, XZ = 18 mm
To form a triangle, we need to check whether the sum of any two sides is greater than the third side. Let's check:
XY + YZ = 11 mm + 12 mm = 23 mm > XZ = 18 mm
YZ + XZ = 12 mm + 18 mm = 30 mm > XY = 11 mm
XY + XZ = 11 mm + 18 mm = 29 mm > YZ = 12 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
B. XY = 16 mm, YZ = 12 mm, XZ = 23 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 12 mm = 28 mm > XZ = 23 mm
YZ + XZ = 12 mm + 23 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 23 mm = 39 mm > YZ = 12 mm
Again, all the combinations are greater than the third side, so a triangle can be formed with these side lengths.
C. XY = 16 mm, YZ = 17 mm, XZ = 18 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 17 mm = 33 mm > XZ = 18 mm
YZ + XZ = 17 mm + 18 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 18 mm = 34 mm > YZ = 17 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
D. XY = 11 mm, YZ = 12 mm, XZ = 28 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 11 mm + 12 mm = 23 mm < XZ = 28 mm
YZ + XZ = 12 mm + 28 mm = 40 mm > XY = 11 mm
XY + XZ = 11 mm + 28 mm = 39 mm > YZ = 12 mm
The first combination is less than the third side, so a triangle cannot be formed with these side lengths.
Therefore, the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
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Sam makes tote bags for a school fundraiser. The fixed costs for making the bags is $30. The cost of the materials for each bag is $8.50. Sam can spend less than a total of $200 on the tote bags. Write an inequality that can be used to determine b , the number of tote bags that can be made.
Which comparison is not correct?
A. 1 > -9
B. 3 < 6
C. -8 > -6
D. -3 < 4
Answer:
The comparison that is not correct is:
C. -8 > -6
This is not correct because -8 is actually less than -6. Therefore, the correct comparison would be -8 < -6.
The other comparisons are correct:
A. 1 > -9 (true, because 1 is greater than -9)
B. 3 < 6 (true, because 3 is less than 6)
D. -3 < 4 (true, because -3 is less than 4)
What is the answer to this question? (Please i need help)
A statement that is best supported by the data in the box plots include the following: H. the interquartile range of the data for the community college is greater than the interquartile range of the data for the university.
What is a box-and-whisker plot?In Mathematics and Statistics, a box plot is a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.
How to calculate the interquartile range (IQR)?Mathematically, interquartile range (IQR) of a data set is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):
Interquartile range (IQR) of university = Q₃ - Q₁
Interquartile range (IQR) of university = 15 - 9
Interquartile range (IQR) of university = 6.
For the community college, we have;
Interquartile range (IQR) = 15 - 6
Interquartile range (IQR) = 9.
Therefore, 9 is greater than 6.
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In how many ways can a committee of two men and one women be formed from a group of ten men and eight women?
Out of a group of ten men & eight women, there are 1320 possible ways to form a committee of two men and one woman.
What is number?Numbers are mathematical units of measurement and labelling. It is a sign or collection of symbols that are used to represent a quantity, usually a real or integer number.
Out of a group of ten men & eight women, there are 1320 possible ways to form a committee of two men and one woman. The idea of combination can be used to arrive to this number.
Calculating the number of possible combinations of a given number of things is done mathematically using the concept of combination. C(n,r) = n! / (r! (n - r)!), where n is the total number of items and r is the number of things to be picked at a time, is the formula used to compute it. In this instance, r is the number of persons to be picked, which is 3, and n is the total number of people to be chosen from the group, which is 18, consisting of 10 males and 8 women.
As a result, there are a total of 10 ways for men and 8 ways for women to form a committee of two men and one woman C(18,3) = 18! / (3! (18 - 3)!) = 18! / (3! 15!) = 1320.
Thus, there are 1320 different methods to create a committee of two men and one woman out of a group of ten men and eight women.
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Mariette has read 4/5 of the class novel. Erika read 0. 5 of it. Riley read less than Mariette but more than Erika. What fraction of the book could Riley have read. Explain
Riley could have read any fraction between 1/2 and 4/5 of the book.
We must determine the range of potential fractions of the book that Riley may have read in order to determine what portion Riley may have read.
Riley must have read less than 4/5 of the book because we know she read less than Mariette. Riley read more than Erika, and because we also know that Riley read more, Riley must have read more than 0.5 of the book.
Therefore, the fraction of the book that Riley could have read is between 0.5 and 4/5, or:
0.5 < Riley's fraction < 4/5
To express this range as a single fraction, we can find a common denominator for 0.5 and 4/5:
0.5 = 2/4
4/5 = 4/4 * 1/5 = 5/5 × 4/25 = 20/25
So the range of possible fractions for Riley is:
2/4 < Riley's fraction < 20/25
We can simplify this range by finding the lowest common denominator of 4 and 25, which is 100:
2/4 = 25/50
20/25 = 80/100
So the range of possible fractions for Riley is:
25/50 < Riley's fraction < 80/100
We can simplify this range by dividing both sides by 50:
1/2 < Riley's fraction < 4/5
Therefore, Riley could have read any fraction between 1/2 and 4/5 of the book.
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The line plot displays the number of roses purchased per day at a grocery store.
A horizontal line starting at 1 with tick marks every one unit up to 10. The line is labeled Number of Rose Bouquets, and the graph is titled Roses Purchased Per Day. There is one dot above 1 and 2. There are two dots above 8. There are three dots above 6, 7, and 9.
Which of the following is the best measure of variability for the data, and what is its value?
The range is the best measure of variability, and it equals 8.
The range is the best measure of variability, and it equals 2.5.
The IQR is the best measure of variability, and it equals 8.
The IQR is the best measure of variability, and it equals 2.5.
The range is the best measure of variability for this data, and it equals 8.
What is range?In statistics, the range is a measure of variability that describes the difference between the largest and smallest values in a dataset. It is the simplest measure of variability and is calculated by subtracting the smallest value in the dataset from the largest value.
According to given information:The range is a measure of variability that tells us the spread of the data, i.e., how far apart the minimum and maximum values are. It is calculated by subtracting the smallest value in the dataset from the largest value.
In the given line plot, the horizontal axis represents the number of rose bouquets purchased per day, and the vertical axis represents the frequency (i.e., how many times that particular number of rose bouquets was purchased). Based on the plot, we can see that the lowest number of rose bouquets purchased in a day is 1, and the highest number is 9. Therefore, the range is 9 - 1 = 8.
In contrast, the IQR (interquartile range) is a measure of variability that gives us an idea of how spread out the middle 50% of the data is. It is calculated by subtracting the 25th percentile (Q1) from the 75th percentile (Q3). Since we do not have the values for Q1 and Q3, we cannot calculate the IQR for this dataset.
Therefore, the range is the best measure of variability for this data, and it equals 8.
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ing walk at
e, in miles, to the
ter x hours is
t 8:00 AM,
minutes
5 miles
5 mile
st office.
graph of the
.5x + 2 is shown.
12. Peter opens an
$600 deposit that earns 8% simple
interest annually. He makes no
other deposits or withdrawals.
Complete the sentences.
This situation can be modeled by a
quadratic
linear
$12
$48
After 4 years, Peter will have
$48
$192
grows
function that
earned
each year.
in interest.
Answer:
Peter opens an account with a $600 deposit that earns 8% simple interest annually. He makes no other deposits or withdrawals.
Complete the sentences:
This situation can be modeled by a linear function that grows in interest.
Peter will earn $48 in interest each year.
Explanation:
Simple interest is calculated as a percentage of the principal amount and does not compound over time. Therefore, the amount of interest earned each year is constant, and the growth of the account is linear.
To calculate the amount of interest earned each year, we multiply the initial deposit by the interest rate:
$600 x 0.08 = $48
Therefore, Peter will earn $48 in interest each year. After four years, he will have earned:
4 x $48 = $192
So his total balance will be:
$600 + $192 = $792
Since the growth of the account is linear, we can model it with a linear function of the form:
y = mx + b
Where y is the total balance, x is the number of years, m is the slope (or rate of growth), and b is the initial balance.
In this case, the slope is the amount of interest earned each year, which is $48, and the initial balance is $600. So the linear function that models this situation is:
y = 48x + 600
11. Jessica is focusing on wrestling this semester. What category does this sport fall into?
The Correct Answer Is: High-strength sports.
explanation:
Because for wrestling you have to use, you're strength. (And I just did the exam and I got it wrong for choosing the wrong answer, so I believe it's my answer. !!so, it's not high-power sports)
I hope it helps you!
:)
If quadrilateral PQRS is a parallelogram, line segment QR is ≅ to line segment QT, and m∠TQR=60°, which angles are congruent to ∠S? Select all that apply.
a.) ∠P
b.) ∠PQR
c.) ∠RQT
d.) ∠QRT
e.) ∠SRQ
f.) ∠TQR
From the given information, you can deduce that triangle QTR is equilateral and equiangular (all angles are 60 degrees)
b, c, d, and f are true
The opposite angles of a parallelogram are congruent (b)
If 2 parallel lines are cut by a transversal, then the corresponding angles are congruent (d)
Angle RQT is congruent to angle QRT, and angle QRT is congruent to angle S. By the transitive property, angle RQT is congruent to angle S (c)
Transitive property, like c (f)
Is the triangle equilateral, isoscele, or scalene?
Answer: This triangle is isoscele
Step-by-step explanation:
1. Calculate the perimeter, area and volume a) Classroom with Length=10m, breadth=8m and height=3m b) Box with Length=40cm, breadth=25cm and height=30cm c) Cabinet with length=80cm, breadth=70cm and height=2m Area Volume 26 a b C Perimeter
a) Classroom:
Perimeter = 2(length + breadth) = 2(10m + 8m) = 36m
Area = length x breadth = 10m x 8m = 80m^2
Volume = length x breadth x height = 10m x 8m x 3m = 240m^3
What is the perimeter, area and volume?b) Box:
Perimeter = 2(length + breadth) = 2(40cm + 25cm) = 130cm
Area = 2(length x breadth + length x height + breadth x height) = 2(40cm x 25cm + 40cm x 30cm + 25cm x 30cm) = 41500cm^2
Volume = length x breadth x height = 40cm x 25cm x 30cm = 30000cm^3
c) Cabinet:
Perimeter = 2(length + breadth) = 2(80cm + 70cm) = 300cm
Area = 2(length x breadth + length x height + breadth x height) = 2(80cm x 70cm + 80cm x 2m + 70cm x 2m) = 12640cm^2
Volume = length x breadth x height = 80cm x 70cm x 2m = 112000cm^3
Note: It's important to use consistent units in calculations. In this case, I converted the dimensions to a common unit (meters or centimeters) before performing the calculations.
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PLEASE HELP ME APSPPPPP!!!!!!!!!
Answer: the 3d shape would be a rectangle. the hight is 3. and the diameter is 10
Step-by-step explanation:
Find the distance of d, of ab
The distance between the coordinates A and B is 2 √(10) units.
What is distance formula?A mathematical method called the distance formula is used to determine how far apart two points in a coordinate plane are from one another. It can be used with any two points (x1, y1) and (x2, y2) and is based on the Pythagorean theorem.
d = √((x2 - x1)² + (y2 - y1)²)
where d is the separation of the two spots.
To put it another way, we may visualise a right triangle created by the two locations and the horizontal and vertical lengths separating them to get the distance between them. The triangle's hypotenuse, or the distance between its two points, is measured using the distance formula.
The distance formula is given as:
d = √((x2 - x1)² + (y2 - y1)²)
Now, for the given coordinates we have:
d = √((1 - (-5))² + (3 - 1)²)
d = √(6² + 2²)
d = √(40)
d = 2 √(10)
Hence, the distance between A and B is 2 √(10) units.
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A raffle is set up with a prize purse. First prize is 50% of the purse, second
is 25%, third is 10%, and fourth through eighth win an equal amount of the
rest. If the prize purse is $10,000, how much does sixth place win?
A. $100
B. $300
(C) $375
D. $1,500
The amount of the sixth place is (B) $300.
The amount of money for each prize can be calculated as follows:
First prize: 50% of $10,000 = $5,000Second prize: 25% of $10,000 = $2,500Third prize: 10% of $10,000 = $1,000The total amount of money awarded for the first three prizes is $8,500, leaving $1,500 for the remaining five prizes.
Since the remaining five prizes are equal, each one is worth $1,500 ÷ 5 = $300.
Therefore, sixth place wins $300.
So the correct answer is (B) $300.
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Becca is construction triangle d e f using the following angles 50°, 65°, 65°,
what mistake did she make?
Becca made a mistake while constructing triangle DEF by using the angles 50°, 65°, and 65°. The mistake she made was violating the triangle inequality theorem.
According to the theorem, the sum of any two sides of a triangle must be greater than the third side. In other words, if we add the lengths of two sides of a triangle, it must be greater than the length of the third side.
Since Becca only used angles to construct the triangle, she did not consider the side lengths of the triangle. Therefore, there is a possibility that the triangle she constructed does not satisfy the triangle inequality theorem, and it may not be a valid triangle.
In order to ensure the triangle is valid, Becca needs to consider the side lengths while constructing the triangle. She could use trigonometric ratios or a ruler and protractor to measure the side lengths and angles accurately.
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Project Option 1
For this option, you will work individually.
Instructions
For this option, you will work individually.
You’ve worked hard in this module to become a pro at equations! Now, you’ll put your skills to the test. Your job is to create an equations portfolio. The format is up to you. Be creative! You may use a slideshow, document, video, etc. As long as all of the parts of the project are addressed, the delivery is up to you.
Your portfolio must include a minimum of the following five types of equations and solutions:
Two one-step equations
Two equations that contains fractions
One equation with distributive property
One equation with decimals
One real-world problem that is solved by an equation
Remember that each equation must include at least one variable. Once you have created each equation, you will solve it and show your work. Pretend that you are teaching the equations to a new pre-algebra student. Or you can actually teach them to a sibling or friend!
This is a total of 7 equations and solutions.
Equations are used to solve different types of problems in mathematics and in the real world.The five types of equation are 2x = 8,2y/2 = 8/2, (1/2)x + 2 = 3,3(x+4)= 21,0.4x + 1.2 = 2.6.
What is Equations Portfolio?
Equations are an essential part of mathematics and have various applications in real-world problems. In this portfolio, we will cover different types of equations and solve them step by step. This portfolio will cover one-step equations, equations with fractions, equations with the distributive property, and equations with decimals.
One-step equations are equations that can be solved in one step. For example, if we have the equation 2x = 8, we can solve it by dividing both sides by 2. Let's solve two one-step equations,
3x = 15
Dividing both sides by 3
3x/3 = 15/3
x = 5
Again,
2y = 8
Dividing both sides by 2
2y/2 = 8/2
y = 4
Equations with fractions are equations that contain fractions. To solve these equations, we need to clear the fractions by multiplying both sides of the equation by the least common multiple (LCM) of the denominators. Let's solve two equations with fractions:
(1/2)x + 2 = 3
Subtracting 2 from both sides
(1/2)x = 1
Multiplying both sides by 2 (LCM of 1/2)
(1/2)x × 2 = 1 × 2
x = 2
(2/3)y - 1 = 3
Adding 1 to both sides
(2/3)y = 4
Multiplying both sides by 3 (LCM of 2/3)
(2/3)y × 3 = 4 × 3
y = 6
Equations with distributive property are equations that involve distributing a number or a variable to the terms inside the parentheses. Let's solve an equation with the distributive property,
3(x + 4) = 21
Distributing 3 to (x + 4)
3x + 12 = 21
Subtracting 12 from both sides
3x = 9
Dividing both sides by 3
x = 3
Equations with decimals are equations that contain decimal numbers. To solve these equations, we need to clear the decimals by multiplying both sides of the equation by a power of 10. Let's solve an equation with decimals,
0.4x + 1.2 = 2.6
Subtracting 1.2 from both sides
0.4x = 1.4
Multiplying both sides by 10 (power of 10 for one decimal place)
0.4x × 10 = 1.4 × 10
4x = 14
Dividing both sides by 4
x = 3.5
Now let's solve a real-world problem using an equation,
Sarah has $500 in her bank account. She wants to buy a dress for $120 and save the rest of the money. How much money will Sarah save?
Let x be the amount of money Sarah saves.
Total money = $500
Money spent on the dress = $120
Money saved = Total money - Money spent on the dress
x = 500 - 120
x = 380
Therefore, Sarah will save $380.
In conclusion, equations are used to solve different types of problems in mathematics and in the real world.
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The five types of equation are 2x = 8,2y/2 = 8/2,(1/2)x + 2 = 3,3(x + 4) = 21,0.4x + 1.2 = 2.6.
What is Equations Portfolio?Equations are an essential part of mathematics and have various applications in real-world problems. In this portfolio, we will cover different types of equations and solve them step by step. This portfolio will cover one-step equations, equations with fractions, equations with the distributive property, and equations with decimals.
One-step equations are equations that can be solved in one step. For example, if we have the equation 2x = 8, we can solve it by dividing both sides by 2. Let's solve two one-step equations,
3x = 15
Dividing both sides by 3
3x/3 = 15/3
x = 5
Again,
2y = 8
Dividing both sides by 2
2y/2 = 8/2
y = 4
Equations with fractions are equations that contain fractions. To solve these equations, we need to clear the fractions by multiplying both sides of the equation by the least common multiple (LCM) of the denominators. Let's solve two equations with fractions:
(1/2)x + 2 = 3
Subtracting 2 from both sides
(1/2)x = 1
Multiplying both sides by 2 (LCM of 1/2)
(1/2)x × 2 = 1 × 2
x = 2
(2/3)y - 1 = 3
Adding 1 to both sides
(2/3)y = 4
Multiplying both sides by 3 (LCM of 2/3)
(2/3)y × 3 = 4 × 3
y = 6
Equations with distributive property are equations that involve distributing a number or a variable to the terms inside the parentheses. Let's solve an equation with the distributive property,
3(x + 4) = 21
Distributing 3 to (x + 4)
3x + 12 = 21
Subtracting 12 from both sides
3x = 9
Dividing both sides by 3
x = 3
Equations with decimals are equations that contain decimal numbers. To solve these equations, we need to clear the decimals by multiplying both sides of the equation by a power of 10. Let's solve an equation with decimals,
0.4x + 1.2 = 2.6
Subtracting 1.2 from both sides
0.4x = 1.4
Multiplying both sides by 10 (power of 10 for one decimal place)
0.4x × 10 = 1.4 × 10
4x = 14
Dividing both sides by 4
x = 3.5
Now let's solve a real-world problem using an equation,
Sarah has $500 in her bank account. She wants to buy a dress for $120 and save the rest of the money. How much money will Sarah save?
Let x be the amount of money Sarah saves.
Total money = $500
Money spent on the dress = $120
Money saved = Total money - Money spent on the dress
x = 500 - 120
x = 380
Therefore, Sarah will save $380.
In conclusion, equations are used to solve different types of problems in mathematics and in the real world.
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Grupo textil M & M destaca que los ingresos de este año vienen dados por la funcion f(x) = (x+2)(-x+9-3) donde "x" es el precio de cada unidad y f(x) es la ganancia expresada en dolares
Para entender mejor esta función, podemos expandirla y simplificarla:
f(x) = (x+2)(-x+6)
f(x) = [tex]-x^2 + 4x + 12[/tex]
Esta es una función cuadrática, lo que significa que tiene la forma de una parábola. El término cuadrático ([tex]-x^2[/tex]) hace que la parábola tenga una concavidad hacia abajo, lo que significa que el valor máximo de la función se encuentra en el vértice de la parábola.
Podemos encontrar el valor del precio de venta que maximiza la ganancia utilizando la fórmula x = -b/(2a), donde "a" es el coeficiente del término cuadrático y "b" es el coeficiente del término lineal.
En este caso, a = -1 y b = 4, por lo que:
x = -4/(2-1)
x = -4/-2
x = 2
Por lo tanto, el precio de venta que maximiza la ganancia es de 2 por unidad. Si se venden las unidades a este precio, la ganancia total sería de:
f(2) = [tex]-2^2 + 4(2) + 12[/tex]
f(2) = -4 + 8 + 12
f(2) = 16 dólares
Es importante tener en cuenta que la función f(x) también puede ser utilizada para calcular la ganancia total para cualquier precio de venta "x". Por ejemplo, si se venden las unidades a 3 por unidad, la ganancia sería:
f(3) = [tex]-3^2 + 4(3) + 12[/tex]
f(3) = -9 + 12 + 12
f(3) = 15 dólares
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micah wants to know the most common style of surfboard used at rhe breakers point. He surverys surfers at breakers point between 8:00 am and 12:00 pm.
3 out of 7 questions. PLEASE help me.
Translate the solid circle 2 units to the left and 2 units down and dilate the solid circle by a scale factor of 2. and the circles are similar
Transforming the circles(a) To move the solid circle exactly onto the dashed circle, we need to perform the following transformations:
Translate the solid circle 2 units to the left and 2 units down.Dilate the solid circle by a scale factor of 2.Therefore, the blank spaces should be filled as follows:
Translate the solid circle 2 units to the left and 2 units down.
Dilate the solid circle by a scale factor of 2.
(b) Yes, the original solid circle and the dashed circle are not similar, because they have different radii.
This is because all circles are similar
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lee had scored the following points in his first 8 games 12,14,14,15,8,10,3,15 enter the number of points lee needs to score in the nest game to increase his keam score to 13 points PLS ANSER FASTE