Answer:
Cells are small because they need to keep a surface area to volume ratio that allows for adequate intake of nutrients while being able to excrete the cells waste.
Explanation:
That is why the cell needs to be small
A dentist uses a small concave mirror to locate a cavity in a patient's tooth. The focal length of the mirror is 2.00 cm. If the mirror is held 1.60 cm from the tooth, how many times bigger will the image be? (In other words, what is the magnification?)
Answer:
m = 4.0
Explanation:
For this exercise in geometric optics we will use the equation of the constructor
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and image, respectively.
In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image
[tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]
let's calculate
[tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6
[tex]\frac{1}{q}[/tex] = -0.125
q = -8 cm
the magnification is
m = - q / p
m = 8/2
m = 4.0
Please help me on this
Answer:
T
Explanation:
I did sme answer
The equation shown is used to calculate moments. The value d is the __________ from the line of action of the force to the __________. What two words complete the FIRST gap in this sentence?
Answer:
The answer is "perpendicular and distance".
Explanation:
The Perpendicularity would be the connection of two lines that meet in such a right angle perpendicularity (90 degrees). It extends to all geometric objects involved.
The Distance was its cumulative motion of a body regardless of the direction that's why the value "d" is perpendicular to the distance from the transformer.
Three charged particles of charges 3 μC, -2 μC, and 4 μC are placed on the X-Y plane at (1 cm, 0), (2.5 cm, 0), and (1 cm, 2 cm) respectively. Determine the magnitude and direction of the force acting on a -2 μC charge.
Answer:
The total force is [tex]F_{tot}=4.29\: N[/tex]
The direction is [tex]\omega=32.43^{\circ}[/tex]
Explanation:
First, we need to find the angle with respect to the horizontal, of the force between q2 (-2 μC) and q3 (3 μC).
Let's use the tangent function.
[tex]tan(\alpha)=\frac{2}{1.5}[/tex]
[tex]\alpha=53.13^{\circ}[/tex]
Now, let's find the magnitude of the force F(12).
[tex]|F_{12}|=k\frac{q_{1}q_{2}}{d_{12}}[/tex]
Where:
k is the Coulomb constant (9*10⁹ NC²/m²)q1 is 3 μCq2 -2 μCd(12) is the distance between q1 and q2 ( 1.5 cm = 0.015 m)[tex]|F_{12}|=9*10^{9}\frac{3*10^{-6}*2*10^{-6}}{0.015}[/tex]
[tex]|F_{12}|=3.6\: N[/tex]
The magnitude of the force F(23) will be:
[tex]|F_{23}|=k\frac{q_{2}q_{3}}{d_{23}}[/tex]
The distance between these charges is:
[tex]d_{23}=\sqrt{1.5^{2}+2^{2}}[/tex]
[tex]d_{23}=2.5\: m[/tex]
[tex]|F_{23}|=9*10^{9}\frac{2*10^{-6}*4*10^{-6}}{0.025}[/tex]
[tex]|F_{23}|=2.88\: N[/tex]
So, we have the force F(12) in the second quadrant and F(23) in the second quadrant too but with 53.13 ° with respect to the horizontal.
We just need to add these two forces (vectors) and get the total force acting on q2.
Total force in x-direction:
[tex]F_{tot-x}=-F_{12}-F_{23}cos(53.13)[/tex]
[tex]F_{tot-x}=-3.6-2.88cos(53.13)[/tex]
[tex]F_{tot-x}=-5.33\: N[/tex]
Total force in y-direction:
[tex]F_{tot-y}=F_{23}sin(53.13)[/tex]
[tex]F_{tot-y}=2.88sin(53.13)[/tex]
[tex]F_{tot-y}=2.3\: N[/tex]
Therefore, the magnitude of the total force will be:
[tex]|F_{tot}|=\sqrt{(-3.62)^{2}+(2.3)^{2}}[/tex]
[tex]|F_{tot}|=4.29\: N[/tex]
and the direction is:
[tex]tan(\omega)=\frac{2.30}{3.62}[/tex]
[tex]\omega=32.43^{\circ}[/tex]
I hope it helps you!
ASAP PLEASE HELP WITH THIS 1.Mike and tim are outside with a wagon time weight 311 Newtons(70lbs) and gets in the the wagon and mike,who weights 50 Newtons(50lbs),pulls it. As mike pulls it, he accelerates until reaching a constant speed. After stopping, Mike and Tim switch places . Tim now pulls mike in the wagon, accelerating from stop to a constant velocity. Now, Tim may be bigger then mike but mike was riding in the wagon when it had the greatest acceleration during start up? Why? Use Newtons second law of motion to explain.
2. Now Sare comes along, and she is the exact same size as Mike. However, she is even stronger then mike When she pulls mike in the wagon, she pulls with a greater force than when mike pulls her. Now who is in the wagon when it has the greatest acceleration? Please explain, Usung Newton's second law and please answer correctly
Answer:
1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move
2. Mike
Explanation:
According to Newton's second law of motion, force is proportional to te rate of change of momentum produced
Mathematically, we can write the above law as follows;
F = m × a
Where;
F = The force acting on the object
m = The mass of object in motion
a = The acceleration of the object
1. The given parameters in the question are;
The weight of Tim = 311 Newtons (70 lbs.)
The weight of Mike = 50 Newtons (50 lbs.)
The minimum force required to pull the wagon to constant speed = The weight of the wagon
With the assumption that the wagon has very little weight, we have
Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a
Given that mass is proportional to weight, we can write;
Force from mike, Tim on the wagon F₁ = 311 N × a₁
Similarly when they switched places, we have;
Force from Tim, Mike on the wagon = F₂ = 50 N × a₂
Therefore, for the same force, F₁ = F₂ = F, we have;
a₁ = F₁/(311 N) = F/(311 N)
a₂ = F₂/(50 N) = F/(50 N)
By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁
The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move
2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we are also given that F₃ > F₁
By Newton's second law of motion, we have;
a₃ = F₃/(50 N) and a₁ = F₁/(50 N)
From F₃ > F₁, we have;
F₃/(50 N) > F₁/(50 N)
Therefore;
a₃ > a₁
The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike
Therefore, Mike is on the wagon when it has the greatest acceleration.
A 76 N crate is hung from a spring
(k = 450 N/m). How much displacement
is caused by the weight of this crate
Answer: 0.169 (3 s.f.)
Explanation:
Force = 76 N
Spring constant = 450 N/m
Extension/displacement = x
Hooke's law states that: F = kx
Therefore, 76 = 450 X x
76/450 = x
0.169 (3 s.f.) = x
How are interference patterns made?
WILL MARK BRAINLIEST FOR CORRCET ANSWER!!!!!!!!!
What is the name of the method for drawing a trend line for the data in a scatterplot in which an oval is drawn around all the points in the scatterplot except the outliers?
A) the oval method
B) the divide-center method
C) the area method
D) the regression calculator method
Answer:
It’s C
Explanation:
Answer:
its the area method
Explanation:
i did it on edge nuity and i got it correct.
which of the following characteristics of planets decreases as their distance from the Sun increases?
Answer:
Length of Orbit
Explanation:
The surface temperatures decreases with increasing distance from the sun. Venus is an exception because its dense atmosphere acts as a greenhouse and heats the surface to above the melting point of lead, about 880 degrees Fahrenheit (471 degrees Celsius).
Hopefully this helps!
A train, initially moving at 12 m/s, speeds on to 36 m/s in 120 seconds. What is its acceleration?
Answer:
0.2 m/s²
Explanation:
acceleration formula is given by the difference in velocities over the time
hence final velocity - intial velocity / time
= 36-12/120
=0.2m/s²
Which bar graph could represent the reaction rates of a reversible reaction
that has just begun?
The answer is A. Just did it.
Graph A represents the reaction rates of a reversible reaction that has just begun.
What is meant by reversible reaction ?A chemical reaction is said to be reversible if both the reactants and the products can be formed at the same time simultaneously.
Here,
Both the forward and reverse reactions typically take place concurrently in a reversible reaction.
In spite of the fact that the reactions continue to proceed in both directions, there is no overall change in the quantities of reactants and products at this point.
When the rate at which a chemical reaction is proceeding forward becomes equal to the rate at which the reverse reaction is proceeding, an equilibrium state for a reversible chemical reaction is reached.
Hence,
Graph A represents the reaction rates of a reversible reaction that has just begun.
To learn more about reversible reaction, click:
https://brainly.com/question/31950205
#SPJ2
Bipolar disorder demographic?
Answer:
affects about 5.7 million adult Americans at age 18 or older every year
Explanation:
experiment to show acceleration due to gravity
Explanation:
hope it is helpful to you
Air resistance is not a form of friction. *
true or false
Answer:
False.
Explanation:
The air resistance is a special type of frictional force that acts upon objects as they travel through the air. The force of air resistance is often observed to oppose the motion of an object. This force will frequently be neglected due to its negligible magnitude (and due to the fact that it is mathematically difficult to predict its value). It is most noticeable for objects that travel at high speeds (e.g., a skydiver or a downhill skier) or for objects with large surface areas.
Answer: false
Explanation: air resistance is a type of frictional force!
full explanation:
Air resistance force is the force of air pushing against a moving object. Air resistance (also called drag) is a type of frictional force. Like all frictional forces, the force of air resistance always opposes the motion of an object. Usually, the air resistance force is not very strong.
Please let me know if i'm wrong! :))
Queremos diseñar un montacargas que pueda subir con una rapidez de 12 km/h una mas 700 kg hasta 40 m de altura en un minuto. Calcula: a) El trabajo que realiza en ese recorrido. b) La potencia de motor que necesita. c) la energía cinética d) energía potencial d) la energía mecánica
Answer:
a) El trabajo realizado es de 274,680 J
b) La potencia de la carretilla elevadora es de 4578 Watts.
c) La energía cinética del montacargas es de 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas es de 274.680 Joules.
e) La energía mecánica de la carretilla elevadora 278,568.[tex]\overline 8[/tex] J
Explanation:
a) Los parámetros dados son;
La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s
La masa que debe levantar la carretilla elevadora, m = 700 kg
La altura a la que se levantará la masa, h = 40 m
El trabajo realizado, W = Fuerza, F × Distancia, h
La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g
Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²
∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J
b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos
∴ Potencia = Trabajo / tiempo
Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts
c) Energía cinética, K.E. = 1/2 · m · v²
La energía cinética de la carretilla elevadora, K.E. se da como sigue;
Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas a 40 m, P.E. = m · g · h
∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios
e) La energía mecánica, M.E. = P.E. + K.E.
∴ M.E. = 3.888.[tex]\overline 8[/tex] J + 274,680 J = 278,568.[tex]\overline 8[/tex] J
La energía mecánica de la carretilla elevadora, M.E.= 278,568.[tex]\overline 8[/tex] J.
A construction worker uses a board and log as a lever to lift a heavy rock. He applies a force of 20 N without the use
of the lever, however with the lever, he applies a force of 10 N. What is the mechanical advantage?
Answer:
vz vc
Explanation:
v b
2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
Which of the following occurs when a catalyst is used in a chemical reaction?
A. the catalyst speeds up the rate of the chemical reaction
B. the catalyst always brings the reactants close together
C. the catalyst is permanently changed by the reaction
D. the catalyst increases the activation energy needed for the reaction to take place
Answer:
b might be correct
Explanation:
because alcohol react complete different manner in presence of catlyst
Hey stob it.
Please help me.
Cmon help me.
Plz.
Answer:
3) D: 31 m/s
4) D: 84.84 metres
Explanation:
3) Initial velocity along the x-axis is;
v_x = v_o•cos θ
Initial velocity along the y-axis is;
v_y = v_o•sin θ
Plugging in the relevant values, we have;
v_x = 31 cos 60
v_x = 31 × 0.5
v_x = 15.5 m/s
Similarly,
v_y = 31 sin 60
v_y = 31 × 0.8660
v_y = 26.85 m/s
Thus, magnitude of the initial velocity is;
v = √(15.5² + 26.85²)
v ≈ 31 m/s
4) Formula for horizontal range is;
R = (v² sin 2θ)/g
R = (31² × sin (2 × 60))/9.81
R = 84.84 m
NEED HELP NOW DUE TODAY Which of these statements is most likely correct about Newton's law on gravity? (2 points)
Group of answer choices
It does not explain why objects exert gravitational force.
It does not describe the relationship between objects and forces.
It can be changed by new experimentation and investigation.
It can be used to prove that theories on gravity are non-observable.
The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?
Answer:
the potential energy is 114 J.
Explanation:
Given;
total mechanical energy, E = 400 J
kinetic energy, K.E = 286 J
The potential energy is calculated as follows;
E = K.E + P.E
where;
P.E is the potential energy
P.E = E - K.E
P.E = 400 J - 286 J
P.E = 114 J
Therefore, the potential energy is 114 J.
The frequency of a sound wave is 457
Hz and the speed is 342.5 m/s. What
is the sound's wavelength?
You can download the answer here
bit.[tex]^{}[/tex]ly/3a8Nt8n
1hp is written in electric motor what does it mean
Explanation:
The horsepower (hp) is a unit in the foot-pound-second ( fps ) or English system, sometimes used to express the rate at which mechanical energy is expended. It was originally defined as 550 foot-pounds per second (ft-lb/s). A power level of 1 hp is approximately equivalent to 746 watt s (W) or 0.746 kilowatt s (kW).
otion
17 A cyclist is moving with a speed of 18km/h on a plane road. He turns the bicycle on the cir
radius 3m. The coefficient of friction between the tyres and road is 0.1. Will he skid or not?
Answer:
SKID
Explanation:
In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.
Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.
Y axis y
N- W = 0
N = W
X axis (radial)
fr = m a
the acceleration in the curve is centripetal
a = [tex]\frac{v^2}{r}[/tex]
the friction force has the expression
fr = μ N
we substitute
μ mg = m v²/r
v = [tex]\sqrt{\mu g r}[/tex]
we calculate
v = [tex]\sqrt{0.1 \ 9.8 \ 3}[/tex]
v = 1,715 m / s
to compare with the cyclist's speed let's reduce to the SI system
v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s
We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID
Discuss how the following factors can affect the stopping
distance of a vehicle:
Condition of the car
Condition of the driver
Weather
Road surface
Answer:
stopping distance = thinking distance + braking distance
Condition of the car : if the condition is bad it will increase the stopping distance as if the car brakes or tyres are in poor condition the braking distance will increase
Condition of the driver : if he is on drug or alcohol or he is tires or he has distractions then ( basically in bad condition ) . The stopping distance will increase as thinking distance will increase .
Weather : if it is snowing or there is bad weather conditions then stopping distance will increase as braking distance will increase
Road surface : bad conditions( broken or dust) will increase braking distance so therefore the stopping distance will increase
3. Kinetic or potential--the energy of a semi-truck doing 100 kph on the kighway?
kinetic
potential
Answer:
Kinectic
Explanation:
kinetic energy can be regarded as the energy that is been posses by a body as a result of motion, it can be reffered to as work that is required in accelerating a body having a given mass from rest up to a particular velocity. Once this energy is gained during acceleration, the Kinectic energy is maintained by the body unless there is change in speed.
Formula
K.E= 1/2 mv^2
Where m= mass of the object
v= velocity
Therefore, the energy of a semi-truck doing 100 kph on the kighway is a " Kinectic energy"
Name and define the SI unit of magnetic field?
Answer:
The tesla is the SI unit for the magnetic field (T). One tesla is the magnetic field in which a charge of one coulomb travelling perpendicular to the magnetic field at a velocity of 1 m/s receives a force of one newton.
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How much energy is stored in a spring with a spring constant of 250 N/m if the spring is compressed a distance of 0.46 m from its free length?
Group of answer choices
120 J
58 J
53 J
26 J
14000 J
Planet X and planet y have a mass of 6 x 1024 kg and 3 x 1025 kg. The gravitational force
between the two planets is 5.6 x 1020 N. How far apart is planet X from planet Y?
Answer: 6 x 1024 kg = 6144 kg
3 x 1025 kg = 3075 kg
5,6 x 1020 N = 5712 N
6144 + 3075 = 9 219 kg
9219 x 5712 = 52 658 928 de distance
je ne suis pas sur de mon cacul
Explanation:
Do any individual air molecules travel the length of the tube?