Who knows this how to do this

Answer:

B

Explanation:

I am pretty sure it is B as the speed is obviously constant but the velocity is not constant as it defines as the rate of speed AND DIRECTION meaning that it is not constant as it always changes direction. And angular velocity is constant.

Answer:

Communication is simply the act of transferring information from one place, person or group to another. Every communication involves (at least) one sender, a message and a recipient. This may sound simple, but communication is actually a very complex subject

[tex] \Large {\underline { \sf {Required \; Solution :}}}[/tex]

We have ―

We've been asked to calculate acceleration.

[tex]\qquad \implies\boxed{\red{\sf{ a = \dfrac{v-u}{t} }}}\\[/tex]

[tex] \twoheadrightarrow \quad \sf {a = \dfrac{30-18}{3} \; ms^{-2} } \\ [/tex]

[tex] \twoheadrightarrow \quad \sf {a =\cancel{ \dfrac{12}{3} \; ms^{-2} }} \\ [/tex]

[tex]\twoheadrightarrow \quad \boxed{\red{\sf{ a = 4 \; ms^{-2} }}}\\[/tex]

Therefore, acceleration of the car is 4 m/s².

Answer:

Hot

Explanation:

GFI or GFCI This device protected from collecting the electric shocks arise from the faults in the electric devices that are used at home. It would be work by comparing the current on the input side that shows the hot side to the current on the outside side that shows the neutral side

In the case when hot wire give 120 VAC current source while on the other hand the neutral wire gives the return path that are given by the hot wire

Hence, the hot would be the answer

Answer:

whats the question

Explanation:

The distance Oscar covered was 6km while the displacement was 2km.

Displacement is defined as the vector whose length is the shortest

distance from the initial to the final position of a point M.

Distance = Total length of space between points

              = 2km+ 2km+ 2km = 6km.

Displacement = 2km.

This is because it is the shortest  distance from the positions in this

scenario.

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Answer: 10 Ω or 2.5 Ω

Explanation:

In series resistance R = 5 Ω + 5 Ω =10 Ω. If resistors are parallel, resistance is

1/R = 1/5Ω+ 1/5Ω and R = 2,5 Ω

The true statement about scientific knowledge is it can be changed as new information becomes available.

option A

Science is a dynamic process, and scientific knowledge is continually evolving as new data and evidence are discovered.

Scientific theories and hypotheses are constantly being tested and refined, and they can be modified or even rejected if new evidence contradicts them.

This is one of the key features of the scientific method - that it is self-correcting and always open to revision based on new evidence.

Thus, the true statement about scientific knowledge is it can be changed as new information becomes available.

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#SPJ1

Answer:

19.9 N/m

Explanation:

From the question,

Applying Hook's law

F = Ke.................. Equation 1

Where F = Force on the spring, k = spring constant, e = extension

But the force on the spring is the weight of the mass

Therefore,

mg = ke.................. Equation 2

Where m = mass. g = acceleration due to gravity

make e the subject of the equation

e = mg/e................ Equation 3

Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,

Constant: g = 9.8 m/s²

Substitute these values into equation 3

e = (0.455×9.8)/0.224

e = 19.9 N/m

The spring constant of the given spring is 20 N/m.

The given parameters:

The spring constant is calculated by applying Hooke's law as follows;

[tex]F = kx\\\\mg = kx\\\\k = \frac{mg}{x} \\\\k = \frac{0.455 \times 9.8}{0.224} \\\\k = 20 \ N/m[/tex]

Thus, the spring constant of the spring is 20 N/m.

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Answer:

The focal length of the lens is +30 and it is a convex lens.

Explanation:

Given that,

The nearest distance of distinct vision of  a hypermetropial person is 60 cm, v = -60 cm

The distance is reduced by 20 cm, u = -20 cm

We need to find the nature and focal length of the lens.

Let f be the focal length of the lens. Using lens formula,

[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{f}=\dfrac{1}{(-60)}-\dfrac{1}{(-20)}\\\\f=+30\ cm[/tex]

So, the focal length of the lens is +30 and it is a convex lens.

In Linear motion the swimmer swims

Answer: A

Explanation: Linear motion.

Answer:

A. Its velocity is decreasing

Explanation:

Answer: A sonic boom is a sound associated with shock waves created when an object travels through the air faster than the speed of sound. Sonic booms generate enormous amounts of sound energy, sounding similar to an explosion or a thunderclap to the human ear. The crack of a supersonic bullet passing overhead or the crack of a bullwhip are examples of a sonic boom in miniature. Sonic booms due to large supersonic aircraft can be particularly loud and startling, tend to awaken people, and may cause minor damage to some structures. They led to prohibition of routine supersonic flight over land. Although they cannot be completely prevented, research suggests that with careful shaping of the vehicle, the nuisance due to the sonic booms may be reduced to the point that overland supersonic flight may become a feasible option. A sonic boom does not occur only at the moment an object crosses the speed of sound; and neither is it heard in all directions emanating from the supersonic object. Rather the boom is a continuous effect that occurs while the object is travelling at supersonic speeds. But it affects only observers that are positioned at a point that intersects a region in the shape of a geometrical cone behind the object. As the object moves, this conical region also moves behind it and when the cone passes over the observer, they will briefly experience the boom.

Explanation:

As incredible as the Concorde was, the sonic booms created by its supersonic flights were so disruptive that most countries restricted or completely prohibited the aircraft from flying over land.  The sonic boom, at its worst, would be heard as a very loud thunder clap that was right overhead. The force of the boom rattled windows and loosened roof tiles. But even when the sonic boom sounded like a “softer” distant thunder clap, it was distracting to people and caused disruption of sleep and interruptions in activity. Imagine that you are driving on your way to work, and with clear skies overhead, you suddenly hear the sound of thunder. Your immediate responses are most likely surprise, shock, and an instinctive search for the source. Being caught by surprise in certain situations is rather annoying, and in others, potentially dangerous. In 1964, the FAA and NASA conducted a six-month sonic boom research project in Oklahoma City – without warning residents beforehand. The experiment consisted of eight sonic booms, every day, for six months. 15,000 complaints and a class action lawsuit were filed. The government lost on appeals. Great idea, guys, just brilliant. When the Concorde was originally designed, in the early 1960s, governments and airlines around the world lined up to place orders. The plane did an around-the-world publicity trip, and was well-received. But as awareness of the sonic boom effect grew, almost every country banned the aircraft. Only the US, Great Britain, and France allowed the Concorde to enter their airspace, and then only to cities in close proximity to the ocean – NYC, London, Paris, and Washington, DC. The Concorde was specifically designed for supersonic flight (specifically, Mach 2) and was very fuel-inefficient at subsonic speeds (less than Mach 1). Unfortunately, it was thus not feasible to fly at supersonic speed over water and then at subsonic speed over land.

What causes a sonic boom?  

When any object moves, it creates waves in front of and behind it. Think of the waves that a boat creates at its bow and stern. In front, the waves are compressed together as the boat sails forward. Behind, the waves spread out away from the boat. In this case, you only see the waves on the surface of the water, and it appears two-dimensional. Similar principles are at play with aircraft. In front of the nose of a plane, air is pushed together and compressed as the aircraft flies forward. Behind the plane, the air creates waves that radiate out and away in the shape of a cone – three-dimensionally.

Answer:

A sonic boom is caused by the shock waves created when an object travels through the air faster than the speed of sound.

Explanation:

When any object moves, it creates waves in front of and behind it. Think of the waves that a boat creates at its bow and stern. In front, the waves are compressed together as the boat sails forward. Behind, the waves spread out away from the boat. Similar principles are at play with aircraft. In front of the nose of a plane, air is pushed together and compressed as the aircraft flies forward. Behind the plane, the air creates waves that radiate out and away in the shape of a cone – three-dimensionally. Things get interesting, and complicated, when you fly faster than the speed of sound – supersonic flight. The nose of a supersonic aircraft pushes ahead of its forward waves. These waves get in the way of the airplane, causing compression which results in a shock wave. Actually, this creates two shocks, one forming as the aircraft passes the front of the wave and then another as it leaves the wave. The shock wave generated stays mostly behind the aircraft, and radiates out in a cone

Answer:

The example of the nonlinear element is a diode and some of the nonlinear elements are not there in the electric circuit is called a linear circuit. Some other examples of the non-linear elements are transistors, vacuum tubes, other semiconductor devices, iron core inductors, and transformers.

Explanation:

Answer: Gravity

Explanation:A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Answer:

C

Explanation:

if you measure your body's flexibility then you can keep track of how flexible you have gotten over time

Answer:

a) tires rubbing, b) the weight has a component parallel to the floor

c) he child's back support, d)  The tension of the rope and weight

Explanation:

In this exercise, we are asked to indicate the origin of the forces for the centripetal movement  parallel to the rope,  e) gravitational force

a) When a car turns, the centripetal force has two origins

* The tires rubbing against the road

* If the road has a lean angle, the component of the weight directed towards the center of the circle also contributes to the centripetal force.

b) the child in general has some degree of inclination with respect to the post, for which the weight has a component parallel to the floor that is responsible for the centripetal movement of the system

c) The bench rotates together with the carousel, so the child's back support is the response to the centripetal force

d) The tension of the rope has two components: the component perpendicular to the movement and the component of the weight (parallel to the rope) the difference of these two forces is the centripetal force

e) The gravitational force of the sun on the earth is what creates the centripetal motion

a centrifugal clutch works, as the name suggests, through centrifugal force. ... The rotation of the hub forces the shoes or flyweights outwards until they come into contact with the clutch drum, the friction material transmits the torque from the flyweights to the drum. The drive is then connected

Answer:

B

Explanation:

Pressure = density × g × height

[tex]p \: = (1.36 \times {10}^{4} )(10)(780 \times {10}^{ - 3} ) \\ p = 1.1 \times {10}^{5} [/tex]

The pressure of the atmosphere, when a barometer reads 780 mm Hg.    Mercury which a density of 1.36 x 10^4 kg /m^3 is B 1.1 x 10^5 N/m^2

This problem can be solved using the formula below

P = dgh................. Equation 1

Where P = Pressure of the atmosphere, d = density of the mercury, h = height of the mercury, g = acceleration due to gravity.

