work out 23% of 42 give your answer correct to one decimal point

5/6 - 3/8

Rewrite the fractions to have a common denominator:

5/6 x 4 = 20/24

3/8 x 3 = 9/24

Now you have 20/24 - 9/24 = 11/24

The answer is D. 11/24

Answer:

D. 11/24

Step by Step Explanation:

Just use cymath.

Answer:

Step-by-step explanation:

11). 6x + 3y = 9

    3(2x + y) = 9

    2x + y = 3

    y = -2x + 3

    Since variables are of single degree therefore, it's a linear function

12). 3y - 2x = -2x - 12

     3y - 2x + 2x = -2x - 12 + 2x

     3y = -12

      y = -4

     Since variable y is of single degree therefore its a linear function.

13). 11y + 4x = -8 + 11y

     11y + 4x - 11y = -8 + 11y - 11y

     4x = -8

      x = -2

      Linear function.

14). 4x - 3 + 2y = 8x - 9

     4x + 2y - 3 - 4x = 8x - 4x - 9

     2y - 3 = 4x - 9

     2y = 4x - 9 + 3

     2y = 4x - 6    

      y = 2x - 3

      Linear function.

Answer:

this is to hard

Step-by-step explanation:

7, 8 ,9 ,0 10

Answer:

B 21.50 dollars

Step-by-step explanation:

Answer:

84 in^2

Step-by-step explanation:

Answer:

84in^2

Step-by-step explanation:

First we can calculate the rectangle which would be

6*11=66

then we can calculate the triangle

we know that the base is 6, so if we cut it in half we get two triangles which could get put back together in another rectangle so we would just need to do

6*3=18

then add them together

66+18=84

Answer: 167

Step-by-step explanation:

Because I just answered it

Answer:

13.7

Step-by-step explanation:

fill the numbers in using pythagorean theory

[tex]a^{2} + b^{2} = c^{2}[/tex]

(the hypotenuse has to be [tex]c^{2}[/tex])

[tex]9.2^{2} + b^{2} = 16.5^{2}[/tex]

[tex]84.64 + b^{2} = 272.25[/tex]

[tex]b^{2} = 187.61[/tex]

(to get [tex]b[/tex] alone you have to find the square root of both sides)

[tex]b = 13.69707[/tex]

round that and you get

[tex]b = 13.7[/tex]!

Answer:

B

Step-by-step explanation:

Pythagorean theorem:

6^2 + (4/2)^2 = x^2

36 + 4 = x^2

40 = x^2

x = [tex]\sqrt{40}[/tex]= [tex]2\sqrt{10}[/tex]

Answer is B

Answer:

≈ 18.3 m²

Step-by-step explanation:

The shaded area (A) is calculated as

A = area of sector - area of right triangle

area of sector = area of circle × fraction of circle

A = πr² × [tex]\frac{90}{360}[/tex]

   = π × 8² × [tex]\frac{1}{4}[/tex] = 64π × [tex]\frac{1}{4}[/tex] = 16π m²

area of triangle = [tex]\frac{1}{2}[/tex] × 8 × 8 = 4 × 8 = 32 m²

shaded area is then

A = 16π - 32 ≈ 18.3 m² ( to the nearest tenth )

Answer:

x=8

Step-by-step explanation:

a=8x-13

b=13x-65

a+b=90

8x-13+13x-65=90

21x=168

x=8

Since 4 peaches x 2 =8, you would would only be able to buy 6 mangos since $1.25 x 6 mangos =$7.5 so it would be $7.5+$8=$15.5 and 6 mangos+4 peaches=10 in total. And he would also save $5.00! :)

Please mark brainliest!

Hope it helps!

Answer:

The answer should be -5+7= 2

Answer:

2

Step-by-step explanation:

[tex]-5-(-7)\\\\-5+7\\\\\boxed{2}[/tex]

We would distribute the '-' into the '-7' to yield the second step.

Hope this helps.

Answer:

x -22

Step-by-step explanation:

Sum = -7            (-22+15 = -7)

Product = -330   (-22*15 = -330)

Factors = -22 , 15

x² - 7x - 330 = x² +15x - 22x - 22 *15

                    = x(x + 15) -22(x + 15)

                   = (x +15)(x -22)

[tex]\frac{x^{2}-7x-330}{x + 15}=\frac{(x+15)(x-22)}{(x+15)}\\\\ =x - 22[/tex]

Given:

The polynomial is

[tex]-x+5x^2+1[/tex]

To find:

The polynomial in the form [tex]ax^2+bx+c[/tex] and find the values of a, b and c.

Solution:

We have,

[tex]-x+5x^2+1[/tex]

Arranging the terms in descending order of their degrees, we get

[tex]=5x^2-x+1[/tex]

[tex]=(5)x^2+(-1)x+1[/tex]

On comparing this polynomial with [tex]ax^2+bx+c[/tex], we get

[tex]a=5,b=-1,c=1[/tex]

Therefore, the value of a is 5, the value of b is -1 and the value of c is 1.

Answer:

3.9

Step-by-step explanation:

3.98371685

Answer:

I deposit $500 in my bank from my check this week. I have to withdraw $550 from my bank to pay my medical bills. I am short -55/55 dollars so I wait to pay my medical bills.

I owe $60 to my school for damage on a school laptop. I only have $5 so I am 55 dollars short.

I withdraw $2,000 from my bank to deposit $1950 a week later. I want to deposit the same amount of money I put last week. I am short 55 dollars.

Step-by-step explanation:

I put different scenarios because I didn't know if any of them were good enough.

Answer:

Helen is correct and Don is wrong

Step-by-step explanation:

Halen wrote the prodect 0.4 for the problem .5×.8. Don says that is not correct since when you multiply tenths by tenths the product will be in the hundreths. Is Don right?

.5 × .8 = 0.4

Helen is correct

Don is wrong because the zero(0) at the end of decimals are usually ignored

Such as: 0.10 ; it is usually written as 0.1

Same thing goes for 0.40 which is written as 0.4

Therefore, Helen is correct and Don is wrong

Answer:

25, 36, 49

Step-by-step explanation:

4 - 1 = 3

9 - 4 = 5

16 - 9 = 7

25 - 16 = 9

36 - 25 = 11

49 - 36 = 13

It goes up by odd numbers

Step-by-step explanation:

As we can see it is a parallelogram so here the diagonals bisect so

6y + 1 = 4y + 9

6y - 4y = 9 - 1

2y = 8

y = 8 / 2

y = 4

2x - 5 =x + 7

2x + x = 7 + 5

3x = 12

x = 12 / 3

x = 4

Hope it will help :)

Answer:

X = 1 , 2

Y = -1 , 2

Z = -2 , -1

Answer:

x= 7

Step-by-step explanation:

Theorem:  The sum of the angles of a triangle is 180

Memorize that theorem

8x - 9 + 63 + 70 = 180

8x + 124 = 180

8x = 56

x= 7

Answer: See explanation

Step-by-step explanation:

The number of comedy films will be:

= 6/(6+8+1) × 135

= 6/15 × 135

= 54 comedy films

The number of action films will be:

= 8/(6+8+1) × 135

= 8/15 × 135

= 72 action films

The number of horror films will be:

= 1/(6+8+1) × 135

= 1/15 × 135

= 9 horror films

Answer

[tex]\frac{573}{400}[/tex]

step-by-step explanation:

[tex]\frac{1.4325}{1}[/tex] ×  [tex]\frac{10000}{10000}[/tex]  =  [tex]\frac{14325}{10000}[/tex]

Simplify

[tex]\frac{14325}{10000}[/tex] ÷[tex]\frac{25}{25}[/tex] = [tex]\frac{573}{400}[/tex]

Answer: i BELIEVE YOUR ANSWER IS

.....  

B

Step-by-step explanation:

Illustrations in reverce order

Explanations:

6. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

You can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes, so you figure out what you want to put in the blank, but make sure it is not a numerical value. Not even ZERO can be plased there.

_______________________________________________

5. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 4[/tex]

You can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

4. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 3\frac{1}{2}[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midine.

_______________________________________________

3. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow \frac{1}{2}[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

2. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

1. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\pi}{1} \\ Amplitude \hookrightarrow N/A[/tex]

Again, you can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period.

I am delighted to assist you at any time.

*I also apologise for the sixth photograph not being present [exercise 1]. The system ALL OF A SUDDEN no longer allows me to display more than five photographs. You will have to see the graph somewhere elce.

Answer:

No

Step-by-step explanation:

7 squared + 10 squared = 149

13 squared = 169

As you can see these two products are not equal. They have to be equal to be a right triangle.

So this triangle is not a right triangle.

Hope that helped you and have a great day!

Answer:

No it is not.

Step-by-step explanation:

Let h = 13, p = 10 and b =7

Using pythagoras theorem,

h² = p² + b²

13² = 10² + 7²

169 = 100 + 49

169 = 149

This is false so the triangle is not a right angled triangle.

Answer:

0.75

Step-by-step explanation: