Answer:
Step-by-step explanation:
Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.
If the weight of an alloy = x kgs
Then weight of copper = [tex]\frac{9}{7+9}\times (x)[/tex]
= [tex]\frac{9}{16}\times (x)[/tex]
And the weight of zinc = [tex]\frac{7}{7+9}\times (x)[/tex]
= [tex]\frac{7}{16}\times (x)[/tex]
If the weight of zinc = 31.5 kg
31.5 = [tex]\frac{7}{16}\times (x)[/tex]
x = [tex]\frac{16\times 31.5}{7}[/tex]
x = 72 kgs
Therefore, weight of copper = [tex]\frac{9}{16}\times (72)[/tex]
= 40.5 kgs
2). i). 2 : 3 = [tex]\frac{2}{3}[/tex]
4 : 5 = [tex]\frac{4}{5}[/tex]
Now we will equalize the denominators of each fraction to compare the ratios.
[tex]\frac{2}{3}\times \frac{5}{5}[/tex] = [tex]\frac{10}{15}[/tex]
[tex]\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}[/tex]
Since, [tex]\frac{12}{15}>\frac{10}{15}[/tex]
Therefore, 4 : 5 > 2 : 3
ii). 11 : 19 = [tex]\frac{11}{19}[/tex]
19 : 21 = [tex]\frac{19}{21}[/tex]
By equalizing denominators of the given fractions,
[tex]\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}[/tex]
And [tex]\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}[/tex]
Since, [tex]\frac{361}{399}>\frac{231}{399}[/tex]
Therefore, 19 : 21 > 11 : 19
iii). [tex]\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}[/tex]
[tex]=\frac{3}{2}[/tex]
[tex]\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}[/tex]
= [tex]\frac{4}{3}[/tex]
Now we equalize the denominators of the fractions,
[tex]\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}[/tex]
And [tex]\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}[/tex]
Since [tex]\frac{9}{6}>\frac{8}{6}[/tex]
Therefore, [tex]\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}[/tex] will be the answer.
IV). [tex]1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}[/tex]
[tex]=\frac{6}{5}\times \frac{3}{4}[/tex]
[tex]=\frac{18}{20}[/tex]
[tex]=\frac{9}{10}[/tex]
Similarly, [tex]\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}[/tex]
[tex]=\frac{4}{15}[/tex]
By equalizing the denominators,
[tex]\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}[/tex]
Similarly, [tex]\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}[/tex]
Since [tex]\frac{270}{300}>\frac{80}{300}[/tex]
Therefore, [tex]1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}[/tex]
V). If a : b = 6 : 5
[tex]\frac{a}{b}=\frac{6}{5}[/tex]
[tex]=\frac{6}{5}\times \frac{2}{2}[/tex]
[tex]=\frac{12}{10}[/tex]
And b : c = 10 : 9
[tex]\frac{b}{c}=\frac{10}{9}[/tex]
Since a : b = 12 : 10
And b : c = 10 : 9
Since b = 10 is common in both the ratios,
Therefore, combined form of the ratios will be,
a : b : c = 12 : 10 : 9
For f(x) = 2x + 1 and g(x) = x2 – 7, find (f – g)(x).
Answer:
-x^2 +2x +8
Step-by-step explanation:
f(x) = 2x + 1
g(x) = x^2 – 7,
(f – g)(x) = 2x +1 - ( x^2 -7)
Distribute the minus sign
= 2x+1 - x^2 +7
Combine like terms
= -x^2 +2x +8
Answer:
its not true. Answer is (f + g)(x) = x2 + 2x - 6
Step-by-step explanation:
Trust me. Good luck.
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 50 feet cubed. A cylinder with height h and radius r. A cylinder with height h and radius r. What is the volume of the sphere?