From the question,

Given: d = 1.36×10⁴ kg/m³, h = 780 mm = 0.78 m,

Constant: g = 10 m/s²

Substitute these values into equation 1

P = (1.36×10⁴)(10)(0.78)

P = 10.608×10⁴ N/m²

P ≈ 1.1×10⁵ N/m²

Hence the right answer is B. 1.1×10⁵ N/m²

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Answer:

the frequency of the fundamental mode of vibration is 199.6 Hz

Explanation:

Given;

tension of the piano wire, T = 765 N

length of the steel wire, L = 0.8 m

mass of the steel wire, m = 6.00 g = 6 x 10⁻³ kg

The frequency of the fundamental mode of vibration is calculated as;

[tex]f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} }[/tex]

where;

μ is the mass per unit length  [tex]= \frac{6.0 \times 10^{-3}}{0.8} = 7.5 \times 10^{-3} \ kg/m[/tex]

[tex]f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 0.8} \sqrt{\frac{765}{7.5 \times 10^{-3}} } \\\\f_o = 199.6 \ Hz[/tex]

Therefore, the frequency of the fundamental mode of vibration is 199.6 Hz

Answer:

a. 0.00266v

b. -0.0016625

the area should be shrunk

Explanation:

the magnitude of the EMF induced in the loop

= area * rate

= 0.014 * 0.19

= 0.00266 V

B we are to solve for the rate at which the are has to be change with B = 1.6

δA/δt = -A/B * dB/dt

= (-0.014 * 0.19) /1.6

= -0.0016625

the sign is negative so the EMT is negative and so the area has to be shrunk.

Answer:

below hun

Explanation:

Bismuth: cosmetics, alloys, fire extinguishers, and ammunition.

Scandium: bicycle frames, fishing rods, golf iron shafts, and baseball bats.

Answer: horizontal speed is 3.9 m/s

Explanation: when ball starts to drop, its vertical speed v0 is zero.

We can calculate dropping time from s = v0t +0.5gt².

Dropping time t= √(2s/g)= √((2·8.0 m)/9.81 m/s²)= 1.277 s

Because ball travels horizontal distance s= 5.0 m

HorizontalSpeed v = s/t = 5.0 m/1.277s= 3,915 m/s

Answer:

the power output needed is  61.25 × 10⁴

Explanation:

The computation of the power output needed is shown below;

Given that

m =  1.5 ×10⁴ kg

v = 25m  ÷ 6.0 s

And g = 9.8 m/sec^2

Now based on the above information

p = f × v

= mg × v

= 1.5 ×10⁴ × 9.8 × 25 ÷ 6

= 61.25 × 10⁴

Hence, the power output needed is  61.25 × 10⁴

Answer:

Air masses tend to move from west to east.

Answer:

a)      v = t² -18 t + 64,    a = 2 t - 18,   b)   a = -18 m / s²,  c)   a = -2 m / s²

Explanation:

In this exercise they tell us the function of position with respect to time

    s = ⅓ t³ - 8 t² + 64 t + 3

a) find the velocity and acceleration.

For this we use the definition of velocity and acceleration

      v = ds / dt

      a = dv / dt

we make the derivatives

      v = t² -18 t + 64

      a = 2 t - 18

b) for this part we substitute t = 1

      a = 2 1 -18

       a = -18 m / s²

c) let's find the time for which v = 0

         0 = t² - 18 t + 64

this expression is a binomial or perfect

        (x + a) ² = x² + 2 a x + a²

in this case

       x = t

       a = 8

        (t-8) ² = t² - 16 t + 64

therefore the velocity is zero for when t = 8 s

the acceleration at this point is

         a = 2 8 - 18

         a = -2 m / s²

Newton's Second Law of Motion states "The rate of change of momentum of a body is directly proportional to the applied unbalanced force in the direction of force".

Answer:

D. the net heat flow is zero

Explanation:

In one cycle of any heat engine, three things happen:

[tex]Q_H = W + Q_C[/tex]

Conclusively, the net heat flow is zero

Answer:

The sum of an object's potential and kinetic energies is called the object's mechanical energy. As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.

Explanation:

Answer:

the potential decrease and kinetic increase

Explanation:

because it goes from a state of rest to a state of movement

Answer:

the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake

Explanation:

This problem can be solved using the kinematics relations, let's start by finding the final velocity of the acceleration period

          v² = v₀² + 2 a₁ x

indicate that the initial velocity is zero

          v² = 2 a₁ x

let's calculate

          v = [tex]\sqrt {2 \ 15.0 \ 645}[/tex]

          v = 143.666 m / s

now for the second interval let's find the distance it takes to stop

          v₂² = v² - 2 a₂ x₂

in this part the final velocity is zero (v₂ = 0)

         0 = v² - 2 a₂ x₂

         x₂ = v² / 2a₂

let's calculate

         x₂ = [tex]\frac{ 143.666^2 }{2 \ 18.2}[/tex]

         x₂ = 573 m

as the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake