Write empirical formula

Answer:

Vapour pressure of the solution is 223.8mmHg

Explanation:

Based on Raoult's law, vapour pressure of a solution decreases related to the vapour pressure of the pure solvent following the equation:

[tex]P_{solution} = X_{solvent}P_{solvent}^0[/tex]

Where P is vapour pressure and X mole fraction of each related substance.

Vapour pressure of pure water is 233.8mmHg

To find Mole fraction of the solution you need to find moles of glycerin and moles of water, mole fraction of water will be:

[tex]\frac{n_{water}}{n_{water}+n_{glycerin}}[/tex]

Moles of water (Molar mass: 18.02g/mol):

125g × (1mol / 18.02g) = 6.937 moles water

Moles of glycerin (Molar mass: 92.09g/mol):

28.5g × (1mol / 92.09g/mol) = 0.309 moles glycerin

Thus, mole fraction of water, X, is:

[tex]\frac{6.937mol}{6.937mol+0.309mol}[/tex]

= 0.957

Replacing in Raoult's law:

[tex]P_{solution} = 0.957*233.8mmHg[/tex]

P = 223.8mm Hg

Answer:

The answer is option a. The evaporation of water from the skin

Explanation:

An endothermic reaction is any synthetic reaction that retains heat from its environment. The ingested energy gives the enactment energy to the reaction to happen.

No new bonds formed, no bonds broken in this example. water molecules go from liquid to vapour (gas ), intermolecular bond exist between polar (-OH) molecules and energy is required to break these bonds during the change from liquid to gas. So, it is endothermic .

Remaining three above examples are exothermic. combustion of gas releases energy(exothermic). burninig of the candle exothermic because the energy released from the oxygen into carbon dioxide and water.oxidation of iron also exothermic

Answer:

0.45 moles

Explanation:

The computation of the number of moles left in the cylinder is shown below:

As we know that

[tex]\frac{n1}{V1} = \frac{n2}{V2}[/tex]

we can say that

[tex]n2 = n1 \times \frac{V2}{V1}[/tex]

where,

n1 = 1.80 moles of gas

V2 = 12.0 L

And, the V1 = 48.0 L

Now placing these values to the above formula

So, the moles of gas in n2 left is

[tex]= 1.80 \times \frac{12.0\ L}{48.0\ L}[/tex]

= 0.45 moles

We simply applied the above formulas so that the n2 moles of gas could arrive

Answer:

[tex]6.022x10^{23}atoms \ Al[/tex]

Explanation:

Hello,

In this case, given the described concept regarding the Avogadro's number, we can easily notice that 27.0 g of aluminium foil has 6.022x10²³ atoms as shown below based on the mass-mole-particles relationship:

[tex]27.0gAl*\frac{1molAl}{27.0gAl} *\frac{6.022x10^{23}atoms \ Al}{1molAl} \\\\=6.022x10^{23}atoms \ Al[/tex]

Notice this is backed up by the fact that aluminium molar mass if 27.0 g/mol.

Best regards.

Answer:

B

Explanation:

It should be 2s² which means the answer is the configuration is missing an electron in the 2s orbital.

Answer:

B.

Explanation:

It should be 2s² which means the answer

is the configuration is missing an electron

in the 2s orbital.

Answer:

198.56g of GaCl3

Explanation:

We'll begin by calculating the number of mole HCl in 2.25 L of a 1.50 M solution of HCl. This is illustrated below:

Molarity of HCl = 1.50 M

Volume = 2.25 L

Mole of HCl =..?

Molarity = mole /Volume

1.5 = mole /2.25

Cross multiply

Mole = 1.5 x 2.25

Mole of HCl = 3.375 mole

Next, we shall determine the number of mole Gallium chloride, GaCl3 produced from the reaction. This is shown below:

2Ga + 6HCl —> 2GaCl3 + 3H2

From the balanced equation above,

6 moles of HCl reacted to produce 2 moles of GaCl3.

Therefore, 3.375 mole of HCl will react to produce = (3.375 x 2)/6 = 1.125 mole of GaCl3.

Therefore, 1.125 moles of GaCl3 were produced from the reaction.

Next, we shall convert 1.125 mole of GaCl3 to grams. This is illustrated below:

Molar mass of GaCl3 = 70 + (35.5x3) = 176.5g/mol

Mole of GaCl3 = 1.125 mole

Mass of GaCl3 =..?

Mole = mass /Molar mass

1.125 = mass of GaCl3 /176.5

Cross multiply

Mass of GaCl3 = 1.125 x 176.5

Mass of GaCl3 = 198.56g

Therefore, 198.56g of GaCl3 were produced from the reaction.

Answer:

5 degrees Celsius.

Explanation:

Temperature measures the average kinetic energy of  particles of the substances. Therefore a temperature of 41 Fahrenheit is the same as 5 degree Celsius

Temperature is used to measure degree or intensity of heat of a particular substance. Temperature is measured by an instrument called thermometer.

Temperature can be measured in degree celsius °c, Kelvin k or in Fahrenheit. Temperature is a physical quantity. Heat always flow from higher temperature source to lower temperature source.

We can convert these units of temperature into one another. The relationship between degree Celsius and  Fahrenheit can be expressed as:

°C={5(°F-32)}÷9

Substituting given values in above equation

°C= {5(41-32)}÷9

°C= 5°C

Therefore a temperature of 41 Fahrenheit is the same as 5 degree Celsius

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Answer:

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

Explanation:

Methanol is CH₃OH.  Oxygen is O₂.  A combustion produces CO₂ and H₂O.  Create an equation using this information and balance.

CH₃OH  +  O₂  ⇒  CO₂  +  H₂O

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

The balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is

CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

From the question,

We are to write a balanced equation for the combustion of liquid methanol in air.

The combustion of liquid methanol in air is the reaction between methanol (CH₃OH) and oxygen (O₂). The reaction yields carbon(IV) oxide and water.

Now, for the balanced equation for the combustion of liquid methanol in air

The balanced chemical equation is

CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

Hence, the balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

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Answer:

lithium is akali metal

Answer:

lithium is an alkali metal as it lies in group 1st in modern perodic table.

Answer:

As the reaction proceeds in the given voltaic cell, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. At the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

Explanation:

A voltaic or galvanic cell is an example of an electrochemical cell.

An electrochemical cell is a device that produces an electric current from chemical reactions occuring within it.

Electrochemical cells have two electrodes; the anode and the cathode. The anode is defined as the electrode where oxidation occurs while the cathode is the electrode where reduction occurs.

The voltaic cell uses two different metal electrodes each immersed in an electrolyte solution. The two electrodes are connected to each other by means of a wire which allows the flow of electrons from the anode to the cathode. The electrolytes are connected by means of a salt bridge which is a junction that connects the electrolytic solution in the anode and cathode compartment. The salt bridge usually consists of a strong electrolyte like NaCl, KCl, Na₂SO₄, etc.

The electrolyte in the salt bridge serves two purposes: it completes the circuit by providing a path for electron flow and it maintains electrical neutrality in both solutions by allowing ions to migrate between them.

As the reaction proceeds in the given voltaic cell above, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. Also, at the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

Answer:

The next part is 8.8

Explanation:

You're gonna subtract 31.3 by 22.5 which is 8.8

You're welcome :)

The value of q-cal is 142.8 J in the reaction of magnesium and hydrochloric acid in a different constant pressure calorimeter with a calorimeter constant of 12.75 J/degrees Celsius.

A calorimeter is a device that measures the amount of heat in a chemical or physical process.

To calculate the value of q-cal (heat absorbed or released by the calorimeter), we need to use the following equation:

q = C * ΔT

Where q is the heat absorbed or released by the calorimeter, C is the calorimeter constant, and ΔT is the change in temperature.

In this case, we know that the calorimeter constant is 12.75 J/degrees Celsius, the initial temperature is 22.5 degrees Celsius, and the final temperature is 33.7 degrees Celsius.

Therefore, we can calculate ΔT as:

ΔT = final temperature - initial temperature

ΔT = 33.7°C - 22.5°C

ΔT = 11.2°C

Substituting these values into the equation, we get:

q = C * ΔT

q = 12.75 J/°C * 11.2°C

q = 142.8 J

Therefore, the value of q-cal is 142.8 J.

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Your question seems incomplete, the probable complete question is:

Suppose you perform the reaction of magnesium and hydrochloric acid in a different constant pressure calorimeter with a calorimeter constant of 12.75 J/degrees Celsius. The initial temperature in the calorimeter is 22.5 degrees Celsius and the final temperature after the reaction is 33.7 degrees Celsius. What is the value of q-cal?

It carries at least one hydroxyl functional group ( i.e -OH ) bound to a saturated carbon atom.

Therefore the functional group present is -OH functional group.

Answer:

Carboxylic acid

Explanation:

Answer:

According to Le Chatelier's principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. ... If we add additional product to a system, the equilibrium will shift to the left, in order to produce more reactants.

Answer:

1. Not to have enough salt water on the foil

2.not cleaning the foil well to remove interfering materials

Answer:

none of these statements is true

according to the question E) None of these statements is true.

The concentration of a chemical substance expresses the amount of a substance present in a mixture. There are many different ways to express concentration. Chemists use the term solute to describe the substance of interest and the term solvent to describe the material in which the solute is dissolved

Quantitative units of concentration include molarity, molality, mass percentage, parts per thousand, parts per million, and parts per billion.

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Answer:

J

Explanation:

Answer:

The type of mixture whose components are seen through our naked eyes is known as heterogeneous mixture. it is a mixture of small constituent parts of substances.

for eg, mixture of sand and sugar.

hope it helps..

Answer:

I'd say elastic

Metallic atomic solids, forming metal objects, can pass electric currents through, need a lot of heat to melt, and since electricity can easily pass through, it's quite tough/impossible to find an insulating point.

Answer:

Conductors allow a flow of current or a charge of flow

I hope this helped! Please rate it the brainlist if possible, thanks

Answer:

THE MOLARITY OF THE SOLUTION IS 0.1039 MOL/DM3

Explanation:

Molarity is the number of moles of solute in a given solution,

Molarity in mol / dm3 = Molarity in g/dm3 / Molar mass

Mass = 15.2 g

Volume of solution = 2.5 l

Molar mass  of NaCl = (23 + 35.5) = 58.5 g/mol

First, we calculate the molarity in g/dm3

Molarity in g/dm3 = mass /volume

= 15.2 g * 1 L  / 2.5 L

=6.08 g /dm3

Hence, we will introduce the values and solve for molarity in mol/dm3

Molarity = 6.08 g/dm3/ 58.5 g/mol

Molarity = 0.1039 mol/dm3

The molarity of the solution is 0.1039 mol/dm3

Answer: CO2(g)+H2O(I) > H2CO3(Aq)

Explanation:

Got it right?

Answer:

Drill bits  

Explanation:

Gemstones such as diamonds are used in drill bits because of their hardness.

They are a 10 on the Mohs scale of hardness, which runs from 0 to 10.

Drill bits are produced from gemstones due to their hardness.

Gemstones are the name given to pieces of minerals  that can be cut and polished valuable accessories.

Gemstones such as diamonds are used in drill bits because of their hardness.

Thus, drill bits are produced using gemstones.

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Answer:

a. pH = 5.22

b. Acidic.

c. pH = 5.14

Explanation:

a. It is possible to find the pH of a buffer using Henderson-Hasselbalch equation (H-H equation):

pH = pKa + log₁₀ [A⁻] / [HA]

Where pKa is -log Ka (For acetic acid =  4.74), [A⁻] is molar concentration of conjugate base (Acetate salt) and [HA] concentration of the weak acid (Acetic acid).

Replacing:

pH = 4.74 + log₁₀ [0.600M] / [0.200M]

You use the concentration of the acetic acid and sodium acetate because you're adding equal volumes, doing the ratio of the species the same

b. As the solution has a pH lower that 7.0, it is considered as a acidic solution.

c. When you add HCl to the buffer, the reaction is:

CH₃COO⁻ + HCl → CH₃COOH + Cl⁻

Where acetate ion reacts with the acid producing acetic acid.

As you have 0.200L of the buffer, 0.100L are of the acetate ion and 0.100L of the acetic acid. Initial moles of both compounds and moles of HCl added are:

CH₃COO⁻: 0.100L ₓ (0.600mol / L) = 0.0600 moles

CH₃COOH: 0.100L ₓ (0.200mol / L) = 0.0200 moles

HCl: 3.0mL = 3x10⁻³L ₓ (0.034mol / L) =  0.00010 moles HCl

The moles added of HCl are the same moles you're consuming of acetate ion and producing of acetic acid. Thus, moles after the reaction are:

CH₃COO⁻: 0.0600 moles - 0.0001 moles = 0.0509 moles

CH₃COOH: 0.0200 moles + 0.0001 moles = 0.0201 moles

Replacing in H-H equation:

pH = 4.74 + log₁₀ [0.0509moles] / [0.0201moles]

(a) The pH of the solution is 5.22

(b) The solution is Acidic

(c) The pH of the resultant solution is 5.14

(a) The pH of a buffer can be calculated by using (H-H equation):

pH = pKa + log₁₀ [A⁻] / [HA]

Where pKa is -log Ka (for acetic acid =  4.74),

[A⁻] is the molar concentration of Acetate salt, and

[HA] concentration of the Acetic acid

According to the question:

pH = 4.74 + log₁₀ [0.600M] / [0.200M]

pH = 5.22

(b) The pH of the solution is lower than 7.0, therefore it is an acidic solution.

(c) After adding HCl to the buffer, the reaction is:

CH₃COO⁻ + HCl → CH₃COOH + Cl⁻

We have 0.200L of the buffer, 0.100L are of the acetate ion and 0.100L of the acetic acid.

The initial amount of compounds added are:

CH₃COO⁻: 0.100L ₓ (0.600mol / L) = 0.0600 moles

CH₃COOH: 0.100L ₓ (0.200mol / L) = 0.0200 moles

HCl: 3.0mL = 3x10⁻³L ₓ (0.034mol / L) =  0.00010 moles HCl

The HCl reacts with the same amount of acetate ion and produces acetic acid. Thus, moles after the reaction are:

CH₃COO⁻: 0.0600 moles - 0.0001 moles = 0.0509 moles

CH₃COOH: 0.0200 moles + 0.0001 moles = 0.0201 moles

From the H-H equation:

pH = 4.74 + log₁₀ [0.0509moles] / [0.0201moles]

pH = 5.14

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Answer:

a. 621.5 mL

b. 17.5 mL

c. 0.875 moles of salt

d. 0.022 M

Explanation:

3 moles of sodium hydroxide react to 1 mol of phosphoric acid in order to produce 1 mol of sodium phosphate and 3 moles of water. The reaction is:

3 NaOH + H₃PO₄  →  Na₃PO₄  +  3H₂O

a. Ratio is 1:3. We convert the mass of the acid, to moles:

4.568 g / 97.994 g/mol = 0.0466 moles

1 mol of acid react to 3 moles of hydroxide, therefore

0.0466 moles will react to (0.0466 . 3) /1 = 0.140 moles

Molarity (M) → mmol / mL

We convert mol to mmol → 0.140 mol . 1000 mmol / 1mol = 140 mmol

mL = mmol / M → 140 mmol / 0.225M = 621.5 mL

b. Ratio is 3:1. We need to determine, the moles of base.

50 mL . 0.404 M = 20.2 mmol → 0.0202 mol of NaOH

3 moles of hydroxide react to 1 mol of acid.

20.2 mmol of hydroxide would react to (20.2 . 1) / 3 = 6.73 mmol

mL = mmol / M → 6.73 mmol / 0.385M = 17.5 mL

c. First of all, we need to find out the limiting reactant:

25 mL . 0.1050M = 2.625 mmoles of base

15mL . 0.08650M = 1.2975 mmoles of acid.

1 mol of acid need 3 moles of base, for reaction

1.2975 mmol of acid would need (1.2975 . 3) /1 = 3.8925 mmol of base

We do not have enough base, so this is the limiting. (we need 3.8925 mmoles and we only have 2.625 mmoles)

So now, we propose:

3 moles of base can produce 1 mol of salt

2.625 mmoles of base would produce (2.625 . 1) /3 = 0.875 mmoles

d. To find out molarity, we need the total volume of solution:

25 mL + 15 mL = 40 mL

0.875 mmoles of salt / 40mL of solution = 0.022 M

Answer:

#1

Explanation:

molarity of EDTA solution 0.0675

no1

Answer:

- Iron is oxidized from 0 to +2.

- Hydrogen is reduced from +1 to 0.

Explanation:

Hello,

In this case, for the given reaction, we must first indicate the oxidation state of each element (notice that HC2H3O is acetic acid)

[tex]Fe ^0(s)+ 2 H^+(C_2H_3O_2)^-(aq) \rightarrow Fe^{2+}(C_2H_3O_2)_2^-(aq) + H_2^0(g)[/tex]

Thereby, notcing that iron is alone at the beginning, it has zero as its oxidation state, but once the reaction is undergone, it changes to +2, moreover, the displaced hydrogen in the acetic acid is with +1 but after the chemical reaction it becomes alone for which its oxidation state is 0, thereby, we find that:

- Iron is oxidized from 0 to +2.

- Hydrogen is reduced from +1 to 0.

Best regards,

Answer:

Adding a catalyst increases the speed of the reaction.

Explanation:

The catalyst increases the reaction rate since what it does is to consume the reagents more easily in order to obtain the products faster.

The catalysts DO NOT ALTER THE QUANTITY OF PRODUCTS OR REAGENTS, that is to say that they do not add grams nor do they intervene in the masses of the chemical compounds of the reaction, they only speed up the procedure.

Answer:

Number of molecules = 1.8267×10^20

Explanation:

From the question, we can deuced that the gases behave ideally, the we can make use of the ideal gas equation, which is expressed below;

PV = nRT

where

P =pressure

V =volume

n = the number of moles

R is the gas constant equal to 0.0821 L·atm/mol·K

T is the absolute temperature

Given:

P = 6.75 atm;

T = 290.0 k,

; V = 1.07 cm³ = 0.001 L

( 6.75 atm)(0.00107 L) = n(0.0821 L·atm/mol·K)(290K)

n = 3.0335167*10^-4 moles

But there are 6.022×10²³ molecules in 1 mole,

Number of molecules = 1.8267×10^20

Answer:

Alcl3 and Cl2

Explanation:

the product above will be formed

Answer:

silver (Ag) and aluminum chloride (AlCl₃)

Explanation:

The reaction between aluminum and silver chloride is a single replacement reaction. A single replacement reaction is when one element switches places with another.

Al + 3AgCl ➔︎ 3Ag + AlCl₃

In the reaction, the cations (positively charged ions) switch places. Aluminum (Al) switches places with Silver (Ag). So, the products of the reaction are silver and aluminum chloride.

Hope this helps.

Answer:

Oxygen

Explanation:

First, list out all the ions in the aqueous solution:

Ag+, NO3-

H+, OH-

In the anode, the substance lose electrons to undergo oxidation.

From the 4 ions, only OH- can lose electrons to form water and oxygen,

4OH- --->  O2 + 2H2O + 4e-

While others tend to gain electrons to form new substances instead (they undergo reduction).

Oxygen is the gas produced.

The gas should be treated as the Oxygen.

here First, list out all the ions that should be in the aqueous solution:

Ag+, NO3-

H+, OH-

In the anode, the substance loses electrons for undergoing oxidation.

From the 4 ions, only OH- can lose electrons to form water and oxygen.

The balanced chemical equation be like

4OH- --->  O2 + 2H2O + 4e-

While on the other hand, it tend to gain electrons to create new substances. Therefore, Oxygen is the gas produced.

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