Answer:
Volume of the sphere is 66.67r/h
Step-by-step explanation:
Hello,
Volume of a sphere = ⁴/₃πr³
Volume of a cylinder = πr²h
The volume of the cylinder = 50ft³
But the cylinder and sphere both have the same radius and height
Volume of a cylinder = πr²h
50 = πr²h
Make r² the subject of formula
r² = 50/πh
Volume of a sphere = ⁴/₃πr³
Put r² into the volume of a sphere
Volume of a sphere = ⁴/₃π(50/πh)r
Volume of a sphere = ⁴/₃ × 50r/h
Volume of a sphere = ²⁰⁰/₃ r/h
Volume of a sphere = 66.67r/h
The volume of the sphere is 66.67r/h
DatGuy! Sekkrit! Wishing! Anyone? Find the discriminant of 3x²+5x-2 = 0
Answer:
49
Step-by-step explanation:
[tex]3x^2+5x-2 = 0[/tex]
Apply discriminant formula : [tex]D = b^2- 4ac[/tex]
[tex]D=discriminant\\b=5\\a=3\\c=-2[/tex]
[tex]D = b^2- 4ac[/tex]
Plug in the values for a, b, and c.
[tex]D = 5^2- 4(3)(-2)[/tex]
Evaluate.
[tex]D = 25- 12(-2)[/tex]
[tex]D = 25- - 24[/tex]
[tex]D=25+24[/tex]
[tex]D=49[/tex]
Answer:
49
Step-by-step explanation:
3x²+5x-2 = 0
This is in the form
ax^2 + bx + c=0
a=3 b=5 c = -2
The discriminant is
b^2 -4ac
5^2 -4(3) (-2)
25 + 24
49
The discriminant is 49
The cosine function reaches a value of 0 when x is equal to
Answer:
Step-by-step explanation:
The values of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.
Find the fraction half way between 1/7 and 1/5
Answer:
6/35
Step-by-step explanation:
add ¹/7+¹/5 =12/35
divide 12/35 by 2
=6/35
Find the vertex of the graph
Answer:
(-3, -11)
i needed to put more characters so here
One liter of paint is needed to cover all 6 sides of a cubical block. How many liters will be needed to cover all 6 sides of a second cubical block whose edge is twice as long as an edge on the first block?
Will mark brainlist
Answer:
4 liters
Step-by-step explanation:
Let's assume that the side lengths of the cubical block are 2 inches.
This means that one of the sides area is 4 in².
Multiplying this by 6 (for there are 6 sides) gets us 24 in².
So one liter of paint covers 24 in².
Now if the side lengths (edge) of the second block is doubled, that means that the side lengths are [tex]2\cdot2 = 4[/tex] inches.
So the area of one side is 16 in².
Multiplying this by 6 (as there are 6 sides) gets us 96 in².
To find how many liters of paint this will take, we divide 96 by 24.
[tex]96\div24=4[/tex]
So 4 liters of paint will be needed for the second cubical block.
Hope this helped!
anyone plss heeelp me...i only need answer 6c..
Answer:
6c1; [tex]Area = 81.12m^2[/tex]
6cii: See Explanation
Step-by-step explanation:
Given
[tex]A = 3p^2[/tex]
[tex]0 \leq p \leq 6[/tex]
Where A represents Area and P represents Width
Required
Solve 6c
Please note that because you only need 6c, I'll solve using calculations;
Solving 6ci:
Area of the cage, when width is 5.2m
Substitute 5.2m for p in[tex]A = 3p^2[/tex]
[tex]A = 3 * 5.2m^2[/tex]
[tex]A = 3 * 27.04m^2[/tex]
[tex]A = 81.12m^2[/tex]
Hence, the area of the cage is 81.12m²
Solving 6cii:
Area of the cage, when width is 40m
From the range of value of p: [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p
However, if the range is extended; the value of Area is as follows;
Substitute 40m for p
[tex]A = 3 * 40m^2[/tex]
[tex]A = 3 * 1600m^2[/tex]
[tex]A = 4,800m^2[/tex]
Please answer this in two minutes
Answer:
366.6 mm²
Step-by-step explanation:
Step 1: find XY using the Law of sines.
Thus,
[tex] \frac{XY}{sin(W)} = \frac{WY}{sin(X)} [/tex]
m < W = 180 - (70+43) (sum of angles in a triangle)
W = 180 - 113 = 67°
WY = 24 mm
X = 43°
XY = ?
[tex] \frac{XY}{sin(67)} = \frac{24}{sin(43)} [/tex]
Cross multiply:
[tex] XY*sin(43) = 24*sin(67) [/tex]
[tex] XY*0.68 = 24*0.92 [/tex]
Divide both sides by 0.68 to solve for XY
[tex] \frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68} [/tex]
[tex] XY = 32.47 [/tex]
XY ≈ 32.5 mm
Step 2: find the area using the formula, ½*XY*WY*sin(Y).
Area = ½*32.5*24*sin(70)
Area = ½*32.5*24*0.94
= 32.5*12*0.94
Area = 366.6 mm² (nearest tenth)
|3x+9|= 30
Answer: x=7, -13
Answer:
[tex]\boxed{x=7, \: x=-13}[/tex]
Step-by-step explanation:
[tex]|3x+9|= 30[/tex]
Solve for absolute value.
There are two possibilities.
One possibility:
[tex]3x+9=30\\3x=21\\x=7[/tex]
Second possibility:
[tex]3x+9=-30\\3x=-39\\x=-13[/tex]
If the family decreases the clothing budget by 3 percent, what amount will it have to spend on clothing?
nearest dollar
$266
$466
$645
$665
Answer: $466
Step-by-step explanation:
Answer:
b.$466
Step-by-step explanation:
In a different plan for area codes the first digit could be any number from 3 through 6 the second digit was either 5,6,7 or 8 and the third digit could be any number except 5. With this plan how many different area codes are possible?
Answer:
144 codes are possible
Step-by-step explanation:
Okay for the first digit, we shall be selecting one out of 3,4,5,6.
Meaning we are selecting one out of four choices
The number of ways this can be done is 4C1 ways = 4 ways
For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways
And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices
So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes
very simple challenge hard question
Answer:
-58.41509433
Step-by-step explanation:
0.4+8(5-0.8*5/8)-5/(2.5)=34.4
[0.4+8(5-4/8)-(2)]=
[0.4+8(40-4)/8)-2=34.4 ( nominator)
15-(8.9-2.6/(2/3))*34*2/5 =-53
15-(8.9-3.9)*68/5
15-5*68/5=
15-68=-53 ( denominator)
(34.4/-53) *90
-58.41509433
This is used for the next few questions: The rating for the new scary movie has a scale of 0 to 10. The average response was that the regular movie attendant enjoyed the movie with 8.3 points and a standard deviation of 0.5 points. What is the percent of people who gave the movie a rating between 6.8 and 8.8? (Write the number as a percent only without a percent sign.)
Answer:
The percentage that of people who gave the movie a rating between 6.8 and 8.8
P(6.8≤X≤8.8) = 83.9≅ 84 percentage
Step-by-step explanation:
Step(i):-
Mean of the Population = 8.3 points
Standard deviation of the Population = 0.5 points
Let 'X' be the random variable in normal distribution
Let X = 6.8
[tex]Z = \frac{x-mean}{S.D} = \frac{6.8-8.3}{0.5} = -3[/tex]
Let X = 8.8
[tex]Z = \frac{x-mean}{S.D} = \frac{8.8-8.3}{0.5} = 1[/tex]
The probability that of people who gave the movie a rating between 6.8 and 8.8
P(6.8≤X≤8.8) = P(-3≤Z≤1)
= P(Z≤1)- P(Z≤-3)
= 0.5 + A(1) - ( 0.5 -A(-3))
= A(1) + A(3) (∵A(-3)=A(3)
= 0.3413 +0.4986 (∵ From Normal table)
= 0.8399
Conclusion:-
The percentage that of people who gave the movie a rating between 6.8 and 8.8
P(6.8≤X≤8.8) = 83.9≅ 84 percentage
which geometric solid is formed by rotating the rectangle about line m?
Answer:
rectangular prism
Step-by-step explanation:
check by rotating the shape in images
The path followed by a roller coaster as it climbs up and descends down from a peak can be modeled by a quadratic function, where h(x) is the height, in feet, and x is the horizontal distance, also in feet. The path begins and ends at the same height, covers a total horizontal distance of 100 feet, and reaches a maximum height of 250 feet. Which of the functions could be used to model this situation? A. h(x)=-0.1x^2-50x+250 B. h(x)=-0.1(x-50)^2+250 C. h(x)=-0.1(x-100)^2+250 D. h(x)=-0.1x^2+100x+250
Answer:
C
Step-by-step explanation:
0.1(x - 100)² + 250
0.1[(x - 100)(x - 100)] + 250
0.1(x² -200x + 10000) + 250
0.1x² - 20x + 1000 + 250
0.1x² - 20x + 1250
0.1x² - 25x + 5x + 1250
0.1x(x - 250) + 5(x + 250)
∴ (0.1x + 5)(x - 250) or (0.1x + 5)(x + 250)
Clinical Trial When XELJANZ (tofacitinib) was administered as part of a clinical trial for this rheumatoid arthritis treatment, 1336 subjects were given 5 mg doses of the drug, and here are the numbers of adverse reactions: 57 had headaches, 21 had hypertension, 60 had upper respiratory tract infections, 51 had nasopharyngitis, and 53 had diarrhea. Does any one of these adverse reactions appear to be much more common than the others? (Hint: Find the relative frequencies using only the adverse reactions, not the total number of treated subjects.)
Answer:
Relative frequencies:
Headaches = 23.55 %
Hypertension = 8.68%
Upper respiratory tract infections =24.79%
Nasopharyngitis = 21.07
Diarrhea = 21.09%
None of these adverse reactions appear to be much more common than the others.
Step-by-step explanation:
Compute frequency:
The number of adverse reactions categories:
Headaches
Hypertension
Upper respiratory tract infections
Nasopharyngitis
Diarrhea
Frequency of each adverse reaction:
Adverse reaction Frequency
Headaches 57
Hypertension 21
Upper respiratory tract infections 60
Nasopharyngitis 51
Diarrhea 53
Compute total frequency
Total frequency is compute dby taking sum of all frequencies;
Sum of frequencies = 57 + 21 + 60 + 51 + 53
= 242
Compute relative frequency:
In order to find if any one of these adverse reactions appear to be much more common than the others, we have to compute relative frequency using these adverse reactions.
By calculating relative frequency we are looking at the number of times a specific adverse reaction appears to be more common, compared to the others.
To calculate relative frequency, divide the frequency of each adverse reaction by the total frequency i.e. 242.
Relative frequency for Headache = 57 / 242
= 0.2355
= 23.55 %
Relative frequency for Hypertension = 21 / 242
= 0.0868
= 8.68 %
Relative frequency for Upper respiratory tract infections = 60 / 242
= 0.2497
= 24.97 %
Relative frequency for Nasopharyngitis = 51 / 242
= 0.2107
= 21.07 %
Relative frequency for Diarrhea = 53 / 242
= 0.2190
= 21.90 %
If you observe the relative frequencies of all the adverse reactions, none of them appear to be much more common than the others. Relative frequencies of headaches, upper respiratory tract infections, nasopharyngitis and diarrhea are almost equally common however, relative of hypertension appears to be very less than the other three.
find the slope and y intercept of the line y=7/5x-3 5/7; 3 3; 7/5 7/5;-3 -3; 7/5
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the question
y = 7/5x - 3
Comparing with the above formula
Slope / m = 7/5c/ y intercept = - 3Hope this helps you
The value of the slope of the line is 7/5 and the y-intercept is -3
Given the line equation :
y = 7/5x - 3The general form of the equation is :
y = bx + cslope = b ; intercept = cComparing the equations :
b = 7/5 c = -3Hence, the slope and y-intercept are 7/5 and -3
Learn more on slopes :https://brainly.com/question/25987747
#SPJ6
There are four inequalities that define the region R.
One of these is y
Find the other three inequalities,
Answer:
[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]
Step-by-step explanation:
The region R is surrounded by 4 lines, the first one is y=x+1, the second one is y=0 or the axis x, and the third and fourth one need to be calcualted.
To find the equation of a line through the points (x1,y1) and (x2, y2) we can use the following equation:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Then, our third line is going to be the line that passes through the points (2,0) and (4,3), so the equation is:
[tex]y=\frac{3-0}{4-2}(x-2)\\y=\frac{3}{2}x-3[/tex]
Our fourth line is the line that passes through the points (3,0) and (0,3), so the equation is:
[tex]y=\frac{3-0}{0-3}(x-3)\\y=-x+3[/tex]
Then we can say that the other three inequalities are:
[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]
If a number is added to the numerator of StartFraction 11 Over 36 EndFraction and twice the number is added to the denominator of StartFraction 11 Over 36 EndFraction , the resulting fraction is equivalent to one third . Find the number.
Answer:
The number is 3
Step-by-step explanation:
The fraction is 11/36
let
x = no. added to the numerator
2x = no. added to denominator
We have,
x+11/2x+36=1/3
Cross multiply
3(x+11) = (2x + 36)
3x + 33 = 2x + 36
Collect like terms
3x - 2x = 36 - 33
x=3
The number is 3
Check:
3+11/6+36=1/3
14/42=1/3
find the value of x and y if the distance of the point (x,y) from (-2,0) and (2,0) are both 14 units.
Answer:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex] are both 14 units from points (-2, 0) and (2, 0).
Step-by-step explanation:
distance formula
[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
We want the distance, d, from points (-2, 0) and (2, 0) to be 14.
Point (-2, 0):
[tex] 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
Point (2, 0):
[tex] 14 = \sqrt{(x - 2)^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
We have a system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
Since the right sides of both equations are equal, we set the left sides equal.
[tex] \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} [/tex]
Square both sides:
[tex] (x + 2)^2 + y^2 = (x - 2)^2 + y^2 [/tex]
Square the binomials and combine like terms.
[tex] x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 [/tex]
[tex] 4x = -4x [/tex]
[tex] 8x = 0 [/tex]
[tex] x = 0 [/tex]
Now we substitute x = 0 in the first equation of the system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(0 + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{4 + y^2} = 14 [/tex]
Square both sides.
[tex] y^2 + 4 = 196 [/tex]
[tex] y^2 = 192 [/tex]
[tex] y = \pm \sqrt{192} [/tex]
[tex] y = \pm \sqrt{64 \times 3} [/tex]
[tex] y = \pm 8\sqrt{3} [/tex]
The points are:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex]
PLEASE HELPPPPPP 65 points
Answer:
x + 2y ≤ 12
x + 2y = 12
Step-by-step explanation:
The teachers can not give more than 12 hours of homework so this is the answer. those are the 2 equations you can use. It under 12 hours or equal to 12 hours.
Answer:
Part A: x + 2y ≤ 12.
Part B: y = -1/2x + 6.
Part C: (0, 0).
Step-by-step explanation:
Part A: The total hours of homework have to be 12 hours, and it has to be either 12 hours or less. So, we have ≤ 12.
They take 1 math course with x hours of homework, so in total, that is 1 * x = x hours of math homework.
They take 2 science courses with y hours of homework, so in total, that is 2 * y = 2y hours of science homework.
The inequality would then be x + 2y ≤ 12.
Part B: x + 2y = 12
2y = -x + 12
y = -1/2x + 6
You can use the Math is Fun: Function Grapher and Calculator to find the graph of the line, shown below.
Part C: Since the inequality uses a ≤ symbol, we know that the shading will be underneath the line. An appropriate point below the line includes (0, 0). We will test out whether it works as a point included in the inequality.
x + 2y ≤ 12
0 + 2 * 0 ≤ 12
0 + 0 ≤ 12
0 ≤ 12
Since this is a true statement, (0, 0) holds true for the inequality.
Hope this helps!
find three examples of corporate logos. do they incorporate symmetry? if so, and what kind? your response should be 3-5 sentences long
Answer:
Symmetry is the property of an object to retain its shape even if it is turned or turned.
The three corporate logos are McDonald, Shell, Snapcaht
McDonald company logo is symmetrical and it is a reflective symmetry.
Shell logo is symmetrical and it is also reflective symmetry.
Snaphcat logo is symmetrical and it is also reflective symmetry.
How does the graph of y = a(x – h)2 + k change if the value of h is doubled? The vertex of the graph moves to a point twice as far from the x-axis. The vertex of the graph moves to a point twice as far from the y-axis. The vertex of the graph moves to a point half as far from the x-axis. The vertex of the graph moves to a point half as far from the y-axis.
Answer:
The vertex of the graph moves to a point twice as far from the y-axis.
Step-by-step explanation:
How does the graph of y = a(x – h)2 + k change if the value of h is doubled?
The vertex of the graph moves to a point twice as far from the x-axis.
The vertex of the graph moves to a point twice as far from the y-axis.because the role of h is to indicate the distance of the vertex from the y-axis.
The vertex of the graph moves to a point half as far from the x-axis.
The vertex of the graph moves to a point half as far from the y-axis.
Transformation involves changing the position of a function.
When h is doubled in [tex]\mathbf{y = a(x - h)^2 + k}[/tex], the vertex of the graph moves to a point twice as far from the y-axis.
The function is given as:
[tex]\mathbf{y = a(x - h)^2 + k}[/tex]
When the value of h is doubled, the new function becomes:
[tex]\mathbf{y' = a(x - 2h)^2 + k}[/tex]
Rewrite as:
[tex]\mathbf{y' = a(x - h- h)^2 + k}[/tex]
The above equation means that:
Function y will be translated to the right by h units
Assume the vertex is:
[tex]\mathbf{Vertex = (2,5)}[/tex]
The new vertex will be:
[tex]\mathbf{Vertex = (4,5)}[/tex]
Comparing the vertices, it means that:
The new function will have its vertex twice as far from the y-axis
Hence, option (b) is correct.
Read more about transformation at:
https://brainly.com/question/13801312
which of the following is equivalent to (x+4)(3x^2+2x)??
Answer:
c
Step-by-step explanation:
Harry took a loan from the bank. D represents Harry's remaining debt (in dollars) after t months. D = -200t + 9000 What was the size of Harry's loan? Please HELPPP Im not allowed to stand up from my chair until i finish this and i've been at it for 1 HOUR PLEASEEEEEEEEEE thank you so much to who ever answers this YOU ARE THE BESTTTTTTT
Answer:
9000
Step-by-step explanation:
the inital ammout which is 9k is the size of the loan
-200 because he years 200 dollars per month
but the start up number is 9000 and he repays the load at 200 dollars a month
plzzzz answer right away will mark BRAINLIST AND FIVE STARS PLUS The table below shows the possible outcomes of rolling a six-sided number cube and flipping a coin. A 7-column table with 2 rows. Column 1 has entries H, T. Column 2 is labeled 1 with entries H 1, T 1. Column 3 is labeled 2 with entries H 2, T 2. Column 4 is labeled 3 with entries H 3, T 3. Column 5 is labeled 4 with entries H 4, T 4. Column 6 is labeled 5 with entries H 5, T 5. Column 7 is labeled 6 with entries H 6, T 6. What is the probability of getting a number less than 3 and a tails? StartFraction 1 over 12 EndFraction StartFraction 1 over 6 EndFraction One-fourth One-third
Answer:
P((1 or 2) and Tail) = 1/6 = StartFraction 1 over 6
Step-by-step explanation:
A six-sided die and a coin.
Probability of getting <3 and tail.
P((1 or 2) and Tail)
= 2/6 * 1/2
= 1/6
Answer:
1/6
Step-by-step explanation:
Please help me.. I'm very confused about this
Answer:
C
Step-by-step explanation:
1:draw a very simple Cartesian plane for the graph
2:label the quadrants 1-4 from top right round to bottom right as 4
3:then apply x>0 (1,2) is top right and y<0 is bottom right (-1,-2)
By visual inspection, determine the best-fitting regression model for the
scatterplot.
Need help ASAP please
Answer:
its a! sorry im so late
Step-by-step explanation:
What is the result of adding these two equations?
62 + 2y = -2
3x - 2y = -5
Answer:
x = -7/9; y = 4/3.
Step-by-step explanation:
I will assume that the top equation is 6x + 2y = -2, and the bottom one is 3x - 2y = -5.
If you add the two...
(6x + 3x) + (2y + (-2y)) = (-2 + (-5))
9x + 0 = -7
9x = -7
x = -7/9
6(-7/9) + 2y = -2
-42/9 + 2y = -18/9
2y = 24/9
y = 24/18
y = 12/9
y = 4/3
Hope this helps!