Answer:
Following are the program to this question:
import java.util.*;//import package for user input
class Interest //defining class Interest
{
static double rate_of_interest = 5.00;//defining static double varaibale
public static double Invest_value()//defining method Invest_value
{
double invest;//defining double variable invest
Scanner inc = new Scanner(System.in);//creating Scanner class object
System.out.print("Enter investment value: ");
invest = inc.nextDouble();//input value in invest variable
return invest;//return invest value
}
public static double calculated_Amount(double invest)//defining method calculated_Amount that accept parameter
{
double amount;//defining double variable
amount = invest+ (invest * (rate_of_interest/100));//use amount to calculat 5 % of invest value
return amount;//return amount value
}
public static void main(String[] as)//defining main method
{
double investment_value;//defining double variable
investment_value= Invest_value();//use investment_value to hold method Invest_value value
System.out.println("The 5% of the invest value: "+ calculated_Amount(investment_value));//use print method to print calculated_Amount value
}
}
Output:
Enter investment value: 3000
The 5% of the invest value: 3150.0
Explanation:
In the above program a class "Interest", is defined inside the class a static double variable "rate_of_interest" is declared that store a double value, in the next step, two methods "Invest_value and calculated_Amount" is declared.
In the "Invest_value" method, scanner class object is created for input value in the "invest" variable and the "calculated_Amount" accepts an "invest" value in its parameter and calculate its 5% and store its value in the "amount" variable.
Inside the main method, the "investment_value" is declared that holds the "Invest_value" method value and pass the value in the "investment_value" variable in the "calculated_Amount" method and prints its return value.
Explain why it is not necessary to create an inbound rule on the internal 192.168.12.10 Windows server so that it can receive the response (ICMP echo reply) from the internal 192.168.12.11 Windows server.
Answer:
The file and printer sharing (Echo Request - ICMPv4-In) rule option should be listed for all profile.
Explanation:
The main reason why it is not compulsory or obligatory to design an inbound rule on the internal 192.168.12.10 Windows server in other to be able to accept the response (ICMP echo reply) generated from the internal 192.168.12.11 Windows server is that the file and printer sharing (Echo Request - ICMPv4-In) rule option or alternative needed to be listed for all profile.
Inbound rules filter or sieve traffic advancing from the network to the local computer based on the filtering conditions set out in the rule.
Consider a system consisting of m resources of the same type, being shared by n processes. Resources can be requested and released by processes only one at a time. Show that the system is deadlock free if the following two conditions hold:__________.
A. The maximum need of each process is between 1 and m resources
B. The sum of all maximum needs is less than m+n.
Answer:
Explanation:
The system will be deadlock free if the below two conditions holds :
Proof below:
Suppose N = Summation of all Need(i), A = Addition of all Allocation(i), M = Addition of all Max(i). Use contradiction to prove.
Suppose this system isn't deadlock free. If a deadlock state exists, then A = m due to the fact that there's only one kind of resource and resources can be requested and released only one at a time.
Condition B, N + A equals M < m + n. Equals N + m < m + n. And we get N < n. It means that at least one process i that Need(i) = 0.
Condition A, Pi can let out at least 1 resource. So there will be n-1 processes sharing m resources now, Condition a and b still hold. In respect to the argument, No process will wait forever or permanently, so there's no deadlock.
A large population of ALOHA users manages to generate 50 requests/sec, including both originals and retransmissions. Time is slotted in units of 40 msec.
Required:
a. What is the chance of success on the first attempt?
b. What is the probability of exactly k collisions and then a success?
c. What is the expected number of transmission attempts needed?
Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt = [tex]e^{-G}G^k[/tex] but k = 0, therefore Probability that there is success on the first attempt = [tex]e^{-G}=e^{-2}=0.135[/tex]
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = [tex][1-e^{-G}]^k=[1-0.135]^k=0.865^k[/tex]
P(success in k+1 attempt) = [tex]e^{-G}=e^{-2}=0.135[/tex]
Probability of exactly k collisions and then a success = [tex]0.865^k0.135[/tex]
c) Expected number of transmission attempts needed = probability of success in k transmission = [tex]e^{G}=e^{2}=7.389[/tex]
A printer is connected locally on Computer1 and is shared on the network. Computer2 installs the shared printer and connects to it. Computer1 considers the printer to be a(n) ________________ printer, and Computer2 considers the printer to be a(n) ________________ printer.
Answer:
A printer is connected locally on Computer1 and is shared on the network. Computer2 installs the shared printer and connects to it. Computer1 considers the printer to be a(n) _____local___________ printer, and Computer2 considers the printer to be a(n) _____network___________ printer.
Explanation:
Any printer installed directly to Computer 1 is a local printer. If this printer is then shared with computers 2 and 3 in a particular networked environment, it becomes a shared printer. For these other computers 2 and 3, the shared printer is a network printer, because it is not locally installed in each of them. There may be some features which network computers cannot use on a shared printer, especially if the printer can scan documents.
vSphere Client is used to install and operate the guest OS. true or false
Answer:
True
Explanation:
A guest Operating System (OS) is a secondary OS to the main installed OS which is the host Operating System (OS). Guest OS can either be a part of a partition or a Virtual Machine (VM). This guest OS is used as a substitute to the host OS.
vSphere Web Client can be installed by using a CD-ROM, DVD or ISO image which has the installation image to make a Virtual Machine (VM) functional.
"The ______ code of a rootkit gets the rootkit installation started and can be activated by clicking on a link to a malicious Web site in an email or opening an infected PDF file."
Answer:
Dropper.
Explanation:
A rootkit can be defined as a collection of hidden malicious computer software applications that gives a hacker, attacker or threat actor unauthorized access to parts of a computer and installed software. Some examples of rootkits are trojan, virus, worm etc.
The dropper code of a rootkit gets the rootkit installation started and can be activated by clicking on a link to a malicious website in an email or opening an infected PDF file such as phishing.
Hence, the dropper code of a rootkit launches and installs the loader program and eventually deletes itself, so it becomes hidden and not be noticed by the owner of the computer.
A rootkit can affect the performance of a computer negatively causing it to run slowly.
g Write a program that asks for the weight of a package and the distance it is to be shipped. This information should be passed to a calculateCharge function that computes and returns the shipping charge to be displayed . The main function should loop to handle multiple packages until a weight of 0 is entered.
Answer:
I am writing a C++ program:
#include <iostream> //to use input output functions
#include<iomanip> // to format the output
using namespace std; // to identify objects like cin cout
void calculateCharge(double weight, double distance); // function prototype
int main(){ //start of main() function body
double w = 0.0, t = 0.0; // w variable is for weight and t is for total
unsigned int d = 0; // d variable is to hold the value of distance
calculateCharge(w, d); } //calls calculateCharge method by passing weight and distance values to this method
void calculateCharge(double weight, double distance){ //method that takes weight and distance as parameters and compute the shipping charge
double charge = 0.0; //to store the value of shipping charges
do { // do while loop to handle multiple packages until a weight of 0 is entered
cout << "Enter weight: " << endl; //prompts user to enter weight
cin >> weight; //reads the input weight value
if (weight == 0){ // if the value of weight is equal to 0
break; } // the loop breaks if value of weight is 0
cout << "Enter distance: " << endl; // if value of weight is not zero then the program precedes by prompting user to enter the value of distance
cin >> distance; //reads the input distance value
cout << fixed << setprecision(2) << endl; //set the precision to 2 means the sets the number of digits of an output to 2 decimal places
if(weight <= 2) //if the value of weight is less than or equals to 2
charge = (distance/500) * 3.10; //compute the charge by this formula
else if(weight > 2 && weight <= 6) //if weight is over 2 kg but not more than 6 kg
charge = (distance/500) * 4.20; //charge is computed by multiplying value of distance to that of weight and if distance is greater than 500 then it is divided by 500 first
else if(weight > 6 && weight <= 10) // if weight is over 6 kg but not more than 10 kg
charge = (distance/500) * 5.30; //compute shipping charges by this formula
else //if weight is over 10 kg
charge = (distance/500) * 6.40; // compute shipping charge by multiplying value of distance to that of 6.40 weight value and if distance is greater than 500 then distance is divided by 500 first
cout << "Shipping charges: $" << charge << "\n"; //display the computed shipping charge
} while (weight != 0); //the loop continues to execute until weight 0 is entered
}
Explanation:
The program is explained in the comments mentioned above. The program has a main() function that declares variable for weight, distance and total and then calls calculateCharge() method passing weight and dsitance in order to compute and return the shipping charge.
In calculateCharge() the user is prompted to enter the values for weight and distance. Then the based on the value of weight , the shipping charge is computed. Shipping charge is computed by multiplying the weight with distance. The distance is assumed to be 500 but if the distance entered by user exceeds 500 then the distance value is divided by 500 and then multiplied by the specified weight (according to if or else if conditions) in order to compute shipping charge. The program has a do while loop that keeps taking input from user until the user enters 0 as the value of weight.
The screenshot of the program and its output is attached.
1. Two TCP entities communicate across a reliable network. Let the normalized time to transmit a fixed length segment equal 1. Assume that the end-to-end propagation delay is 3 and that it takes 2 to deliver data from a received segment to the transport user. The receiver initially grants a credit of 7 segments. The receiver uses a conservative flow control policy and updates its credit allocation at every opportunity. What is the maximum achievable throughput
Answer:
The answer is "0.77"
Explanation:
The fixed-length segment value = 1
The propagation time of one end to another end is = 3
The Transfer power to move the consumer from the obtained segment = 2
The second last sender assigns a loan = 7 segments
The overall transmission time = 3+2+3 = 8
The maximum throughput value is:
[tex]\to \frac{7}{(1 + 8)}\\\\ \to \frac{7}{9}\\\\\to 0.77[/tex]
Similar to Wi-Fi, ____ is designed to provide internet access to fixed locations (sometimes called hot zones), but the coverage is significantly larger
Answer:
WiMAX.
Explanation:
WiMAX is an acronym for Worldwide Interoperability for Microwave Access, it is a wireless communications which is primarily based on the IEEE 802.16 standards for creating Metropolitan Area Network (MAN) for the internet users.
Similar to Wi-Fi, WiMAX is designed to provide internet access to fixed locations (sometimes called hot zones), but the coverage is significantly larger.
WiMAX is capable of covering large metropolitan distance of several kilometers while Wi-Fi covers just a local (short) area measured in meters.
Generally, WiMAX was invented by the WiMAX forum and is a telecommunications standard protocol that provides fixed and fully mobile internet access services over a wide range.
A systems administrator wants to replace the process of using a CRL to verify certificate validity. Frequent downloads are becoming problematic. Which of the following would BEST suit the administrators needs?
A. OCSP
B. CSR
C. Key escrow
D. CA
Answer:
A. OCSP
Explanation:
Online Certificate Status Protocol (OCSP) is an Internet Protocol that is used as an alternative for CRL and is used to obtain the revocation status of a digital certificate.
A certificate revocation list (CRL) is a set of digital certificates that have been rendered invalid/revoked by the Certificate Authority (CA) because they can no longer be trusted.
Because an OCSP response uses less data than a CRL, it would be best suited to the administrator's needs.
Start with the following Python code. alphabet = "abcdefghijklmnopqrstuvwxyz" test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"] test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"] # From Section 11.2 of: # Downey, A. (2015). Think Python: How to think like a computer scientist. Needham, Massachusetts: Green Tree Press. def histogram(s): d = dict() for c in s: if c not in d: d[c] = 1 else: d[c] += 1 return d Copy the code above into your program but write all the other code for this assignment yourself. Do not copy any code from another source. Part 1 Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False. Implement has_duplicates by creating a histogram using the histogram function above. Do not use any of the implementations of has_duplicates that are given in your textbook. Instead, your implementation should use the counts in the histogram to decide if there are any duplicates. Write a loop over the strings in the provided test_dups list. Print each string in the list and whether or not it has any duplicates based on the return value of has_duplicates for that string. For example, the output for "aaa" and "abc" would be the following. aaa has duplicates abc has no duplicates Print a line like one of the above for each of the strings in test_dups. Part 2 Write a function called missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that are not in the argument string. The letters in the returned string should be in alphabetical order. Your implementation should use a histogram from the histogram function. It should also use the global variable alphabet. It should use this global variable directly, not through an argument or a local copy. It should loop over the letters in alphabet to determine which are missing from the input parameter. The function missing_letters should combine the list of missing letters into a string and return that string. Write a loop over the strings in list test_miss and call missing_letters with each string. Print a line for each string listing the missing letters. For example, for the string "aaa", the output should be the following. aaa is missing letters bcdefghijklmnopqrstuvwxyz If the string has all the letters in alphabet, the output should say it uses all the letters. For example, the output for the string alphabet itself would be the following. abcdefghijklmnopqrstuvwxyz uses all the letters Print a line like one of the above for each of the strings in test_miss. Submit your Python program. It should include the following. The provided code for alphabet, test_dups, test_miss, and histogram. Your implementation of the has_duplicates function. A loop that outputs duplicate information for each string in test_dups. Your implementation of the missing_letters function. A loop that outputs missing letters for each string in test_miss. Also submit the output from running your program. Your submission will be assessed using the following Aspects. Does the program include a function called has_duplicates that takes a string parameter and returns a boolean? Does the has_duplicates function call the histogram function? Does the program include a loop over the strings in test_dups that calls has_duplicate on each string? Does the program correctly identify whether each string in test_dups has duplicates? Does the program include a function called missing_letters that takes a string parameter and returns a string parameter? Does the missing_letters function call the histogram function? Does the missing_letters function use the alphabet global variable directly? Does the program include a loop over the strings in test_miss that calls missing_letters on each string? Does the program correctly identify the missing letters for each string in test_miss, including each string that "uses all the letters"?
Answer:
alphabet = "abcdefghijklmnopqrstuvwxyz"
test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]
test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]
# From Section 11.2 of: # Downey, A. (2015). Think Python: How to think like a computer scientist. Needham, Massachusetts: Green Tree Press.
def histogram(s):
d = dict()
for c in s:
if c not in d:
d[c] = 1
else:
d[c] += 1
return d
#Part 1 Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.
def has_duplicates(stringP):
dic = histogram(stringP)
for key,value in dic.items():
if value>1:
return True
return False
# Implement has_duplicates by creating a histogram using the histogram function above. Write a loop over the strings in the provided test_dups list.
# Print each string in the list and whether or not it has any duplicates based on the return value of has_duplicates for that string.
# For example, the output for "aaa" and "abc" would be the following. aaa has duplicates abc has no duplicates Print a line like one of the above for each of the strings in test_dups.
print("***Implementation of has_duplicates fuction***")
for sTr in test_dups:
if has_duplicates(sTr):
print(sTr+": has duplicates")
else:
print(sTr+": has no duplicates")
#Part 2 Write a function called missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that are not in the argument string.
#The letters in the returned string should be in alphabetical order. Your implementation should use a histogram from the histogram function. It should also use the global variable alphabet.
#It should use this global variable directly, not through an argument or a local copy. It should loop over the letters in alphabet to determine which are missing from the input parameter.
#The function missing_letters should combine the list of missing letters into a string and return that string.
def missing_letters(sTr):
missingLettersList = []
dic = histogram(sTr)
for l in alphabet:
if l not in dic:
missingLettersList.append(l)
missingLettersList.sort()
return "".join(missingLettersList)
#Write a loop over the strings in list test_miss and call missing_letters with each string. Print a line for each string listing the missing letters.
#For example, for the string "aaa", the output should be the following. aaa is missing letters bcdefghijklmnopqrstuvwxyz
#If the string has all the letters in alphabet, the output should say it uses all the letters.
#For example, the output for the string alphabet itself would be the following. abcdefghijklmnopqrstuvwxyz uses all the letters
#Print a line like one of the above for each of the strings in test_miss.
print("\n***Implementation of missing_letters fuction***")
for lTm in test_miss:
sTr = missing_letters(lTm.replace(" ",""))
if sTr!="":
print(lTm+" is missing letters "+sTr)
else:
print(lTm +" uses all the letters")
Describe in detail how TCP packets flow in the case of TCP handoff, along with the information on source and destination addresses in the various headers.
Answer:
Following are the answer to this question:
Explanation:
There will be several ways to provide it, although it is simpler to let another front side Will work out a three-way handshake or transfer packages to there with a Server chosen. Its application responds TCP packets with both the destination node of the front end.
The very first packet was sent to a computer as an option. Mention, even so, that perhaps the end of the queue end remains in the loop in this scenario. Rather than obtaining this information from the front end like in the primary healthcare services, you have the advantage of this capability: its selected server helps to generate TCP state.
#Write a function called "in_parentheses" that accepts a
#single argument, a string representing a sentence that
#contains some words in parentheses. Your function should
#return the contents of the parentheses.
#
#For example:
#
# in_parentheses("This is a sentence (words!)") -> "words!"
#
#If no text appears in parentheses, return an empty string.
#Note that there are several edge cases introduced by this:
#all of the following function calls would return an empty
#string:
#
# in_parentheses("No parentheses")
# in_parentheses("Open ( only")
# in_parentheses("Closed ) only")
# in_parentheses("Closed ) before ( open")
#
#You may assume, however, that there will not be multiple
#open or closed parentheses.
#Write your function here!
def in_parentheses(a_string):
import re
regex = re.compile(".*?\((.*?)\)")
result = re.findall(regex, a_string)
return(result)
#Below are some lines of code that will test your function.
#You can change the value of the variable(s) to test your
#function with different inputs.
#
#If your function works correctly, this will originally
#print (including the blank lines):
#words!
#
#as he is doing right now
#
#
#!
print(in_parentheses("This is a sentence (words!)."))
print(in_parentheses("No parentheses here!"))
print(in_parentheses("David tends to use parentheses a lot (as he is doing right now). It tends to be quite annoying."))
print(in_parentheses("Open ( only"))
print(in_parentheses("Closed ) only"))
print(in_parentheses("Closed ) before ( open"))
print(in_parentheses("That's a lot of test cases(!)"))
Answer:
import regex as re
def in_parentheses(a_string):
regeX = re.compile(".*?\((.*?)\)")
result = re.findall(regeX, a_string)
return str(result).replace("[","").replace("]","")
print("test 1: "+in_parentheses("Open ( only"))
print("test 2: "+in_parentheses("This is a sentence (words!)."))
Lily is in her first year of undergraduate coursework and has not yet declared a major. She has attended a lot of career fairs and undergraduate major "open house" events to investigate her options. Marcia's theory of identity status suggests that the dimension Lily is most concerned with is the_____of 1 dimension.
Answer:
exploration
Explanation:
According to Marcia's theory of identity, the status suggests that the dimension Lily is most concerned with is the exploration dimension.
James E. Marcia who came up with the Marcia's theory of identity is a clinical and developmental psychologist. He also once taught at Simon Fraser University which is located in British Columbia, Canada and also in the State University of New York at Buffalo in Upstate, New York City.
James E. Marcia is also very much involved in clinical private practice, community consultation, clinical psychology supervision, and also in international clinical-developmental research and teaching.
A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the attenuation in decibels?
Answer:
[tex]Attenuation = 0.458\ db[/tex]
Explanation:
Given
Power at point A = 100W
Power at point B = 90W
Required
Determine the attenuation in decibels
Attenuation is calculated using the following formula
[tex]Attenuation = 10Log_{10}\frac{P_s}{P_d}[/tex]
Where [tex]P_s = Power\ Inpu[/tex]t and [tex]P_d = Power\ outpu[/tex]t
[tex]P_s = 100W[/tex]
[tex]P_d = 90W[/tex]
Substitute these values in the given formula
[tex]Attenuation = 10Log_{10}\frac{P_s}{P_d}[/tex]
[tex]Attenuation = 10Log_{10}\frac{100}{90}[/tex]
[tex]Attenuation = 10 * 0.04575749056[/tex]
[tex]Attenuation = 0.4575749056[/tex]
[tex]Attenuation = 0.458\ db[/tex] (Approximated)
Which of the following statements represents the number of columns in a regular two-dimensional array named values?
A) values[0].length
B) values.length
C) values.length)
D) values[0].length0
E) values.getColumnLength0)
Answer:
(a) values[0].length
Explanation:
In programming languages such as Java, an array is a collection of data of the same type. For example, a and b below are an example of an array.
a = {5, 6, 7, 9}
b = {{2,3,4}, {3,5,4}, {6,8,5}, {1,4,6}}
But while a is a one-dimensional array, b is a regular two-dimensional array. A two-dimensional array is typically an array of one-dimensional arrays.
Now, a few thing to note about a two-dimensional array:
(i) The number of rows in a 2-dimensional array is given by;
arrayname.length
For example, to get the number of rows in array b above, we simply write;
b.length which will give 4
(ii) The number of columns in a 2-dimensional array is given by;
arrayname[0].length
This is with an assumption that all rows have same number of columns.
To get the number of columns in array b above, we simply write;
b[0].length which will give 3
Therefore, for a regular two-dimensional array named values, the number of columns is represented by: values[0].length
If the current date is Monday, February 26, 2017, what will be displayed by the alert dialog box after the following code executes? var thisDay = new Date(); alert(thisDay.toDateString());
Answer:
Mon Feb 26 2017
Explanation:
Since the current date is considered as Monday, February 26, 2017, thisDay will be set to that value.
The toDateString() method returns the first three letters of the name of the day (The first letter is capitalized), the first three letters of the name of the month (The first letter is capitalized), the day of the month as an integer, and the year as an integer (There are spaces between all)
Which are true of the Transmission Control Protocol (TCP)? Multiple answers: You can select more than one option A it supports full duplex communication B it has graceful connection shutdown C its connections are logical D its data is sent as a discrete messages E it is an end-to-end protocol
Answer:
A, B, C, D and E
Explanation:
Transmission Control protocol (TCP) is a protocol that describes how connections are made and maintained between devices in a network which will help applications in these devices communicate and transmit data.
The following are some of the features of TCP:
i. It supports full duplex communication: In other words, TCP allows for concurrent transmission of data in both directions.
ii. it has a graceful connection shutdown: TCP allows for graceful termination and closing of connection. This means that when there is no more data to be sent by any of the communicating devices, rather than just close connection from its end, it first informs the other device about its completion and asks if it's safe to close the connection. From there, if the other device then says it doesn't have any data to send either, they then reach a consensus to close the connection at their respective ends.
iii. Its connections are logical: TCP makes use of the reliability and flow control mechanisms which require that it initialize and maintain some status information for each stream of data. This status information containing sockets, sequence numbers and window sizes is called a logical connection.
iv. Data is sent as discrete messages: Like other discrete messages, the IP treats the data in TCP as discrete messages by placing them into the IP datagram and transmitting to the target host.
v. It is an end-to-end protocol: TCP governs the way data is transmitted between two devices at their respective ends to ensure reliable delivery. In other words, it is responsible for the transmission of data from a source to one or more destinations. It sits on the operating system of the source and also on the operating system(s) of the destination(s).
Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in the file. You function should be case-insensitive so 'Hello' and 'hello' are treated as the same word. You should ignore words of length 2 or less. Also, be sure to remove punctuation and digits.
>>>wordcount('frankenstein.txt')
artifice 1
resting 2
compact 1
service 3
Answer:
I am writing a Python program. Let me know if you want the program in some other programming language.
import string #to use string related functions
def wordcount(filename): # function that takes a text file name as parameter and returns the number of occurrences of every word in file
file = open(filename, "r") # open the file in read mode
wc = dict() # creates a dictionary
for sentence in file: # loop through each line of the file
sentence = sentence.strip() #returns the text, removing empty spaces
sentence=sentence.lower() #converts each line to lowercase to avoid case sensitivity
sentence = sentence.translate(sentence.maketrans("", "", string.punctuation)) #removes punctuation from every line of the text file
words = sentence.split(" ") # split the lines into a list of words
for word in words: #loops through each word of the file
if len(word)>2: #checks if the length of the word is greater than 2
if word in wc: # if the word is already in dictionary
wc[word] = wc[word] + 1 #if the word is already present in dict wc then add 1 to the count of that word
else: #if the word is not already present
wc[word] = 1 # word is added to the wc dict and assign 1 to the count of that word
for w in list(wc.keys()): #prints the list of words and their number of occurrences
print(w, wc[w]) #prints word: occurrences in key:value format of dict
wordcount("file.txt") #calls wordcount method and passes name of the file to that method
Explanation:
The program has a function wordcount that takes the name of a text file (filename) as parameter.
open() method is used to open the file in read mode. "r" represents the mode and it means read mode. Then a dictionary is created and named as wc. The first for loop, iterates through each line (sentence) of the text file. strip() method is used to remove extra empty spaces or new line character from each sentence of the file, then each sentence is converted to lower case using lower() method to avoid case sensitivity. Now the words "hello" and "Hello" are treated as the same word.
sentence = sentence.translate(sentence.maketrans("", "", string.punctuation)) statement uses two methods i.e. maketrans() and translate(). maketrans() specifies the punctuation characters that are to be deleted from the sentences and returns a translation table. translate() method uses the table that maketrans() returns in order to replace a character to its mapped character and returns the lines of text file after performing these translations.
Next the split() method is used to break these sentences into a list of words. Second for loop iterates through each word of the text file. As its given to ignore words of length 2 or less, so an IF statement is used to check if the length of word is greater than 2. If this statement evaluates to true then next statement: if word in wc: is executed which checks if the word is already present in dictionary. If this statement evaluates to true then 1 is added to the count of that word. If the word is not already present then the word is added to the wc dictionary and 1 s assigned to the count of that word.
Next the words along with their occurrences is printed. The program and its output are attached as screenshot. Since the frankenstein.txt' is not provided so I am using my own text file.
Do Exercise 6.4 from your textbook using recursion and the is_divisible function from Section 6.4. Your program may assume that both arguments to is_power are positive integers. Note that the only positive integer that is a power of "1" is "1" itself. After writing your is_power function, include the following test cases in your script to exercise the function and print the results: print("is_power(10, 2) returns: ", is_power(10, 2)) print("is_power(27, 3) returns: ", is_power(27, 3)) print("is_power(1, 1) returns: ", is_power(1, 1)) print("is_power(10, 1) returns: ", is_power(10, 1)) print("is_power(3, 3) returns: ", is_power(3, 3))
Answer:
Here is the python method:
def is_power(n1, n2): # function that takes two positive integers n1 and n2 as arguments
if(not n1>0 and not n2>0): #if n1 and n2 are not positive integers
print("The number is not a positive integer so:") # print this message if n1 and n2 are negative
return None # returns none when value of n1 and n2 is negative.
elif n1 == n2: #first base case: if both the numbers are equal
return True #returns True if n1=n2
elif n2==1: #second base case: if the value of n2 is equal to 1
return False #returns False if n2==1
else: #recursive step
return is_divisible(n1, n2) and is_power(n1/n2, n2) #call divisible method and is_power method recursively to determine if the number is the power of another
Explanation:
Here is the complete program.
def is_divisible(a, b):
if a % b == 0:
return True
else:
return False
def is_power(n1, n2):
if(not n1>0 and not n2>0):
print("The number is not a positive integer so:")
return None
elif n1 == n2:
return True
elif n2==1:
return False
else:
return is_divisible(n1, n2) and is_power(n1/n2, n2)
print("is_power(10, 2) returns: ", is_power(10, 2))
print("is_power(27, 3) returns: ", is_power(27, 3))
print("is_power(1, 1) returns: ", is_power(1, 1))
print("is_power(10, 1) returns: ", is_power(10, 1))
print("is_power(3, 3) returns: ", is_power(3, 3))
print("is_power(-10, -1) returns: ", is_power(-10, -1))
The first method is is_divisible method that takes two numbers a and b as arguments. It checks whether a number a is completely divisible by number b. The % modulo operator is used to find the remainder of the division. If the remainder of the division is 0 it means that the number a is completely divisible by b otherwise it is not completely divisible. The method returns True if the result of a%b is 0 otherwise returns False.
The second method is is_power() that takes two numbers n1 and n2 as arguments. The if(not n1>0 and not n2>0) if statement checks if these numbers i.e. n1 and n2 are positive or not. If these numbers are not positive then the program prints the message: The number is not a positive integer so. After displaying this message the program returns None instead of True of False because of negative values of n1 and n2.
If the values of n1 and n2 are positive integers then the program checks its first base case: n1 == n2. Suppose the value of n1 = 1 and n2 =1 Then n1 is a power of n2 if both of them are equal. So this returns True if both n1 and n2 are equal.
Now the program checks its second base case n2 == 1. Lets say n1 is 10 and n2 is 1 Then the function returns False because there is no positive integer that is the power of 1 except 1 itself.
Now the recursive case return is_divisible(n1, n2) and is_power(n1/n2, n2) calls is_divisible() method and is_power method is called recursively in this statement. For example if n1 is 27 and n2 is 3 then this statement:
is_divisible(n1, n2) returns True because 27 is completely divisible by 3 i.e. 27 % 3 = 0
is_power(n1/n2,n2) is called. This method will be called recursively until the base condition is reached. You can see it has two arguments n1/n2 and n2. n1/n2 = 27/3 = 9 So this becomes is_power(9,3)
The base cases are checked. Now this else statement is again executed return is_divisible(n1, n2) and is_power(n1/n2, n2) as none of the above base cases is evaluated to true. when is_divisible() returns True as 9 is completely divisible by 3 i.e. 9%3 =0 and is_power returns (9/3,3) which is (3,3). So this becomes is_power(3,3)
Now as value of n1 becomes 3 and value of n2 becomes 3. So the first base case elif n1 == n2: condition now evaluates to true as 3=3. So it returns True. Hence the result of this statement print("is_power(10, 2) returns: ", is_power(10, 2)) is:
is_power(27, 3) returns: True
Following are the program to the given question:
Program Explanation:
Defining a method "is_divisible" that takes two variable "a,b" inside the parameter.Usinge the return keyword that modulas parameter value and checks its value equal to 0, and return its value.In the next step, another method "is_power" is declared that takes two parameter "a,b".Inside the method, a conditional statement is declared, in which three if block is used. Inside the two if block it checks "a, b" value that is "odd number" and return bool value that is "True, False".In the last, if block is used checks "is_power" method value, and use multiple print method to call and prints its value.Program:
def is_divisible(a, b):#defining a method is_divisible that takes two parameters
return a % b == 0#using return keyword that modulas parameter value and checks its value equal to 0
def is_power(a, b):#defining a method is_power that takes two parameters
if a == 1:#defining if block that checks a value equal to 1 or check odd number condition
return True#return value True
if b == 1:#defining if block that checks b value equal to 1 or check odd number condition
return False#return value False
if not is_divisible(a, b):#defining if block that check method is_divisible value
return False##return value False
return is_power(a/b, b)#using return keyword calls and return is_power method
print("is_power(10, 2) returns: ", is_power(10, 2))#using print method that calls is_power which accepts two parameter
print("is_power(27, 3) returns: ", is_power(27, 3))#using print method that calls is_power which accepts two parameter
print("is_power(1, 1) returns: ", is_power(1, 1))#using print method that calls is_power which accepts two parameter
print("is_power(10, 1) returns: ", is_power(10, 1))#using print method that calls is_power which accepts two parameter
print("is_power(3, 3) returns: ", is_power(3, 3))#using print method that calls is_power which accepts two parameter
Output:
Please find the attached file.
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The most widely used presentation software program is Microsoft PowerPoint. You can produce a professional and memorable presentation using this program if you plan ahead and follow important design guidelines. What text and background should you use in a darkened room
Answer:
Light text on a dark background
Explanation:
Microsoft PowerPoint is an application software in which the company ables to introduce themselves by making slides and presented to an audience in an easy and innovative way. In this, we can add pictures, sound, video by adding the different text, colors, backgrounds, etc
For memorable and professional presentations, the light text on a dark background is a best combination as it is easy to read and give the best view of the message you want to convey.
Oops, we made a mistake: we created a key "short" and gave it the value "tall", but we wanted to give it the value "long" instead. Write the line of code that will change the value associated with the key "short" to "long". Be consistent in whether you use single or double quotes to declare your strings: our autograder assumes you'll be consistent.
Answer:
Using java
//assuming that hashmap object name is ChangeMap
ChangeMap. replace("short", "long");
System.out.println("New HashMap: "
+ ChangeMap.toString());
Explanation:
From the above we have used the replace method to replace the value of the "short" key in the hashtable with "long" instead of the previous value "tall". We have used the printed the hashtable to the console using println and the ".toString()" method that we added to the function's parameter.
Create an application in Java that asks a user for a number of hours, days, weeks, and years. It then computes the equivalent number of minutes (ignoring leap years).
Answer:
//import the Scanner class
import java.util.Scanner;
//Begin class definition
public class NumberOfMinutes{
//Begin main method
public static void main(String []args){
//Create an object of the Scanner class
Scanner input = new Scanner(System.in);
//initialize a variable nm to hold the number of minutes
int nm = 0;
//Prompt the use to enter the number of hours
System.out.println("Please enter the number of hours");
//Receive the input using the Scanner object and
//Store the entered number of hours in a variable nh
int nh = input.nextInt();
//Prompt the user to enter the number of days
System.out.println("Please enter the number of days");
//Receive the input using the Scanner object and
//Store the entered number of days in a variable nd
int nd = input.nextInt();
//Prompt the user to enter the number of weeks
System.out.println("Please enter the number of weeks");
//Receive the input using the Scanner object and
//Store the entered number of weeks in variable nw
int nw = input.nextInt();
//Prompt the user to enter the number of years
System.out.println("Please enter the number of years");
//Receive the input using the Scanner object and
//Store the entered number of years in a variable ny
int ny = input.nextInt();
//Convert number of hours to minutes and
//add the result to the nm variable
nm += nh * 60;
//Convert number of days to minutes and
//add the result to the nm variable
nm += nd * 24 * 60;
//Convert number of weeks to minutes and
//add the result to the nm variable
nm += nw * 7 * 24 * 60;
//Convert number of years to minutes and
//add the result to the nm variable
nm += ny * 52 * 7 * 24 * 60;
//Display the number of minutes which is stored in nm
System.out.println("The number of minutes is " + nm);
} //End main method
} //End of class definition
Sample Output:Please enter the number of hours
>>12
Please enter the number of days
>>2
Please enter the number of weeks
>>4
Please enter the number of years
>>5
The number of minutes is 2664720
Explanation:
The code contains comments explaining every line of the program. Please go through the comments. The actual lines of executable code are written in bold face to distinguish them from comments.
A sample output has also been provided above. Also, a snapshot of the program file, showing the well-formatted code, has been attached to this response.
#Write a function called after_second that accepts two #arguments: a target string to search, and string to search #for. The function should return everything in the first #string *after* the *second* occurrence of the search term. #You can assume there will always be at least two #occurrences of the search term in the first string. # #For example: # after_second("11223344554321", "3") -> 44554321 # #The search term "3" appears at indices 4 and 5. So, this #returns everything from the index 6 to the end. # # after_second("heyyoheyhi!", "hey") -> hi! # #The search term "hey" appears at indices 0 and 5. The #search term itself is three characters. So, this returns #everything from the index 8 to the end. # #Hint: This may be more complicated than it looks! You'll #have to look at the length of the search string and #either modify the target string or take advantage of the #extra arguments you can pass to find(). #Write your function here!
Answer:
Following are the code to this question:
def after_second(s,sub):#defining a method a fter_second
first = s.find(sub)#defining a variable first that hold method find value
if first != -1:#defining if block to check first variable value not equal to -1 using slicing
s = s[len(sub)+first:]#defining s variable to calculate sub parameter length of parameter and use slicing
second = s.find(sub)#defining second variable to calculate find method value
if second != -1:#defining if block to calculate second variable slicing
return s[len(sub)+second:]#return s variable value
print(after_second("heyyoheyhi","hey"))#defining print method to call after_second method
print(after_second("11223344554321","3"))#defining print method to call after_second method
Output:
hi
44554321
Explanation:
In the above python code a method "after_second" is declared, that accepts two-variable "s, and sub" as the parameter inside the method a first variable is declared that uses the inbuilt method "find" to find the value and stores it value. In the next step, two if blocks are used, in which both if blocks use the slicing to checks its value is not equal to "-1".
In the first, if block the first variable is declared that uses the s variable to calculate subparameter length by using slicing and defines the second variable that finds its value and stores its value. In the next, if block the s variable is used to return its calculated value, and at the end of the print, the method is used to call the method by passing parameter value and prints its return value.Some network applications defer configuration until a service is needed. For example, a computer can wait until a user attempts to print a document before the software searches for available printers.
What is the chief advantage of deferred configuration?
Answer:
The drivers wont be loaded and the deamons will not be running in the background unnecessarily, that makes the processes to run more faster
Explanation:
The chief advantage of deferred configuration or the advantage when some network applications defer configuration until a service is needed is that the drivers won't be loaded and the deamons will not be running in the background unnecessarily or when idle, that makes the processes to run more faster.
Network configuration is the activity which involves setting up a network's controls, flow and operation to assist the network communication of an organization or network owner.
When Windows deletes the driver package and driver files, in what situation might it not delete driver files used by the device that is being uninstalled?
Answer:
when there is no junk
Explanation:
If you choose the checkbox next to “Delete the driver software from this device,” your computer will no longer contain the driver or any associated registry keys. Either method will prevent you from using the device until you reinstall the device driver.
What is situation deletes driver files used by the device?To connect and communicate with particular devices, a computer needs device drivers.
It may be taken out without any trouble. However, it also comes with the installers for your PC's drivers. You will need to go to the manufacturer's website to download them again if you accidentally delete them.
Therefore, No, unless your new driver is broken and corrupts data. Install the driver if it comes from a reliable source. It is not intended to. Having a backup system that keeps your data safe in case of issues is a good idea.
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#SPJ5
A__________provides an easier way for people to communicate with a computer than a graphical user interface (GUI).
Answer:
Natural language processing
Explanation:
NLP, because many people can use a device better when they can talk to it just like it is another person. Some systems that use an NLP are voice assistants such as Alexa and Siri.
How I to turn this ''loop while'' in ''loop for''?
var i = 0;
while (i < 20) {
var lineY = 20 + (i * 20);
line(0, lineY, 400, lineY);
i++;
}
Answer:
for (var i = 0; i <20; i++)
{
var lineY = 20 + (i * 20);
line(0, lineY, 400, lineY);
}
Explanation:
To turn the loop while to for loop, you start by considering the iterating variable i and its iterating operations which are;
var i = 0; while (i < 20) and i++;
Where var i = 0; is the initializing statement
(i < 20) is the conditional statement
i++ is the increment
The next is to combine these operations to a for loop; using the following syntax: for(initializing; condition; increment){}
This gives: for(var i = 0; i<20; i++)
Hence, the full code snippet is:
for (var i = 0; i <20; i++)
{
var lineY = 20 + (i * 20);
line(0, lineY, 400, lineY);
}
Boolean expressions control _________________ Select one: a. recursion b. conditional execution c. alternative execution d. all of the above
Answer:
Option D, all of the above, is the right answer.
Explanation:
A Boolean expression is an expression in Computer Science. It is employed in programming languages that create a Boolean value when it is evaluated. There may be a true or false Boolean value. These expressions correspond to propositional formularies in logic. In Boolean expression, the expression 3 > 5 is evaluated as false while 5 > 3 is evaluated as true
Boolean expressions control all of the above method execution and as such option d is correct.
What is Boolean expressions?A Boolean expression is known to be a kind of logical statement that is said to be one of the two options that is it can be TRUE or FALSE .
Conclusively, Note that Boolean expressions are used to compare two or more data of any type only if both parts of the expression have equal basic data type. Boolean expressions control recursion, conditional execution and alternative execution.
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function of network security
Answer:ffffffffffffgggggg
Explanation:vvvc