You testify as an expert witness in a case involving an accident in which car A slid into the rear of car B, which was stopped at a red light along a road headed down a hill (Fig. 6-25). You find that the slope of the hill is u " 12.03, that the cars were separated by distance d " 24.0 m when the driver of car A put the car into a slide (it lacked any automatic anti-brake-lock system), and that the speed of car A at the onset of braking was v0 " 18.0 m/s.With what speed did car A hit car B if the coefficient of kinetic friction was (a) 0.60 (dry road surface) and (b) 0.10 (road surface covered with wet leaves)

Answer:

Mass is a measure of the amount of matter in an object.

Explanation:

A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.

A stone is dropped from a bridge and it experiences a uniformly accelerated rectilinear motion. It takes 2.3 s for the stone to reach the water.

We can calculate the height of the bridge, which is equal to the displacement of the stone, using the following kinematic equation.

[tex]s = ut + \frac{1}{2} a t^{2} = (0m/s)(2.3 s) + \frac{1}{2} (9.8m/s^{2} ) (2.3s)^{2} = 26 m[/tex]

where,

A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.

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Answer:

(a). The magnitude of the acceleration of the crate is 1.44 m/s².

(b). The direction  of the crate is 34.60°.

Explanation:

Given that,

Mass of crate = 26.1 kg

Coefficient of kinetic friction = 0.347

We need to calculate the resultant force

Using figure

[tex]F'=\sqrt{(F_{x}+F_{z})^2+F_{y}^2}[/tex]

Put the value into the formula

[tex]F'=\sqrt{(88\cos{55}+54)^2+(88\sin 54)^2}[/tex]

[tex]F'=126.4\ N[/tex]

(a). We need to calculate the acceleration of the crate

Using formula of sum of force

[tex]\sum{F}=F'-\mu N[/tex]

[tex]ma_{total}=F'-\mu mg[/tex]

[tex]a_{total}=\dfrac{F'}{m}-\mu g[/tex]

Put the value into thr formula

[tex]a_{total}=\dfrac{126.4}{26.1}-0.347\times9.8[/tex]

[tex]a_{total}=1.44\ m/s^2[/tex]

(b). We need to calculate the direction

Using formula of the direction

[tex]\theta=\tan^{-1}(\dfrac{F_{y}}{F_{x}+F_{z}})[/tex]

Put the value into the formula

[tex]\theta=\tan^{-1}(\dfrac{88\sin55}{88\cos55+54})[/tex]

[tex]\theta=34.60^{\circ}[/tex]

Hence, (a). The magnitude of the acceleration of the crate is 1.44 m/s².

The direction  of the crate is 34.60°.

Answer:

Hope this helps

Explanation:

Josh Gibson, (born December 21, 1911, Buena Vista, Georgia, U.S.—died January 20, 1947, Pittsburgh, Pennsylvania), American professional baseball catcher who was one of the most prodigious home run hitters in the game’s history. Known as “the black Babe Ruth,” Gibson is considered to be the greatest player who never played in the major leagues, there being an unwritten rule (enforced until the year of his death) against hiring black ballplayers

The given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.

Given data:

A boy slides down and friction causes him to slow down and stop.

In the given problem, when boy was sliding down, then he was in the state of motion, such that the when the he reaches at the bottom of hill, the friction plays the role of external agent to stop its motion.

This shows that the first law of motion is clearly followed which says that, "If an object is in motion, then it will be in motion until and unless any external force is applied on it". This is also known as law of inertia.

Thus, we can conclude that the given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.

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Explanation:

One of the interesting things about projectile motion is that the horizontal motion is independent of the vertical motion. Recall that in freefall, an object continually experiences a downward acceleration of 9.80ms2 but has no horizontal acceleration.

Force is the physical action that can give acceleration to a body upon which it is applied

The true statements about the forces and accelerations of each when they collide are;

The reasons why the above statements are true are given as follows:

Known:

Mass of the truck, m₁ = 5,000 kg

Mass of the car, m₂ = 1,000 kg

Velocity of the truck = [tex]v_t[/tex]

Velocity of the car = [tex]v_c[/tex]

According to Newton's third law of motion, action and reaction are equal and opposite

Force, F = Mass, m × Acceleration, a

Let a₁ represent the acceleration of the truck and let a₂ represent the acceleration of the car, we have;

F = 5,000 × a₁ = 1,000 × a₂

[tex]a_2 = \dfrac{5,000 \ kg}{1,000 \ kg} \times a_1 = 5 \cdot a_1[/tex]

Therefore;

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Answer:

a. Approximately  3.21 seconds

b. Approximately  5.196 m/s

Explanation:

a. The height from which the object is dropped = 20 meters

The location of the occurrence = The moon

The acceleration due to gravity on the moon  = 1.62 m/s²

The time it took the object to to impact the moon is given by the equation of free fall as follows;

h = 1/2·a·t²

Where;

h =The height from which the object is allowed to freely fall = 20 meters

a = The acceleration due to gravity on the moon  = 1.62 m/s²

t = The time of motion of the object

Substituting the values, gives;

20 = 1/2 × 1.62 × t²

t² = 20/(1.2 × 1.62) ≈ 10.23 s²

t = √ 10.23 ≈ 3.21 s

The time in motion of the object before impact, t = 3.21 seconds

b. The final speed, v is given from the equation for speed under free fall, which is presented as follows;

v = u + a·t

Where

u = The initial vertical velocity = 0

Substituting the values gives;

v = 0 + 1.62 × 3.21 ≈ 5.196 m/s

The final speed, v with which the object impacts the moon ≈ 5.196 m/s

Answer:

128

Explanation:

One clomiter is 1.06 multipled by 80

Answer:

5.3

Explanation:

Answer:

5.3 m/s east

Explanation:

Answer: Motion

Explanation:

Answer:

73.1 m/s

Explanation:

Given:

Δx = 160 m

v = 6.9 m/s

t = 4 s

Find: v₀

Δx = ½ (v + v₀) t

160 m = ½ (6.9 m/s + v₀) (4 s)

v₀ = 73.1 m/s

Answer:

A. air resistance

Explanation:

I think so

Answer: 1102.5 meters

Explanation:

Answer:

Hope the answer helped you. if yes pls follow me

Explanation:

the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.

Answer:

the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.

Explanation:

"who"

Answer:

Basketball has a mass of 0.1kg

m = 0.1 kg

The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero

a = 0m/s²

The constant speed is 6m/s

v = 6m/s

So, force to keep it moving with this constant speed can be calculated using Newton second law of motion

F = ma

F = m × 0

F = 0N

So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.

Answer: C

Explanation: after reading it over and over shes the most reasonable. But I could be wrong so be cautious.

According to the question, Maria would be best classified as being in identity diffusion. So, option (C) is correct answer.

People who are experiencing identity diffusion haven't chosen an ideological or occupational route for the future and aren't making any effort to do so. Identity diffusion occurs during adolescence, a time when individuals are attempting to define their identities, but it can also last into adulthood.

In the question, Maria has adopted her parents’ identification as Protestant without considering other options. She   haven't chosen an ideological or occupational route for the future and aren't making any effort to do so.  So, Maria  would be best classified as being in identity diffusion.

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#SPJ6

Answer:

False, it travels left.

Explanation:

Hello.

In this case, we can answer this with an example. If we have 200 g and we want that value in a larger unit, for instance, kilogram, the following conversion is performed since 1 kg equals 1000 g:

[tex]200g*\frac{1kg}{1000kg}=0.200g[/tex]

Whereas we needed to move the decimal point from right to left, which means that it travels left, that is why the statement is false.

Best regards.

19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m

21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg

22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J

23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON

24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m

25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m

21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg

22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J

23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON

24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m

25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m

21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg

22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J

23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON

24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m

25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m

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Answer:

The correct option is;

D. The nervous system signals smooth muscles in the blood vessels to contract to increase blood pressure

Explanation:

The contraction or relaxation of the vascular smooth muscles lead to the blood vessel volume change and blood pressure change such that the blood is redirected to regions of the body that requires instantaneous increased oxygen intake. As such the nervous system signals the blood vessel's vascular smooth muscle to contract, through vasoconstriction so as to raise the blood pressure, when the blood pressure is low.

Answer:

15 cm

Explanation:

using the thin lens formula for convex lens

                            [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\\ \\where f = focal length \\ p = object distance \\ q = image distance\\[/tex]

 so,

         [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p} \\\\\frac{1}{q} = \frac{1}{10} - \frac{1}{30} \\\frac{1}{q} = \frac{2}{30}\\\frac{1}{q} = \frac{1}{15cm}[/tex]

so,

    q = 15 cm

Answer:

in electric lamp

Electric Energy to Heat and Light Energy

Explanation:

Answer:

Ex: an electric fan transforms electric energy to kinetic energy

Or

Chemical energy to heat and light energy

Explanation:

Hope this helps

Answer:

Explanation:

Given data

initital velocity u=15m/s

deceleration a=3m/s^2

time t= 4 seconds

final velocity v= ?

Applying the expression

v=u+at------1

substituting our data into the expression we have

v=15+3*4

v=15+12

v=27m/s

The velocity after 4 seconds is 27m/s

Answer:

The independent variable is the variable that is changing.

Explanation:

I gave you this because you did not give us the work for use to see.

Given parameters:

Initial volume  = 75cm³

New volume  = 30cm³

New pressure  = 110Pa

Unknown:

Initial pressure = ?

Solution:

Condition: temperature is constant

We simply apply Boyle's law to this problem:

   " the volume of a fixed mass(mole) of a gas varies inversely as the pressure changes if the temperature is constant".

  Mathematically;

          P₁ V₁  = P₂ V₂

where P and V are pressure and volume values

          1 and 2 are the initial and final states.

Input the parameters and solve for P₁;

     P₁ x 75  = 110 x 30

   P₁ = 44Pa

The initial pressure is 44Pa

Answer:

1. rotation. 2. axis

Explanation:

The Earths rotation on its axis causes day and night

Answer:

The maximum frequency of revolution is 3.6 Hz.

Explanation:

Given that,

Mass = 8 kg

Distance = 400 mm

Tension = 800 N

We need to calculate the velocity

Using centripetal force

[tex]F=\dfrac{mv^2}{r}[/tex]

Where, F= tension

m = mass

v= velocity

r = radius of circle

Put the value into the formula

[tex]800=\dfrac{8\times v^2}{200\times10^{-3}}[/tex]

[tex]v^2=\sqrt{\dfrac{800\times200\times10^{-3}}{8}}[/tex]

[tex]v=4.47\ m/s[/tex]

We need to calculate the maximum frequency of revolution

Using formula of frequency

[tex]f=\dfrac{v}{2\pi r}[/tex]

Put the value into the formula

[tex]f=\dfrac{4.47}{2\pi\times200\times10^{-3}}[/tex]

[tex]f=3.6\ Hz[/tex]

Hence, The maximum frequency of revolution is 3.6 Hz.