Answer:
It is directly proportional to the source charge.
Explanation:
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A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s2. What is the mass of the car? (Use the formula m=F/a)
the answer is 198.23
Force(f) = 18344 N
Acceleration(a) = 92.54 m/s²
we know that m=f/a
m=18344/92.54</p><p>
ma 198.23 kg
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Add the following vectors:
(a) (12, 5) + (6, 3)
(b) (−3, 8) + (6, −2)
(c) (3, 8, −7) + (7, 2, 17)
(d) (a, b, c) + (d, e, f)
Answer:
a. (18,8)
b. (3, 6)
c. (10, 10, 10)
d. (a+d, b+e, c+f)
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Which of the following choices is not part of the scientific method
Answer:
What are the choices?
Explanation:
As part of a carnival game, a 5.00 kg target is freely hanging from a very long and very light wire. Contestants can use one of two 1.5 kg balls to try to hit the target and deflect it high enough to win a prize. Ball A will have an elastic collision and bounce back toward you while ball B will have a nearly perfectly inelastic collision, but rather than sticking to the target, the ball will just drop straight downward to the ground after the collision. You can throw each ball with a velocity of 12 m/s. You are the first to try the game and which ball should you throw? Calculate the expected height the target will reach after each is thrown.
Answer:
Height ball A will deflect the target is 2.65 m
Height ball A will deflectthe target is 2.2 m
Ball A, will deflect the target to greater height, thus i will throw ball A
Explanation:
Given;
mass of the target, m₁ = 5.00 kg
mass of the ball, m₂ = 1.5 kg
initial velocity of each throw, u = 12 m/s
Throwing ball A; apply the principle of conservation linear momentum for elastic collision;
m₁u₁ + m₂u₂ = v₁m₁ + v₂m₂
The initial velocity of the target, u₁ = 0
The ball bounced back at the same speed, v₂ = -12 m/s
the velocity of the target after collision, = v₁
0 + 1.5 x 12 = v₁(5) + (-12 x 1.5)
18 = 5v₁ - 18
18 + 18 = 5v₁
36 = 5v₁
v₁ = 36/5
v₁ = 7.2 m/s
The vertical height reached by the target is given by;
v₁² = u₁² + 2gh
v₁² = 0 + 2gh
v₁² = 2gh
h = v₁² / 2g
h = (7.2)² / (2 x 9.8)
h = 2.65 m
Throwing ball B; apply the principle of conservation energy for the inelastic collision;
the kinetic energy of the ball will be converted to the potential energy of the target.
¹/₂m₁u₂² = mgh
¹/₂(1.5)(12)² = (5 x 9.8)h
108 = 49h
h = 108 / 49
h = 2.2 m
Ball A will deflect the target to greater height, thus i will throw ball A.
A fundraising company agrees to donate an extra $75 for every $100 the school raises through selling cookies. Part A: What is the constant of proportionality
Answer:
3/4 0r 0.75
Explanation:
Let E represent the extra cash.
Let R represent the amount raised.
From the question given above, we can say that:
The extra cash (E) is directly proportional to the amount raised (R) i.e
Extra cash (E) ∝ Amount raised (R)
E ∝ R
E = KR
NOTE: K is the constant of proportionality.
With the above formula, we can obtain the value of K as follow:
Extra cash (E) = $ 75
Amount raised (R) = $ 100
Constant of proportionality (K) =?
E = KR
75 = K × 100
Divide both side by 100
K = 75/100
K = 3/4 0r 0.75
Thus, the constant of proportionality is 3/4 0r 0.75
Pierce conducts an experiment in which waves collide in a way that the energy increases. What has occurred?
Answer:
The best and most correct answer among the choices provided by the question is the third choice. What he observed on the waves is the constructive interference. I hope my answer has come to your help. God bless and have a nice day ahead!
Explanation:
Answer:
Pierce conducts an experiment in which waves collide in a way that the energy increases. What has occurred?
refraction
reflection
constructive interference <<<---CORRECT
destructive interference
Explanation:
2021 EDGE
A jet must reach a velocity of 75 m/s for takeoff. If the runway is
2100 meters long, what must the constant acceleration be?
Answer:
[tex]a=1.33\ m/s^2[/tex]
Explanation:
Given that,
Initialy, the jet is at rest, u = 0
Final velocity of the jet, v = 75 m/s
Distance, d = 2100 m
We need to find the acceleration of the jet. It is based on the concept of equation of kinematics. Using third equation of motion, w get :
[tex]v^2-u^2=2ad[/tex]
a is acceleration
[tex]75^2=2a\times 2100\\\\a=\dfrac{75^2}{2\times 2100}\\\\a=1.33\ m/s^2[/tex]
So, the acceleration of the jet is [tex]1.33\ m/s^2[/tex].
Engineers are using computer models to study train collisions to design safer
train cars. They start by modeling an elastic collision between two train cars
traveling toward each other. Car 1 is traveling east at 6 m/s and has a mass
of 3,154 kg, Car 2 is traveling west at 23 m/s and has a mass of 8,296 kg.
After the collision, car 1 has a final velocity of 7 m/s west. What is the final
velocity of car 2?
A. 18 m/s east
B. 23 m/s west
C. 23 m/s east
D. 18 m/s west
SUN
Answer:
18 m/s west
Explanation:
The correct option is C. 23 m/s east
What is law of conservation of momentum ?Conservation of momentum states that For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.
using conservation of momentum
m1v1 + m2v2 = m1 v1' + m2 v2'
Given
m1 = 3154 kg
v1= 6m/s
m2 = 8296 kg
v2 = 23 m/s
v1' = 7m/s
v2' = ?
3154 * 6 + 8296 * 23 = 3154 * 7 + 8296 v2'
209732 - 22078 = 8296 v2'
187654 = 8296 v2'
v2' = 22.62 ≈ 23 m/s east
correct option is C. 23 m/s east
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A cheetah can run at a maximum speed
91 km/h and a gazelle can run at a maximum speed of 72.7 km/h.
If both animals are running at full speed,
with the gazelle 87.5 m ahead, how long before
the cheetah catches its prey?
Answer in units of s.
Answer:
Approximately 17.21 seconds
Explanation:
With subtraction, we have the gazelle 18.3 km/h slower than the cheetah, which is about 5.08333 m/s. As the gazelle is 87.5 meters ahead of the cheetah, 87.5 divided by 5.083333333 is about 17.21 seconds.
A storm is moving east toward your house at an average speed of 35 km an hour if the storm is currently 80 km from your house and how much time do you expect it to arrive
Answer: 2 hours 17 minutes
Explanation: 80/35h = 16/7 = 2hrs 17 minutes
A 100 kg disc with radius 1.6 m is spinning horizontally at 25 rad/s. You place a 20 kg brick quickly and gently on the disc so that it sticks to the edge of the disc. Determine the final angular speed of the disc-brick system.
Answer:
20.83rad/s
Explanation:
Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the mass of the disc and Brick respectively
u1 and u2 are the linear velocities respectively
v is their final velocity of the block-disc system
Given
m1 = 100kg
m2 = 20kg
u1 = wr =25×1.6
u1 = 40m/s
u2 = 0m/s (brick is stationary)
Substitute and the final linear velocity v
100(40)+20(0) = (100+20)v
4000 = 120v
v = 4000/120
v = 33.3m/s
From the formula;
v = wr
w = v/r
w= 33.3/1.6
w = 20.83rad/s.
Hence the final angular speed of the disc-brick system is 20.83rad/s
Imagine that you throw a rock into the air. When you release the rock, it is moving at 19.4 m/s. The rock flies straight up into the air and returns back to your hand. For how long was the rock in the air? Note: acceleration due to gravity is -9.81 m/s/s.
Answer:
4 s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 19.4 m/s.
Acceleration due to gravity (g) = –9.81 m/s²
Total time (T) =.?
Next, we shall determine the time take by the rock to get to the maximum height. This can be obtained as follow:
NOTE: At maximum height, the final velocity is zero.
Initial velocity (u) = 19.4 m/s.
Acceleration due to gravity (g) = –9.81 m/s²
Final velocity (v) = 0 m/s
Time taken to reach the maximum height (t) =.?
v = u + gt
0 = 19.4 + (–9.81 × t)
0 = 19.4 – 9.81t
Collect like terms
0 – 19.4 = –9.81t
–19.4 = –9.81t
Divide both side by –9.81
t = –19.4 / –9.81
t ≈ 2 s
Thus, it took approximately 2 s for the rock to reach its maximum height.
Finally, we shall determine the total time spent by the rock in the air as follow:
Time taken to reach the maximum height (t) = 2 s
Total time spent in air (T) =?
The total time (T) spent by the rock in the air will be two times the time taken (t) to reach the maximum height i.e
T = 2t
t = 2 s
T = 2 × 2
T = 4 s
Therefore, the rock spent approximately 4 s in the air.
Which of the following are examples of
molecules? Check all that apply.
two carbon atoms bonded to each other
a carbon atom
a chain of one hundred carbon atoms bonded
to one another
a carbon atom bonded to an oxygen atom
Answer:
two carbon atoms bonded to each other
a chain of one hundred carbon atoms bonded to one another
a carbon atom bonded to an oxygen atom
two carbon atoms bonded to each other a carbon atom, a chain of one hundred carbon atoms bonded to one another, a carbon atom bonded to an oxygen atom all these are examples of molecules, therefore all the given options are the correct answer
What is a molecule?The smallest component of a substance that still has its content and characteristics is called a molecule. It is constructed of two or more atoms connected by chemical bonds. Moles are the foundation of chemistry. Molecules are designated by their elemental symbol and a subscript indicating their atom count.
Atoms are the fundamental unit of an element. They consist of a nucleus and surrounding electrons. When an atom has an incomplete electron shell, it is said to have valence electrons. When two or more atoms come together to share outer shell valence electrons, a covalent bond is formed,
Since molecules include two carbon atoms bonded to each other, one carbon atom, a chain of hundred carbon atoms bonded to one another, and a carbon atom bonded to an oxygen atom, all of the suggested answers are correct.
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A ball is thrown horizontally from a 12 m
building with a speed of 2.0 m/s.
-high
How far from the base of the building does the ball hit the ground ?
Answer:
24
Explanation:
you multiply 2.0x12
I need help pls !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
figure d
Explanation:
Like chargers attract one another
nope. opposite charges attract. like charges repel.
Which pairs of elements could not react to form an Ionic compound
Answer:
Sodium and calcium
Explanation:
Answer:
Ionic bond is the name given to one of the three ways in which atoms can interact with each other. The other forms of interaction between atoms are the covalent bond, which occurs between atoms of ametals, hydrogens, or ametal and hydrogen, and the metallic bond, which occurs only between atoms of the same metal.
Explanation
:The atoms of the chemical elements that participate in the ionic bond must present, necessarily, the nature of gaining or losing electrons, thus, the ionic bond can occur between:
a metal and an ametal;
a metal and hydrogen.
Sodium: metallic element, as it has the characteristic of losing electron; belonging to the IA family, atomic number 11, with an electron in the valence shell.
Chlorine: ametalic element, as it has the characteristic of gaining electrons; belonging to the VIIA family, with atomic number 17.
During a baseball game, a hitter strikes the ball with a bat. When this happens, the ball
and the bat exert a force on each other. Why does the ball accelerate away from the bat
more than the bat accelerates away from the ball?
a. The ball has less mass, so it exerts less force on the bat.
b. The bat exerts more force than the ball because the batter is exerting a force
on the bat as it hits the ball.
c. The ball has less mass, so the equal force on the ball and the bat causes
greater acceleration of the ball.
d. The ball has a greater velocity before the collision, so the force affects the ball
more than it affects the bat.
Answer:
The answer is c
Explanation:
The lungs are large organs which contain smaller, expandable sacs.
These sacs greatly increase the surface area of the lungs.
Why is a large surface area important to the function of the lungs? A. Large amounts of liquid wastes and fatty tissue must be stored in the lungs. B. Oxygen in air taken in by the lungs must move quickly through the lung tissue and into the blood. C. The lungs must be very sturdy and rigid so they cannot move. D. The lungs must be able to filter oxygen from water while the organism is swimming.
Answer:
B. It is B because without this much space for oxygen and blood to flow and go through, we would not survive.
Explanation:
a single frictionless roller coaster car of mass m=750 kg tops the first hill with speed v=15 m/s ar height h =40m as shown
1) Find the speed of the car at B and C
2) if mass m were doubled, would the speed at B increase, decrease, or remain the same?
1. The speed of the roller coaster car at point B and C: are 19.8 m/s and 0 m/s respectively.
2. If mass (m) of the roller coaster car were doubled, the speed at B would increase because energy is dependent on the mass of an object.
Given the following data:
Mass of roller coaster car = 750 kgSpeed of roller coaster car = 15 m/sHeight = 40 meters1. To find the speed of the roller coaster car at point B and C:
First of all, we would determine the potential energy of the roller coaster car by using the formula:
[tex]P.E = mgh[/tex]
Where:
m is the mass of object.g is the acceleration due to gravity ([tex]9.8\;m/s^2[/tex]).h is the height of an object.From the diagram, height at point B = [tex]\frac{h}{2} = \frac{40}{2} = 20[/tex] meters
[tex]P.E = 750(9.8)(20)[/tex]
P.E = 147000 Joules.
Next, we would determine the speed by applying the law of conservation of energy.
[tex]Kinetic\;energy = Potential\;energy\\\\\frac{1}{2} mv^2 = mgh[/tex]
Substituting the values, we have;
[tex]147000 = \frac{1}{2} (750)v^2\\\\147000 = 375v^2\\\\v^2 = \frac{147000}{375} \\\\v^2 = 392\\\\v = \sqrt{392}[/tex]
Speed, v = 19.8 m/s
From the diagram, at point C, the speed is equal to zero (0) meters per seconds.
2. If mass (m) of the roller coaster car were doubled, the speed at B would increase because energy is dependent on the mass of an object.
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When a heavy football player and a light one run into each other, who exerts more force?
Answer:
When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.
Explanation:
Tell which is the answer
help please
Answer: a constant? im not sure that just sounds like itd be right.
Explanation:
Answer:
b
Explanation:
because he isn't moving
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What are the basic building blocks of matter?
electrons
atoms
molecules
compounds
Answer:
an atom
Explanation: atom then matter
Answer:
the basic building blocks that make up matter are called atoms.
the wire is 5.20 cm from the charge and carries a current of 68.5 A in a direction opposite to that of the moving charge. Calculate the magnitude of the force on the charge.
Complete Question
A 6.00-µc charge is moving with a speed of 7.50x10^4 m/s parallel to a very long, straight wire. the wire is 5.20 cm from the charge and carries a current of 68.5 A in a direction opposite to that of the moving charge. Calculate the magnitude of the force on the charge.
Answer:
The value is [tex]F =1.20 *10^{-4} \ N[/tex]
Explanation:
From the question we are told that
The magnitude of the charge is [tex]Q = 6.00\muC = 6.00 *10^{-6} \ C[/tex]
The speed is [tex]v = 7.50 *10^{4} \ m/s[/tex]
The distance of the wire from the charge is [tex]d = 5.20 \ cm = 0.0520 \ m[/tex]
The current flowing through the wire in the opposite direction to the charge is [tex]I _2 = 68.5 \ A[/tex]
Gnerally the magnitude of force on that charge is mathematically represented as
[tex]F = qvB[/tex]
Here B is magnetic field which is mathematically represented as
[tex]B = \frac{\mu_o * I}{2\pi d}[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
So
[tex]F = qv[\frac{\mu_o * I}{2\pi d}][/tex]
=> [tex]F = 6.0*10^{-6} * (7.50 *10^{4})[\frac{4\pi * 10^{-7} * 68.5 }{2* 3.142 * 0.0520 }][/tex]
=> [tex]F =1.20 *10^{-4} \ N[/tex]
wavelength = 5.4 cm and frequency = 9.4 Hz
What is the speed
2) A boat travels 12.0 m while it reduces its velocity from 9.5 m/s to 5.5 m/s. What is the
boat's acceleration while it travels that distance?
Answer:
2.5m/s^2
Explanation:
Note that the boat is reducing its speed. It is having negative acceleration or deceleration.
V^2 = u^2 -2as ( minus sign is used because of speed is reduced)
Given that,
s = 12 m
v = 5.5 m/s
u = 9.5 m/s
a = (v^2 - u^2) ÷ (-2s)
a= ( 5.5^2 - 9.5^2) ÷ ( -2× 12)
a = 2.5 m/s^2
The acceleration of the boat is -2.5 m/s²
The given paramters;
distance traveled by the boat, d = 12 m
initial velocity of the boat, u = 9.5 m/s
final velocity of the boat, v = 5.5 m/s
The acceleration of the boat is calculated as;
[tex]v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(5.5)^2 -(9.5)^2 }{2(12)} \\\\a = -2.5 \ m/s^2[/tex]
Thus, the deceleration of the boat is 2.5 m/s²
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An unbalanced force of 23 N is applied to a 13 kg mass. What is the acceleration of the
mass?
Answer:
1.77 m/s^2
Explanation:
since it is unbalanced there must be net force(resultant force)
[tex]net \: force \: = accleration \: \times mass[/tex]
net force = 23N
mass = 13kg
a = x
x = 23/13
= 1.769...
approximately = 1.77 m/s^2
A bus rolls to a stop along a horizontal road without the driver applying the brakes,
What answer choice BEST explains why this occurred?
A. The natural state of the bus is not to be in motion.
B. The bus ran out of momentum.
C. The force of gravity slowed the bus until it stopped.
D. The opposing force of friction stopped the train.
Answer:
should be d because friction allows things to go faster or slower
Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 2.857 m/s/s. The acceleration lasts for 15.5 s. What is the final speed of the car and how much ground does it cover during this acceleration?
Given parameters:
Initial velocity = 0m/s
Acceleration = 2.857m/s²
Time = 15.5s
Unknown:
Final speed of the car = ?
Solution:
We use one of the motion equations to solve this problem;
V = U + at
Where V is the final velocity
U is the initial velocity
a is the acceleration
t is the time taken
V = 0 + 2.857 x 15.5 = 44.28m/s
What are four metals other than iron that can be made to exhibit magnetic properties? Fill in the blank. Every magnet has _______ unlike poles. The _______ within a magnet lies between the north and south poles. If the north pole of a bar magnet is brought near the _______ pole of another magnet, the two magnets will repel one another. A material that’s attracted by a magnet but doesn’t necessarily become a magnet itself is called a/an _______ material.
Answer:
Four metals other than iron that can be made to exhibit magnetic properties are nickel, cobalt, manganese, and chromium.
two
neutral region
north
magnetic
Explanation:
PennFoster
The four metals other than iron that can be made to exhibit magnetic properties are:
NickelCobaltManganeseChromium.
Furthermore, the words which can be used to accurately complete the sentences below are:
Two Neutral region North MagneticThe magnet has two unlike poles and in the neutral region, there is the South and North poles.
The North and South poles repel each other and a magnet can attract any material which contains iron materials.
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