You are in Paris, 50. m up on an Eiffel Tower support leg observation deck. If you throw a euro downward at a velocity of -1.0 m/s, how long would it take the coin to hit the ground?​

Answer:

Explanation:

The mechanical advantage of a pulley with three ropes is one.

is incorrect. It is 3

Answer:

escape the earth I think

In Newton's cannonball experiment, is the velocity is larger than the orbital velocity the Cannon ball will escape the Earth. Thus, the correct option is 3.

In this experiment, Newton visualizes a stone that is a cannonball which is being projected on top of a very high mountain. And, if there were no gravitational force or air resistance in that area, the body should follow a straight line path away from the Earth, in the direction in which it was projected.

If the cannonball is launched at a velocity that matches the orbital velocity of the planet, then it will not be able to be drawn in by gravitational force due to the Earth which results into moving away from the cannonball at the same speed at which the cannonball itself is falling.

If the velocity of the cannonball is larger than the orbital velocity than the ball will escape the Earth.

Therefore, the correct option is 3.

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Answer:

35.2644

I suppose mew is refractive index

Explanation:

( sin i ) / (sin r) = refractive index

( sin 60) / (sin r) = 1.5

( sin 60) / 1.5 =sin r

r=35.844

sorry if I'm wrong

The density of the liquid will be equal to   [tex]\rho=0.892 \ \dfrac{g}{cm^3}[/tex]

The density of an object is defined as the ratio of the mass of an object to the volume of the object.

Volume of tube = 2^2 * pi * 30 = 377 cm^3

Volume of tube submerged = 25* 377 / 30 = 314 cm^3

Buoyancy = weight of liquid displaced

Volume of liquid displaced = 314 cm^3

Mass of tube and lead = 250 + 30 = 280 g

Now from the mass density by definition

[tex]\rho = \dfrac{m}{v}[/tex]

[tex]m=\rho \times v[/tex]

Mass of liquid displaced = Mass being supported

[tex]314 \times \rho = 280 g[/tex]

[tex]\rho= \dfrac{280}{ 314 } = .892 \frac{g}{cm^3}[/tex]

Thus the density of the liquid will be equal to   [tex]\rho=0.892 \ \dfrac{g}{cm^3}[/tex]

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The density of the liquid is 1.67 g/[tex]cm^3[/tex].

The volume of the tube is

30 * 4 * 3.14 * 0.25 = 94.2 [tex]cm^3[/tex].

The mass of the lead pellets and the plastic tube is

30 + 250 = 280 g.

The volume of the lead pellets is

250 / 11.34 = 22 [tex]cm^3[/tex].

The volume of the liquid that the tube displaces is

94.2 - 22 = 72 [tex]cm^3[/tex].

The density of the liquid is

280 / 72 = 1.67 g/ [tex]cm^3[/tex].

Therefore, the density of the liquid is 1.67 g/ [tex]cm^3[/tex].

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Answer:

i think it's C thx correct me if wrong

Answer: The answer is hupa loopa

Explanation:

it changes ever 9.8 m/sec2.

Answer:

F1 = G m1 m2 / R^2        force of attraction

F2 = G m1 m2 / (R/2)^2

F2 / F1 = 4       the force of gravity will be quadrupled

The speed of the block at the displacement from the equilibrium position is 1.062 m/s.

The given parameters:

The speed of the block is calculated by applying the principle of conservation of mechanical energy as shown below;

[tex]\frac{1}{2} mv^2 = \frac{1}{2}kx^2\\\\mv^2 = kx^2\\\\v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{800 \times 0.13^2}{12} } \\\\v = 1.062 \ m/s[/tex]

Thus, the speed of the block at the displacement from the equilibrium position is 1.062 m/s.

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Answer:

The speed of the block at the displacement from the equilibrium position is 1.1266 m/s.

Step-by-step explanation:

Solution :

Using principle of conservation of mechanical energy formula to find the speed of the block :

[tex]\begin{gathered} \longrightarrow{\pmb{\sf{\frac{1}{2} mv^2 = \frac{1}{2}kx^2}}}\end{gathered}[/tex]

As per given data information in the question we have :

Substituting all the given values in the formula to find the speed of the block

[tex]\longrightarrow{\sf{ \: \:\dfrac{1}{2} mv^2 = \dfrac{1}{2}kx^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: \cancel{\dfrac{1}{2}}mv^2 = \cancel{\dfrac{1}{2}}kx^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: mv^2 = kx^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v^2 = \dfrac{kx^2}{m}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: \sqrt{{v}^{2} } = \sqrt{ \dfrac{kx^2}{m}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{kx^2}{m}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{800 \times {0.13}^{2}}{12}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{800 \times {0.13} \times 0.13}{12}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{800 \times 0.0169}{12}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{13.52}{12}}}}[/tex]

[tex]{\star{\underline{\boxed{\rm{\red{ v \approx 1.1266 \: m/s}}}}}}[/tex]

Hence, the speed of block is 1.1266 m/s.

[tex] \rule{300}{1.5}[/tex]

Hi there!

a.

We know that:

[tex]\Sigma F_y = 0 \\\\\Sigma F_x = 0[/tex]

Begin by determining the forces in the vertical direction:

W = weight of traffic light

T₁sinθ = vertical component of T₁

T₂sinθ = vertical component of T₂

b.

The ropes provide a horizontal force:

T₁cosθ = Horizontal component of T1

T₂cosθ = Horizontal component of T2

Thus:

0 = T₁cosθ  - T₂cosθ

T₁cosθ = T₂cosθ

T₁ = T₂

c.

Since the angles for both ropes are the same, we can say that:

T₁ = T₂

Sum the forces:

ΣFy = T₁sinθ + T₁sinθ - W = 0

2T₁sinθ = W

d.

Now, we can begin by solving for the tensions:

2T₁sinθ = W

[tex]T_1 = T_2 = \frac{W}{2sin\theta} = \frac{100}{2sin(37)} = \boxed{83.08 N}[/tex]

Answer:

In the inner vote part of the earth

Answer:

λ/2 = length of pipe

The pipe is open at both ends having wavelength of A-N-A or antinode-node-antinode which is 1/2 wavelength

λ = 331 m/s / (65.4 / s) = 5.06 m     wavelength of sound

L = 5.06 m / 2 = 2.53 m      length of pipe

Answer:

(a) The force changes its magnitude with respect to displacement, hence the total work will be sum of increment of work in three steps:-

step 1 . from 0 to 0.25m .

force = 0.6 N

displacement= 0.25m

work done =( force × displacement) = (0.25 × 0.6 ) = 0.15 joule.

step 2:- .

work done in moving from 0.25 to 0.50 m.

work done = ( force × displacement) = ( 0.4 × 0.25) = 0.10 Joule. .

step 3 :-

work done in moving from 0.50 to 0.75 m

work done = 0.8 × 0.25 = 0.200 joule.

hence total work done = ( 0.20+0.10+0.15) = 0.45 joule. ans

(b) similar concept you have to use here also.

step 1:

from 0.20 to 0.50, force of magnitude 0.4 N acts on the object.

Work done = ( 0.50-0.20)× 0.4 = 0.30 × 0.4 = 0.12 joule.

step :- 2

from 0.50 to 0.55 , force of magnitude 0.8 N acts on the block.

work done = 0.8× ( 0.55- 0.50) = 0.04 joule

total work done = 0.04 + 0.12 = 0.16 joule. ans

Over the past few decades man has always embarked on different space exploration by traveling to the moon. A typical Journey to the moon from Earth will take about 3 days in recent times.

Research on space exploration is still growing and expanding, with large amount of funding and support globally.

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Answer:

c. speed

Explanation:

In a distant-time graph the x value is usually the time and the y value is usually the distance.

If slope is the change in y over the change in x, on a distant time graph the slope would be the change in time over the change in distance

Or time / distance.

Time / distance happens to calculate speed.

Thus, the slope of a line on a distant-time graph is speed.

[tex]\huge\textbf{Hey there!}[/tex]

[tex]\large\textbf{The formula for Slope of a line is: }\mathbf{m = \dfrac{rise}{run}}\large\textbf{ whereas it is}\\\large\textbf{equal to/equivalent to }\mathbf{ \dfrac{y_2 - y_1}{x_2- x_1} \ .}\\\\\large\textbf{Basically, the slope of the line is measured with its }\\\large\textbf{\underline{steepness}. The word steepness simply means a}\\\lage\textbf{very sharp slope.}[/tex]

[tex]\large\textbf{On slope of a line on distant-time graph is basically how }\\\large\textbf{ \boxed{\bf FAST} a particular object is.}[/tex]

[tex]\large\textbf{Now, that we got that information out of the way we}\\\large\textbf{can find out our answer.}[/tex]

[tex]\large\textbf{The formula for distance is: }\mathbf{d= \sqrt{(x_2 - x_1)^2 + (y_2 +y_1)^2}}}[/tex]

[tex]\large\textsf{We cannot say that OPTION A isn't your answer because you}\\\large\textsf{cannot calculate slope of a line on a distant-time graph. You}\\\large\textsf{cannot calculate the speed of the object by using that formula.}\\\large\textsf{So, this eliminates Option A. as your answer.}[/tex]

[tex]\large\textbf{The formula of time is: }\mathbf{time = \dfrac{distance}{speed}}[/tex]

[tex]\large\textsf{Yes, it calculates the distance but it doesn't calculate how fast a(n)}\\\large\textsf{object is going. So this eliminates Option B. as your answer.}[/tex]

[tex]\large\textsf{The formula for speed is: }\mathbf{s = \dfrac{d}{t}}\large\textbf{ whereas s = \underline{speed}, }\\\large\textsf{d = \underline{distance} you have \underline{traveled}, \& t = \underline{time} that has}\\\large\textsf{been \underline{elapsed}.}\\\large\textsf{Option C. could possibly be your answer}[/tex]

[tex]\large\textbf{Option C. seems to be the closes to your result than the}\\\large\textbf{to your answer.}[/tex]

[tex]\large\boxed{\text{Therefore, your answer should be: \boxed{\textbf{Option C. Speed}}}}\huge\checkmark[/tex]

[tex]\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

yes the answer is C. 32.16

Answer:

An unbalanced force

Explanation:

Answer:

Force

Explanation:

Trust me

[tex]\text{Given that,}\\\\\text{Acceleration, a = -3.2 m s}^{-2}\\\\\text{Time, t = 14 sec}\\\\\text{Velocity, v = 8 m s}^{-1}\\\\\text{Initial velocity, v}_0 = ?\\\\\\v = v_0 +at\\\\\implies v_0 = v -at = 8 -(-3.2)(14) = 8 + 44.8 =52.8~ \text{m s}^{-1}[/tex]

Answer:

don't know ....?

Explanation:

Please help

According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:

A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.

B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.

C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.

D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.

Answer:

3.1×10⁻¹¹ N is

Explanation:

is the answer

Answer:

There is no scientific evidence that playing specifically l badminton makes you a better person, but sport and exercise in general release hormones which can make you feel more happy therefore making you nicer to the people around you and 'a better person'.

Answer:

It's true because playing any sport makes a person happy. So a happy person is a better person.

Please Mark as brainliest.

Answer:

A

Explanation:

acceleration = velocity / time

Hope that helps

Answer:

D

Explanation:

Average acceleration = final velocity- initial velocity, divided by elapsed time.

ā = V - Vo/t

= change in velocity ÷ change in time

In Newton's cannonball experiment, if the velocity is equal to the orbital velocity then the cannonball will stay in Orbit.

Newtons cannonball experiment stated that the distance that a cannonball will travel, before being drawn into the Earth by the forces of gravity, is dependent on the initial velocity.

Therefore, if the cannonball is launched at a velocity that matches the orbital velocity, then it will not be able to be drawn in by gravity due to the Earth moving away from the cannonball at the same speed at which the cannonball itself is falling.

This means that the cannonball will continue to fall without reaching the Earth, therefore staying in orbit, much like that of the moon or planets around the sun.

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Answer:

1800 J

Explanation:

GPE= mgh

60*3*10

=1800 J

whats the restraunt called

Based on the scenario, Remy has likely been influenced by framing effect.

In Psychology, framing effect can be defined as a cognitive bias wherein a person's choice from a group of options is primarily influenced by the positive or negative connotations pertaining to the options.

In this scenario, Remy did a research on the barbecue restaurant and finds that there are a number of both negative and positive reviews about it. However, he convinced himself by relying on the positive reviews and decides to go to the restaurant.

In conclusion, we can deduce that Remy has likely been influenced by framing effect.

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Answer:

B

Explanation:

Wave length is the height perpendicular verically of a wave

Answer:

b

Explanation:

makes the most sense to me

The final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

The given parameters:

The final velocity of the cannon ball when it strikes the earth is calculated by applying the principle of conservation of energy as follows;

[tex]P.E_i + K.E_i = P.E_f + K.E_f\\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = g(0) + \frac{1}{2} v_f^2\\\\2gh_i + v_i^2 = v_f^2\\\\v_f = \sqrt{2gh_i + v_i^2 } \\\\v_f = \sqrt{(2 \times 9.8 \times 50) \ \ + \ \ 30^2} \\\\v_f = 43.36 \ m/s[/tex]

Thus, the final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

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Answer:

Ethanol-filled thermometers are used in preference to mercury for meteorological measurements of minimum temperatures and can be used down to −70 °C (−94 °F). The physical limitation of the ability of a thermometer to measure low temperature is the freezing point of the liquid used.

Answer:

Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

Explanation: