12) A survey found that 60% of the people by used cars. If a car dealership has 3,500 car buyers, predict how
many buyers purchased a used car.

12x = (10)(11)

12x=110

x=110÷12

x=55/6

Answer:

D.f(x)=2x-9and g(x)=X+9/2

Answer:

12.56m²

Step-by-step explanation:

So the formula for the circumference of a circle is π x diameter, so we just have to plug into our equation (we're using 3.14 as π):

3.14 x 4 = 12.56

So the circumference of your circle is 12.56 meters²

hope this helps:)

Answer:

It's Sin.

Thumbs-up (^_-)

Step-by-step explanation:

the answer is A ,since the unknown side is opposite while the known side is the hypotenuse

Answer:

Options A, C, E

hope it helps

please mark brainliest

Answer:

3 shares

Step-by-step explanation

Answer:

1. 50000

2.

i 274625000cm

ii 274.625m

Step-by-step explanation:

1. Area of a rectangle: length*width

250*200=50000cm

2. Volume of a cube: length^3

i 650^3=274625000cm

ii 650 cm=6.5m; 6.5^3=274.625m

Answer:

B

Step-by-step explanation:

Use quadratic formula

the area of a rectangle is the product of its length and width.

Answer:

1/3P

Step-by-step explanation:

P/3 is equal to 1/3P

Answer:

2/10 I believe

Step-by-step explanation:

3/10 + 4/10= 7/10

9/10 - 7/10 = 2/10

Step-by-step explanation:

perimeter = 2×(7+5) = 2×12= 24 units

area = 7×5 = 35 sq. units

Answer:

P(0) = 0.055

P(1) = 0.16

P(2) = 0.231

P(3) = 0.224

P(4) = 0.162

P(5 or more) = 0.168

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Here λ = 2.90 is the average number of bacteria colonies per field.

This means that [tex]\mu = 2.90[/tex]

Compute P(r) for r = 0, 1, 2, 3, 4, and 5 or more.

[tex]P(0) = \frac{e^{-2.9}*(2.9)^{0}}{(0)!} = 0.055[/tex]

[tex]P(1) = \frac{e^{-2.9}*(2.9)^{1}}{(1)!} = 0.16[/tex]

[tex]P(2) = \frac{e^{-2.9}*(2.9)^{2}}{(2)!} = 0.231[/tex]

[tex]P(3) = \frac{e^{-2.9}*(2.9)^{3}}{(3)!} = 0.224[/tex]

[tex]P(4) = \frac{e^{-2.9}*(2.9)^{4}}{(4)!} = 0.162[/tex]

5 or more:

This is

[tex]P(X \geq 5) - 1 - P(X < 5)[/tex]

In which:

[tex]P(X < 5)  = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.055 + 0.16 + 0.231 + 0.224 + 0.162 = 0.832[/tex]

[tex]P(X \geq 5) - 1 - P(X < 5) = 1 - 0.832 = 0.168[/tex]

So

P(5 or more) = 0.168

Answer:

(x-6)^3x-5 =6

Step-by-step explanation:

logb a=c ------>  b^c =a

Answer:

5 years

Step-by-step explanation:

3000x.06=180 interest per year.

900/180 =5 years to earn 900 interest.

Answer:

3) (I) Numeric , and (II) Numeric

Step-by-step explanation:

Numeric variable:

The variable assume number values.

Categorical values:

The variable assumes labels. Examples are yes/no, good/bad.

(I) Fuel economy (miles per gallon) of used car

(II) Number of auto insurance claims in a month

Both of these variables are numbers, none have labels, so they are both numeric. The correct answer is given by option 3).

Answer:

we have

secθ = 2

[tex] \frac{1}{cos θ} [/tex]=2

Cosθ =[tex] \frac{1}{2 }[/tex]

[tex] \frac{b}{h }=\frac{1}{2 }[/tex]

b=1

h=2

p=[tex] \sqrt{2²-1} = \sqrt{3} [/tex]

again

Cot θ=[tex] \frac{b}{p }[/tex]

Cot θ=[tex] \frac{1}{ \sqrt{3}} [/tex]

Cot θ=[tex] \frac{\sqrt{3}}{3} [/tex]

It lies in Quadrant III cot is positive

Cot θ=[tex] \frac{\sqrt{3}}{3} [/tex]

b. (sqrt 3)/3

Well formatted version of question:

Find the expected value of a random variable x having the following probability distribution.

x (-5,-1,0,1,5,8)

Probability (.12, .16, .28, .22, .12, .1)

Answer:

0.86

Step-by-step explanation:

The expected value E(X) is calculated as :

E(X) = Σ(x * p(x))

(-5)(0.12) + (-1)(0.16) + (0)(0.28) + 1(0.22) + 5(0.12) + 8(0.10)

-0.6 + -0.16 + 0 + 0.22 + 0.6 + 0.8

= 0.86

9514 1404 393

Answer:

  13, 22

Step-by-step explanation:

Let s represent the smaller. The sum of the numbers is ...

  s + (s+9) = 35

  2s = 26 . . . . . . subtract 9

  s = 13

  s+9 = 22

The two numbers are 13 and 22.

_____

Additional comment

As you can see, the smaller number is half the difference of the sum and difference: s = (35-9)/2. This is the generic solution to a "sum and difference" problem.

Answer:

0.433

Step-by-step explanation:

From the given information;

Let represent Urn 1 to be Q₁ ;

Urn 2 to be Q₂

and the event that a blue token is taken should be R

SO,

Given that:

Urn 1 comprises of 4 blue token and 9 red tokens,

Then, the probability of having a blue token | urn 1 picked is:

 [tex]P(R|Q_1) = \dfrac{4}{4+9}[/tex]

[tex]= \dfrac{4}{13}[/tex]

Urn 2 comprises of 12 blue token and 5 red tokens;

Thus [tex]P(R| Q_2) = \dfrac{12}{12+5}[/tex]

[tex]=\dfrac{12}{17}[/tex]

SO, if two coins are flipped, the probability of having two heads = [tex]\dfrac{1}{4}[/tex]

(since (H,H) is the only way)

Also, the probability of having at least one single tail = [tex]\dfrac{3}{4}[/tex]

(since (H,T), (T,H), (T,T) are the only possible outcome)

Thus: so far we knew:

[tex]P(Q_2) = \dfrac{1}{4} \\ \\ P(Q_2) = \dfrac{3}{4}[/tex]

We can now apply Naive-Bayes Theorem;

So, the probability P(of the token from Urn 2| the token is blue) = [tex]P(Q_2|R)[/tex]

[tex]P(Q_2|R) = \dfrac{P(R \cap Q_2)}{P(R)} \\ \\ = \dfrac{P(R|Q_2) * P(Q_2)}{P(R|Q_2) \ P(R_2) + P(R|Q_1) \ P(Q_1)} \\ \\ \\ \\ = \dfrac{\dfrac{12}{17} \times \dfrac{1}{4} }{\dfrac{12}{17} \times \dfrac{1}{4} + \dfrac{4}{13} \times \dfrac{3}{4}} \\ \\ \\ = \dfrac{13}{30}[/tex]

= 0.433

Number of ways to choose two colors of three colors when order of choice is relevant and relevant are 6 and 3 respectively.

Permutation refers to placing all members of a set in a particular order or choice of order. Combination is a way of selecting items from a collection, so the order of selection (unlike permutation) does not matter.  

Given,

Three colors, red, blue and green

a) Number of ways of choosing 2 colors out of three colors when order matter

= ³p₂

= 3!/(3-2)!

= (3×2×1)

= 6

b) a) Number of ways of choosing 2 colors out of three colors when order does not matter

= ³C₂

= 3!/(3-2)!2!

= (3×2×1)/(2×1)

= 3

Hence, when 6 and 3 are the number of ways to choose 2 colors from three colors when order matter and dose not matter respectively.

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Answer:

100degrees

Step-by-step explanation:

From the given diagram;

<2 = <6 (corresponding angle)

Since <6 + 80 = 180

<6 = 180 - 80

<6 = 100 degrees

Since <2 = <6, hence <2 = 100degrees

If you came for a short answer

A=1.50

B=1

a) Each jigsaw puzzle costs $1.5.

b) Each paddle ball paddle costs $1.

Given that Do-Nothing #1 paid $8 for 2 paddle ball paddles and 4 jigsaw puzzles.

Do-Nothing #2 paid $18 for 3 paddle ball paddles and 10 jigsaw puzzles.

We need to find how much each cost.

Let's solve the problem step by step.

Let's assume the cost of each jigsaw puzzle is 'x' dollars, and the cost of each paddle ball paddle is 'y' dollars.

According to the given information:

The first person paid $8 for 2 paddle ball paddles and 4 jigsaw puzzles. So, we can write the equation as:

2y + 4x = 8............. eq(i)

The second person paid $18 for 3 paddle ball paddles and 10 jigsaw puzzles. So, we can write the equation as:

3y + 10x = 18............. eq(ii)

Now, we can solve these two equations to find the values of 'x' and 'y'.

To do so, we can multiply Equation 1 by 3 and Equation 2 by 2 to eliminate the 'y' term:

6y + 12x = 24............. eq(iii)

6y + 20x = 36............. eq(iv)

Subtracting Equation 3 from Equation 4, we get:

6y + 20x - (6y + 12x) = 36 - 24

6y + 20x - 6y - 12x = 12

8x = 12

x = 12/8

x = 1.5

Now, substitute the value of 'x' back into Equation 1 to find 'y':

2y + 4(1.5) = 8

2y + 6 = 8

2y = 8 - 6

2y = 2

y = 2/2

y = 1

So, the cost of each jigsaw puzzle is $1.5, and the cost of each paddle ball paddle is $1.

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Answer:

Hello! In this picture I marked the new dot for that point and reflected it across the x axis!

The original coordinates are: 5, -3

and the new coordinates are: 5, 3

Hope that helps!