You have a Rectangle with sides of 5ft and 8ft; solve for its perimeter and area.

[tex]Area = \frac{(6 + 10) \times 7}{2} \\ [/tex]

[tex]Area = \frac{16 \times 7}{2} \\ [/tex]

[tex]Area = \frac{2 \times 8 \times 7}{2} \\ [/tex]

[tex]Area = 8 \times 7[/tex]

[tex]Area = 56 \: \: {in}^{2} [/tex]

Answer:

Area: [tex]56in^2[/tex]

Step-by-step explanation:

The formula for the area of a trapezoid is:

[tex]A = \frac{a+b}{2}h[/tex]

so replacing with the given values we get:

[tex]a = 6in\\h = 7in\\b = 10in[/tex]

[tex]A = \frac{6in+10in}{2}7in = 56in^2[/tex]

So our final answer is [tex]56in^2[/tex]

Answer:

perimeter=114

AREA= 308

Step-by-step explanation:

A^2 + B^2=C^2

then A+B=+C= P for triangle

52= triangle perimeter

rectangle:

(l+w)*2=p for rectangle=62

then add 52+62= 114

AREA- Triangle

b*h/2

22*10=220

220/2

= 110

AREA- Rectangle

l*w=A

22*9=198

ADD BOTH AREAS

198+110=308

HOPE IT HELPS

[tex]\begin{array}{llll} x~-2y=-13\\ 5x+2y=-17\\ \cline{1-1} 6x+0y=-30 \end{array}\qquad \implies 6x=-30\implies x=\cfrac{-30}{6}\implies x=-5 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting on the 1st equation}}{(-5)-2y=-13\implies }-2y=-8\implies y = \cfrac{-8}{-2}\implies y = 4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (-5~~,~~4)~\hfill[/tex]

Answer:

C = -1 1/9° or -1.11°

Step-by-step explanation:

Use the formula given, and input 30 for F

[tex]C = 5/9(F - 32)\\\\C = 5/9(30 - 32)\\\\C = 5/9(-2)\\\\C = -10/9 = -1 \frac{1}9 = -1.11[/tex]

30°F ≈ -1.11°C

-Chetan K

This value is approximate.

==================================================

Explanation:

You're given a temperature of 30 degrees F and your teacher wants to know the Celsius version of this temperature. Plug in F = 30 and simplify.

[tex]C = \frac{5}{9}(F-32)\\\\C = \frac{5}{9}(30-32)\\\\C = \frac{5}{9}(-2)\\\\C \approx 0.5555*(-2)\\\\C \approx -1.111\\\\[/tex]

The temperature 30 degrees F converts to approximately -1.111 degrees C. Fahrenheit temperatures below 32 degrees are below 0 when converted over to Celsius.

Answer:

7y-3.5+7y-3.5+3.5y+10+3.5y+10

Step-by-step explanation:

21y+13

pls brainliest

Answer:

Reflection across the x-axis

Step-by-step explanation:

Rule of thumb: If the figure is diagonal, it is x-axis, but if it is horizontal, it is the y-axis.

Answer:

t=(37+root89)/32,(37-root89)/32

Step-by-step explanation:

Solve the equation:

23=3+37t-16t^2

Answer:

rubbing it against your hair it causes friction and with friction comes energy

Answer:

hello what the answer is B 3 because i knowdis that the answer is correct how i know is because i done it a piece of paper and my answer that i got was B

Step-by-step explanation:

The perimeter of a triangle is the sum of its side lengths.

The perimeter of triangle ACD is 40 units

Start by calculating the values of x and y, using the following equivalent ratios

[tex]6 : 4 = x - 2 : x - 4[/tex]

[tex]6 : 10 = 6 + x - 2 : y[/tex]

So, we have:

[tex]6 : 4 = x - 2 : x - 4[/tex]

Express as fraction

[tex]\frac 64 = \frac{x-2}{x-4}[/tex]

Cross multiply

[tex]6x - 24 = 4x - 8[/tex]

Collect like terms

[tex]6x - 4x = 24 - 8[/tex]

[tex]2x = 16[/tex]

Divide both sides by 2

[tex]x = 8[/tex]

Also, we have:

[tex]6 : 10 = 6 + x - 2 : y[/tex]

Express as fraction

[tex]\frac 6{10} = \frac{6 + x -2}{y}[/tex]

Substitute 8 for x

[tex]\frac 6{10} = \frac{6 + 8 -2}{y}[/tex]

[tex]\frac 6{10} = \frac{12}{y}[/tex]

Cross multiply

[tex]6y = 120[/tex]

Divide both sides by 6

[tex]y = 20[/tex]

The perimeter of triangle ACD is then calculated as:

[tex]P =6 + x - 2 + y + x - 4 + 4[/tex]

Substitute values for x and y

[tex]P =6 + 8 - 2 + 20 + 8 - 4 + 4[/tex]

[tex]P =40[/tex]

Hence, the perimeter of triangle ACD is 40 units

Read more about perimeter at:

https://brainly.com/question/19576164

Answer: [tex]\frac{1}{7^8}[/tex] or [tex]\frac{1}{5764801}[/tex]

Step-by-step explanation:

First, since the two roots (7) are the same, you subtract the exponents, which gives you -6 - 2 to get -8, giving you [tex]7^{-8}[/tex]

Next, you change [tex]7^{-8}[/tex] to [tex]\frac{1}{7^8}[/tex] or [tex]\frac{1}{5764801}[/tex]

I hope that helps :)

Answer: so 14 dollars in total

Step-by-step explanation:

Answer: Based on the current non-complete question, the answer Trinity earned $14.

Step-by-step explanation: 8 + 6 = 14.

x = total amount of gumballs

let's start subtracting the balls she's giving away

[tex]\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}[/tex]

[tex]\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }[/tex]

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

[tex]\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}[/tex]

she will score 18 goals

Step-by-step explanation:

6×3=18

Answer:

30

Step-by-step explanation:

i did the math lol

Answer:

Can I have some vbucks?

Answer:

1):Reaction

2):Action

3):Thought

4): Dialogue

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hoped this helped.

Answer: c

Step-by-step explanation: I JUST ANSWERED BOTH PARTs

Answer:

C

Step-by-step explanation:

Answer:

Length = 24

Step-by-step explanation:

It says, " Both the length and  width are increased by the same amount..." this means that both 12m and 5m were increased. So 12 + 12 = 24 and 5 + 5 = 10.

lol Looks like someone has the same math assignment as me

Explanation:

(I). 5/6 (4X+8) = (3/8) X - (1/4)

→ [{5(4X) + 5(8)}/6] = (3/8)X - (1/4)

→ [{20X + 40}/6] = (3/8)X - (1/4)

→ [{(20X/6) + (40/6) = (3/7)X - (1/4)

Now,

shift all variables fraction on LHS and constant fraction on RHS.

→ [(20X/6) - (3X/7)]= -(1/4) - (40/6)

Take the LCM of LHS denominator of 6&7 is 42.

→ [(140X - 18X)/42] = -(1/4)-(40/6)

→ [(122X)/42] = -(1/4)-(40/6)

Again take the LCM of the denominator in RHS i.e 4&6 is 12.

→ [(122X)/42] = (-12 - 80)/4

→ [(122X)/42] = (-92)/4

By doing Cross multiply the fraction, we get

→ 4(122X) = 42(-92)

→ 488X = -3 864

→ X = -3 864÷488

Therefore, X = -3864/488

Answer: Hence, the value of X for the given problem is -3864:488.

Explanation:

ii)Given algebraic equation is: 5(3p-5)+4p=5p-6(p+4)

→ 15p - 25 + 4p = 5p - 6p + 24

Shift all variables in LHS and constant on RHS.

→ 15p + 4p +6p = 25+24

→ 19p + 6p = 49

→ 25p = 49

Shift the number 25 from LHS to RHS.

Therefore, p = 49/25.

Answer: Hence, the value of P for the given algebraic equation is 49/25.

Answer:

2.5 feet for each bow

Step-by-step explanation:

15/6= 2.5

Answer:

y = −x + 5

Explanation:

Use the slope formula and slope-intercept form y = mx + b to find the equation.

Hope this helped. Have a good one!

Answer:

See below

Step-by-step explanation:

Remember that y=mx+b:

1) y = -3x+7

2) y = 1/4x-5

Answer:

both of your answers are b

Step-by-step explanation:

20. difference means subtract

21. assosiative property has to deal with three numbers while communitive is 2 numbers

[tex]\text{Given that,}\\\\\dfrac{dy}{dx} = x^2 y^2\\\\ \implies \dfrac{d^2 y}{dx^2} = x^2\cdot 2y \dfrac{dy}{dx}+ y^2 \cdot 2x\\\\\implies \dfrac{d^2 y}{dx^2} = x^2 \cdot 2y \cdot x^2 y^2 +2xy^2\\\\\implies \dfrac{d^2 y}{dx^2} =2x^4y^3 + 2xy^2 = 2xy^2(x^3y+1)[/tex]